JavaScript new Date Ordinal (st, nd, rd, th)
If at all possible, without JavaScript libraries or lots of clunky code I am looking for the simplest way to format a date two weeks from now in the following format:
13th March 2013
The code I am using is:
var newdate = new Date(+new Date + 12096e5);
document.body.innerHTML = newdate;
which returns the date and time two weeks from now, but like this:
Wed Mar 27 2013 21:50:29 GMT+0000 (GMT Standard Time)
Here is the code in jsFiddle.
Any help would be appreciated!
javascript date ordinal-indicator
add a comment |
If at all possible, without JavaScript libraries or lots of clunky code I am looking for the simplest way to format a date two weeks from now in the following format:
13th March 2013
The code I am using is:
var newdate = new Date(+new Date + 12096e5);
document.body.innerHTML = newdate;
which returns the date and time two weeks from now, but like this:
Wed Mar 27 2013 21:50:29 GMT+0000 (GMT Standard Time)
Here is the code in jsFiddle.
Any help would be appreciated!
javascript date ordinal-indicator
apart from a missing "of" I have no problem with that date
– mplungjan
Mar 13 '13 at 22:05
try this stackoverflow.com/questions/1056728/…
– ebram khalil
Mar 13 '13 at 22:05
I was wondering how to do exactly the opposite ? I don't want to bring up new thread so if someone has the link I'd appreciate it
– v0d1ch
Nov 25 '14 at 13:40
add a comment |
If at all possible, without JavaScript libraries or lots of clunky code I am looking for the simplest way to format a date two weeks from now in the following format:
13th March 2013
The code I am using is:
var newdate = new Date(+new Date + 12096e5);
document.body.innerHTML = newdate;
which returns the date and time two weeks from now, but like this:
Wed Mar 27 2013 21:50:29 GMT+0000 (GMT Standard Time)
Here is the code in jsFiddle.
Any help would be appreciated!
javascript date ordinal-indicator
If at all possible, without JavaScript libraries or lots of clunky code I am looking for the simplest way to format a date two weeks from now in the following format:
13th March 2013
The code I am using is:
var newdate = new Date(+new Date + 12096e5);
document.body.innerHTML = newdate;
which returns the date and time two weeks from now, but like this:
Wed Mar 27 2013 21:50:29 GMT+0000 (GMT Standard Time)
Here is the code in jsFiddle.
Any help would be appreciated!
javascript date ordinal-indicator
javascript date ordinal-indicator
edited Aug 9 '18 at 22:37
dhilt
8,01742142
8,01742142
asked Mar 13 '13 at 22:02
user1635828user1635828
156124
156124
apart from a missing "of" I have no problem with that date
– mplungjan
Mar 13 '13 at 22:05
try this stackoverflow.com/questions/1056728/…
– ebram khalil
Mar 13 '13 at 22:05
I was wondering how to do exactly the opposite ? I don't want to bring up new thread so if someone has the link I'd appreciate it
– v0d1ch
Nov 25 '14 at 13:40
add a comment |
apart from a missing "of" I have no problem with that date
– mplungjan
Mar 13 '13 at 22:05
try this stackoverflow.com/questions/1056728/…
– ebram khalil
Mar 13 '13 at 22:05
I was wondering how to do exactly the opposite ? I don't want to bring up new thread so if someone has the link I'd appreciate it
– v0d1ch
Nov 25 '14 at 13:40
apart from a missing "of" I have no problem with that date
– mplungjan
Mar 13 '13 at 22:05
apart from a missing "of" I have no problem with that date
– mplungjan
Mar 13 '13 at 22:05
try this stackoverflow.com/questions/1056728/…
– ebram khalil
Mar 13 '13 at 22:05
try this stackoverflow.com/questions/1056728/…
– ebram khalil
Mar 13 '13 at 22:05
I was wondering how to do exactly the opposite ? I don't want to bring up new thread so if someone has the link I'd appreciate it
– v0d1ch
Nov 25 '14 at 13:40
I was wondering how to do exactly the opposite ? I don't want to bring up new thread so if someone has the link I'd appreciate it
– v0d1ch
Nov 25 '14 at 13:40
add a comment |
12 Answers
12
active
oldest
votes
Here:
JSFiddle
var fortnightAway = new Date(+new Date + 12096e5),
date = fortnightAway.getDate(),
month = ["January","February","March","April","May","June","July",
"August","September","October","November","December"][fortnightAway.getMonth()];
function nth(d)
if (d > 3 && d < 21) return 'th';
switch (d % 10)
case 1: return "st";
case 2: return "nd";
case 3: return "rd";
default: return "th";
document.body.innerHTML = date + nth(date) + " " +
month + " " +
fortnightAway.getFullYear();
2
Good work.... Thanks
– Elby
May 27 '14 at 6:03
Works perfect... +1 ford>3 && d<21
– ĆĦΔŇĐŘΔ ŇΔҜҜΔ
Apr 17 '15 at 10:25
For clarity, I'd probably code the exceptions as either: if (n == 11 || n == 12 || n == 13) return "th"; or: if (n >= 11 && n <= 13) return "th";
– krick
Dec 15 '16 at 22:36
That is missing 21,22,23
– mplungjan
Dec 16 '16 at 5:12
if (d == 0) return ''; ... if used outside of a date context
– John
Apr 13 '18 at 14:47
|
show 1 more comment
Here is a one liner inspired by the other answers. It is tested and will take 0 and negative numbers.
function getOrdinalNum(n)
return n + (n > 0 ? ['th', 'st', 'nd', 'rd'][(n > 3 && n < 21)
1
tested 1 to 31 and it works correctly
– johnc
Oct 22 '17 at 17:34
add a comment |
Lots of formatting answers, so I'll just work on the nth of any integer-
Number.prototype.nth= function()
if(this%1) return this;
var s= this%100;
if(s>3 && s<21) return this+'th';
switch(s%10)
case 1: return this+'st';
case 2: return this+'nd';
case 3: return this+'rd';
default: return this+'th';
The if is for teens, so 13 is 13th and not 13rd.
– kennebec
Mar 13 '13 at 22:32
Why thethis%1
? Mod 1 is always 0 so the statement will always fail, no?
– Forage
Mar 21 '18 at 11:10
add a comment |
I was doing this for dates as well, but because the day of month can only be between 1 and 31, I ended up with a simplified solution.
function dateOrdinal(dom) ;
or compact version using conditional operators
function dateOrdinal(d) 2==d?"nd":23==d;
http://jsben.ch/#/DrBpl
add a comment |
Lots of answers, here's another:
function addOrd(n)
// Return date string two weeks from now (14 days) in
// format 13th March 2013
function formatDatePlusTwoWeeks(d)
var months = ['January','February','March','April','May','June',
'July','August','September','October','November','December'];
// Copy date object so don't modify original
var e = new Date(d);
// Add two weeks (14 days)
e.setDate(e.getDate() + 14);
return addOrd(e.getDate()) + ' ' + months[e.getMonth()] + ' ' + e.getFullYear();
alert(formatDatePlusTwoWeeks(new Date(2013,2,13))); // 27th March 2013
add a comment |
I'm a bit late to the party, but this should work:
function ordinal(number)
number = Number(number)
if(!number
function specialFormat(date)
// add two weeks
date = new Date(+date + 12096e5)
var months = [
'January'
, 'February'
, 'March'
, 'April'
, 'May'
, 'June'
, 'July'
, 'August'
, 'September'
, 'October'
, 'November'
, 'December'
]
var formatted = ordinal(date.getDate())
formatted += ' ' + months[date.getMonth()]
return formatted + ' ' + date.getFullYear()
document.body.innerHTML = specialFormat(new Date())
add a comment |
As many has mentioned, here is another answer.
This is directly based on @kennebec's answer, which I found the most simplest way to get this date Ordinal generated for given JavaScript
date:
I created two prototype function
as follows:
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Note: just include the above prototype
functions within your JS Script
and use it as described bellow.
And whenever there is a JS
date I need to generate the date with date ordinal I use that prototype method as follows on that JS
date:
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
And it will print out date with date ordinal as shown in the following live demo:
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
.
add a comment |
A short and compact solution:
function format(date, tmp)
// 14 days from today
console.log('14 days from today: ' +
format(new Date(+new Date + 14 * 864e5)));
// test formatting for all dates within a month from today
var day = 864e5, today = +new Date;
for(var i = 0; i < 32; i++)
console.log('Today + ' + i + ': ' + format(new Date(today + i * day)))
(The compact regex-based approach for getting the ordinal suffix appears several places around the web, original source unknown)
add a comment |
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
add a comment |
Super simple functional implementation:
const ordinal = (d) =>
const nth = '1': 'st', '2': 'nd', '3': 'rd'
return `$d$nth[d] `
const monthNames = ['January','February','March','April','May','June','July','August','September','October','November','December']
const dateString = (date) => `$ordinal(date.getDate()) $monthNames[date.getMonth()] $date.getFullYear()`
// Use like this:
dateString(new Date()) // 18th July 2016
Unfortunately this method is too simple and doesn't work for days like the 21st.
– Tom
Oct 22 '16 at 23:36
add a comment |
Strongly inspired by @user2309185's.
const ordinal = (d) => 'th')
1
I found an issue with this,13
=13rd
– haakym
Feb 16 '17 at 22:39
add a comment |
Here is an easy solution:
var date = today.getDate() + (today.getDate() % 10 == 1 && today.getDate() != 11 ? + 'st': (today.getDate() % 10 == 2 && today.getDate() != 12 ? + 'nd':
(today.getDate() % 10 == 3 && today.getDate() != 13 ? + 'rd':'th')));
running this in scratchpad gives "today not defined."
– Nick
Jan 7 '18 at 6:22
add a comment |
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12 Answers
12
active
oldest
votes
12 Answers
12
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here:
JSFiddle
var fortnightAway = new Date(+new Date + 12096e5),
date = fortnightAway.getDate(),
month = ["January","February","March","April","May","June","July",
"August","September","October","November","December"][fortnightAway.getMonth()];
function nth(d)
if (d > 3 && d < 21) return 'th';
switch (d % 10)
case 1: return "st";
case 2: return "nd";
case 3: return "rd";
default: return "th";
document.body.innerHTML = date + nth(date) + " " +
month + " " +
fortnightAway.getFullYear();
2
Good work.... Thanks
– Elby
May 27 '14 at 6:03
Works perfect... +1 ford>3 && d<21
– ĆĦΔŇĐŘΔ ŇΔҜҜΔ
Apr 17 '15 at 10:25
For clarity, I'd probably code the exceptions as either: if (n == 11 || n == 12 || n == 13) return "th"; or: if (n >= 11 && n <= 13) return "th";
– krick
Dec 15 '16 at 22:36
That is missing 21,22,23
– mplungjan
Dec 16 '16 at 5:12
if (d == 0) return ''; ... if used outside of a date context
– John
Apr 13 '18 at 14:47
|
show 1 more comment
Here:
JSFiddle
var fortnightAway = new Date(+new Date + 12096e5),
date = fortnightAway.getDate(),
month = ["January","February","March","April","May","June","July",
"August","September","October","November","December"][fortnightAway.getMonth()];
function nth(d)
if (d > 3 && d < 21) return 'th';
switch (d % 10)
case 1: return "st";
case 2: return "nd";
case 3: return "rd";
default: return "th";
document.body.innerHTML = date + nth(date) + " " +
month + " " +
fortnightAway.getFullYear();
2
Good work.... Thanks
– Elby
May 27 '14 at 6:03
Works perfect... +1 ford>3 && d<21
– ĆĦΔŇĐŘΔ ŇΔҜҜΔ
Apr 17 '15 at 10:25
For clarity, I'd probably code the exceptions as either: if (n == 11 || n == 12 || n == 13) return "th"; or: if (n >= 11 && n <= 13) return "th";
– krick
Dec 15 '16 at 22:36
That is missing 21,22,23
– mplungjan
Dec 16 '16 at 5:12
if (d == 0) return ''; ... if used outside of a date context
– John
Apr 13 '18 at 14:47
|
show 1 more comment
Here:
JSFiddle
var fortnightAway = new Date(+new Date + 12096e5),
date = fortnightAway.getDate(),
month = ["January","February","March","April","May","June","July",
"August","September","October","November","December"][fortnightAway.getMonth()];
function nth(d)
if (d > 3 && d < 21) return 'th';
switch (d % 10)
case 1: return "st";
case 2: return "nd";
case 3: return "rd";
default: return "th";
document.body.innerHTML = date + nth(date) + " " +
month + " " +
fortnightAway.getFullYear();
Here:
JSFiddle
var fortnightAway = new Date(+new Date + 12096e5),
date = fortnightAway.getDate(),
month = ["January","February","March","April","May","June","July",
"August","September","October","November","December"][fortnightAway.getMonth()];
function nth(d)
if (d > 3 && d < 21) return 'th';
switch (d % 10)
case 1: return "st";
case 2: return "nd";
case 3: return "rd";
default: return "th";
document.body.innerHTML = date + nth(date) + " " +
month + " " +
fortnightAway.getFullYear();
var fortnightAway = new Date(+new Date + 12096e5),
date = fortnightAway.getDate(),
month = ["January","February","March","April","May","June","July",
"August","September","October","November","December"][fortnightAway.getMonth()];
function nth(d)
if (d > 3 && d < 21) return 'th';
switch (d % 10)
case 1: return "st";
case 2: return "nd";
case 3: return "rd";
default: return "th";
document.body.innerHTML = date + nth(date) + " " +
month + " " +
fortnightAway.getFullYear();
var fortnightAway = new Date(+new Date + 12096e5),
date = fortnightAway.getDate(),
month = ["January","February","March","April","May","June","July",
"August","September","October","November","December"][fortnightAway.getMonth()];
function nth(d)
if (d > 3 && d < 21) return 'th';
switch (d % 10)
case 1: return "st";
case 2: return "nd";
case 3: return "rd";
default: return "th";
document.body.innerHTML = date + nth(date) + " " +
month + " " +
fortnightAway.getFullYear();
edited Nov 12 '18 at 10:00
answered Mar 13 '13 at 22:11
mplungjanmplungjan
88.6k22126182
88.6k22126182
2
Good work.... Thanks
– Elby
May 27 '14 at 6:03
Works perfect... +1 ford>3 && d<21
– ĆĦΔŇĐŘΔ ŇΔҜҜΔ
Apr 17 '15 at 10:25
For clarity, I'd probably code the exceptions as either: if (n == 11 || n == 12 || n == 13) return "th"; or: if (n >= 11 && n <= 13) return "th";
– krick
Dec 15 '16 at 22:36
That is missing 21,22,23
– mplungjan
Dec 16 '16 at 5:12
if (d == 0) return ''; ... if used outside of a date context
– John
Apr 13 '18 at 14:47
|
show 1 more comment
2
Good work.... Thanks
– Elby
May 27 '14 at 6:03
Works perfect... +1 ford>3 && d<21
– ĆĦΔŇĐŘΔ ŇΔҜҜΔ
Apr 17 '15 at 10:25
For clarity, I'd probably code the exceptions as either: if (n == 11 || n == 12 || n == 13) return "th"; or: if (n >= 11 && n <= 13) return "th";
– krick
Dec 15 '16 at 22:36
That is missing 21,22,23
– mplungjan
Dec 16 '16 at 5:12
if (d == 0) return ''; ... if used outside of a date context
– John
Apr 13 '18 at 14:47
2
2
Good work.... Thanks
– Elby
May 27 '14 at 6:03
Good work.... Thanks
– Elby
May 27 '14 at 6:03
Works perfect... +1 for
d>3 && d<21
– ĆĦΔŇĐŘΔ ŇΔҜҜΔ
Apr 17 '15 at 10:25
Works perfect... +1 for
d>3 && d<21
– ĆĦΔŇĐŘΔ ŇΔҜҜΔ
Apr 17 '15 at 10:25
For clarity, I'd probably code the exceptions as either: if (n == 11 || n == 12 || n == 13) return "th"; or: if (n >= 11 && n <= 13) return "th";
– krick
Dec 15 '16 at 22:36
For clarity, I'd probably code the exceptions as either: if (n == 11 || n == 12 || n == 13) return "th"; or: if (n >= 11 && n <= 13) return "th";
– krick
Dec 15 '16 at 22:36
That is missing 21,22,23
– mplungjan
Dec 16 '16 at 5:12
That is missing 21,22,23
– mplungjan
Dec 16 '16 at 5:12
if (d == 0) return ''; ... if used outside of a date context
– John
Apr 13 '18 at 14:47
if (d == 0) return ''; ... if used outside of a date context
– John
Apr 13 '18 at 14:47
|
show 1 more comment
Here is a one liner inspired by the other answers. It is tested and will take 0 and negative numbers.
function getOrdinalNum(n)
return n + (n > 0 ? ['th', 'st', 'nd', 'rd'][(n > 3 && n < 21)
1
tested 1 to 31 and it works correctly
– johnc
Oct 22 '17 at 17:34
add a comment |
Here is a one liner inspired by the other answers. It is tested and will take 0 and negative numbers.
function getOrdinalNum(n)
return n + (n > 0 ? ['th', 'st', 'nd', 'rd'][(n > 3 && n < 21)
1
tested 1 to 31 and it works correctly
– johnc
Oct 22 '17 at 17:34
add a comment |
Here is a one liner inspired by the other answers. It is tested and will take 0 and negative numbers.
function getOrdinalNum(n)
return n + (n > 0 ? ['th', 'st', 'nd', 'rd'][(n > 3 && n < 21)
Here is a one liner inspired by the other answers. It is tested and will take 0 and negative numbers.
function getOrdinalNum(n)
return n + (n > 0 ? ['th', 'st', 'nd', 'rd'][(n > 3 && n < 21)
answered Jun 7 '17 at 17:00
The MartinThe Martin
16112
16112
1
tested 1 to 31 and it works correctly
– johnc
Oct 22 '17 at 17:34
add a comment |
1
tested 1 to 31 and it works correctly
– johnc
Oct 22 '17 at 17:34
1
1
tested 1 to 31 and it works correctly
– johnc
Oct 22 '17 at 17:34
tested 1 to 31 and it works correctly
– johnc
Oct 22 '17 at 17:34
add a comment |
Lots of formatting answers, so I'll just work on the nth of any integer-
Number.prototype.nth= function()
if(this%1) return this;
var s= this%100;
if(s>3 && s<21) return this+'th';
switch(s%10)
case 1: return this+'st';
case 2: return this+'nd';
case 3: return this+'rd';
default: return this+'th';
The if is for teens, so 13 is 13th and not 13rd.
– kennebec
Mar 13 '13 at 22:32
Why thethis%1
? Mod 1 is always 0 so the statement will always fail, no?
– Forage
Mar 21 '18 at 11:10
add a comment |
Lots of formatting answers, so I'll just work on the nth of any integer-
Number.prototype.nth= function()
if(this%1) return this;
var s= this%100;
if(s>3 && s<21) return this+'th';
switch(s%10)
case 1: return this+'st';
case 2: return this+'nd';
case 3: return this+'rd';
default: return this+'th';
The if is for teens, so 13 is 13th and not 13rd.
– kennebec
Mar 13 '13 at 22:32
Why thethis%1
? Mod 1 is always 0 so the statement will always fail, no?
– Forage
Mar 21 '18 at 11:10
add a comment |
Lots of formatting answers, so I'll just work on the nth of any integer-
Number.prototype.nth= function()
if(this%1) return this;
var s= this%100;
if(s>3 && s<21) return this+'th';
switch(s%10)
case 1: return this+'st';
case 2: return this+'nd';
case 3: return this+'rd';
default: return this+'th';
Lots of formatting answers, so I'll just work on the nth of any integer-
Number.prototype.nth= function()
if(this%1) return this;
var s= this%100;
if(s>3 && s<21) return this+'th';
switch(s%10)
case 1: return this+'st';
case 2: return this+'nd';
case 3: return this+'rd';
default: return this+'th';
edited Mar 13 '13 at 22:30
answered Mar 13 '13 at 22:14
kennebeckennebec
79.4k2186117
79.4k2186117
The if is for teens, so 13 is 13th and not 13rd.
– kennebec
Mar 13 '13 at 22:32
Why thethis%1
? Mod 1 is always 0 so the statement will always fail, no?
– Forage
Mar 21 '18 at 11:10
add a comment |
The if is for teens, so 13 is 13th and not 13rd.
– kennebec
Mar 13 '13 at 22:32
Why thethis%1
? Mod 1 is always 0 so the statement will always fail, no?
– Forage
Mar 21 '18 at 11:10
The if is for teens, so 13 is 13th and not 13rd.
– kennebec
Mar 13 '13 at 22:32
The if is for teens, so 13 is 13th and not 13rd.
– kennebec
Mar 13 '13 at 22:32
Why the
this%1
? Mod 1 is always 0 so the statement will always fail, no?– Forage
Mar 21 '18 at 11:10
Why the
this%1
? Mod 1 is always 0 so the statement will always fail, no?– Forage
Mar 21 '18 at 11:10
add a comment |
I was doing this for dates as well, but because the day of month can only be between 1 and 31, I ended up with a simplified solution.
function dateOrdinal(dom) ;
or compact version using conditional operators
function dateOrdinal(d) 2==d?"nd":23==d;
http://jsben.ch/#/DrBpl
add a comment |
I was doing this for dates as well, but because the day of month can only be between 1 and 31, I ended up with a simplified solution.
function dateOrdinal(dom) ;
or compact version using conditional operators
function dateOrdinal(d) 2==d?"nd":23==d;
http://jsben.ch/#/DrBpl
add a comment |
I was doing this for dates as well, but because the day of month can only be between 1 and 31, I ended up with a simplified solution.
function dateOrdinal(dom) ;
or compact version using conditional operators
function dateOrdinal(d) 2==d?"nd":23==d;
http://jsben.ch/#/DrBpl
I was doing this for dates as well, but because the day of month can only be between 1 and 31, I ended up with a simplified solution.
function dateOrdinal(dom) ;
or compact version using conditional operators
function dateOrdinal(d) 2==d?"nd":23==d;
http://jsben.ch/#/DrBpl
edited Feb 15 '17 at 23:06
answered Feb 15 '17 at 22:57
fredli74fredli74
213
213
add a comment |
add a comment |
Lots of answers, here's another:
function addOrd(n)
// Return date string two weeks from now (14 days) in
// format 13th March 2013
function formatDatePlusTwoWeeks(d)
var months = ['January','February','March','April','May','June',
'July','August','September','October','November','December'];
// Copy date object so don't modify original
var e = new Date(d);
// Add two weeks (14 days)
e.setDate(e.getDate() + 14);
return addOrd(e.getDate()) + ' ' + months[e.getMonth()] + ' ' + e.getFullYear();
alert(formatDatePlusTwoWeeks(new Date(2013,2,13))); // 27th March 2013
add a comment |
Lots of answers, here's another:
function addOrd(n)
// Return date string two weeks from now (14 days) in
// format 13th March 2013
function formatDatePlusTwoWeeks(d)
var months = ['January','February','March','April','May','June',
'July','August','September','October','November','December'];
// Copy date object so don't modify original
var e = new Date(d);
// Add two weeks (14 days)
e.setDate(e.getDate() + 14);
return addOrd(e.getDate()) + ' ' + months[e.getMonth()] + ' ' + e.getFullYear();
alert(formatDatePlusTwoWeeks(new Date(2013,2,13))); // 27th March 2013
add a comment |
Lots of answers, here's another:
function addOrd(n)
// Return date string two weeks from now (14 days) in
// format 13th March 2013
function formatDatePlusTwoWeeks(d)
var months = ['January','February','March','April','May','June',
'July','August','September','October','November','December'];
// Copy date object so don't modify original
var e = new Date(d);
// Add two weeks (14 days)
e.setDate(e.getDate() + 14);
return addOrd(e.getDate()) + ' ' + months[e.getMonth()] + ' ' + e.getFullYear();
alert(formatDatePlusTwoWeeks(new Date(2013,2,13))); // 27th March 2013
Lots of answers, here's another:
function addOrd(n)
// Return date string two weeks from now (14 days) in
// format 13th March 2013
function formatDatePlusTwoWeeks(d)
var months = ['January','February','March','April','May','June',
'July','August','September','October','November','December'];
// Copy date object so don't modify original
var e = new Date(d);
// Add two weeks (14 days)
e.setDate(e.getDate() + 14);
return addOrd(e.getDate()) + ' ' + months[e.getMonth()] + ' ' + e.getFullYear();
alert(formatDatePlusTwoWeeks(new Date(2013,2,13))); // 27th March 2013
answered Mar 13 '13 at 22:28
RobGRobG
98.4k19108146
98.4k19108146
add a comment |
add a comment |
I'm a bit late to the party, but this should work:
function ordinal(number)
number = Number(number)
if(!number
function specialFormat(date)
// add two weeks
date = new Date(+date + 12096e5)
var months = [
'January'
, 'February'
, 'March'
, 'April'
, 'May'
, 'June'
, 'July'
, 'August'
, 'September'
, 'October'
, 'November'
, 'December'
]
var formatted = ordinal(date.getDate())
formatted += ' ' + months[date.getMonth()]
return formatted + ' ' + date.getFullYear()
document.body.innerHTML = specialFormat(new Date())
add a comment |
I'm a bit late to the party, but this should work:
function ordinal(number)
number = Number(number)
if(!number
function specialFormat(date)
// add two weeks
date = new Date(+date + 12096e5)
var months = [
'January'
, 'February'
, 'March'
, 'April'
, 'May'
, 'June'
, 'July'
, 'August'
, 'September'
, 'October'
, 'November'
, 'December'
]
var formatted = ordinal(date.getDate())
formatted += ' ' + months[date.getMonth()]
return formatted + ' ' + date.getFullYear()
document.body.innerHTML = specialFormat(new Date())
add a comment |
I'm a bit late to the party, but this should work:
function ordinal(number)
number = Number(number)
if(!number
function specialFormat(date)
// add two weeks
date = new Date(+date + 12096e5)
var months = [
'January'
, 'February'
, 'March'
, 'April'
, 'May'
, 'June'
, 'July'
, 'August'
, 'September'
, 'October'
, 'November'
, 'December'
]
var formatted = ordinal(date.getDate())
formatted += ' ' + months[date.getMonth()]
return formatted + ' ' + date.getFullYear()
document.body.innerHTML = specialFormat(new Date())
I'm a bit late to the party, but this should work:
function ordinal(number)
number = Number(number)
if(!number
function specialFormat(date)
// add two weeks
date = new Date(+date + 12096e5)
var months = [
'January'
, 'February'
, 'March'
, 'April'
, 'May'
, 'June'
, 'July'
, 'August'
, 'September'
, 'October'
, 'November'
, 'December'
]
var formatted = ordinal(date.getDate())
formatted += ' ' + months[date.getMonth()]
return formatted + ' ' + date.getFullYear()
document.body.innerHTML = specialFormat(new Date())
edited Aug 8 '13 at 18:21
answered Aug 8 '13 at 18:15
GabeGabe
1365
1365
add a comment |
add a comment |
As many has mentioned, here is another answer.
This is directly based on @kennebec's answer, which I found the most simplest way to get this date Ordinal generated for given JavaScript
date:
I created two prototype function
as follows:
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Note: just include the above prototype
functions within your JS Script
and use it as described bellow.
And whenever there is a JS
date I need to generate the date with date ordinal I use that prototype method as follows on that JS
date:
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
And it will print out date with date ordinal as shown in the following live demo:
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
.
add a comment |
As many has mentioned, here is another answer.
This is directly based on @kennebec's answer, which I found the most simplest way to get this date Ordinal generated for given JavaScript
date:
I created two prototype function
as follows:
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Note: just include the above prototype
functions within your JS Script
and use it as described bellow.
And whenever there is a JS
date I need to generate the date with date ordinal I use that prototype method as follows on that JS
date:
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
And it will print out date with date ordinal as shown in the following live demo:
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
.
add a comment |
As many has mentioned, here is another answer.
This is directly based on @kennebec's answer, which I found the most simplest way to get this date Ordinal generated for given JavaScript
date:
I created two prototype function
as follows:
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Note: just include the above prototype
functions within your JS Script
and use it as described bellow.
And whenever there is a JS
date I need to generate the date with date ordinal I use that prototype method as follows on that JS
date:
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
And it will print out date with date ordinal as shown in the following live demo:
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
.
As many has mentioned, here is another answer.
This is directly based on @kennebec's answer, which I found the most simplest way to get this date Ordinal generated for given JavaScript
date:
I created two prototype function
as follows:
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Note: just include the above prototype
functions within your JS Script
and use it as described bellow.
And whenever there is a JS
date I need to generate the date with date ordinal I use that prototype method as follows on that JS
date:
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
And it will print out date with date ordinal as shown in the following live demo:
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
.
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
edited Oct 14 '15 at 20:05
answered Oct 14 '15 at 19:49
Randika VishmanRandika Vishman
4,72723958
4,72723958
add a comment |
add a comment |
A short and compact solution:
function format(date, tmp)
// 14 days from today
console.log('14 days from today: ' +
format(new Date(+new Date + 14 * 864e5)));
// test formatting for all dates within a month from today
var day = 864e5, today = +new Date;
for(var i = 0; i < 32; i++)
console.log('Today + ' + i + ': ' + format(new Date(today + i * day)))
(The compact regex-based approach for getting the ordinal suffix appears several places around the web, original source unknown)
add a comment |
A short and compact solution:
function format(date, tmp)
// 14 days from today
console.log('14 days from today: ' +
format(new Date(+new Date + 14 * 864e5)));
// test formatting for all dates within a month from today
var day = 864e5, today = +new Date;
for(var i = 0; i < 32; i++)
console.log('Today + ' + i + ': ' + format(new Date(today + i * day)))
(The compact regex-based approach for getting the ordinal suffix appears several places around the web, original source unknown)
add a comment |
A short and compact solution:
function format(date, tmp)
// 14 days from today
console.log('14 days from today: ' +
format(new Date(+new Date + 14 * 864e5)));
// test formatting for all dates within a month from today
var day = 864e5, today = +new Date;
for(var i = 0; i < 32; i++)
console.log('Today + ' + i + ': ' + format(new Date(today + i * day)))
(The compact regex-based approach for getting the ordinal suffix appears several places around the web, original source unknown)
A short and compact solution:
function format(date, tmp)
// 14 days from today
console.log('14 days from today: ' +
format(new Date(+new Date + 14 * 864e5)));
// test formatting for all dates within a month from today
var day = 864e5, today = +new Date;
for(var i = 0; i < 32; i++)
console.log('Today + ' + i + ': ' + format(new Date(today + i * day)))
(The compact regex-based approach for getting the ordinal suffix appears several places around the web, original source unknown)
function format(date, tmp)
// 14 days from today
console.log('14 days from today: ' +
format(new Date(+new Date + 14 * 864e5)));
// test formatting for all dates within a month from today
var day = 864e5, today = +new Date;
for(var i = 0; i < 32; i++)
console.log('Today + ' + i + ': ' + format(new Date(today + i * day)))
function format(date, tmp)
// 14 days from today
console.log('14 days from today: ' +
format(new Date(+new Date + 14 * 864e5)));
// test formatting for all dates within a month from today
var day = 864e5, today = +new Date;
for(var i = 0; i < 32; i++)
console.log('Today + ' + i + ': ' + format(new Date(today + i * day)))
edited May 16 '17 at 17:16
answered May 14 '17 at 19:33
Tomas LangkaasTomas Langkaas
2,5661725
2,5661725
add a comment |
add a comment |
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
add a comment |
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
add a comment |
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
Date.prototype.getMonthName = function(shorten)
var monthsNames = ["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"];
var monthIndex = this.getMonth();
var tempIndex = -1;
if (monthIndex == 0) tempIndex = 0 ;
if (monthIndex == 1) tempIndex = 1 ;
if (monthIndex == 2) tempIndex = 2 ;
if (monthIndex == 3) tempIndex = 3 ;
if (monthIndex == 4) tempIndex = 4 ;
if (monthIndex == 5) tempIndex = 5 ;
if (monthIndex == 6) tempIndex = 6 ;
if (monthIndex == 7) tempIndex = 7 ;
if (monthIndex == 8) tempIndex = 8 ;
if (monthIndex == 9) tempIndex = 9 ;
if (monthIndex == 10) tempIndex = 10 ;
if (monthIndex == 11) tempIndex = 11 ;
if (tempIndex > -1)
this.monthName = (shorten) ? monthsNames[tempIndex].substring(0, 3) : monthsNames[tempIndex];
else
this.monthName = "";
return this.monthName;
;
Date.prototype.getDateWithDateOrdinal = function()
var d = this.getDate(); // from here on I've used Kennebec's answer, but improved it.
if(d>3 && d<21) return d+'th';
switch (d % 10)
case 1: return d+"st";
case 2: return d+"nd";
case 3: return d+"rd";
default: return d+"th";
;
var myDate = new Date();
// You may have to check your JS Console in the web browser to see the following
console.log("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
// or I will update the Div. using jQuery
$('#date').html("date with date ordinal: "+myDate.getDateWithDateOrdinal()+" "+myDate.getMonthName()+" "+myDate.getFullYear());
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="date"></p>
answered Apr 14 '18 at 19:12
user3516819user3516819
12
12
add a comment |
add a comment |
Super simple functional implementation:
const ordinal = (d) =>
const nth = '1': 'st', '2': 'nd', '3': 'rd'
return `$d$nth[d] `
const monthNames = ['January','February','March','April','May','June','July','August','September','October','November','December']
const dateString = (date) => `$ordinal(date.getDate()) $monthNames[date.getMonth()] $date.getFullYear()`
// Use like this:
dateString(new Date()) // 18th July 2016
Unfortunately this method is too simple and doesn't work for days like the 21st.
– Tom
Oct 22 '16 at 23:36
add a comment |
Super simple functional implementation:
const ordinal = (d) =>
const nth = '1': 'st', '2': 'nd', '3': 'rd'
return `$d$nth[d] `
const monthNames = ['January','February','March','April','May','June','July','August','September','October','November','December']
const dateString = (date) => `$ordinal(date.getDate()) $monthNames[date.getMonth()] $date.getFullYear()`
// Use like this:
dateString(new Date()) // 18th July 2016
Unfortunately this method is too simple and doesn't work for days like the 21st.
– Tom
Oct 22 '16 at 23:36
add a comment |
Super simple functional implementation:
const ordinal = (d) =>
const nth = '1': 'st', '2': 'nd', '3': 'rd'
return `$d$nth[d] `
const monthNames = ['January','February','March','April','May','June','July','August','September','October','November','December']
const dateString = (date) => `$ordinal(date.getDate()) $monthNames[date.getMonth()] $date.getFullYear()`
// Use like this:
dateString(new Date()) // 18th July 2016
Super simple functional implementation:
const ordinal = (d) =>
const nth = '1': 'st', '2': 'nd', '3': 'rd'
return `$d$nth[d] `
const monthNames = ['January','February','March','April','May','June','July','August','September','October','November','December']
const dateString = (date) => `$ordinal(date.getDate()) $monthNames[date.getMonth()] $date.getFullYear()`
// Use like this:
dateString(new Date()) // 18th July 2016
answered Jul 19 '16 at 3:50
user2309185user2309185
1731210
1731210
Unfortunately this method is too simple and doesn't work for days like the 21st.
– Tom
Oct 22 '16 at 23:36
add a comment |
Unfortunately this method is too simple and doesn't work for days like the 21st.
– Tom
Oct 22 '16 at 23:36
Unfortunately this method is too simple and doesn't work for days like the 21st.
– Tom
Oct 22 '16 at 23:36
Unfortunately this method is too simple and doesn't work for days like the 21st.
– Tom
Oct 22 '16 at 23:36
add a comment |
Strongly inspired by @user2309185's.
const ordinal = (d) => 'th')
1
I found an issue with this,13
=13rd
– haakym
Feb 16 '17 at 22:39
add a comment |
Strongly inspired by @user2309185's.
const ordinal = (d) => 'th')
1
I found an issue with this,13
=13rd
– haakym
Feb 16 '17 at 22:39
add a comment |
Strongly inspired by @user2309185's.
const ordinal = (d) => 'th')
Strongly inspired by @user2309185's.
const ordinal = (d) => 'th')
answered Jan 26 '17 at 11:26
Adán Sánchez de Pedro CrespoAdán Sánchez de Pedro Crespo
273
273
1
I found an issue with this,13
=13rd
– haakym
Feb 16 '17 at 22:39
add a comment |
1
I found an issue with this,13
=13rd
– haakym
Feb 16 '17 at 22:39
1
1
I found an issue with this,
13
= 13rd
– haakym
Feb 16 '17 at 22:39
I found an issue with this,
13
= 13rd
– haakym
Feb 16 '17 at 22:39
add a comment |
Here is an easy solution:
var date = today.getDate() + (today.getDate() % 10 == 1 && today.getDate() != 11 ? + 'st': (today.getDate() % 10 == 2 && today.getDate() != 12 ? + 'nd':
(today.getDate() % 10 == 3 && today.getDate() != 13 ? + 'rd':'th')));
running this in scratchpad gives "today not defined."
– Nick
Jan 7 '18 at 6:22
add a comment |
Here is an easy solution:
var date = today.getDate() + (today.getDate() % 10 == 1 && today.getDate() != 11 ? + 'st': (today.getDate() % 10 == 2 && today.getDate() != 12 ? + 'nd':
(today.getDate() % 10 == 3 && today.getDate() != 13 ? + 'rd':'th')));
running this in scratchpad gives "today not defined."
– Nick
Jan 7 '18 at 6:22
add a comment |
Here is an easy solution:
var date = today.getDate() + (today.getDate() % 10 == 1 && today.getDate() != 11 ? + 'st': (today.getDate() % 10 == 2 && today.getDate() != 12 ? + 'nd':
(today.getDate() % 10 == 3 && today.getDate() != 13 ? + 'rd':'th')));
Here is an easy solution:
var date = today.getDate() + (today.getDate() % 10 == 1 && today.getDate() != 11 ? + 'st': (today.getDate() % 10 == 2 && today.getDate() != 12 ? + 'nd':
(today.getDate() % 10 == 3 && today.getDate() != 13 ? + 'rd':'th')));
edited Jan 7 '18 at 9:07
Ishan Thilina Somasiri
8381021
8381021
answered Jan 7 '18 at 6:00
JayJay
1
1
running this in scratchpad gives "today not defined."
– Nick
Jan 7 '18 at 6:22
add a comment |
running this in scratchpad gives "today not defined."
– Nick
Jan 7 '18 at 6:22
running this in scratchpad gives "today not defined."
– Nick
Jan 7 '18 at 6:22
running this in scratchpad gives "today not defined."
– Nick
Jan 7 '18 at 6:22
add a comment |
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apart from a missing "of" I have no problem with that date
– mplungjan
Mar 13 '13 at 22:05
try this stackoverflow.com/questions/1056728/…
– ebram khalil
Mar 13 '13 at 22:05
I was wondering how to do exactly the opposite ? I don't want to bring up new thread so if someone has the link I'd appreciate it
– v0d1ch
Nov 25 '14 at 13:40