How to impose a subtype not to include the super type?

How to impose a subtype not to include the super type?



Practical problem:

Let's imagine the client of a spectacle-house makes a reservation for a concert.

Some tickets for the concert have a seat.

The client brings a spouse.
Restriction:

1. Either both the ticket of the client and the corresponding spouse's ticket are seated OR both are not seated.

How do I impose this restriction at the typelevel?



What I initially thought:


case class Ticket[S <: Option[String]](id: String, seat: S)

case class ConcertReservation[A <: Option[String]](userTicket: Ticket[A],
spouseTicket: Ticket[A])

val concertReservation =
ConcertReservation(
userTicket = Ticket(id = "id1", seat = Some("<seatId>")),
spouseTicket = Ticket(id = "id2", seat = None)
)



With this I wanted to impose, via the type parameter A on ConcertReservation[A], that userTicket and spouseTicket must be of the same type.

Doing this allows the compiler to catch the above violation of the restriction:


ConcertReservation[A]


Error:(12, 26) type mismatch;
found : .....Temp.Ticket[Some[String]]
required: .....Ticket[Option[String]]
Note: Some[String] <: Option[String], but class Ticket is invariant in type S.
You may wish to define S as +S instead. (SLS 4.5)
userTicket = Ticket(id = "id1", seat = Some("assad")),



But it is possible to overcome this. For example with the code below (which compiles):


val concertReservation2: ConcertReservation[Option[String]] =
ConcertReservation(
userTicket = Ticket(id = "id1", seat = Some("assad")),
spouseTicket = Ticket(id = "id2", seat = None)
)



Is there a idiomatic way to achieve what I want? Some kind of "pattern" perhaps?

Thanks,






Maybe you should use assert? Write in the body of ConcertReservation validation logic assert((userTicket.nonEmpty && spouseTicket.nonEmpty) || (userTicket.isEmpty && spouseTicket.isEmpty))

– Aleksey Isachenkov
Sep 10 '18 at 17:16



assert


ConcertReservation


assert((userTicket.nonEmpty && spouseTicket.nonEmpty) || (userTicket.isEmpty && spouseTicket.isEmpty))






That would work in practice. Thanks for the trouble of answering. I am however looking for the type-level solution. The one that can be verified at compile time.

– Carlos Teixeira
Sep 10 '18 at 17:21






Also, you can create two subtypes of ConcertReservation with Some+Some and None+None reservations and make ConcertReservation abstract and sealed (like Option with its subclasses Some and None).

– Aleksey Isachenkov
Sep 10 '18 at 17:25



ConcertReservation


ConcertReservation






if you want a type restriction change ConcertReservation type parameter to [A <: Some[String]], the problem threre is that you cant assign a set with Option("id"), onyl Some("id")

– Sebastian Celestino
Sep 10 '18 at 17:46




3 Answers
3



If you copy the definition of =!= ("non-equal types") from this answer, you can then use it to make sure that A isn't Option[String]:


=!=


A


Option[String]


case class ConcertReservation[A <: Option[String]](userTicket: Ticket[A], spouseTicket: Ticket[A])
(implicit ev: A =!= Option[String])



This results in the expected behavior:


val seated1 = Ticket(id = "id1", seat = Some("1"))
val seated2 = Ticket(id = "id2", seat = Some("2"))
val unseated1 = Ticket(id = "id3", seat = None)
val unseated2 = Ticket(id = "id4", seat = None)

ConcertReservation(seated1, seated2) // compiles
ConcertReservation(unseated1, unseated2) // compiles
ConcertReservation(seated1, unseated1) // does not compile
ConcertReservation[Option[String]](seated1, unseated1) // does not compile either!



You can set up Ticket as a trait and then do some implicit type checking.


Ticket


trait


sealed trait Ticketval id: String
case class SeatedTicket(override val id: String, seat: String) extends Ticket
case class StandingTicket(override val id: String) extends Ticket



Next, you can take the type of the two parameters separately, and include an implicit check that they are equal as a parameter. You can also add a type inequality check to make sure the type isn't Ticket, but that will require you to include a library like shapeless, or do some more mucking around with the type system.


case class Reservation[T1 <: Ticket, T2 <: Ticket](user: T1, spouse: T2)(implicit ev: T1 =:= T2, ev2: T1 =:!= Ticket)



When T1 and T2 match, it works fine, but when they are different, the type system can pick up the error.


val sit1 = SeatedTicket("1","1A")
val sit2 = SeatedTicket("2","1B")
val stand1 = StandingTicket("3")
val stand2 = StandingTicket("4")
Reservation(sit1, sit2) //Runs fine
Reservation(stand1, stand2) //Runs fine
Reservation(sit1,stand1) //error: Cannot prove that SeatedTicket =:= StandingTicket.






But Reservation[Ticket, Ticket](sit1,stand1) would still compile, wouldn't it?

– Tzach Zohar
Sep 10 '18 at 18:28


Reservation[Ticket, Ticket](sit1,stand1)






@TzachZohar Oops, forgot to test that, you're right. I think it's fixable with a T1 =:!= Ticket check with shapeless, but don't currently have the time to verify. When I get a chance I'll verify then fix/delete this.

– Ethan
Sep 10 '18 at 19:12


T1 =:!= Ticket



As per my understanding of the problem, whether the seats are allocated or not is known only at the runtime, you cannot have a compile-time check for this.



But if you really want to achieve restriction for both or none, you should use:
seats: Option[(String, String)] or if you want to check on runtime then you can do some pattern matching over both the seats:


seats: Option[(String, String)]


val valid = (userTicket.seat, spouseTicket.seat) match
case (Some(_), Some(_))



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