How to search forked repos for repository using GitHub API?










0














I'm using GitHub API to search list of repositories forked from specific repository



For example I want to find list of all forked repositories (7,118) for Express.js using this query: https://api.github.com/search/repositories?q=repo:expressjs/express+fork:only



But this shows nothing in result:




"total_count": 0,
"incomplete_results": false,
"items": [

]



Is it possible to build such query?










share|improve this question


























    0














    I'm using GitHub API to search list of repositories forked from specific repository



    For example I want to find list of all forked repositories (7,118) for Express.js using this query: https://api.github.com/search/repositories?q=repo:expressjs/express+fork:only



    But this shows nothing in result:




    "total_count": 0,
    "incomplete_results": false,
    "items": [

    ]



    Is it possible to build such query?










    share|improve this question
























      0












      0








      0







      I'm using GitHub API to search list of repositories forked from specific repository



      For example I want to find list of all forked repositories (7,118) for Express.js using this query: https://api.github.com/search/repositories?q=repo:expressjs/express+fork:only



      But this shows nothing in result:




      "total_count": 0,
      "incomplete_results": false,
      "items": [

      ]



      Is it possible to build such query?










      share|improve this question













      I'm using GitHub API to search list of repositories forked from specific repository



      For example I want to find list of all forked repositories (7,118) for Express.js using this query: https://api.github.com/search/repositories?q=repo:expressjs/express+fork:only



      But this shows nothing in result:




      "total_count": 0,
      "incomplete_results": false,
      "items": [

      ]



      Is it possible to build such query?







      github github-api






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 10 '18 at 10:16









      Massimo

      268




      268






















          1 Answer
          1






          active

          oldest

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          1














          You can do it with Forks in REST API v3:



          https://api.github.com/repos/expressjs/express/forks


          I hope this can help you.






          share|improve this answer




















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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            You can do it with Forks in REST API v3:



            https://api.github.com/repos/expressjs/express/forks


            I hope this can help you.






            share|improve this answer

























              1














              You can do it with Forks in REST API v3:



              https://api.github.com/repos/expressjs/express/forks


              I hope this can help you.






              share|improve this answer























                1












                1








                1






                You can do it with Forks in REST API v3:



                https://api.github.com/repos/expressjs/express/forks


                I hope this can help you.






                share|improve this answer












                You can do it with Forks in REST API v3:



                https://api.github.com/repos/expressjs/express/forks


                I hope this can help you.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 10 '18 at 13:37









                Sm Yamashita

                180214




                180214



























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