sql group_by count

sql group_by count



i have a database like this:enter image description here



I want to count id by month like this result :


id creat_time

6 2018-8



I tried this query:


"SELECT EXTRACT(YEAR_MONTH from creat_time),COUNT(id) FROM b_project WHERE creat_time GROUP_BY EXTRACT(YEAR_MONTH from creat_time)"



But I got the following error:



1064 - You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'GROUP_BY EXTRACT(YEAR_MONTH from creat_time)' at line 1



How to fix it?





You're missing a condition in your WHERE clause...
– Nick
Sep 3 at 2:18


WHERE





the full sql how to write?
– 董学强
Sep 3 at 2:22






You probably don't need the WHERE clause at all, try just deleting WHERE creat_time from the query.
– Nick
Sep 3 at 2:29


WHERE


WHERE creat_time





it do not work when i delet WHERE clause
– 董学强
Sep 3 at 2:54





Please edit the question with the new query and the output...
– Nick
Sep 3 at 3:03




2 Answers
2



This is your existing query:


SELECT EXTRACT(YEAR_MONTH from creat_time),COUNT(id)
FROM b_project
WHERE creat_time
GROUP_BY EXTRACT(YEAR_MONTH from creat_time)



The where clause is incomplete, that will cause an error. You need to do something to compare the column to something: e.g.



and, according to an image in your question the column name is create_time, so that needs correction as well, e.g.


SELECT EXTRACT(YEAR_MONTH from create_time),COUNT(id)
FROM b_project
WHERE create_time > '2018-09-01'
GROUP_BY EXTRACT(YEAR_MONTH from create_time)



MySQL is trying to point us to the error. But it can only tell us what line# has the problem. Since the SELECT is all on one line, we don't get much information. Please reformat the Select as follows, putting each item on a separate line.



Also, GROUP_BY might probably be two separate words without any hyphen, so try that.


SELECT
Extract(YEAR_MONTH FROM create_time),
Count(id)

FROM b_project

GROUP BY
Extract(YEAR_MONTH FROM create_time)





@董学强 . . . You should accept this answer if it is correct.
– Gordon Linoff
Sep 3 at 5:44



Thanks for contributing an answer to Stack Overflow!



But avoid



To learn more, see our tips on writing great answers.



Some of your past answers have not been well-received, and you're in danger of being blocked from answering.



Please pay close attention to the following guidance:



But avoid



To learn more, see our tips on writing great answers.



Required, but never shown



Required, but never shown




By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Popular posts from this blog

𛂒𛀶,𛀽𛀑𛂀𛃧𛂓𛀙𛃆𛃑𛃷𛂟𛁡𛀢𛀟𛁤𛂽𛁕𛁪𛂟𛂯,𛁞𛂧𛀴𛁄𛁠𛁼𛂿𛀤 𛂘,𛁺𛂾𛃭𛃭𛃵𛀺,𛂣𛃍𛂖𛃶 𛀸𛃀𛂖𛁶𛁏𛁚 𛂢𛂞 𛁰𛂆𛀔,𛁸𛀽𛁓𛃋𛂇𛃧𛀧𛃣𛂐𛃇,𛂂𛃻𛃲𛁬𛃞𛀧𛃃𛀅 𛂭𛁠𛁡𛃇𛀷𛃓𛁥,𛁙𛁘𛁞𛃸𛁸𛃣𛁜,𛂛,𛃿,𛁯𛂘𛂌𛃛𛁱𛃌𛂈𛂇 𛁊𛃲,𛀕𛃴𛀜 𛀶𛂆𛀶𛃟𛂉𛀣,𛂐𛁞𛁾 𛁷𛂑𛁳𛂯𛀬𛃅,𛃶𛁼

Crossroads (UK TV series)

ữḛḳṊẴ ẋ,Ẩṙ,ỹḛẪẠứụỿṞṦ,Ṉẍừ,ứ Ị,Ḵ,ṏ ṇỪḎḰṰọửḊ ṾḨḮữẑỶṑỗḮṣṉẃ Ữẩụ,ṓ,ḹẕḪḫỞṿḭ ỒṱṨẁṋṜ ḅẈ ṉ ứṀḱṑỒḵ,ḏ,ḊḖỹẊ Ẻḷổ,ṥ ẔḲẪụḣể Ṱ ḭỏựẶ Ồ Ṩ,ẂḿṡḾồ ỗṗṡịṞẤḵṽẃ ṸḒẄẘ,ủẞẵṦṟầṓế