convert array with dict to variables

I have an array with dict

tag_list = ['Key': 'backup', 'Value': 'true',
'Key': 'backup_daily', 'Value': '7']


I'd like to convert it to variables, such as:

tag_backup = 'true'
tag_backup_daily = '7'


Any easy way to do that?

If no need to convert it to variables, any other better way to reference these key/value directly?

The best I want to do is to reference as below ways.

tag_list['backup'] = "true"
tag_list['backup_daily'] = "7"


Thanks to @Lev Zakharov 's answer, I did with below ways.

>>> new_list = x['Key']: x['Value'] for x in tag_list
>>> new_list['backup']
'true'
>>> new_list['backup_daily']
'7'


3 Answers
3

Use simple dict comprehension:

x['Key']:x['Value'] for x in tag_list


Result:

'backup': 'true', 'backup_daily': '7'


new_list = x['Key']:x['Value'] for x in tag_list['TagList']

You could use globals():

globals()

tag_list = ['Key': 'backup', 'Value': 'true',
'Key': 'backup_daily', 'Value': '7']

for x in tag_list:
globals()[f"tag_x['Key']"] = x['Value']

print(tag_backup) # true
print(tag_backup_daily) # 7


f

globals()['tag_Key'.format(**t)] = t['Value']

You just use a for loop

for

In [184]: def to_dict(tags):
...: d =
...: for t in tags:
...: d[t['Key']] = t['Value']
...: return d
...:

In [185]: to_dict(tag_list)
Out[185]: 'backup': 'true', 'backup_daily': '7'


You could also use map and lambda to create a container of tuples and then convert to a dict with its constructor

map

lambda

tuple

dict

In [178]: dict(map(lambda d: (d['Key'], d['Value']), tag_list))
Out[178]: 'backup': 'true', 'backup_daily': '7'


Note, that this is a lot slower due to the dict constructor

dict

In [207]: %timeit to_dict(tag_list)
The slowest run took 31.74 times longer than the fastest. This could mean that an intermediate result is being cached.
1000000 loops, best of 3: 431 ns per loop

In [181]: %timeit d['Key']: d['Value'] for d in tag_list
The slowest run took 44.42 times longer than the fastest. This could mean that an intermediate result is being cached.
1000000 loops, best of 3: 457 ns per loop

In [182]: %timeit dict(map(lambda d: (d['Key'], d['Value']), tag_list))
The slowest run took 7.72 times longer than the fastest. This could mean that an intermediate result is being cached.
1000000 loops, best of 3: 1.21 µs per loop


aws lambda

for

for loop

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