slice a list of strings from index[0] till random index

slice a list of strings from index[0] till random index



I am trying to slice a list of strings from index[0] till a random index.
The index number where the slicing needs to end, is always at the index number that holds a "(".
The code i'm trying is as follow


new_name = [[:x:] if x == "(" else x for x in new_name]



I always get invalid syntax error.
How can i make this work?



thx in advance





[:x:] why is this?
– Sandeep Kadapa
Sep 2 at 6:00


[:x:]





due to the fact that i don't know on what index number the "(" is, i thought that i could use x as an replacing value for the index number
– Falcjh
Sep 2 at 6:20





Please upvote and accept if any of the solutions provided your required result.
– Sandeep Kadapa
Nov 12 at 4:34


upvote and accept




2 Answers
2



The x variable in the for expression is assigned to each character in new_name for each iteration, not the index of each character.


x


for


new_name



For your purpose you should simply use the str.find() method to get the index of a given character in a string:


str.find()


new_name = new_name[:new_name.find('(')]



List Comprehension method:


l = list('sandeep(Kadapa)')

[i for i in iter(lambda x=iter(l): next(x),'(')]

['s', 'a', 'n', 'd', 'e', 'e', 'p']



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