slice a list of strings from index[0] till random index
slice a list of strings from index[0] till random index
I am trying to slice a list of strings from index[0] till a random index.
The index number where the slicing needs to end, is always at the index number that holds a "(".
The code i'm trying is as follow
new_name = [[:x:] if x == "(" else x for x in new_name]
I always get invalid syntax error.
How can i make this work?
thx in advance
[:x:]
due to the fact that i don't know on what index number the "(" is, i thought that i could use x as an replacing value for the index number
– Falcjh
Sep 2 at 6:20
Please
upvote and accept
if any of the solutions provided your required result.– Sandeep Kadapa
Nov 12 at 4:34
upvote and accept
2 Answers
2
The x
variable in the for
expression is assigned to each character in new_name
for each iteration, not the index of each character.
x
for
new_name
For your purpose you should simply use the str.find()
method to get the index of a given character in a string:
str.find()
new_name = new_name[:new_name.find('(')]
List Comprehension method:
l = list('sandeep(Kadapa)')
[i for i in iter(lambda x=iter(l): next(x),'(')]
['s', 'a', 'n', 'd', 'e', 'e', 'p']
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[:x:]
why is this?– Sandeep Kadapa
Sep 2 at 6:00