How to define an integer variable in networkx for a graph?
0
I am trying to draw an empty graph with n number of nodes.
I tried
e = nx.Graph()
for i in range (0,n):
e.add_node(n)
I tried adding n == int
I get this error TypeError: 'type' object cannot be interpreted as an integer
python-3.x networkx
edited Nov 8 at 20:29
darthbith
6,04342648
asked Nov 8 at 16:25
Pumpkinpeach
165
add a comment |
0
I am trying to draw an empty graph with n number of nodes.
I tried
e = nx.Graph()
for i in range (0,n):
e.add_node(n)
I tried adding n == int
I get this error TypeError: 'type' object cannot be interpreted as an integer
python-3.x networkx
edited Nov 8 at 20:29
darthbith
6,04342648
asked Nov 8 at 16:25
Pumpkinpeach
165
Your problem is that each time through the loop, you're adding noden, rather than nodei.
– Joel
Nov 8 at 17:49
Even if you change toe.add_node(i), your code can be improved... For example in pythonrange(0,n)is the same thing asrange(n).
– Joel
Nov 8 at 17:50
And networkx has a commandadd_nodes_fromwhich can add multiple nodes at once. So your loop could be replaced bye.add_nodes_from(range(n)).
– Joel
Nov 8 at 17:51
@pumpkinpeach Please stop tagging all of your questions with [anaconda], [jupyter], and [spyder] unless they specifically have something to do with those environments. These general questions apply to any Python environment or REPL, so should be left general. Thank you!
– darthbith
Nov 8 at 20:30
add a comment |
0
0
0
I am trying to draw an empty graph with n number of nodes.
I tried
e = nx.Graph()
for i in range (0,n):
e.add_node(n)
I tried adding n == int
I get this error TypeError: 'type' object cannot be interpreted as an integer
python-3.x networkx
edited Nov 8 at 20:29
darthbith
6,04342648
asked Nov 8 at 16:25
Pumpkinpeach
165
I am trying to draw an empty graph with n number of nodes.
I tried
e = nx.Graph()
for i in range (0,n):
e.add_node(n)
I tried adding n == int
I get this error TypeError: 'type' object cannot be interpreted as an integer
python-3.x networkx
python-3.x networkx
edited Nov 8 at 20:29
darthbith
6,04342648
asked Nov 8 at 16:25
Pumpkinpeach
165
edited Nov 8 at 20:29
darthbith
6,04342648
asked Nov 8 at 16:25
Pumpkinpeach
165
edited Nov 8 at 20:29
darthbith
6,04342648
edited Nov 8 at 20:29
darthbith
6,04342648
edited Nov 8 at 20:29
darthbith
6,04342648
6,04342648
asked Nov 8 at 16:25
Pumpkinpeach
165
asked Nov 8 at 16:25
Pumpkinpeach
165
asked Nov 8 at 16:25
Pumpkinpeach
165
165
Your problem is that each time through the loop, you're adding noden, rather than nodei.
– Joel
Nov 8 at 17:49
Even if you change toe.add_node(i), your code can be improved... For example in pythonrange(0,n)is the same thing asrange(n).
– Joel
Nov 8 at 17:50
And networkx has a commandadd_nodes_fromwhich can add multiple nodes at once. So your loop could be replaced bye.add_nodes_from(range(n)).
– Joel
Nov 8 at 17:51
@pumpkinpeach Please stop tagging all of your questions with [anaconda], [jupyter], and [spyder] unless they specifically have something to do with those environments. These general questions apply to any Python environment or REPL, so should be left general. Thank you!
– darthbith
Nov 8 at 20:30
add a comment |
Your problem is that each time through the loop, you're adding noden, rather than nodei.
– Joel
Nov 8 at 17:49
Even if you change toe.add_node(i), your code can be improved... For example in pythonrange(0,n)is the same thing asrange(n).
– Joel
Nov 8 at 17:50
And networkx has a commandadd_nodes_fromwhich can add multiple nodes at once. So your loop could be replaced bye.add_nodes_from(range(n)).
– Joel
Nov 8 at 17:51
@pumpkinpeach Please stop tagging all of your questions with [anaconda], [jupyter], and [spyder] unless they specifically have something to do with those environments. These general questions apply to any Python environment or REPL, so should be left general. Thank you!
– darthbith
Nov 8 at 20:30
Your problem is that each time through the loop, you're adding node
n, rather than node i.– Joel
Nov 8 at 17:49
Your problem is that each time through the loop, you're adding node
n, rather than node i.– Joel
Nov 8 at 17:49
Even if you change to
e.add_node(i), your code can be improved... For example in python range(0,n) is the same thing as range(n).– Joel
Nov 8 at 17:50
Even if you change to
e.add_node(i), your code can be improved... For example in python range(0,n) is the same thing as range(n).– Joel
Nov 8 at 17:50
And networkx has a command
add_nodes_from which can add multiple nodes at once. So your loop could be replaced by e.add_nodes_from(range(n)).– Joel
Nov 8 at 17:51
And networkx has a command
add_nodes_from which can add multiple nodes at once. So your loop could be replaced by e.add_nodes_from(range(n)).– Joel
Nov 8 at 17:51
@pumpkinpeach Please stop tagging all of your questions with [anaconda], [jupyter], and [spyder] unless they specifically have something to do with those environments. These general questions apply to any Python environment or REPL, so should be left general. Thank you!
– darthbith
Nov 8 at 20:30
@pumpkinpeach Please stop tagging all of your questions with [anaconda], [jupyter], and [spyder] unless they specifically have something to do with those environments. These general questions apply to any Python environment or REPL, so should be left general. Thank you!
– darthbith
Nov 8 at 20:30
add a comment |
1 Answer
1
active
oldest
votes
1
Try:
import networkx as nx
n = 10
e = nx.Graph()
for i in range (n):
e.add_node(i)
nx.draw_networkx(e)
Output:
answered Nov 8 at 17:28
Scott Boston
51.2k72955
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Try:
import networkx as nx
n = 10
e = nx.Graph()
for i in range (n):
e.add_node(i)
nx.draw_networkx(e)
Output:
answered Nov 8 at 17:28
Scott Boston
51.2k72955
add a comment |
1
Try:
import networkx as nx
n = 10
e = nx.Graph()
for i in range (n):
e.add_node(i)
nx.draw_networkx(e)
Output:
answered Nov 8 at 17:28
Scott Boston
51.2k72955
add a comment |
1
1
1
Try:
import networkx as nx
n = 10
e = nx.Graph()
for i in range (n):
e.add_node(i)
nx.draw_networkx(e)
Output:
answered Nov 8 at 17:28
Scott Boston
51.2k72955
Try:
import networkx as nx
n = 10
e = nx.Graph()
for i in range (n):
e.add_node(i)
nx.draw_networkx(e)
Output:
answered Nov 8 at 17:28
Scott Boston
51.2k72955
answered Nov 8 at 17:28
Scott Boston
51.2k72955
answered Nov 8 at 17:28
Scott Boston
51.2k72955
answered Nov 8 at 17:28
Scott Boston
51.2k72955
51.2k72955
add a comment |
add a comment |
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Your problem is that each time through the loop, you're adding node
n, rather than nodei.– Joel
Nov 8 at 17:49
Even if you change to
e.add_node(i), your code can be improved... For example in pythonrange(0,n)is the same thing asrange(n).– Joel
Nov 8 at 17:50
And networkx has a command
add_nodes_fromwhich can add multiple nodes at once. So your loop could be replaced bye.add_nodes_from(range(n)).– Joel
Nov 8 at 17:51
@pumpkinpeach Please stop tagging all of your questions with [anaconda], [jupyter], and [spyder] unless they specifically have something to do with those environments. These general questions apply to any Python environment or REPL, so should be left general. Thank you!
– darthbith
Nov 8 at 20:30