ProcessBuilder: process doesn't finish without “redirectOutput”
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I'm automating a gradle build using Java. I execute "gradlew.bat" in a Process created from a ProcessBuilder. Here's the code:
ProcessBuilder gradlewProcessBuilder = new ProcessBuilder(mainDirPath.concat("\android\gradlew.bat"), "assembleDebug");
gradlewProcessBuilder.directory(new File(mainDirPath.concat("/android")));
gradlewProcessBuilder.redirectOutput(ProcessBuilder.Redirect.INHERIT); //This is the line
Process gradlewProcess = gradlewProcessBuilder.start();
gradlewProcess.waitFor();
Now this code works flawlessly, but it outputs the gradle console through the application console and I don't want that. If I delete this line:
gradlewProcessBuilder.redirectOutput(ProcessBuilder.Redirect.INHERIT);
The process hangs in waitFor() indefinitely.
I have absolutely no idea how could redirectOutput have effect over this, any light you can shed is welcome.
java java-8 process processbuilder
asked Nov 8 at 19:55
Milanesa-chan
213
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0
down vote
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I'm automating a gradle build using Java. I execute "gradlew.bat" in a Process created from a ProcessBuilder. Here's the code:
ProcessBuilder gradlewProcessBuilder = new ProcessBuilder(mainDirPath.concat("\android\gradlew.bat"), "assembleDebug");
gradlewProcessBuilder.directory(new File(mainDirPath.concat("/android")));
gradlewProcessBuilder.redirectOutput(ProcessBuilder.Redirect.INHERIT); //This is the line
Process gradlewProcess = gradlewProcessBuilder.start();
gradlewProcess.waitFor();
Now this code works flawlessly, but it outputs the gradle console through the application console and I don't want that. If I delete this line:
gradlewProcessBuilder.redirectOutput(ProcessBuilder.Redirect.INHERIT);
The process hangs in waitFor() indefinitely.
I have absolutely no idea how could redirectOutput have effect over this, any light you can shed is welcome.
java java-8 process processbuilder
asked Nov 8 at 19:55
Milanesa-chan
213
1
If not redirecting the output, how is the output handled? See also When Runtime.exec() won't for many good tips on creating and handling a process correctly. Then ignore it refers toexecand use aProcessBuilderto create the process. Also break aString argintoString argsto account for things like paths containing space characters.
– Andrew Thompson
Nov 9 at 2:58
When you don’t redirect the output, you must read it. If you don’t, where’s the problem? Just redirect it. But you can do the whole thing as simple asnew ProcessBuilder(mainDirPath + "\android\gradlew.bat", "assembleDebug") .directory(new File(mainDirPath + "/android")) .inheritIO() .start() .waitFor()
– Holger
Nov 9 at 7:51
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm automating a gradle build using Java. I execute "gradlew.bat" in a Process created from a ProcessBuilder. Here's the code:
ProcessBuilder gradlewProcessBuilder = new ProcessBuilder(mainDirPath.concat("\android\gradlew.bat"), "assembleDebug");
gradlewProcessBuilder.directory(new File(mainDirPath.concat("/android")));
gradlewProcessBuilder.redirectOutput(ProcessBuilder.Redirect.INHERIT); //This is the line
Process gradlewProcess = gradlewProcessBuilder.start();
gradlewProcess.waitFor();
Now this code works flawlessly, but it outputs the gradle console through the application console and I don't want that. If I delete this line:
gradlewProcessBuilder.redirectOutput(ProcessBuilder.Redirect.INHERIT);
The process hangs in waitFor() indefinitely.
I have absolutely no idea how could redirectOutput have effect over this, any light you can shed is welcome.
java java-8 process processbuilder
asked Nov 8 at 19:55
Milanesa-chan
213
I'm automating a gradle build using Java. I execute "gradlew.bat" in a Process created from a ProcessBuilder. Here's the code:
ProcessBuilder gradlewProcessBuilder = new ProcessBuilder(mainDirPath.concat("\android\gradlew.bat"), "assembleDebug");
gradlewProcessBuilder.directory(new File(mainDirPath.concat("/android")));
gradlewProcessBuilder.redirectOutput(ProcessBuilder.Redirect.INHERIT); //This is the line
Process gradlewProcess = gradlewProcessBuilder.start();
gradlewProcess.waitFor();
Now this code works flawlessly, but it outputs the gradle console through the application console and I don't want that. If I delete this line:
gradlewProcessBuilder.redirectOutput(ProcessBuilder.Redirect.INHERIT);
The process hangs in waitFor() indefinitely.
I have absolutely no idea how could redirectOutput have effect over this, any light you can shed is welcome.
java java-8 process processbuilder
java java-8 process processbuilder
asked Nov 8 at 19:55
Milanesa-chan
213
asked Nov 8 at 19:55
Milanesa-chan
213
edited Nov 8 at 20:24
asked Nov 8 at 19:55
Milanesa-chan
213
asked Nov 8 at 19:55
Milanesa-chan
213
asked Nov 8 at 19:55
Milanesa-chan
213
213
1
If not redirecting the output, how is the output handled? See also When Runtime.exec() won't for many good tips on creating and handling a process correctly. Then ignore it refers toexecand use aProcessBuilderto create the process. Also break aString argintoString argsto account for things like paths containing space characters.
– Andrew Thompson
Nov 9 at 2:58
When you don’t redirect the output, you must read it. If you don’t, where’s the problem? Just redirect it. But you can do the whole thing as simple asnew ProcessBuilder(mainDirPath + "\android\gradlew.bat", "assembleDebug") .directory(new File(mainDirPath + "/android")) .inheritIO() .start() .waitFor()
– Holger
Nov 9 at 7:51
add a comment |
1
If not redirecting the output, how is the output handled? See also When Runtime.exec() won't for many good tips on creating and handling a process correctly. Then ignore it refers toexecand use aProcessBuilderto create the process. Also break aString argintoString argsto account for things like paths containing space characters.
– Andrew Thompson
Nov 9 at 2:58
When you don’t redirect the output, you must read it. If you don’t, where’s the problem? Just redirect it. But you can do the whole thing as simple asnew ProcessBuilder(mainDirPath + "\android\gradlew.bat", "assembleDebug") .directory(new File(mainDirPath + "/android")) .inheritIO() .start() .waitFor()
– Holger
Nov 9 at 7:51
1
1
If not redirecting the output, how is the output handled? See also When Runtime.exec() won't for many good tips on creating and handling a process correctly. Then ignore it refers to
exec and use a ProcessBuilder to create the process. Also break a String arg into String args to account for things like paths containing space characters.– Andrew Thompson
Nov 9 at 2:58
If not redirecting the output, how is the output handled? See also When Runtime.exec() won't for many good tips on creating and handling a process correctly. Then ignore it refers to
exec and use a ProcessBuilder to create the process. Also break a String arg into String args to account for things like paths containing space characters.– Andrew Thompson
Nov 9 at 2:58
When you don’t redirect the output, you must read it. If you don’t, where’s the problem? Just redirect it. But you can do the whole thing as simple as
new ProcessBuilder(mainDirPath + "\android\gradlew.bat", "assembleDebug") .directory(new File(mainDirPath + "/android")) .inheritIO() .start() .waitFor()– Holger
Nov 9 at 7:51
When you don’t redirect the output, you must read it. If you don’t, where’s the problem? Just redirect it. But you can do the whole thing as simple as
new ProcessBuilder(mainDirPath + "\android\gradlew.bat", "assembleDebug") .directory(new File(mainDirPath + "/android")) .inheritIO() .start() .waitFor()– Holger
Nov 9 at 7:51
add a comment |
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If not redirecting the output, how is the output handled? See also When Runtime.exec() won't for many good tips on creating and handling a process correctly. Then ignore it refers to
execand use aProcessBuilderto create the process. Also break aString argintoString argsto account for things like paths containing space characters.– Andrew Thompson
Nov 9 at 2:58
When you don’t redirect the output, you must read it. If you don’t, where’s the problem? Just redirect it. But you can do the whole thing as simple as
new ProcessBuilder(mainDirPath + "\android\gradlew.bat", "assembleDebug") .directory(new File(mainDirPath + "/android")) .inheritIO() .start() .waitFor()– Holger
Nov 9 at 7:51