Merge 3 arrays in to one

Merge 3 arrays in to one



I have a array like following Array i want to merge that array with another 2 arrays. i have tried with array merge function and it failed can you suggest any other way.


(
[0] => stdClass Object
(
[field_name] => mem_goup_name
[table_name] => membership_group
[field_id] => 15
)

[1] => stdClass Object
(
[field_name] => mem_group_description
[table_name] => membership_group
[field_id] => 17
)


)



And I want to set these 2 arrays to that former array


Array
(
[fiter_15] => 5
[fiter_17] => 2
)
Array
(
[operator_15] => 3
[operator_17] => 1
)



which means like this, (the key with the number must equal to the field_id).


[0] => stdClass Object
(
[field_name] => mem_goup_name
[table_name] => membership_group
[field_id] => 15,
[fiter_15] => 5,
[operator_15] => 3
)

[1] => stdClass Object
(
[field_name] => mem_group_description
[table_name] => membership_group
[field_id] => 17,
[fiter_17] => 2,
[operator_17] => 1
)



This is what I have tried so far.


$operator = array();
$filter = array();
$field_ids = array();

foreach ($fitered_values as $key => $value)

if (strpos($key, 'operator_') !== false)
$operator[$key] = $value;


if (strpos($key, 'fiter_') !== false)
$filter[$key] = $value;


if (strpos($key, 'field_ids_') !== false)
$field_ids[$key] = $value;







Have you tried any solutions?
– Rinsad Ahmed
Aug 24 at 4:01





@RinsadAhmed $operator = array(); $filter = array(); $field_ids = array(); foreach ($fitered_values as $key => $value) if (strpos($key, 'operator_') !== false) $operator[$key] = $value; if (strpos($key, 'fiter_') !== false) $filter[$key] = $value; if (strpos($key, 'field_ids_') !== false) $field_ids[$key] = $value;
– user8911972
Aug 24 at 4:03





Please edit your question with that.
– Rinsad Ahmed
Aug 24 at 4:03




2 Answers
2



You can loop the first array and use preg_grep to find the keys.

I grep the array_keys of array2 and the output is intersected to get the array items.

Then I merge it in to the main array1.


$arr2 = array_merge($filter, $operator);

foreach($arr1 as $key => $item)
$temp = preg_grep("/.*_" . $item['field_id'] . "/", Array_keys($arr2));
$arr1[$key] = array_merge($arr1[$key] , array_intersect_key($arr2, array_flip($temp)));

var_dump($arr1);



https://3v4l.org/3Inbb



Also, why do you have two accounts?
filter array by string and separate in to 2 arrays



Please check below and let me know if it works for you.


$arr1 = array(
0 => (object)array
(
'field_name' => 'mem_goup_name',
'table_name' => 'membership_group',
'field_id' => 15
),
1 => (object)array
(
'field_name' => 'mem_group_description',
'table_name' => 'membership_group',
'field_id' => 17
)
);


$arr2 = array
(
'fiter_15' => 5,
'fiter_17' => 2
);
$arr3 = array
(
'operator_15' => 3,
'operator_17' => 1
);

foreach( $arr1 as $key => $value )

$key1= 'filter_'.$value->field_id;
$key2 = 'operator_'.$value->field_id;
$arr1[$key]->$key1 = $arr2['fiter_'.$value->field_id];
$arr1[$key]->$key2 = $arr3['operator_'.$value->field_id];

print_r($arr1);





Preeti answers on SO should include what the answer does and not only "try this".
– Andreas
Aug 24 at 5:35





This code may give an notice that an array item does not exist if 'field_id' from the first array does not exist in the other two.
– Andreas
Aug 24 at 5:38






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