JQuery - Get value after delimiter alternative?
JQuery - Get value after delimiter alternative?
I've already searched this up before and tried using both pop()
and lastIndexOf
but it doesn't work well on looped dropdown.
pop()
lastIndexOf
Is there any alternative to getting the value after a delimiter, one that does not remove it from the list?
Here's my code:
$(document).ready(function ()
$('#VehicleID').change(function ()
var vehdrv = ($('#VehicleID :selected').val());
var drvid = vehdrv.split("_").pop();
var vehid = vehdrv.split("_")[0];
$('#VehicleID :selected').val(vehid);
//alert($('#VehicleID :selected').val());
if (drvid > 0)
$('#DriverID').find("option").show().not("option[value*='" + drvid + "']").hide();
$("#DriverID").val(drvid);
//$("#DriverID").val(
//$("#DriverID").find("option:visible:first").val())
else
$("#DriverID").find("option").show();
$("#DriverID").val(
$("#DriverID").find("option:visible:first").val())
).trigger("change");
)
My Dropdowns from the controller:
public ActionResult ReserveInitial()
ViewBag.VehicleID = db.Vehicles.Where(item => item.IsReserved == false).Select(a => new SelectListItem
Value = a.VehicleID.ToString() + "_" + a.DriverID.ToString(),
Text = a.VehicleMake + " - " + a.PlateNumber,
);
ViewBag.DriverID = db.Drivers.Select(a => new SelectListItem
Value = a.DriverID.ToString(),
Text = a.DriverLastName + ", " + a.DriverFirstName
);
return View();
EDIT
This is how the string would look like if the VehicleID is linked to a Driver:
"14_5"
if the VehicleID is not associated with a Driver it would look like this:
"15_0"
@ChrisCousins Thanks for the advice, added how the string would look like.
– Joshua
Aug 23 at 17:05
2 Answers
2
var parts = vehdrv.split("_");
var drvid = parts[1];
var vehid = parts[0];
Still the same result, it removes the drvid value after the same vehid value is picked again.
– Joshua
Aug 23 at 17:19
You can try this
var vehdrv = $('#VehicleID').val().match(/[^_]+/g);
var drvid = vehdrv[0];
var vehid = vehdrv[1];
console.log(drvid,vehid);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input id="VehicleID" type="text" value="14_5" name="text">
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When posting a question about finding element(s) in a string, please add in a couple of examples of what the original elements look like, for instance "xxx_yyy_zzz" or something. It is hard to deduce from your code what you expect the strings to look like.
– Chris Cousins
Aug 23 at 16:53