Applying a lower bound threshold on a list

Multi tool use
Multi tool use

Applying a lower bound threshold on a list



Consider the following list


list=0,0,0,10^-18,10^-15,10^-12,10^-10,1,1



How can I apply a threshold on the list that will give a lower bound for the values. For example


ApplyThreshold[list,10^-12];



will yield an outcome of


10^-12,10^-12,10^-12,10^-12,10^-12,10^-12,10^-10,1,1



and


ApplyThreshold[list,10^-9];



will yield an outcome of


10^-9,10^-9,10^-9,10^-9,10^-9,10^-9,10^-9,1,1




3 Answers
3



You can use Clip, Ramp or Max:


Clip


Ramp


Max


Clip[list, 10^-9, ∞]



1/1000000000, 1/1000000000, 1/1000000000, 1/1000000000,
1/1000000000, 1/1000000000, 1/1000000000, 1, 1


Ramp[list - 10^-9] + 10^-9 === Max[#, 10^-9] & /@ list === %



True



Timings:


SeedRandom[1]
lst = RandomReal[1, 100000];

(r1 = Ramp[lst - 10^-9] + 10^-9 ;) // RepeatedTiming // First



0.00017


(r2 = Clip[lst , 10^-9, Infinity];) // RepeatedTiming // First



0.000221


(r3 = Max[#, 10^-9] & /@ lst ;) // RepeatedTiming // First



0.129


(r4 = Map[crit[#, 1*10^-12] &, lst ];) // RepeatedTiming // First (* from Alexei's answer*)



0.185


r1 == r2 == r3 == r4



True



Try the following. This si your list:


lst = 0, 0, 0, 10^-18, 10^-15, 10^-12, 10^-10, 1, 1



This function transforms any number to what you want:


crit[x_, y_] := If[x >= y, x, y];



This applies it to the list:


Map[crit[#, 1*10^-12] &, lst]

(* 1/1000000000000, 1/1000000000000, 1/1000000000000, 1/1000000000000,
1/1000000000000, 1/1000000000000, 1/10000000000, 1, 1 *)



Here is another example of yours:


Map[crit[#, 1*10^-9] &, lst]

(* 1/1000000000, 1/1000000000, 1/1000000000, 1/1000000000,
1/1000000000, 1/1000000000, 1/1000000000, 1, 1 *)



Have fun!



You can do this succinctly with the ReplaceAll (/.) and Condition (/;) operators:


ReplaceAll (/.)


Condition (/;)


list /. x_ /; x < 10^-12 -> 10^-12






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