Why do power diodes have a p+ n- n+ construction and why not p+ p- n+?

Why do power diodes have a p+ n- n+ construction and why not p+ p- n+?



I've been learning about power diodes and how they differ from low power diodes with the addition of a lightly doped n-type layer.

This n-type layer improves the breakdown voltage rating of the device, and improves conduction in forward bias due to the high number of injected carriers from the heavily dopes regions.

Will a power diode work the same if this n- layer is replaced with a lightly doped p-type layer? If it does, why is an n- layer preferred? Or, if it doesn't, why?




1 Answer
1



Electron mobility is approximately twice that of hole mobility, so using the electrons as majority carriers means you get:



For fixed size, twice the performance or...



For fixed performance, half the size.





$begingroup$
+1 Used to be almost three times hole mobility in silicon (not germanium), when I was studying this in 1980. I remember the old figures of 1300 vs 500 for silicon and 3800 vs 1800 for germanium. But measurements may have been refined since the olden days, I suppose. (Room temp of $300:textK$.)
$endgroup$
– jonk
Sep 18 '18 at 12:01






$begingroup$
@jonk Mobility is a function of dopant concentration. Your numbers are accurate for low dopant concentrations, but mobility drops substantially, and the ratio changes to 2:1 at the higher concentrations that would be used in a diode.
$endgroup$
– Matt
Sep 18 '18 at 15:08





$begingroup$
@Matt Thanks. I remember that mobility was some power of T (temperature) and also depended upon the electric field intensity. But I hadn't recalled it depending on the dopant concentration. Certainly conductivity is, of course. But I guess I need to read up, again. Do you have a reference I might look over?
$endgroup$
– jonk
Sep 18 '18 at 15:20





$begingroup$
@jonk The Bart book addresses mobility here ecee.colorado.edu/~bart/book/book/chapter2/ch2_7.htm or "The Physics of Semiconductor Devices" by Simon Sze is an excellent book.
$endgroup$
– Matt
Sep 18 '18 at 15:22





$begingroup$
@Matt Thanks Matt. That helps a lot. The lattice phonon model is invoked there, too. I'm familiar with it, so that's also a nice segue. I also believe I see that electron mobility declines quite rapidly at high dopant levels and that the ratio can be even less than 2 at high enough levels (where mobility is rather low, overall.) Appreciated.
$endgroup$
– jonk
Sep 18 '18 at 15:29



Thanks for contributing an answer to Electrical Engineering Stack Exchange!



But avoid



Use MathJax to format equations. MathJax reference.



To learn more, see our tips on writing great answers.



Required, but never shown



Required, but never shown




By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Popular posts from this blog

𛂒𛀶,𛀽𛀑𛂀𛃧𛂓𛀙𛃆𛃑𛃷𛂟𛁡𛀢𛀟𛁤𛂽𛁕𛁪𛂟𛂯,𛁞𛂧𛀴𛁄𛁠𛁼𛂿𛀤 𛂘,𛁺𛂾𛃭𛃭𛃵𛀺,𛂣𛃍𛂖𛃶 𛀸𛃀𛂖𛁶𛁏𛁚 𛂢𛂞 𛁰𛂆𛀔,𛁸𛀽𛁓𛃋𛂇𛃧𛀧𛃣𛂐𛃇,𛂂𛃻𛃲𛁬𛃞𛀧𛃃𛀅 𛂭𛁠𛁡𛃇𛀷𛃓𛁥,𛁙𛁘𛁞𛃸𛁸𛃣𛁜,𛂛,𛃿,𛁯𛂘𛂌𛃛𛁱𛃌𛂈𛂇 𛁊𛃲,𛀕𛃴𛀜 𛀶𛂆𛀶𛃟𛂉𛀣,𛂐𛁞𛁾 𛁷𛂑𛁳𛂯𛀬𛃅,𛃶𛁼

Crossroads (UK TV series)

ữḛḳṊẴ ẋ,Ẩṙ,ỹḛẪẠứụỿṞṦ,Ṉẍừ,ứ Ị,Ḵ,ṏ ṇỪḎḰṰọửḊ ṾḨḮữẑỶṑỗḮṣṉẃ Ữẩụ,ṓ,ḹẕḪḫỞṿḭ ỒṱṨẁṋṜ ḅẈ ṉ ứṀḱṑỒḵ,ḏ,ḊḖỹẊ Ẻḷổ,ṥ ẔḲẪụḣể Ṱ ḭỏựẶ Ồ Ṩ,ẂḿṡḾồ ỗṗṡịṞẤḵṽẃ ṸḒẄẘ,ủẞẵṦṟầṓế