comparing the return value of fgetc() to a random digit

I am trying to read a file until i hit a random int between 1 and 5 and then read the word next to that int into an array. Before trying to compare a random int with the return value of fgetc(), the code was working well (It read chars into an array until an end of line). Now, when i am in the debugger, i see that the return value of fgetc() for the integers i am looking for is the ASCII decimal value, not the actual integer. So when i compare with the random int, it is never found. I don't understand how to get this right. Here is the code, sorry for the comments being in french, they are not relevant.

int lectureMot(FILE *listePtr, char motsecret)

int caracLu;
int nbLettres = 0;
int numRand;
numRand = rand()%((6-1)+1);

/*Ouverture du fichier texte de la liste*/
listePtr = fopen("Liste.txt","r");

/*Verification de l'ouverture du fichier*/
if (listePtr == NULL)

printf("Erreur a l'ouverture de la liste");
return(EXIT_FAILURE);

else

/*Lire jusqu'au nombre random*/
while((caracLu = fgetc(listePtr)) != numRand);

/*Lire le mot et le mettre dans le tableau*/
while((caracLu = fgetc(listePtr)) != 'n')

motsecret[nbLettres] = (char)caracLu;
nbLettres = ++nbLettres;


/*Fermeture du fichier liste*/
fclose(listePtr);
return nbLettres;



1 Answer
1

Just add '0' character to your digit:

Change

numRand = rand()%((6-1)+1);


to

numRand = (rand()%((6-1)+1)) + '0';


'0'

rand()%((6-1)+1)

'0'

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