Misunderstanding of percentage increase [duplicate]
$begingroup$
This question already has an answer here:
Meaning of “Percent increase”
1 answer
If something increase $50$ to $200$, I know that it is $400%$ increment using common sense.
I can get this using $dfrac20050times 100% = 400%$.
If something increase $50$ to $52$, I know that it is $4%$ increment using common sense.
But if I apply the same logic, $dfrac5250times 100% = 104%$.
What is the problem in my logic?
percentages
edited Aug 29 '18 at 0:30
Chase Ryan Taylor
4,43721531
asked Aug 28 '18 at 6:54
I am the Most Stupid PersonI am the Most Stupid Person
25327
$endgroup$
marked as duplicate by Delta-u, Adrian Keister, José Carlos Santos, Strants, sds Aug 29 '18 at 17:50
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
|
show 7 more comments
$begingroup$
This question already has an answer here:
Meaning of “Percent increase”
1 answer
If something increase $50$ to $200$, I know that it is $400%$ increment using common sense.
I can get this using $dfrac20050times 100% = 400%$.
If something increase $50$ to $52$, I know that it is $4%$ increment using common sense.
But if I apply the same logic, $dfrac5250times 100% = 104%$.
What is the problem in my logic?
percentages
edited Aug 29 '18 at 0:30
Chase Ryan Taylor
4,43721531
asked Aug 28 '18 at 6:54
I am the Most Stupid PersonI am the Most Stupid Person
25327
$endgroup$
marked as duplicate by Delta-u, Adrian Keister, José Carlos Santos, Strants, sds Aug 29 '18 at 17:50
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
25
$begingroup$
It is worth mentioning that your mistake is very common. For small increases, the percentage is usually correct. As the increase gets larger, mistakes become frequent. It is common to confuse $4$ times bigger with $400 %$ more. Think about $100 %$ bigger which means double and not the same.
$endgroup$
– badjohn
Aug 28 '18 at 7:56
$begingroup$
@badjohn Yes, Even after doing maths for AL and even after getting "B" grade I am really ashamed of myself.
$endgroup$
– I am the Most Stupid Person
Aug 28 '18 at 8:22
2
$begingroup$
Don't be too harsh on yourself, as I said, it is a common mistake. An interesting question is at what point people tend to switch. $100 %$ is usually correctly interpreted as double. By your example of $400 %$, the mistake is common. How is $200 %$ commonly perceived?
$endgroup$
– badjohn
Aug 28 '18 at 9:32
8
$begingroup$
Note that the other words around the percent number itself make a big difference. $200$ is $400%$ of $50$, but $200$ is a $300%$ increase from $50$, or is $300%$ more than $50$. $52$ is $104%$ of $50$, but $52$ is a $4%$ increase from $50$, or is $4%$ more than $50$. "Percent more than" is equal to "percent of" minus $100$.
$endgroup$
– Todd Wilcox
Aug 28 '18 at 13:19
1
$begingroup$
I have heard an anecdotal story on percentage increase: There was a debate on "Do law students have to study Mathematics?" The lawyer claimed it was not necessary for them. The mathematician asked him the question: "Last year there were $80$ crimes, this year there were $100$ crimes. How much percentage increase is this?" The lawyer quickly and with confidence replied "$20$ percent"... The moral of the story is the mathematics is necessary for each and every subject and profession.
$endgroup$
– farruhota
Aug 28 '18 at 14:31
|
show 7 more comments
$begingroup$
This question already has an answer here:
Meaning of “Percent increase”
1 answer
If something increase $50$ to $200$, I know that it is $400%$ increment using common sense.
I can get this using $dfrac20050times 100% = 400%$.
If something increase $50$ to $52$, I know that it is $4%$ increment using common sense.
But if I apply the same logic, $dfrac5250times 100% = 104%$.
What is the problem in my logic?
percentages
edited Aug 29 '18 at 0:30
Chase Ryan Taylor
4,43721531
asked Aug 28 '18 at 6:54
I am the Most Stupid PersonI am the Most Stupid Person
25327
$endgroup$
This question already has an answer here:
Meaning of “Percent increase”
1 answer
If something increase $50$ to $200$, I know that it is $400%$ increment using common sense.
I can get this using $dfrac20050times 100% = 400%$.
If something increase $50$ to $52$, I know that it is $4%$ increment using common sense.
But if I apply the same logic, $dfrac5250times 100% = 104%$.
What is the problem in my logic?
This question already has an answer here:
Meaning of “Percent increase”
1 answer
percentages
percentages
edited Aug 29 '18 at 0:30
Chase Ryan Taylor
4,43721531
asked Aug 28 '18 at 6:54
I am the Most Stupid PersonI am the Most Stupid Person
25327
edited Aug 29 '18 at 0:30
Chase Ryan Taylor
4,43721531
asked Aug 28 '18 at 6:54
I am the Most Stupid PersonI am the Most Stupid Person
25327
edited Aug 29 '18 at 0:30
Chase Ryan Taylor
4,43721531
edited Aug 29 '18 at 0:30
Chase Ryan Taylor
4,43721531
edited Aug 29 '18 at 0:30
Chase Ryan Taylor
4,43721531
4,43721531
asked Aug 28 '18 at 6:54
I am the Most Stupid PersonI am the Most Stupid Person
25327
asked Aug 28 '18 at 6:54
I am the Most Stupid PersonI am the Most Stupid Person
25327
asked Aug 28 '18 at 6:54
I am the Most Stupid PersonI am the Most Stupid Person
25327
25327
marked as duplicate by Delta-u, Adrian Keister, José Carlos Santos, Strants, sds Aug 29 '18 at 17:50
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Delta-u, Adrian Keister, José Carlos Santos, Strants, sds Aug 29 '18 at 17:50
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
25
$begingroup$
It is worth mentioning that your mistake is very common. For small increases, the percentage is usually correct. As the increase gets larger, mistakes become frequent. It is common to confuse $4$ times bigger with $400 %$ more. Think about $100 %$ bigger which means double and not the same.
$endgroup$
– badjohn
Aug 28 '18 at 7:56
$begingroup$
@badjohn Yes, Even after doing maths for AL and even after getting "B" grade I am really ashamed of myself.
$endgroup$
– I am the Most Stupid Person
Aug 28 '18 at 8:22
2
$begingroup$
Don't be too harsh on yourself, as I said, it is a common mistake. An interesting question is at what point people tend to switch. $100 %$ is usually correctly interpreted as double. By your example of $400 %$, the mistake is common. How is $200 %$ commonly perceived?
$endgroup$
– badjohn
Aug 28 '18 at 9:32
8
$begingroup$
Note that the other words around the percent number itself make a big difference. $200$ is $400%$ of $50$, but $200$ is a $300%$ increase from $50$, or is $300%$ more than $50$. $52$ is $104%$ of $50$, but $52$ is a $4%$ increase from $50$, or is $4%$ more than $50$. "Percent more than" is equal to "percent of" minus $100$.
$endgroup$
– Todd Wilcox
Aug 28 '18 at 13:19
1
$begingroup$
I have heard an anecdotal story on percentage increase: There was a debate on "Do law students have to study Mathematics?" The lawyer claimed it was not necessary for them. The mathematician asked him the question: "Last year there were $80$ crimes, this year there were $100$ crimes. How much percentage increase is this?" The lawyer quickly and with confidence replied "$20$ percent"... The moral of the story is the mathematics is necessary for each and every subject and profession.
$endgroup$
– farruhota
Aug 28 '18 at 14:31
|
show 7 more comments
25
$begingroup$
It is worth mentioning that your mistake is very common. For small increases, the percentage is usually correct. As the increase gets larger, mistakes become frequent. It is common to confuse $4$ times bigger with $400 %$ more. Think about $100 %$ bigger which means double and not the same.
$endgroup$
– badjohn
Aug 28 '18 at 7:56
$begingroup$
@badjohn Yes, Even after doing maths for AL and even after getting "B" grade I am really ashamed of myself.
$endgroup$
– I am the Most Stupid Person
Aug 28 '18 at 8:22
2
$begingroup$
Don't be too harsh on yourself, as I said, it is a common mistake. An interesting question is at what point people tend to switch. $100 %$ is usually correctly interpreted as double. By your example of $400 %$, the mistake is common. How is $200 %$ commonly perceived?
$endgroup$
– badjohn
Aug 28 '18 at 9:32
8
$begingroup$
Note that the other words around the percent number itself make a big difference. $200$ is $400%$ of $50$, but $200$ is a $300%$ increase from $50$, or is $300%$ more than $50$. $52$ is $104%$ of $50$, but $52$ is a $4%$ increase from $50$, or is $4%$ more than $50$. "Percent more than" is equal to "percent of" minus $100$.
$endgroup$
– Todd Wilcox
Aug 28 '18 at 13:19
1
$begingroup$
I have heard an anecdotal story on percentage increase: There was a debate on "Do law students have to study Mathematics?" The lawyer claimed it was not necessary for them. The mathematician asked him the question: "Last year there were $80$ crimes, this year there were $100$ crimes. How much percentage increase is this?" The lawyer quickly and with confidence replied "$20$ percent"... The moral of the story is the mathematics is necessary for each and every subject and profession.
$endgroup$
– farruhota
Aug 28 '18 at 14:31
25
25
$begingroup$
It is worth mentioning that your mistake is very common. For small increases, the percentage is usually correct. As the increase gets larger, mistakes become frequent. It is common to confuse $4$ times bigger with $400 %$ more. Think about $100 %$ bigger which means double and not the same.
$endgroup$
– badjohn
Aug 28 '18 at 7:56
$begingroup$
It is worth mentioning that your mistake is very common. For small increases, the percentage is usually correct. As the increase gets larger, mistakes become frequent. It is common to confuse $4$ times bigger with $400 %$ more. Think about $100 %$ bigger which means double and not the same.
$endgroup$
– badjohn
Aug 28 '18 at 7:56
$begingroup$
@badjohn Yes, Even after doing maths for AL and even after getting "B" grade I am really ashamed of myself.
$endgroup$
– I am the Most Stupid Person
Aug 28 '18 at 8:22
$begingroup$
@badjohn Yes, Even after doing maths for AL and even after getting "B" grade I am really ashamed of myself.
$endgroup$
– I am the Most Stupid Person
Aug 28 '18 at 8:22
2
2
$begingroup$
Don't be too harsh on yourself, as I said, it is a common mistake. An interesting question is at what point people tend to switch. $100 %$ is usually correctly interpreted as double. By your example of $400 %$, the mistake is common. How is $200 %$ commonly perceived?
$endgroup$
– badjohn
Aug 28 '18 at 9:32
$begingroup$
Don't be too harsh on yourself, as I said, it is a common mistake. An interesting question is at what point people tend to switch. $100 %$ is usually correctly interpreted as double. By your example of $400 %$, the mistake is common. How is $200 %$ commonly perceived?
$endgroup$
– badjohn
Aug 28 '18 at 9:32
8
8
$begingroup$
Note that the other words around the percent number itself make a big difference. $200$ is $400%$ of $50$, but $200$ is a $300%$ increase from $50$, or is $300%$ more than $50$. $52$ is $104%$ of $50$, but $52$ is a $4%$ increase from $50$, or is $4%$ more than $50$. "Percent more than" is equal to "percent of" minus $100$.
$endgroup$
– Todd Wilcox
Aug 28 '18 at 13:19
$begingroup$
Note that the other words around the percent number itself make a big difference. $200$ is $400%$ of $50$, but $200$ is a $300%$ increase from $50$, or is $300%$ more than $50$. $52$ is $104%$ of $50$, but $52$ is a $4%$ increase from $50$, or is $4%$ more than $50$. "Percent more than" is equal to "percent of" minus $100$.
$endgroup$
– Todd Wilcox
Aug 28 '18 at 13:19
1
1
$begingroup$
I have heard an anecdotal story on percentage increase: There was a debate on "Do law students have to study Mathematics?" The lawyer claimed it was not necessary for them. The mathematician asked him the question: "Last year there were $80$ crimes, this year there were $100$ crimes. How much percentage increase is this?" The lawyer quickly and with confidence replied "$20$ percent"... The moral of the story is the mathematics is necessary for each and every subject and profession.
$endgroup$
– farruhota
Aug 28 '18 at 14:31
$begingroup$
I have heard an anecdotal story on percentage increase: There was a debate on "Do law students have to study Mathematics?" The lawyer claimed it was not necessary for them. The mathematician asked him the question: "Last year there were $80$ crimes, this year there were $100$ crimes. How much percentage increase is this?" The lawyer quickly and with confidence replied "$20$ percent"... The moral of the story is the mathematics is necessary for each and every subject and profession.
$endgroup$
– farruhota
Aug 28 '18 at 14:31
|
show 7 more comments
6 Answers
6
active
oldest
votes
$begingroup$
Percentage increase is $$fractextnew number - old numbertextold numbertimes 100 %$$
The right comptuation should be $$frac200-5050 times 100 %=300%$$
answered Aug 28 '18 at 6:56
Siong Thye GohSiong Thye Goh
103k1468119
$endgroup$
add a comment |
$begingroup$
If something increases from $50$ to $200$, it increases by $300%$ and has a new value that is $400%$ of the old value.
Similarly, if something increases from $50$ to $52$, it increases by $4%$ to a new value that is $104%$ of the old one.
answered Aug 28 '18 at 7:11
5xum5xum
91.5k394161
$endgroup$
add a comment |
$begingroup$
The convention is that "percentage increase" is the number of percentage points that are added.
So it is assumed that you always start with $100%$ of a number and then add an $n%$ percent increase to that, so you end up with $(100 + n)%$ of the original number.
If you take the ratio of the starting and ending amounts and multiply by $100%,$
you end up with the figure $(100 + n)%.$ You then have to subtract $100%$ if what you want is the percentage increase.
Indeed $52$ is $104%$ of $50,$ but the added amount is only $2,$ which is $4%$ of $50.$
Likewise $200$ is $400%$ of $50,$ but the added amount is only $150,$ which is $300%$ of $50.$
answered Aug 28 '18 at 13:57
David KDavid K
55.3k344120
$endgroup$
add a comment |
$begingroup$
You are making the classic mistake of confusing ratio with change.
$ratio = fracnew;valueold;value$
$percentage;ratio = fracnew;valueold;value times 100%$
$difference = new;value - old;value$
$percentage;change = fracdifferenceold;value times 100% = fracnew;value - old;valueold;value times 100%$
Change is more commonly known as growth or increase.
answered Aug 28 '18 at 14:26
Peter PaffPeter Paff
1812
$endgroup$
add a comment |
$begingroup$
This is were the ratio makes more sense
That is when
50:400
are divided one both sides by 50 giving us
1:8
so my understanding is that it is eight times more.
answered Aug 29 '18 at 4:03
Brahm BothmaBrahm Bothma
215
$endgroup$
1
$begingroup$
50/400 reduces to 1/8 not 1/4
$endgroup$
– Peter Paff
Jan 31 at 13:28
$begingroup$
Thank you - applied your correction. Peter Paff.
$endgroup$
– Brahm Bothma
Feb 6 at 14:19
add a comment |
$begingroup$
If you see your question, you'll see that you have answered it yourself. In the second statement, you said 50 to 52 increment means 4% which is equal to 100 subtracted from 104 which you have calculated. Similarly, if you subtract 100 from 400 you will get 300%.
answered Aug 28 '18 at 18:52
DeveshDevesh
211
$endgroup$
add a comment |
6 Answers
6
active
oldest
votes
6 Answers
6
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Percentage increase is $$fractextnew number - old numbertextold numbertimes 100 %$$
The right comptuation should be $$frac200-5050 times 100 %=300%$$
answered Aug 28 '18 at 6:56
Siong Thye GohSiong Thye Goh
103k1468119
$endgroup$
add a comment |
$begingroup$
Percentage increase is $$fractextnew number - old numbertextold numbertimes 100 %$$
The right comptuation should be $$frac200-5050 times 100 %=300%$$
answered Aug 28 '18 at 6:56
Siong Thye GohSiong Thye Goh
103k1468119
$endgroup$
add a comment |
$begingroup$
Percentage increase is $$fractextnew number - old numbertextold numbertimes 100 %$$
The right comptuation should be $$frac200-5050 times 100 %=300%$$
answered Aug 28 '18 at 6:56
Siong Thye GohSiong Thye Goh
103k1468119
$endgroup$
Percentage increase is $$fractextnew number - old numbertextold numbertimes 100 %$$
The right comptuation should be $$frac200-5050 times 100 %=300%$$
answered Aug 28 '18 at 6:56
Siong Thye GohSiong Thye Goh
103k1468119
answered Aug 28 '18 at 6:56
Siong Thye GohSiong Thye Goh
103k1468119
answered Aug 28 '18 at 6:56
Siong Thye GohSiong Thye Goh
103k1468119
answered Aug 28 '18 at 6:56
Siong Thye GohSiong Thye Goh
103k1468119
103k1468119
add a comment |
add a comment |
$begingroup$
If something increases from $50$ to $200$, it increases by $300%$ and has a new value that is $400%$ of the old value.
Similarly, if something increases from $50$ to $52$, it increases by $4%$ to a new value that is $104%$ of the old one.
answered Aug 28 '18 at 7:11
5xum5xum
91.5k394161
$endgroup$
add a comment |
$begingroup$
If something increases from $50$ to $200$, it increases by $300%$ and has a new value that is $400%$ of the old value.
Similarly, if something increases from $50$ to $52$, it increases by $4%$ to a new value that is $104%$ of the old one.
answered Aug 28 '18 at 7:11
5xum5xum
91.5k394161
$endgroup$
add a comment |
$begingroup$
If something increases from $50$ to $200$, it increases by $300%$ and has a new value that is $400%$ of the old value.
Similarly, if something increases from $50$ to $52$, it increases by $4%$ to a new value that is $104%$ of the old one.
answered Aug 28 '18 at 7:11
5xum5xum
91.5k394161
$endgroup$
If something increases from $50$ to $200$, it increases by $300%$ and has a new value that is $400%$ of the old value.
Similarly, if something increases from $50$ to $52$, it increases by $4%$ to a new value that is $104%$ of the old one.
answered Aug 28 '18 at 7:11
5xum5xum
91.5k394161
answered Aug 28 '18 at 7:11
5xum5xum
91.5k394161
answered Aug 28 '18 at 7:11
5xum5xum
91.5k394161
answered Aug 28 '18 at 7:11
5xum5xum
91.5k394161
91.5k394161
add a comment |
add a comment |
$begingroup$
The convention is that "percentage increase" is the number of percentage points that are added.
So it is assumed that you always start with $100%$ of a number and then add an $n%$ percent increase to that, so you end up with $(100 + n)%$ of the original number.
If you take the ratio of the starting and ending amounts and multiply by $100%,$
you end up with the figure $(100 + n)%.$ You then have to subtract $100%$ if what you want is the percentage increase.
Indeed $52$ is $104%$ of $50,$ but the added amount is only $2,$ which is $4%$ of $50.$
Likewise $200$ is $400%$ of $50,$ but the added amount is only $150,$ which is $300%$ of $50.$
answered Aug 28 '18 at 13:57
David KDavid K
55.3k344120
$endgroup$
add a comment |
$begingroup$
The convention is that "percentage increase" is the number of percentage points that are added.
So it is assumed that you always start with $100%$ of a number and then add an $n%$ percent increase to that, so you end up with $(100 + n)%$ of the original number.
If you take the ratio of the starting and ending amounts and multiply by $100%,$
you end up with the figure $(100 + n)%.$ You then have to subtract $100%$ if what you want is the percentage increase.
Indeed $52$ is $104%$ of $50,$ but the added amount is only $2,$ which is $4%$ of $50.$
Likewise $200$ is $400%$ of $50,$ but the added amount is only $150,$ which is $300%$ of $50.$
answered Aug 28 '18 at 13:57
David KDavid K
55.3k344120
$endgroup$
add a comment |
$begingroup$
The convention is that "percentage increase" is the number of percentage points that are added.
So it is assumed that you always start with $100%$ of a number and then add an $n%$ percent increase to that, so you end up with $(100 + n)%$ of the original number.
If you take the ratio of the starting and ending amounts and multiply by $100%,$
you end up with the figure $(100 + n)%.$ You then have to subtract $100%$ if what you want is the percentage increase.
Indeed $52$ is $104%$ of $50,$ but the added amount is only $2,$ which is $4%$ of $50.$
Likewise $200$ is $400%$ of $50,$ but the added amount is only $150,$ which is $300%$ of $50.$
answered Aug 28 '18 at 13:57
David KDavid K
55.3k344120
$endgroup$
The convention is that "percentage increase" is the number of percentage points that are added.
So it is assumed that you always start with $100%$ of a number and then add an $n%$ percent increase to that, so you end up with $(100 + n)%$ of the original number.
If you take the ratio of the starting and ending amounts and multiply by $100%,$
you end up with the figure $(100 + n)%.$ You then have to subtract $100%$ if what you want is the percentage increase.
Indeed $52$ is $104%$ of $50,$ but the added amount is only $2,$ which is $4%$ of $50.$
Likewise $200$ is $400%$ of $50,$ but the added amount is only $150,$ which is $300%$ of $50.$
answered Aug 28 '18 at 13:57
David KDavid K
55.3k344120
answered Aug 28 '18 at 13:57
David KDavid K
55.3k344120
answered Aug 28 '18 at 13:57
David KDavid K
55.3k344120
answered Aug 28 '18 at 13:57
David KDavid K
55.3k344120
55.3k344120
add a comment |
add a comment |
$begingroup$
You are making the classic mistake of confusing ratio with change.
$ratio = fracnew;valueold;value$
$percentage;ratio = fracnew;valueold;value times 100%$
$difference = new;value - old;value$
$percentage;change = fracdifferenceold;value times 100% = fracnew;value - old;valueold;value times 100%$
Change is more commonly known as growth or increase.
answered Aug 28 '18 at 14:26
Peter PaffPeter Paff
1812
$endgroup$
add a comment |
$begingroup$
You are making the classic mistake of confusing ratio with change.
$ratio = fracnew;valueold;value$
$percentage;ratio = fracnew;valueold;value times 100%$
$difference = new;value - old;value$
$percentage;change = fracdifferenceold;value times 100% = fracnew;value - old;valueold;value times 100%$
Change is more commonly known as growth or increase.
answered Aug 28 '18 at 14:26
Peter PaffPeter Paff
1812
$endgroup$
add a comment |
$begingroup$
You are making the classic mistake of confusing ratio with change.
$ratio = fracnew;valueold;value$
$percentage;ratio = fracnew;valueold;value times 100%$
$difference = new;value - old;value$
$percentage;change = fracdifferenceold;value times 100% = fracnew;value - old;valueold;value times 100%$
Change is more commonly known as growth or increase.
answered Aug 28 '18 at 14:26
Peter PaffPeter Paff
1812
$endgroup$
You are making the classic mistake of confusing ratio with change.
$ratio = fracnew;valueold;value$
$percentage;ratio = fracnew;valueold;value times 100%$
$difference = new;value - old;value$
$percentage;change = fracdifferenceold;value times 100% = fracnew;value - old;valueold;value times 100%$
Change is more commonly known as growth or increase.
answered Aug 28 '18 at 14:26
Peter PaffPeter Paff
1812
answered Aug 28 '18 at 14:26
Peter PaffPeter Paff
1812
answered Aug 28 '18 at 14:26
Peter PaffPeter Paff
1812
answered Aug 28 '18 at 14:26
Peter PaffPeter Paff
1812
1812
add a comment |
add a comment |
$begingroup$
This is were the ratio makes more sense
That is when
50:400
are divided one both sides by 50 giving us
1:8
so my understanding is that it is eight times more.
answered Aug 29 '18 at 4:03
Brahm BothmaBrahm Bothma
215
$endgroup$
1
$begingroup$
50/400 reduces to 1/8 not 1/4
$endgroup$
– Peter Paff
Jan 31 at 13:28
$begingroup$
Thank you - applied your correction. Peter Paff.
$endgroup$
– Brahm Bothma
Feb 6 at 14:19
add a comment |
$begingroup$
This is were the ratio makes more sense
That is when
50:400
are divided one both sides by 50 giving us
1:8
so my understanding is that it is eight times more.
answered Aug 29 '18 at 4:03
Brahm BothmaBrahm Bothma
215
$endgroup$
1
$begingroup$
50/400 reduces to 1/8 not 1/4
$endgroup$
– Peter Paff
Jan 31 at 13:28
$begingroup$
Thank you - applied your correction. Peter Paff.
$endgroup$
– Brahm Bothma
Feb 6 at 14:19
add a comment |
$begingroup$
This is were the ratio makes more sense
That is when
50:400
are divided one both sides by 50 giving us
1:8
so my understanding is that it is eight times more.
answered Aug 29 '18 at 4:03
Brahm BothmaBrahm Bothma
215
$endgroup$
This is were the ratio makes more sense
That is when
50:400
are divided one both sides by 50 giving us
1:8
so my understanding is that it is eight times more.
answered Aug 29 '18 at 4:03
Brahm BothmaBrahm Bothma
215
edited Feb 6 at 14:18
answered Aug 29 '18 at 4:03
Brahm BothmaBrahm Bothma
215
answered Aug 29 '18 at 4:03
Brahm BothmaBrahm Bothma
215
answered Aug 29 '18 at 4:03
Brahm BothmaBrahm Bothma
215
215
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50/400 reduces to 1/8 not 1/4
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– Peter Paff
Jan 31 at 13:28
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Thank you - applied your correction. Peter Paff.
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– Brahm Bothma
Feb 6 at 14:19
add a comment |
1
$begingroup$
50/400 reduces to 1/8 not 1/4
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– Peter Paff
Jan 31 at 13:28
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Thank you - applied your correction. Peter Paff.
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– Brahm Bothma
Feb 6 at 14:19
1
1
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50/400 reduces to 1/8 not 1/4
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– Peter Paff
Jan 31 at 13:28
$begingroup$
50/400 reduces to 1/8 not 1/4
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– Peter Paff
Jan 31 at 13:28
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Thank you - applied your correction. Peter Paff.
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– Brahm Bothma
Feb 6 at 14:19
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Thank you - applied your correction. Peter Paff.
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– Brahm Bothma
Feb 6 at 14:19
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If you see your question, you'll see that you have answered it yourself. In the second statement, you said 50 to 52 increment means 4% which is equal to 100 subtracted from 104 which you have calculated. Similarly, if you subtract 100 from 400 you will get 300%.
answered Aug 28 '18 at 18:52
DeveshDevesh
211
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add a comment |
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If you see your question, you'll see that you have answered it yourself. In the second statement, you said 50 to 52 increment means 4% which is equal to 100 subtracted from 104 which you have calculated. Similarly, if you subtract 100 from 400 you will get 300%.
answered Aug 28 '18 at 18:52
DeveshDevesh
211
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add a comment |
$begingroup$
If you see your question, you'll see that you have answered it yourself. In the second statement, you said 50 to 52 increment means 4% which is equal to 100 subtracted from 104 which you have calculated. Similarly, if you subtract 100 from 400 you will get 300%.
answered Aug 28 '18 at 18:52
DeveshDevesh
211
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If you see your question, you'll see that you have answered it yourself. In the second statement, you said 50 to 52 increment means 4% which is equal to 100 subtracted from 104 which you have calculated. Similarly, if you subtract 100 from 400 you will get 300%.
answered Aug 28 '18 at 18:52
DeveshDevesh
211
answered Aug 28 '18 at 18:52
DeveshDevesh
211
answered Aug 28 '18 at 18:52
DeveshDevesh
211
answered Aug 28 '18 at 18:52
DeveshDevesh
211
211
add a comment |
add a comment |
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It is worth mentioning that your mistake is very common. For small increases, the percentage is usually correct. As the increase gets larger, mistakes become frequent. It is common to confuse $4$ times bigger with $400 %$ more. Think about $100 %$ bigger which means double and not the same.
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– badjohn
Aug 28 '18 at 7:56
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@badjohn Yes, Even after doing maths for AL and even after getting "B" grade I am really ashamed of myself.
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– I am the Most Stupid Person
Aug 28 '18 at 8:22
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Don't be too harsh on yourself, as I said, it is a common mistake. An interesting question is at what point people tend to switch. $100 %$ is usually correctly interpreted as double. By your example of $400 %$, the mistake is common. How is $200 %$ commonly perceived?
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– badjohn
Aug 28 '18 at 9:32
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Note that the other words around the percent number itself make a big difference. $200$ is $400%$ of $50$, but $200$ is a $300%$ increase from $50$, or is $300%$ more than $50$. $52$ is $104%$ of $50$, but $52$ is a $4%$ increase from $50$, or is $4%$ more than $50$. "Percent more than" is equal to "percent of" minus $100$.
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– Todd Wilcox
Aug 28 '18 at 13:19
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I have heard an anecdotal story on percentage increase: There was a debate on "Do law students have to study Mathematics?" The lawyer claimed it was not necessary for them. The mathematician asked him the question: "Last year there were $80$ crimes, this year there were $100$ crimes. How much percentage increase is this?" The lawyer quickly and with confidence replied "$20$ percent"... The moral of the story is the mathematics is necessary for each and every subject and profession.
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– farruhota
Aug 28 '18 at 14:31