How To Use Conditional Statements in R?
sortinoIndex is a vector that contain NA and numeric numbers I want create a loop to extract only the numeric numbers and save them into sortino1
how can I do? I did this but does not work can you help me?
sortino1<-numeric()
for (i in 1:252)
if(sortinoIndex[i]!=NA)
sortino1[i]<-sortinoIndex[i]
r if-statement
asked Nov 12 '18 at 19:22
Tommaso DellolmoTommaso Dellolmo
75
add a comment |
sortinoIndex is a vector that contain NA and numeric numbers I want create a loop to extract only the numeric numbers and save them into sortino1
how can I do? I did this but does not work can you help me?
sortino1<-numeric()
for (i in 1:252)
if(sortinoIndex[i]!=NA)
sortino1[i]<-sortinoIndex[i]
r if-statement
asked Nov 12 '18 at 19:22
Tommaso DellolmoTommaso Dellolmo
75
Your loop doesn't do what you want it to do. Have you tried running it?
– Hong Ooi
Nov 12 '18 at 19:32
Nothing ever "equals" (or for that matter "not equals") an NA. Learn to useis.na
– 42-
Nov 12 '18 at 19:56
add a comment |
sortinoIndex is a vector that contain NA and numeric numbers I want create a loop to extract only the numeric numbers and save them into sortino1
how can I do? I did this but does not work can you help me?
sortino1<-numeric()
for (i in 1:252)
if(sortinoIndex[i]!=NA)
sortino1[i]<-sortinoIndex[i]
r if-statement
asked Nov 12 '18 at 19:22
Tommaso DellolmoTommaso Dellolmo
75
sortinoIndex is a vector that contain NA and numeric numbers I want create a loop to extract only the numeric numbers and save them into sortino1
how can I do? I did this but does not work can you help me?
sortino1<-numeric()
for (i in 1:252)
if(sortinoIndex[i]!=NA)
sortino1[i]<-sortinoIndex[i]
r if-statement
r if-statement
asked Nov 12 '18 at 19:22
Tommaso DellolmoTommaso Dellolmo
75
asked Nov 12 '18 at 19:22
Tommaso DellolmoTommaso Dellolmo
75
asked Nov 12 '18 at 19:22
Tommaso DellolmoTommaso Dellolmo
75
asked Nov 12 '18 at 19:22
Tommaso DellolmoTommaso Dellolmo
75
asked Nov 12 '18 at 19:22
Tommaso DellolmoTommaso Dellolmo
75
75
Your loop doesn't do what you want it to do. Have you tried running it?
– Hong Ooi
Nov 12 '18 at 19:32
Nothing ever "equals" (or for that matter "not equals") an NA. Learn to useis.na
– 42-
Nov 12 '18 at 19:56
add a comment |
Your loop doesn't do what you want it to do. Have you tried running it?
– Hong Ooi
Nov 12 '18 at 19:32
Nothing ever "equals" (or for that matter "not equals") an NA. Learn to useis.na
– 42-
Nov 12 '18 at 19:56
Your loop doesn't do what you want it to do. Have you tried running it?
– Hong Ooi
Nov 12 '18 at 19:32
Your loop doesn't do what you want it to do. Have you tried running it?
– Hong Ooi
Nov 12 '18 at 19:32
Nothing ever "equals" (or for that matter "not equals") an NA. Learn to use
is.na– 42-
Nov 12 '18 at 19:56
Nothing ever "equals" (or for that matter "not equals") an NA. Learn to use
is.na– 42-
Nov 12 '18 at 19:56
add a comment |
2 Answers
2
active
oldest
votes
In R, we typically won't use a for loop to do something like this, because it is very slow compared to implementing the same loop in C++.
Instead, we'll use a vectorized operation:
Create some data:
set.seed(10)
sortinoIndex <- sample(c(NA,1:10),25, replace = TRUE)
Remove NA values:
sortino1 <- sortinoIndex[!is.na(sortinoIndex)]
print(sortino1)
[1] 5 3 4 7 2 3 2 6 4 7 6 1 6 3 4 2 4 9 9 6 8 3 4
answered Nov 12 '18 at 19:27
Mako212Mako212
4,2971827
add a comment |
We can use complete.cases
sortinoIndex[complete.cases(sortinoIndex)]
answered Nov 12 '18 at 19:28
akrunakrun
412k13200276
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
In R, we typically won't use a for loop to do something like this, because it is very slow compared to implementing the same loop in C++.
Instead, we'll use a vectorized operation:
Create some data:
set.seed(10)
sortinoIndex <- sample(c(NA,1:10),25, replace = TRUE)
Remove NA values:
sortino1 <- sortinoIndex[!is.na(sortinoIndex)]
print(sortino1)
[1] 5 3 4 7 2 3 2 6 4 7 6 1 6 3 4 2 4 9 9 6 8 3 4
answered Nov 12 '18 at 19:27
Mako212Mako212
4,2971827
add a comment |
In R, we typically won't use a for loop to do something like this, because it is very slow compared to implementing the same loop in C++.
Instead, we'll use a vectorized operation:
Create some data:
set.seed(10)
sortinoIndex <- sample(c(NA,1:10),25, replace = TRUE)
Remove NA values:
sortino1 <- sortinoIndex[!is.na(sortinoIndex)]
print(sortino1)
[1] 5 3 4 7 2 3 2 6 4 7 6 1 6 3 4 2 4 9 9 6 8 3 4
answered Nov 12 '18 at 19:27
Mako212Mako212
4,2971827
add a comment |
In R, we typically won't use a for loop to do something like this, because it is very slow compared to implementing the same loop in C++.
Instead, we'll use a vectorized operation:
Create some data:
set.seed(10)
sortinoIndex <- sample(c(NA,1:10),25, replace = TRUE)
Remove NA values:
sortino1 <- sortinoIndex[!is.na(sortinoIndex)]
print(sortino1)
[1] 5 3 4 7 2 3 2 6 4 7 6 1 6 3 4 2 4 9 9 6 8 3 4
answered Nov 12 '18 at 19:27
Mako212Mako212
4,2971827
In R, we typically won't use a for loop to do something like this, because it is very slow compared to implementing the same loop in C++.
Instead, we'll use a vectorized operation:
Create some data:
set.seed(10)
sortinoIndex <- sample(c(NA,1:10),25, replace = TRUE)
Remove NA values:
sortino1 <- sortinoIndex[!is.na(sortinoIndex)]
print(sortino1)
[1] 5 3 4 7 2 3 2 6 4 7 6 1 6 3 4 2 4 9 9 6 8 3 4
answered Nov 12 '18 at 19:27
Mako212Mako212
4,2971827
answered Nov 12 '18 at 19:27
Mako212Mako212
4,2971827
answered Nov 12 '18 at 19:27
Mako212Mako212
4,2971827
answered Nov 12 '18 at 19:27
Mako212Mako212
4,2971827
4,2971827
add a comment |
add a comment |
We can use complete.cases
sortinoIndex[complete.cases(sortinoIndex)]
answered Nov 12 '18 at 19:28
akrunakrun
412k13200276
add a comment |
We can use complete.cases
sortinoIndex[complete.cases(sortinoIndex)]
answered Nov 12 '18 at 19:28
akrunakrun
412k13200276
add a comment |
We can use complete.cases
sortinoIndex[complete.cases(sortinoIndex)]
answered Nov 12 '18 at 19:28
akrunakrun
412k13200276
We can use complete.cases
sortinoIndex[complete.cases(sortinoIndex)]
answered Nov 12 '18 at 19:28
akrunakrun
412k13200276
answered Nov 12 '18 at 19:28
akrunakrun
412k13200276
answered Nov 12 '18 at 19:28
akrunakrun
412k13200276
answered Nov 12 '18 at 19:28
akrunakrun
412k13200276
412k13200276
add a comment |
add a comment |
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Your loop doesn't do what you want it to do. Have you tried running it?
– Hong Ooi
Nov 12 '18 at 19:32
Nothing ever "equals" (or for that matter "not equals") an NA. Learn to use
is.na– 42-
Nov 12 '18 at 19:56