How to easily move an entire drawing?










3















I have this drawing below. How can I easily move the entire tikzpicture somewhere else ?



begintikzpicture
foreach x in0,...,4
draw (0,x ,4) -- (4,x ,4);
draw (x ,0,4) -- (x ,4,4);
draw (4,x ,4) -- (4,x ,0);
draw (x ,4,4) -- (x ,4,0);
draw (4,0,x ) -- (4,4,x );
draw (0,4,x ) -- (4,4,x );

endtikzpicture


What I mean by easy should be like



begintikzpicture, origin=1.0,1.0
foreach x in0,...,4
draw (0,x ,4) -- (4,x ,4);
draw (x ,0,4) -- (x ,4,4);
draw (4,x ,4) -- (4,x ,0);
draw (x ,4,4) -- (x ,4,0);
draw (4,0,x ) -- (4,4,x );
draw (0,4,x ) -- (4,4,x );

endtikzpicture









share|improve this question

















  • 1





    node should be the answer!

    – Friendly Ghost
    Aug 27 '18 at 5:45






  • 1





    Could you please add your use-case? It is hard to tell how to shift this picture (tikz has options for shift), if we do not know in which context it should be shifted.

    – TeXnician
    Aug 27 '18 at 6:32






  • 4





    Not sure what it means to move the tikzpicture. But if you want to move something in the picture use beginscope[shift=(<x>,<y>)] <content to be moved> endscope where the shift amount is <x> in the x-direction and <y> in the y-direction.

    – Peter Grill
    Aug 27 '18 at 8:09
















3















I have this drawing below. How can I easily move the entire tikzpicture somewhere else ?



begintikzpicture
foreach x in0,...,4
draw (0,x ,4) -- (4,x ,4);
draw (x ,0,4) -- (x ,4,4);
draw (4,x ,4) -- (4,x ,0);
draw (x ,4,4) -- (x ,4,0);
draw (4,0,x ) -- (4,4,x );
draw (0,4,x ) -- (4,4,x );

endtikzpicture


What I mean by easy should be like



begintikzpicture, origin=1.0,1.0
foreach x in0,...,4
draw (0,x ,4) -- (4,x ,4);
draw (x ,0,4) -- (x ,4,4);
draw (4,x ,4) -- (4,x ,0);
draw (x ,4,4) -- (x ,4,0);
draw (4,0,x ) -- (4,4,x );
draw (0,4,x ) -- (4,4,x );

endtikzpicture









share|improve this question

















  • 1





    node should be the answer!

    – Friendly Ghost
    Aug 27 '18 at 5:45






  • 1





    Could you please add your use-case? It is hard to tell how to shift this picture (tikz has options for shift), if we do not know in which context it should be shifted.

    – TeXnician
    Aug 27 '18 at 6:32






  • 4





    Not sure what it means to move the tikzpicture. But if you want to move something in the picture use beginscope[shift=(<x>,<y>)] <content to be moved> endscope where the shift amount is <x> in the x-direction and <y> in the y-direction.

    – Peter Grill
    Aug 27 '18 at 8:09














3












3








3


1






I have this drawing below. How can I easily move the entire tikzpicture somewhere else ?



begintikzpicture
foreach x in0,...,4
draw (0,x ,4) -- (4,x ,4);
draw (x ,0,4) -- (x ,4,4);
draw (4,x ,4) -- (4,x ,0);
draw (x ,4,4) -- (x ,4,0);
draw (4,0,x ) -- (4,4,x );
draw (0,4,x ) -- (4,4,x );

endtikzpicture


What I mean by easy should be like



begintikzpicture, origin=1.0,1.0
foreach x in0,...,4
draw (0,x ,4) -- (4,x ,4);
draw (x ,0,4) -- (x ,4,4);
draw (4,x ,4) -- (4,x ,0);
draw (x ,4,4) -- (x ,4,0);
draw (4,0,x ) -- (4,4,x );
draw (0,4,x ) -- (4,4,x );

endtikzpicture









share|improve this question














I have this drawing below. How can I easily move the entire tikzpicture somewhere else ?



begintikzpicture
foreach x in0,...,4
draw (0,x ,4) -- (4,x ,4);
draw (x ,0,4) -- (x ,4,4);
draw (4,x ,4) -- (4,x ,0);
draw (x ,4,4) -- (x ,4,0);
draw (4,0,x ) -- (4,4,x );
draw (0,4,x ) -- (4,4,x );

endtikzpicture


What I mean by easy should be like



begintikzpicture, origin=1.0,1.0
foreach x in0,...,4
draw (0,x ,4) -- (4,x ,4);
draw (x ,0,4) -- (x ,4,4);
draw (4,x ,4) -- (4,x ,0);
draw (x ,4,4) -- (x ,4,0);
draw (4,0,x ) -- (4,4,x );
draw (0,4,x ) -- (4,4,x );

endtikzpicture






tikz-pgf






share|improve this question













share|improve this question











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share|improve this question










asked Aug 27 '18 at 5:37









KongKong

5122719




5122719







  • 1





    node should be the answer!

    – Friendly Ghost
    Aug 27 '18 at 5:45






  • 1





    Could you please add your use-case? It is hard to tell how to shift this picture (tikz has options for shift), if we do not know in which context it should be shifted.

    – TeXnician
    Aug 27 '18 at 6:32






  • 4





    Not sure what it means to move the tikzpicture. But if you want to move something in the picture use beginscope[shift=(<x>,<y>)] <content to be moved> endscope where the shift amount is <x> in the x-direction and <y> in the y-direction.

    – Peter Grill
    Aug 27 '18 at 8:09













  • 1





    node should be the answer!

    – Friendly Ghost
    Aug 27 '18 at 5:45






  • 1





    Could you please add your use-case? It is hard to tell how to shift this picture (tikz has options for shift), if we do not know in which context it should be shifted.

    – TeXnician
    Aug 27 '18 at 6:32






  • 4





    Not sure what it means to move the tikzpicture. But if you want to move something in the picture use beginscope[shift=(<x>,<y>)] <content to be moved> endscope where the shift amount is <x> in the x-direction and <y> in the y-direction.

    – Peter Grill
    Aug 27 '18 at 8:09








1




1





node should be the answer!

– Friendly Ghost
Aug 27 '18 at 5:45





node should be the answer!

– Friendly Ghost
Aug 27 '18 at 5:45




1




1





Could you please add your use-case? It is hard to tell how to shift this picture (tikz has options for shift), if we do not know in which context it should be shifted.

– TeXnician
Aug 27 '18 at 6:32





Could you please add your use-case? It is hard to tell how to shift this picture (tikz has options for shift), if we do not know in which context it should be shifted.

– TeXnician
Aug 27 '18 at 6:32




4




4





Not sure what it means to move the tikzpicture. But if you want to move something in the picture use beginscope[shift=(<x>,<y>)] <content to be moved> endscope where the shift amount is <x> in the x-direction and <y> in the y-direction.

– Peter Grill
Aug 27 '18 at 8:09






Not sure what it means to move the tikzpicture. But if you want to move something in the picture use beginscope[shift=(<x>,<y>)] <content to be moved> endscope where the shift amount is <x> in the x-direction and <y> in the y-direction.

– Peter Grill
Aug 27 '18 at 8:09











3 Answers
3






active

oldest

votes


















5














You can use a scope environment with options indicating a [shift=(1,1)] translation
Your code becomes so:



begintikzpicture
beginscope[shift=(1,1)]
foreach x in0,...,4
draw (0,x ,4) -- (4,x ,4);
draw (x ,0,4) -- (x ,4,4);
draw (4,x ,4) -- (4,x ,0);
draw (x ,4,4) -- (x ,4,0);
draw (4,0,x ) -- (4,4,x );
draw (0,4,x ) -- (4,4,x );

endscope
endtikzpicture





share|improve this answer






























    4














    Somewhat similar to Raven's answer, but perhaps less brutal and more accurate (since nodes have a width). Technically it extends the bounding box, but in a document (other than standalone) it does shift the picture. This thing does not work well with overlay.



    documentclass[parskip]scrartcl
    usepackage[margin=15mm]geometry
    usepackagetikz
    tikzsetshift entire picture/.style n args=2execute at end picture=
    pgfmathtruncatemacrotmpxsign(#1)
    pgfmathtruncatemacrotmpysign(#2)
    ifnumtmpx=1
    ifnumtmpy=1
    path[use as bounding box] ([xshift=-#1,yshift=-#2]current bounding box.south west) rectangle
    (current bounding box.north east);
    else
    path[use as bounding box] ([xshift=-#1]current bounding box.south west) rectangle
    ([yshift=-#2]current bounding box.north east);
    fi
    else
    ifnumtmpy=1
    path[use as bounding box] ([yshift=-#2]current bounding box.south west) rectangle
    ([xshift=-#1]current bounding box.north east);
    else
    path[use as bounding box] (current bounding box.south west) rectangle
    ([xshift=-#1,yshift=-#2]current bounding box.north east);
    fi
    fi
    begindocument
    begintikzpicture[shift entire picture=3cm-5cm]
    foreach x in0,...,4
    draw (0,x ,4) -- (4,x ,4);
    ifnumx=0
    draw (x ,0,4) -- (x ,4,4);
    else
    draw (x ,0,4) -- (x ,0.1,4) (x ,0.9,4) -- (x ,1.1,4)
    (x ,1.9,4) -- (x ,2.1,4) (x ,2.9,4) -- (x ,3.1,4)
    (x ,3.9,4) -- (x ,4,4);
    fi
    draw (4,x ,4) -- (4,x ,0);
    ifnumx=0
    draw (x ,4,4) -- (x ,4,0);
    else
    draw (x,4,0) -- (x,4,0.1) (x,4,0.9) -- (x,4,1.1)
    (x,4,1.9) -- (x,4,2.1) (x,4,2.9) -- (x,4,3.1)
    (x,4,3.9) -- (x,4,4);
    fi
    draw (4,0,x ) -- (4,4,x );
    draw (0,4,x ) -- (4,4,x );


    endtikzpicture
    enddocument





    share|improve this answer

























    • Couldn't the problem of the node having a width be overcome if setting the node's shape to be a coordinate?

      – Raven
      Aug 27 '18 at 11:59






    • 1





      @Raven Yes, of course. But even then your method is only accurate if you place the coordinate at some distance relative to the bounding box. The bounding box also takes into account the line widths, not just the coordinates involved in the paths,

      – marmot
      Aug 27 '18 at 12:03


















    2














    It might not be the most elegant solution but it works:



    begintikzpicture
    % Create "shifting node" that shifts all following coordinates by (5,6)
    node at (-5,-6) ;
    foreach x in0,...,4
    draw (0,x ,4) -- (4,x ,4);
    draw (x ,0,4) -- (x ,4,4);
    draw (4,x ,4) -- (4,x ,0);
    draw (x ,4,4) -- (x ,4,0);
    draw (4,0,x ) -- (4,4,x );
    draw (0,4,x ) -- (4,4,x );

    endtikzpicture


    This basically works by adding an invisible node to where the origin lays after the picture has been "shifted". That way there is some content in that area preventing it from being clipped away by tikz (which I assume is happening when simply using the shift option for the whole image).



    Further clarification on the shift-option as provided by @TeXnician in the comments:

    [The shift option] does shift the coordinate origin (transform every coordinate). As the bounding box is trimmed you will still not notice it in an ordinary context (it is handy sometimes, though).






    share|improve this answer




















    • 2





      This way of extending the bounding box is possible, but does it really do the same as "shift" (have you tried the option)?

      – TeXnician
      Aug 27 '18 at 6:31











    • I have tried it and it doesn't do anything at all (at least when passed to the tikzpicture-environment) which is why I even came up with adding the invisible reference point...

      – Raven
      Aug 27 '18 at 8:32












    • Well, that's not entirely right. It does shift the coordinate origin (transform every coordinate). As the bounding box is trimmed you will still not notice it in an ordinary context (it is handy sometimes, though). I just asked, because your last sentence is based on an assumption.

      – TeXnician
      Aug 27 '18 at 8:40











    • Yeah that is what I figured and it's actually what I tried to say in my last sentence. I will integrate your comment in my answer in order to avoid future confusion.

      – Raven
      Aug 27 '18 at 8:48










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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    5














    You can use a scope environment with options indicating a [shift=(1,1)] translation
    Your code becomes so:



    begintikzpicture
    beginscope[shift=(1,1)]
    foreach x in0,...,4
    draw (0,x ,4) -- (4,x ,4);
    draw (x ,0,4) -- (x ,4,4);
    draw (4,x ,4) -- (4,x ,0);
    draw (x ,4,4) -- (x ,4,0);
    draw (4,0,x ) -- (4,4,x );
    draw (0,4,x ) -- (4,4,x );

    endscope
    endtikzpicture





    share|improve this answer



























      5














      You can use a scope environment with options indicating a [shift=(1,1)] translation
      Your code becomes so:



      begintikzpicture
      beginscope[shift=(1,1)]
      foreach x in0,...,4
      draw (0,x ,4) -- (4,x ,4);
      draw (x ,0,4) -- (x ,4,4);
      draw (4,x ,4) -- (4,x ,0);
      draw (x ,4,4) -- (x ,4,0);
      draw (4,0,x ) -- (4,4,x );
      draw (0,4,x ) -- (4,4,x );

      endscope
      endtikzpicture





      share|improve this answer

























        5












        5








        5







        You can use a scope environment with options indicating a [shift=(1,1)] translation
        Your code becomes so:



        begintikzpicture
        beginscope[shift=(1,1)]
        foreach x in0,...,4
        draw (0,x ,4) -- (4,x ,4);
        draw (x ,0,4) -- (x ,4,4);
        draw (4,x ,4) -- (4,x ,0);
        draw (x ,4,4) -- (x ,4,0);
        draw (4,0,x ) -- (4,4,x );
        draw (0,4,x ) -- (4,4,x );

        endscope
        endtikzpicture





        share|improve this answer













        You can use a scope environment with options indicating a [shift=(1,1)] translation
        Your code becomes so:



        begintikzpicture
        beginscope[shift=(1,1)]
        foreach x in0,...,4
        draw (0,x ,4) -- (4,x ,4);
        draw (x ,0,4) -- (x ,4,4);
        draw (4,x ,4) -- (4,x ,0);
        draw (x ,4,4) -- (x ,4,0);
        draw (4,0,x ) -- (4,4,x );
        draw (0,4,x ) -- (4,4,x );

        endscope
        endtikzpicture






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Aug 27 '18 at 9:19









        AndréCAndréC

        9,49611447




        9,49611447





















            4














            Somewhat similar to Raven's answer, but perhaps less brutal and more accurate (since nodes have a width). Technically it extends the bounding box, but in a document (other than standalone) it does shift the picture. This thing does not work well with overlay.



            documentclass[parskip]scrartcl
            usepackage[margin=15mm]geometry
            usepackagetikz
            tikzsetshift entire picture/.style n args=2execute at end picture=
            pgfmathtruncatemacrotmpxsign(#1)
            pgfmathtruncatemacrotmpysign(#2)
            ifnumtmpx=1
            ifnumtmpy=1
            path[use as bounding box] ([xshift=-#1,yshift=-#2]current bounding box.south west) rectangle
            (current bounding box.north east);
            else
            path[use as bounding box] ([xshift=-#1]current bounding box.south west) rectangle
            ([yshift=-#2]current bounding box.north east);
            fi
            else
            ifnumtmpy=1
            path[use as bounding box] ([yshift=-#2]current bounding box.south west) rectangle
            ([xshift=-#1]current bounding box.north east);
            else
            path[use as bounding box] (current bounding box.south west) rectangle
            ([xshift=-#1,yshift=-#2]current bounding box.north east);
            fi
            fi
            begindocument
            begintikzpicture[shift entire picture=3cm-5cm]
            foreach x in0,...,4
            draw (0,x ,4) -- (4,x ,4);
            ifnumx=0
            draw (x ,0,4) -- (x ,4,4);
            else
            draw (x ,0,4) -- (x ,0.1,4) (x ,0.9,4) -- (x ,1.1,4)
            (x ,1.9,4) -- (x ,2.1,4) (x ,2.9,4) -- (x ,3.1,4)
            (x ,3.9,4) -- (x ,4,4);
            fi
            draw (4,x ,4) -- (4,x ,0);
            ifnumx=0
            draw (x ,4,4) -- (x ,4,0);
            else
            draw (x,4,0) -- (x,4,0.1) (x,4,0.9) -- (x,4,1.1)
            (x,4,1.9) -- (x,4,2.1) (x,4,2.9) -- (x,4,3.1)
            (x,4,3.9) -- (x,4,4);
            fi
            draw (4,0,x ) -- (4,4,x );
            draw (0,4,x ) -- (4,4,x );


            endtikzpicture
            enddocument





            share|improve this answer

























            • Couldn't the problem of the node having a width be overcome if setting the node's shape to be a coordinate?

              – Raven
              Aug 27 '18 at 11:59






            • 1





              @Raven Yes, of course. But even then your method is only accurate if you place the coordinate at some distance relative to the bounding box. The bounding box also takes into account the line widths, not just the coordinates involved in the paths,

              – marmot
              Aug 27 '18 at 12:03















            4














            Somewhat similar to Raven's answer, but perhaps less brutal and more accurate (since nodes have a width). Technically it extends the bounding box, but in a document (other than standalone) it does shift the picture. This thing does not work well with overlay.



            documentclass[parskip]scrartcl
            usepackage[margin=15mm]geometry
            usepackagetikz
            tikzsetshift entire picture/.style n args=2execute at end picture=
            pgfmathtruncatemacrotmpxsign(#1)
            pgfmathtruncatemacrotmpysign(#2)
            ifnumtmpx=1
            ifnumtmpy=1
            path[use as bounding box] ([xshift=-#1,yshift=-#2]current bounding box.south west) rectangle
            (current bounding box.north east);
            else
            path[use as bounding box] ([xshift=-#1]current bounding box.south west) rectangle
            ([yshift=-#2]current bounding box.north east);
            fi
            else
            ifnumtmpy=1
            path[use as bounding box] ([yshift=-#2]current bounding box.south west) rectangle
            ([xshift=-#1]current bounding box.north east);
            else
            path[use as bounding box] (current bounding box.south west) rectangle
            ([xshift=-#1,yshift=-#2]current bounding box.north east);
            fi
            fi
            begindocument
            begintikzpicture[shift entire picture=3cm-5cm]
            foreach x in0,...,4
            draw (0,x ,4) -- (4,x ,4);
            ifnumx=0
            draw (x ,0,4) -- (x ,4,4);
            else
            draw (x ,0,4) -- (x ,0.1,4) (x ,0.9,4) -- (x ,1.1,4)
            (x ,1.9,4) -- (x ,2.1,4) (x ,2.9,4) -- (x ,3.1,4)
            (x ,3.9,4) -- (x ,4,4);
            fi
            draw (4,x ,4) -- (4,x ,0);
            ifnumx=0
            draw (x ,4,4) -- (x ,4,0);
            else
            draw (x,4,0) -- (x,4,0.1) (x,4,0.9) -- (x,4,1.1)
            (x,4,1.9) -- (x,4,2.1) (x,4,2.9) -- (x,4,3.1)
            (x,4,3.9) -- (x,4,4);
            fi
            draw (4,0,x ) -- (4,4,x );
            draw (0,4,x ) -- (4,4,x );


            endtikzpicture
            enddocument





            share|improve this answer

























            • Couldn't the problem of the node having a width be overcome if setting the node's shape to be a coordinate?

              – Raven
              Aug 27 '18 at 11:59






            • 1





              @Raven Yes, of course. But even then your method is only accurate if you place the coordinate at some distance relative to the bounding box. The bounding box also takes into account the line widths, not just the coordinates involved in the paths,

              – marmot
              Aug 27 '18 at 12:03













            4












            4








            4







            Somewhat similar to Raven's answer, but perhaps less brutal and more accurate (since nodes have a width). Technically it extends the bounding box, but in a document (other than standalone) it does shift the picture. This thing does not work well with overlay.



            documentclass[parskip]scrartcl
            usepackage[margin=15mm]geometry
            usepackagetikz
            tikzsetshift entire picture/.style n args=2execute at end picture=
            pgfmathtruncatemacrotmpxsign(#1)
            pgfmathtruncatemacrotmpysign(#2)
            ifnumtmpx=1
            ifnumtmpy=1
            path[use as bounding box] ([xshift=-#1,yshift=-#2]current bounding box.south west) rectangle
            (current bounding box.north east);
            else
            path[use as bounding box] ([xshift=-#1]current bounding box.south west) rectangle
            ([yshift=-#2]current bounding box.north east);
            fi
            else
            ifnumtmpy=1
            path[use as bounding box] ([yshift=-#2]current bounding box.south west) rectangle
            ([xshift=-#1]current bounding box.north east);
            else
            path[use as bounding box] (current bounding box.south west) rectangle
            ([xshift=-#1,yshift=-#2]current bounding box.north east);
            fi
            fi
            begindocument
            begintikzpicture[shift entire picture=3cm-5cm]
            foreach x in0,...,4
            draw (0,x ,4) -- (4,x ,4);
            ifnumx=0
            draw (x ,0,4) -- (x ,4,4);
            else
            draw (x ,0,4) -- (x ,0.1,4) (x ,0.9,4) -- (x ,1.1,4)
            (x ,1.9,4) -- (x ,2.1,4) (x ,2.9,4) -- (x ,3.1,4)
            (x ,3.9,4) -- (x ,4,4);
            fi
            draw (4,x ,4) -- (4,x ,0);
            ifnumx=0
            draw (x ,4,4) -- (x ,4,0);
            else
            draw (x,4,0) -- (x,4,0.1) (x,4,0.9) -- (x,4,1.1)
            (x,4,1.9) -- (x,4,2.1) (x,4,2.9) -- (x,4,3.1)
            (x,4,3.9) -- (x,4,4);
            fi
            draw (4,0,x ) -- (4,4,x );
            draw (0,4,x ) -- (4,4,x );


            endtikzpicture
            enddocument





            share|improve this answer















            Somewhat similar to Raven's answer, but perhaps less brutal and more accurate (since nodes have a width). Technically it extends the bounding box, but in a document (other than standalone) it does shift the picture. This thing does not work well with overlay.



            documentclass[parskip]scrartcl
            usepackage[margin=15mm]geometry
            usepackagetikz
            tikzsetshift entire picture/.style n args=2execute at end picture=
            pgfmathtruncatemacrotmpxsign(#1)
            pgfmathtruncatemacrotmpysign(#2)
            ifnumtmpx=1
            ifnumtmpy=1
            path[use as bounding box] ([xshift=-#1,yshift=-#2]current bounding box.south west) rectangle
            (current bounding box.north east);
            else
            path[use as bounding box] ([xshift=-#1]current bounding box.south west) rectangle
            ([yshift=-#2]current bounding box.north east);
            fi
            else
            ifnumtmpy=1
            path[use as bounding box] ([yshift=-#2]current bounding box.south west) rectangle
            ([xshift=-#1]current bounding box.north east);
            else
            path[use as bounding box] (current bounding box.south west) rectangle
            ([xshift=-#1,yshift=-#2]current bounding box.north east);
            fi
            fi
            begindocument
            begintikzpicture[shift entire picture=3cm-5cm]
            foreach x in0,...,4
            draw (0,x ,4) -- (4,x ,4);
            ifnumx=0
            draw (x ,0,4) -- (x ,4,4);
            else
            draw (x ,0,4) -- (x ,0.1,4) (x ,0.9,4) -- (x ,1.1,4)
            (x ,1.9,4) -- (x ,2.1,4) (x ,2.9,4) -- (x ,3.1,4)
            (x ,3.9,4) -- (x ,4,4);
            fi
            draw (4,x ,4) -- (4,x ,0);
            ifnumx=0
            draw (x ,4,4) -- (x ,4,0);
            else
            draw (x,4,0) -- (x,4,0.1) (x,4,0.9) -- (x,4,1.1)
            (x,4,1.9) -- (x,4,2.1) (x,4,2.9) -- (x,4,3.1)
            (x,4,3.9) -- (x,4,4);
            fi
            draw (4,0,x ) -- (4,4,x );
            draw (0,4,x ) -- (4,4,x );


            endtikzpicture
            enddocument






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Aug 27 '18 at 11:18

























            answered Aug 27 '18 at 10:54









            marmotmarmot

            105k4124237




            105k4124237












            • Couldn't the problem of the node having a width be overcome if setting the node's shape to be a coordinate?

              – Raven
              Aug 27 '18 at 11:59






            • 1





              @Raven Yes, of course. But even then your method is only accurate if you place the coordinate at some distance relative to the bounding box. The bounding box also takes into account the line widths, not just the coordinates involved in the paths,

              – marmot
              Aug 27 '18 at 12:03

















            • Couldn't the problem of the node having a width be overcome if setting the node's shape to be a coordinate?

              – Raven
              Aug 27 '18 at 11:59






            • 1





              @Raven Yes, of course. But even then your method is only accurate if you place the coordinate at some distance relative to the bounding box. The bounding box also takes into account the line widths, not just the coordinates involved in the paths,

              – marmot
              Aug 27 '18 at 12:03
















            Couldn't the problem of the node having a width be overcome if setting the node's shape to be a coordinate?

            – Raven
            Aug 27 '18 at 11:59





            Couldn't the problem of the node having a width be overcome if setting the node's shape to be a coordinate?

            – Raven
            Aug 27 '18 at 11:59




            1




            1





            @Raven Yes, of course. But even then your method is only accurate if you place the coordinate at some distance relative to the bounding box. The bounding box also takes into account the line widths, not just the coordinates involved in the paths,

            – marmot
            Aug 27 '18 at 12:03





            @Raven Yes, of course. But even then your method is only accurate if you place the coordinate at some distance relative to the bounding box. The bounding box also takes into account the line widths, not just the coordinates involved in the paths,

            – marmot
            Aug 27 '18 at 12:03











            2














            It might not be the most elegant solution but it works:



            begintikzpicture
            % Create "shifting node" that shifts all following coordinates by (5,6)
            node at (-5,-6) ;
            foreach x in0,...,4
            draw (0,x ,4) -- (4,x ,4);
            draw (x ,0,4) -- (x ,4,4);
            draw (4,x ,4) -- (4,x ,0);
            draw (x ,4,4) -- (x ,4,0);
            draw (4,0,x ) -- (4,4,x );
            draw (0,4,x ) -- (4,4,x );

            endtikzpicture


            This basically works by adding an invisible node to where the origin lays after the picture has been "shifted". That way there is some content in that area preventing it from being clipped away by tikz (which I assume is happening when simply using the shift option for the whole image).



            Further clarification on the shift-option as provided by @TeXnician in the comments:

            [The shift option] does shift the coordinate origin (transform every coordinate). As the bounding box is trimmed you will still not notice it in an ordinary context (it is handy sometimes, though).






            share|improve this answer




















            • 2





              This way of extending the bounding box is possible, but does it really do the same as "shift" (have you tried the option)?

              – TeXnician
              Aug 27 '18 at 6:31











            • I have tried it and it doesn't do anything at all (at least when passed to the tikzpicture-environment) which is why I even came up with adding the invisible reference point...

              – Raven
              Aug 27 '18 at 8:32












            • Well, that's not entirely right. It does shift the coordinate origin (transform every coordinate). As the bounding box is trimmed you will still not notice it in an ordinary context (it is handy sometimes, though). I just asked, because your last sentence is based on an assumption.

              – TeXnician
              Aug 27 '18 at 8:40











            • Yeah that is what I figured and it's actually what I tried to say in my last sentence. I will integrate your comment in my answer in order to avoid future confusion.

              – Raven
              Aug 27 '18 at 8:48















            2














            It might not be the most elegant solution but it works:



            begintikzpicture
            % Create "shifting node" that shifts all following coordinates by (5,6)
            node at (-5,-6) ;
            foreach x in0,...,4
            draw (0,x ,4) -- (4,x ,4);
            draw (x ,0,4) -- (x ,4,4);
            draw (4,x ,4) -- (4,x ,0);
            draw (x ,4,4) -- (x ,4,0);
            draw (4,0,x ) -- (4,4,x );
            draw (0,4,x ) -- (4,4,x );

            endtikzpicture


            This basically works by adding an invisible node to where the origin lays after the picture has been "shifted". That way there is some content in that area preventing it from being clipped away by tikz (which I assume is happening when simply using the shift option for the whole image).



            Further clarification on the shift-option as provided by @TeXnician in the comments:

            [The shift option] does shift the coordinate origin (transform every coordinate). As the bounding box is trimmed you will still not notice it in an ordinary context (it is handy sometimes, though).






            share|improve this answer




















            • 2





              This way of extending the bounding box is possible, but does it really do the same as "shift" (have you tried the option)?

              – TeXnician
              Aug 27 '18 at 6:31











            • I have tried it and it doesn't do anything at all (at least when passed to the tikzpicture-environment) which is why I even came up with adding the invisible reference point...

              – Raven
              Aug 27 '18 at 8:32












            • Well, that's not entirely right. It does shift the coordinate origin (transform every coordinate). As the bounding box is trimmed you will still not notice it in an ordinary context (it is handy sometimes, though). I just asked, because your last sentence is based on an assumption.

              – TeXnician
              Aug 27 '18 at 8:40











            • Yeah that is what I figured and it's actually what I tried to say in my last sentence. I will integrate your comment in my answer in order to avoid future confusion.

              – Raven
              Aug 27 '18 at 8:48













            2












            2








            2







            It might not be the most elegant solution but it works:



            begintikzpicture
            % Create "shifting node" that shifts all following coordinates by (5,6)
            node at (-5,-6) ;
            foreach x in0,...,4
            draw (0,x ,4) -- (4,x ,4);
            draw (x ,0,4) -- (x ,4,4);
            draw (4,x ,4) -- (4,x ,0);
            draw (x ,4,4) -- (x ,4,0);
            draw (4,0,x ) -- (4,4,x );
            draw (0,4,x ) -- (4,4,x );

            endtikzpicture


            This basically works by adding an invisible node to where the origin lays after the picture has been "shifted". That way there is some content in that area preventing it from being clipped away by tikz (which I assume is happening when simply using the shift option for the whole image).



            Further clarification on the shift-option as provided by @TeXnician in the comments:

            [The shift option] does shift the coordinate origin (transform every coordinate). As the bounding box is trimmed you will still not notice it in an ordinary context (it is handy sometimes, though).






            share|improve this answer















            It might not be the most elegant solution but it works:



            begintikzpicture
            % Create "shifting node" that shifts all following coordinates by (5,6)
            node at (-5,-6) ;
            foreach x in0,...,4
            draw (0,x ,4) -- (4,x ,4);
            draw (x ,0,4) -- (x ,4,4);
            draw (4,x ,4) -- (4,x ,0);
            draw (x ,4,4) -- (x ,4,0);
            draw (4,0,x ) -- (4,4,x );
            draw (0,4,x ) -- (4,4,x );

            endtikzpicture


            This basically works by adding an invisible node to where the origin lays after the picture has been "shifted". That way there is some content in that area preventing it from being clipped away by tikz (which I assume is happening when simply using the shift option for the whole image).



            Further clarification on the shift-option as provided by @TeXnician in the comments:

            [The shift option] does shift the coordinate origin (transform every coordinate). As the bounding box is trimmed you will still not notice it in an ordinary context (it is handy sometimes, though).







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Aug 27 '18 at 8:50

























            answered Aug 27 '18 at 6:24









            RavenRaven

            1,032114




            1,032114







            • 2





              This way of extending the bounding box is possible, but does it really do the same as "shift" (have you tried the option)?

              – TeXnician
              Aug 27 '18 at 6:31











            • I have tried it and it doesn't do anything at all (at least when passed to the tikzpicture-environment) which is why I even came up with adding the invisible reference point...

              – Raven
              Aug 27 '18 at 8:32












            • Well, that's not entirely right. It does shift the coordinate origin (transform every coordinate). As the bounding box is trimmed you will still not notice it in an ordinary context (it is handy sometimes, though). I just asked, because your last sentence is based on an assumption.

              – TeXnician
              Aug 27 '18 at 8:40











            • Yeah that is what I figured and it's actually what I tried to say in my last sentence. I will integrate your comment in my answer in order to avoid future confusion.

              – Raven
              Aug 27 '18 at 8:48












            • 2





              This way of extending the bounding box is possible, but does it really do the same as "shift" (have you tried the option)?

              – TeXnician
              Aug 27 '18 at 6:31











            • I have tried it and it doesn't do anything at all (at least when passed to the tikzpicture-environment) which is why I even came up with adding the invisible reference point...

              – Raven
              Aug 27 '18 at 8:32












            • Well, that's not entirely right. It does shift the coordinate origin (transform every coordinate). As the bounding box is trimmed you will still not notice it in an ordinary context (it is handy sometimes, though). I just asked, because your last sentence is based on an assumption.

              – TeXnician
              Aug 27 '18 at 8:40











            • Yeah that is what I figured and it's actually what I tried to say in my last sentence. I will integrate your comment in my answer in order to avoid future confusion.

              – Raven
              Aug 27 '18 at 8:48







            2




            2





            This way of extending the bounding box is possible, but does it really do the same as "shift" (have you tried the option)?

            – TeXnician
            Aug 27 '18 at 6:31





            This way of extending the bounding box is possible, but does it really do the same as "shift" (have you tried the option)?

            – TeXnician
            Aug 27 '18 at 6:31













            I have tried it and it doesn't do anything at all (at least when passed to the tikzpicture-environment) which is why I even came up with adding the invisible reference point...

            – Raven
            Aug 27 '18 at 8:32






            I have tried it and it doesn't do anything at all (at least when passed to the tikzpicture-environment) which is why I even came up with adding the invisible reference point...

            – Raven
            Aug 27 '18 at 8:32














            Well, that's not entirely right. It does shift the coordinate origin (transform every coordinate). As the bounding box is trimmed you will still not notice it in an ordinary context (it is handy sometimes, though). I just asked, because your last sentence is based on an assumption.

            – TeXnician
            Aug 27 '18 at 8:40





            Well, that's not entirely right. It does shift the coordinate origin (transform every coordinate). As the bounding box is trimmed you will still not notice it in an ordinary context (it is handy sometimes, though). I just asked, because your last sentence is based on an assumption.

            – TeXnician
            Aug 27 '18 at 8:40













            Yeah that is what I figured and it's actually what I tried to say in my last sentence. I will integrate your comment in my answer in order to avoid future confusion.

            – Raven
            Aug 27 '18 at 8:48





            Yeah that is what I figured and it's actually what I tried to say in my last sentence. I will integrate your comment in my answer in order to avoid future confusion.

            – Raven
            Aug 27 '18 at 8:48

















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