How to Get a Count of Records Using Partitioning in Oracle
I have the following query:
SELECT
F.IID,
F.E_NUM AS M_E_NUM,
MCI.E_NUM AS MCI_E_NUM,
F.C_NUM AS M_C_NUM,
MCI.C_NUM AS MCI_C_NUM,
F.ET_ID AS M_ET_ID,
EDIE.ET_ID AS ED_INDV_ET_ID,
COUNT(*) OVER (PARTITION BY F.IID) IID_COUNT
FROM FT_T F JOIN CEMEI_T MCI ON F.IID = MCI.IID
JOIN EDE_T EDE ON MCI.E_NUM = EDE.E_NUM
JOIN EDIE_T EDIE ON EDIE.IID = F.IID AND EDIE.ET_ID = EDE.ET_ID
WHERE
F.DEL_F = 'N'
AND MCI.EFF_END_DT IS NULL
AND MCI.TOS = 'BVVB'
AND EDE.PTEND_DT IS NULL
AND EDE.DEL_S = 'N'
AND EDE.CUR_IND = 'A'
AND EDIE.TAR_N = 'Y'
AND F.IID IN
(
SELECT DISTINCT IID
FROM FT_T
WHERE GROUP_ID = 'BG'
AND DEL_F = 'N'
AND (IID, E_NUM) NOT IN
(
SELECT IID, E_NUM FROM CEMEI_T
WHERE TOS = 'BVVB' AND EFF_END_DT IS NULL
)
);
I am basically grabbing information from several tables and creating a flat record of them.
Everything works accordingly except now I need to find out whether there are two records in FT_T table with identical IID's and display that count as part of the result set.
I tried to use partitioning but all the rows in the result set return a single count even though there are ones that have 2 records with identical IID's in FT_T.
The reason I initially said that I'm gathering information from several tables is due to the fact that FT_T might not have all the information I need if two records are not available for the same IID, so I have to retrieve them from other tables JOINed in the query. However, I need to know which FT_T.IID's have two records in FT_T (or greater than one).
sql oracle oracle12c window-functions
add a comment |
I have the following query:
SELECT
F.IID,
F.E_NUM AS M_E_NUM,
MCI.E_NUM AS MCI_E_NUM,
F.C_NUM AS M_C_NUM,
MCI.C_NUM AS MCI_C_NUM,
F.ET_ID AS M_ET_ID,
EDIE.ET_ID AS ED_INDV_ET_ID,
COUNT(*) OVER (PARTITION BY F.IID) IID_COUNT
FROM FT_T F JOIN CEMEI_T MCI ON F.IID = MCI.IID
JOIN EDE_T EDE ON MCI.E_NUM = EDE.E_NUM
JOIN EDIE_T EDIE ON EDIE.IID = F.IID AND EDIE.ET_ID = EDE.ET_ID
WHERE
F.DEL_F = 'N'
AND MCI.EFF_END_DT IS NULL
AND MCI.TOS = 'BVVB'
AND EDE.PTEND_DT IS NULL
AND EDE.DEL_S = 'N'
AND EDE.CUR_IND = 'A'
AND EDIE.TAR_N = 'Y'
AND F.IID IN
(
SELECT DISTINCT IID
FROM FT_T
WHERE GROUP_ID = 'BG'
AND DEL_F = 'N'
AND (IID, E_NUM) NOT IN
(
SELECT IID, E_NUM FROM CEMEI_T
WHERE TOS = 'BVVB' AND EFF_END_DT IS NULL
)
);
I am basically grabbing information from several tables and creating a flat record of them.
Everything works accordingly except now I need to find out whether there are two records in FT_T table with identical IID's and display that count as part of the result set.
I tried to use partitioning but all the rows in the result set return a single count even though there are ones that have 2 records with identical IID's in FT_T.
The reason I initially said that I'm gathering information from several tables is due to the fact that FT_T might not have all the information I need if two records are not available for the same IID, so I have to retrieve them from other tables JOINed in the query. However, I need to know which FT_T.IID's have two records in FT_T (or greater than one).
sql oracle oracle12c window-functions
Could you provide some sample data and expect result?
– D-Shih
Nov 12 '18 at 1:38
add a comment |
I have the following query:
SELECT
F.IID,
F.E_NUM AS M_E_NUM,
MCI.E_NUM AS MCI_E_NUM,
F.C_NUM AS M_C_NUM,
MCI.C_NUM AS MCI_C_NUM,
F.ET_ID AS M_ET_ID,
EDIE.ET_ID AS ED_INDV_ET_ID,
COUNT(*) OVER (PARTITION BY F.IID) IID_COUNT
FROM FT_T F JOIN CEMEI_T MCI ON F.IID = MCI.IID
JOIN EDE_T EDE ON MCI.E_NUM = EDE.E_NUM
JOIN EDIE_T EDIE ON EDIE.IID = F.IID AND EDIE.ET_ID = EDE.ET_ID
WHERE
F.DEL_F = 'N'
AND MCI.EFF_END_DT IS NULL
AND MCI.TOS = 'BVVB'
AND EDE.PTEND_DT IS NULL
AND EDE.DEL_S = 'N'
AND EDE.CUR_IND = 'A'
AND EDIE.TAR_N = 'Y'
AND F.IID IN
(
SELECT DISTINCT IID
FROM FT_T
WHERE GROUP_ID = 'BG'
AND DEL_F = 'N'
AND (IID, E_NUM) NOT IN
(
SELECT IID, E_NUM FROM CEMEI_T
WHERE TOS = 'BVVB' AND EFF_END_DT IS NULL
)
);
I am basically grabbing information from several tables and creating a flat record of them.
Everything works accordingly except now I need to find out whether there are two records in FT_T table with identical IID's and display that count as part of the result set.
I tried to use partitioning but all the rows in the result set return a single count even though there are ones that have 2 records with identical IID's in FT_T.
The reason I initially said that I'm gathering information from several tables is due to the fact that FT_T might not have all the information I need if two records are not available for the same IID, so I have to retrieve them from other tables JOINed in the query. However, I need to know which FT_T.IID's have two records in FT_T (or greater than one).
sql oracle oracle12c window-functions
I have the following query:
SELECT
F.IID,
F.E_NUM AS M_E_NUM,
MCI.E_NUM AS MCI_E_NUM,
F.C_NUM AS M_C_NUM,
MCI.C_NUM AS MCI_C_NUM,
F.ET_ID AS M_ET_ID,
EDIE.ET_ID AS ED_INDV_ET_ID,
COUNT(*) OVER (PARTITION BY F.IID) IID_COUNT
FROM FT_T F JOIN CEMEI_T MCI ON F.IID = MCI.IID
JOIN EDE_T EDE ON MCI.E_NUM = EDE.E_NUM
JOIN EDIE_T EDIE ON EDIE.IID = F.IID AND EDIE.ET_ID = EDE.ET_ID
WHERE
F.DEL_F = 'N'
AND MCI.EFF_END_DT IS NULL
AND MCI.TOS = 'BVVB'
AND EDE.PTEND_DT IS NULL
AND EDE.DEL_S = 'N'
AND EDE.CUR_IND = 'A'
AND EDIE.TAR_N = 'Y'
AND F.IID IN
(
SELECT DISTINCT IID
FROM FT_T
WHERE GROUP_ID = 'BG'
AND DEL_F = 'N'
AND (IID, E_NUM) NOT IN
(
SELECT IID, E_NUM FROM CEMEI_T
WHERE TOS = 'BVVB' AND EFF_END_DT IS NULL
)
);
I am basically grabbing information from several tables and creating a flat record of them.
Everything works accordingly except now I need to find out whether there are two records in FT_T table with identical IID's and display that count as part of the result set.
I tried to use partitioning but all the rows in the result set return a single count even though there are ones that have 2 records with identical IID's in FT_T.
The reason I initially said that I'm gathering information from several tables is due to the fact that FT_T might not have all the information I need if two records are not available for the same IID, so I have to retrieve them from other tables JOINed in the query. However, I need to know which FT_T.IID's have two records in FT_T (or greater than one).
sql oracle oracle12c window-functions
sql oracle oracle12c window-functions
edited Nov 12 '18 at 8:21
a_horse_with_no_name
300k46458550
300k46458550
asked Nov 12 '18 at 1:36
NuCradleNuCradle
136110
136110
Could you provide some sample data and expect result?
– D-Shih
Nov 12 '18 at 1:38
add a comment |
Could you provide some sample data and expect result?
– D-Shih
Nov 12 '18 at 1:38
Could you provide some sample data and expect result?
– D-Shih
Nov 12 '18 at 1:38
Could you provide some sample data and expect result?
– D-Shih
Nov 12 '18 at 1:38
add a comment |
2 Answers
2
active
oldest
votes
Perhaps you need to calculate the count before the join and filtering:
SELECT . . .
FROM (SELECT F.*,
COUNT(*) OVER (PARTITION BY F.IID) as IID_CNT
FROM FT_T F
) JOIN
CEMEI_T MCI
ON F.IID = MCI.IID JOIN
EDE_T EDE
ON MCI.E_NUM = EDE.E_NUM JOIN
EDIE_T EDIE
ON EDIE.IID = F.IID AND EDIE.ET_ID = EDE.ET_ID
. . .
That makes sense, however, I just realized that my partition should, not only be overF.IID, but also a hard coded value from some other column, e.g. F.TYPE = 'A' as there might be multiple rows with the identicalF.IID's but I should only consider the ones in my window withF.TYPE='A'. Is there a way to include conditions in the partition window?
– NuCradle
Nov 12 '18 at 5:27
Hmm... perhaps throw that in the WHERE clause of that partition window subquery! But I guess the count is still going to be over allTYPE's, no?
– NuCradle
Nov 12 '18 at 5:48
@NuCradle . . . It is only possible to answer the question that you ask, and the question is about countingF.IID.
– Gordon Linoff
Nov 12 '18 at 13:01
add a comment |
this is merely a comment/observation, but formatting is needed
You use of in(...) with select distinct and not in(...,...) seems complex and could be a problem if some values are NULL. I suggest you consider using EXISTS and NOT EXISTS instead. e.g.
AND EXISTS (
SELECT
NULL
FROM FT_T
WHERE F.IID = FT_T.IID
AND FT_T.GROUP_ID = 'BG'
AND FT_T.DEL_F = 'N'
AND NOT EXISTS (
SELECT
NULL
FROM CEMEI_T
WHERE FT_T.IID = CEMEI_T.IID
AND FT_T.E_NUM = CEMEI_T.E_NUM
AND CEMEI_T.TOS = 'BVVB'
AND CEMEI_T.EFF_END_DT IS NULL
)
)
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Perhaps you need to calculate the count before the join and filtering:
SELECT . . .
FROM (SELECT F.*,
COUNT(*) OVER (PARTITION BY F.IID) as IID_CNT
FROM FT_T F
) JOIN
CEMEI_T MCI
ON F.IID = MCI.IID JOIN
EDE_T EDE
ON MCI.E_NUM = EDE.E_NUM JOIN
EDIE_T EDIE
ON EDIE.IID = F.IID AND EDIE.ET_ID = EDE.ET_ID
. . .
That makes sense, however, I just realized that my partition should, not only be overF.IID, but also a hard coded value from some other column, e.g. F.TYPE = 'A' as there might be multiple rows with the identicalF.IID's but I should only consider the ones in my window withF.TYPE='A'. Is there a way to include conditions in the partition window?
– NuCradle
Nov 12 '18 at 5:27
Hmm... perhaps throw that in the WHERE clause of that partition window subquery! But I guess the count is still going to be over allTYPE's, no?
– NuCradle
Nov 12 '18 at 5:48
@NuCradle . . . It is only possible to answer the question that you ask, and the question is about countingF.IID.
– Gordon Linoff
Nov 12 '18 at 13:01
add a comment |
Perhaps you need to calculate the count before the join and filtering:
SELECT . . .
FROM (SELECT F.*,
COUNT(*) OVER (PARTITION BY F.IID) as IID_CNT
FROM FT_T F
) JOIN
CEMEI_T MCI
ON F.IID = MCI.IID JOIN
EDE_T EDE
ON MCI.E_NUM = EDE.E_NUM JOIN
EDIE_T EDIE
ON EDIE.IID = F.IID AND EDIE.ET_ID = EDE.ET_ID
. . .
That makes sense, however, I just realized that my partition should, not only be overF.IID, but also a hard coded value from some other column, e.g. F.TYPE = 'A' as there might be multiple rows with the identicalF.IID's but I should only consider the ones in my window withF.TYPE='A'. Is there a way to include conditions in the partition window?
– NuCradle
Nov 12 '18 at 5:27
Hmm... perhaps throw that in the WHERE clause of that partition window subquery! But I guess the count is still going to be over allTYPE's, no?
– NuCradle
Nov 12 '18 at 5:48
@NuCradle . . . It is only possible to answer the question that you ask, and the question is about countingF.IID.
– Gordon Linoff
Nov 12 '18 at 13:01
add a comment |
Perhaps you need to calculate the count before the join and filtering:
SELECT . . .
FROM (SELECT F.*,
COUNT(*) OVER (PARTITION BY F.IID) as IID_CNT
FROM FT_T F
) JOIN
CEMEI_T MCI
ON F.IID = MCI.IID JOIN
EDE_T EDE
ON MCI.E_NUM = EDE.E_NUM JOIN
EDIE_T EDIE
ON EDIE.IID = F.IID AND EDIE.ET_ID = EDE.ET_ID
. . .
Perhaps you need to calculate the count before the join and filtering:
SELECT . . .
FROM (SELECT F.*,
COUNT(*) OVER (PARTITION BY F.IID) as IID_CNT
FROM FT_T F
) JOIN
CEMEI_T MCI
ON F.IID = MCI.IID JOIN
EDE_T EDE
ON MCI.E_NUM = EDE.E_NUM JOIN
EDIE_T EDIE
ON EDIE.IID = F.IID AND EDIE.ET_ID = EDE.ET_ID
. . .
answered Nov 12 '18 at 1:52
Gordon LinoffGordon Linoff
778k35307410
778k35307410
That makes sense, however, I just realized that my partition should, not only be overF.IID, but also a hard coded value from some other column, e.g. F.TYPE = 'A' as there might be multiple rows with the identicalF.IID's but I should only consider the ones in my window withF.TYPE='A'. Is there a way to include conditions in the partition window?
– NuCradle
Nov 12 '18 at 5:27
Hmm... perhaps throw that in the WHERE clause of that partition window subquery! But I guess the count is still going to be over allTYPE's, no?
– NuCradle
Nov 12 '18 at 5:48
@NuCradle . . . It is only possible to answer the question that you ask, and the question is about countingF.IID.
– Gordon Linoff
Nov 12 '18 at 13:01
add a comment |
That makes sense, however, I just realized that my partition should, not only be overF.IID, but also a hard coded value from some other column, e.g. F.TYPE = 'A' as there might be multiple rows with the identicalF.IID's but I should only consider the ones in my window withF.TYPE='A'. Is there a way to include conditions in the partition window?
– NuCradle
Nov 12 '18 at 5:27
Hmm... perhaps throw that in the WHERE clause of that partition window subquery! But I guess the count is still going to be over allTYPE's, no?
– NuCradle
Nov 12 '18 at 5:48
@NuCradle . . . It is only possible to answer the question that you ask, and the question is about countingF.IID.
– Gordon Linoff
Nov 12 '18 at 13:01
That makes sense, however, I just realized that my partition should, not only be over
F.IID, but also a hard coded value from some other column, e.g. F.TYPE = 'A' as there might be multiple rows with the identical F.IID's but I should only consider the ones in my window with F.TYPE='A'. Is there a way to include conditions in the partition window?– NuCradle
Nov 12 '18 at 5:27
That makes sense, however, I just realized that my partition should, not only be over
F.IID, but also a hard coded value from some other column, e.g. F.TYPE = 'A' as there might be multiple rows with the identical F.IID's but I should only consider the ones in my window with F.TYPE='A'. Is there a way to include conditions in the partition window?– NuCradle
Nov 12 '18 at 5:27
Hmm... perhaps throw that in the WHERE clause of that partition window subquery! But I guess the count is still going to be over all
TYPE's, no?– NuCradle
Nov 12 '18 at 5:48
Hmm... perhaps throw that in the WHERE clause of that partition window subquery! But I guess the count is still going to be over all
TYPE's, no?– NuCradle
Nov 12 '18 at 5:48
@NuCradle . . . It is only possible to answer the question that you ask, and the question is about counting
F.IID.– Gordon Linoff
Nov 12 '18 at 13:01
@NuCradle . . . It is only possible to answer the question that you ask, and the question is about counting
F.IID.– Gordon Linoff
Nov 12 '18 at 13:01
add a comment |
this is merely a comment/observation, but formatting is needed
You use of in(...) with select distinct and not in(...,...) seems complex and could be a problem if some values are NULL. I suggest you consider using EXISTS and NOT EXISTS instead. e.g.
AND EXISTS (
SELECT
NULL
FROM FT_T
WHERE F.IID = FT_T.IID
AND FT_T.GROUP_ID = 'BG'
AND FT_T.DEL_F = 'N'
AND NOT EXISTS (
SELECT
NULL
FROM CEMEI_T
WHERE FT_T.IID = CEMEI_T.IID
AND FT_T.E_NUM = CEMEI_T.E_NUM
AND CEMEI_T.TOS = 'BVVB'
AND CEMEI_T.EFF_END_DT IS NULL
)
)
add a comment |
this is merely a comment/observation, but formatting is needed
You use of in(...) with select distinct and not in(...,...) seems complex and could be a problem if some values are NULL. I suggest you consider using EXISTS and NOT EXISTS instead. e.g.
AND EXISTS (
SELECT
NULL
FROM FT_T
WHERE F.IID = FT_T.IID
AND FT_T.GROUP_ID = 'BG'
AND FT_T.DEL_F = 'N'
AND NOT EXISTS (
SELECT
NULL
FROM CEMEI_T
WHERE FT_T.IID = CEMEI_T.IID
AND FT_T.E_NUM = CEMEI_T.E_NUM
AND CEMEI_T.TOS = 'BVVB'
AND CEMEI_T.EFF_END_DT IS NULL
)
)
add a comment |
this is merely a comment/observation, but formatting is needed
You use of in(...) with select distinct and not in(...,...) seems complex and could be a problem if some values are NULL. I suggest you consider using EXISTS and NOT EXISTS instead. e.g.
AND EXISTS (
SELECT
NULL
FROM FT_T
WHERE F.IID = FT_T.IID
AND FT_T.GROUP_ID = 'BG'
AND FT_T.DEL_F = 'N'
AND NOT EXISTS (
SELECT
NULL
FROM CEMEI_T
WHERE FT_T.IID = CEMEI_T.IID
AND FT_T.E_NUM = CEMEI_T.E_NUM
AND CEMEI_T.TOS = 'BVVB'
AND CEMEI_T.EFF_END_DT IS NULL
)
)
this is merely a comment/observation, but formatting is needed
You use of in(...) with select distinct and not in(...,...) seems complex and could be a problem if some values are NULL. I suggest you consider using EXISTS and NOT EXISTS instead. e.g.
AND EXISTS (
SELECT
NULL
FROM FT_T
WHERE F.IID = FT_T.IID
AND FT_T.GROUP_ID = 'BG'
AND FT_T.DEL_F = 'N'
AND NOT EXISTS (
SELECT
NULL
FROM CEMEI_T
WHERE FT_T.IID = CEMEI_T.IID
AND FT_T.E_NUM = CEMEI_T.E_NUM
AND CEMEI_T.TOS = 'BVVB'
AND CEMEI_T.EFF_END_DT IS NULL
)
)
answered Nov 12 '18 at 2:14
Used_By_AlreadyUsed_By_Already
23k22038
23k22038
add a comment |
add a comment |
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Could you provide some sample data and expect result?
– D-Shih
Nov 12 '18 at 1:38