What's wrong with this ANTLR grammar?
I want to parse query expressions that look like this:
Person Name=%John%
(Person Name=John% and Address=%Ontario%)
Person Fullname_3="John C. Smith"
But I'm totally new to Antlr4 and can't even figure out how to parse one single TABLE FIELD=QUERY clause. When I run the grammar below in Go as target, I get
line 1:7 mismatched input 'Name' expecting 'not', '(', FIELDNAME
for a simple query like
Person Name=John
Why can't the Grammar parse FIELDNAME via parsing fieldsearch->field EQ searchterm->FIELDNAME?
I guess I'm misunderstanding something very fundamental here about how Antlr Grammars work, but what?
/* ANTLR Grammar for Minidb Query Language */
grammar Mdb;
start : searchclause EOF ;
searchclause
: table expr
;
expr
: fieldsearch
| unop fieldsearch
| LPAREN expr relop expr RPAREN
;
unop
: NOT
;
relop
: AND
| OR
;
fieldsearch
: field EQ searchterm
;
field
: FIELDNAME
;
table
: TABLENAME
;
searchterm
: STRING
;
AND
: 'and'
;
OR
: 'or'
;
NOT
: 'not'
;
EQ
: '='
;
LPAREN
: '('
;
RPAREN
: ')'
;
fragment VALID_ID_START
: ('a' .. 'z') | ('A' .. 'Z') | '_'
;
fragment VALID_ID_CHAR
: VALID_ID_START | ('0' .. '9')
;
TABLENAME
: VALID_ID_START VALID_ID_CHAR*
;
FIELDNAME
: VALID_ID_START VALID_ID_CHAR*
;
STRING: '"' ~('n'|'"')* ('"' | panic("syntax-error - unterminated string literal") ) ;
WS
: [ rnt] + -> skip
;
antlr antlr4 context-free-grammar
add a comment |
I want to parse query expressions that look like this:
Person Name=%John%
(Person Name=John% and Address=%Ontario%)
Person Fullname_3="John C. Smith"
But I'm totally new to Antlr4 and can't even figure out how to parse one single TABLE FIELD=QUERY clause. When I run the grammar below in Go as target, I get
line 1:7 mismatched input 'Name' expecting 'not', '(', FIELDNAME
for a simple query like
Person Name=John
Why can't the Grammar parse FIELDNAME via parsing fieldsearch->field EQ searchterm->FIELDNAME?
I guess I'm misunderstanding something very fundamental here about how Antlr Grammars work, but what?
/* ANTLR Grammar for Minidb Query Language */
grammar Mdb;
start : searchclause EOF ;
searchclause
: table expr
;
expr
: fieldsearch
| unop fieldsearch
| LPAREN expr relop expr RPAREN
;
unop
: NOT
;
relop
: AND
| OR
;
fieldsearch
: field EQ searchterm
;
field
: FIELDNAME
;
table
: TABLENAME
;
searchterm
: STRING
;
AND
: 'and'
;
OR
: 'or'
;
NOT
: 'not'
;
EQ
: '='
;
LPAREN
: '('
;
RPAREN
: ')'
;
fragment VALID_ID_START
: ('a' .. 'z') | ('A' .. 'Z') | '_'
;
fragment VALID_ID_CHAR
: VALID_ID_START | ('0' .. '9')
;
TABLENAME
: VALID_ID_START VALID_ID_CHAR*
;
FIELDNAME
: VALID_ID_START VALID_ID_CHAR*
;
STRING: '"' ~('n'|'"')* ('"' | panic("syntax-error - unterminated string literal") ) ;
WS
: [ rnt] + -> skip
;
antlr antlr4 context-free-grammar
add a comment |
I want to parse query expressions that look like this:
Person Name=%John%
(Person Name=John% and Address=%Ontario%)
Person Fullname_3="John C. Smith"
But I'm totally new to Antlr4 and can't even figure out how to parse one single TABLE FIELD=QUERY clause. When I run the grammar below in Go as target, I get
line 1:7 mismatched input 'Name' expecting 'not', '(', FIELDNAME
for a simple query like
Person Name=John
Why can't the Grammar parse FIELDNAME via parsing fieldsearch->field EQ searchterm->FIELDNAME?
I guess I'm misunderstanding something very fundamental here about how Antlr Grammars work, but what?
/* ANTLR Grammar for Minidb Query Language */
grammar Mdb;
start : searchclause EOF ;
searchclause
: table expr
;
expr
: fieldsearch
| unop fieldsearch
| LPAREN expr relop expr RPAREN
;
unop
: NOT
;
relop
: AND
| OR
;
fieldsearch
: field EQ searchterm
;
field
: FIELDNAME
;
table
: TABLENAME
;
searchterm
: STRING
;
AND
: 'and'
;
OR
: 'or'
;
NOT
: 'not'
;
EQ
: '='
;
LPAREN
: '('
;
RPAREN
: ')'
;
fragment VALID_ID_START
: ('a' .. 'z') | ('A' .. 'Z') | '_'
;
fragment VALID_ID_CHAR
: VALID_ID_START | ('0' .. '9')
;
TABLENAME
: VALID_ID_START VALID_ID_CHAR*
;
FIELDNAME
: VALID_ID_START VALID_ID_CHAR*
;
STRING: '"' ~('n'|'"')* ('"' | panic("syntax-error - unterminated string literal") ) ;
WS
: [ rnt] + -> skip
;
antlr antlr4 context-free-grammar
I want to parse query expressions that look like this:
Person Name=%John%
(Person Name=John% and Address=%Ontario%)
Person Fullname_3="John C. Smith"
But I'm totally new to Antlr4 and can't even figure out how to parse one single TABLE FIELD=QUERY clause. When I run the grammar below in Go as target, I get
line 1:7 mismatched input 'Name' expecting 'not', '(', FIELDNAME
for a simple query like
Person Name=John
Why can't the Grammar parse FIELDNAME via parsing fieldsearch->field EQ searchterm->FIELDNAME?
I guess I'm misunderstanding something very fundamental here about how Antlr Grammars work, but what?
/* ANTLR Grammar for Minidb Query Language */
grammar Mdb;
start : searchclause EOF ;
searchclause
: table expr
;
expr
: fieldsearch
| unop fieldsearch
| LPAREN expr relop expr RPAREN
;
unop
: NOT
;
relop
: AND
| OR
;
fieldsearch
: field EQ searchterm
;
field
: FIELDNAME
;
table
: TABLENAME
;
searchterm
: STRING
;
AND
: 'and'
;
OR
: 'or'
;
NOT
: 'not'
;
EQ
: '='
;
LPAREN
: '('
;
RPAREN
: ')'
;
fragment VALID_ID_START
: ('a' .. 'z') | ('A' .. 'Z') | '_'
;
fragment VALID_ID_CHAR
: VALID_ID_START | ('0' .. '9')
;
TABLENAME
: VALID_ID_START VALID_ID_CHAR*
;
FIELDNAME
: VALID_ID_START VALID_ID_CHAR*
;
STRING: '"' ~('n'|'"')* ('"' | panic("syntax-error - unterminated string literal") ) ;
WS
: [ rnt] + -> skip
;
antlr antlr4 context-free-grammar
antlr antlr4 context-free-grammar
asked Nov 10 '18 at 18:24
Eric '3ToedSloth'Eric '3ToedSloth'
1947
1947
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Try looking at the tokens produced for that input using grun Mdb tokens -tokens. It will tell you that the input consists of two table names, an equals sign and then another table name. To match your grammar it would have needed to be a table name, a field name, an equals sign and a string.
The first problem is that TABLENAME and FIELDNAME have the exact same definition. In cases where two lexer rules would produce a match of the same length on the current input, ANTLR prefers the one that comes first in the grammar. So it will never produce a FIELDNAME token. To fix that just replace both of those rules with a single ID rule. If you want to, you can then introduce parser rules tableName : ID ; and fieldName : ID ; if you want to keep the names.
The other problem is more straight forward: John simply does not match your rules for a string since it's not in quotes. If you do want to allow John as a valid search term, you might want to define it as searchterm : STRING | ID ; instead of only allowing STRINGs.
Perfect reply, I understand the problem now. Thank you so much!
– Eric '3ToedSloth'
Nov 10 '18 at 22:07
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
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oldest
votes
Try looking at the tokens produced for that input using grun Mdb tokens -tokens. It will tell you that the input consists of two table names, an equals sign and then another table name. To match your grammar it would have needed to be a table name, a field name, an equals sign and a string.
The first problem is that TABLENAME and FIELDNAME have the exact same definition. In cases where two lexer rules would produce a match of the same length on the current input, ANTLR prefers the one that comes first in the grammar. So it will never produce a FIELDNAME token. To fix that just replace both of those rules with a single ID rule. If you want to, you can then introduce parser rules tableName : ID ; and fieldName : ID ; if you want to keep the names.
The other problem is more straight forward: John simply does not match your rules for a string since it's not in quotes. If you do want to allow John as a valid search term, you might want to define it as searchterm : STRING | ID ; instead of only allowing STRINGs.
Perfect reply, I understand the problem now. Thank you so much!
– Eric '3ToedSloth'
Nov 10 '18 at 22:07
add a comment |
Try looking at the tokens produced for that input using grun Mdb tokens -tokens. It will tell you that the input consists of two table names, an equals sign and then another table name. To match your grammar it would have needed to be a table name, a field name, an equals sign and a string.
The first problem is that TABLENAME and FIELDNAME have the exact same definition. In cases where two lexer rules would produce a match of the same length on the current input, ANTLR prefers the one that comes first in the grammar. So it will never produce a FIELDNAME token. To fix that just replace both of those rules with a single ID rule. If you want to, you can then introduce parser rules tableName : ID ; and fieldName : ID ; if you want to keep the names.
The other problem is more straight forward: John simply does not match your rules for a string since it's not in quotes. If you do want to allow John as a valid search term, you might want to define it as searchterm : STRING | ID ; instead of only allowing STRINGs.
Perfect reply, I understand the problem now. Thank you so much!
– Eric '3ToedSloth'
Nov 10 '18 at 22:07
add a comment |
Try looking at the tokens produced for that input using grun Mdb tokens -tokens. It will tell you that the input consists of two table names, an equals sign and then another table name. To match your grammar it would have needed to be a table name, a field name, an equals sign and a string.
The first problem is that TABLENAME and FIELDNAME have the exact same definition. In cases where two lexer rules would produce a match of the same length on the current input, ANTLR prefers the one that comes first in the grammar. So it will never produce a FIELDNAME token. To fix that just replace both of those rules with a single ID rule. If you want to, you can then introduce parser rules tableName : ID ; and fieldName : ID ; if you want to keep the names.
The other problem is more straight forward: John simply does not match your rules for a string since it's not in quotes. If you do want to allow John as a valid search term, you might want to define it as searchterm : STRING | ID ; instead of only allowing STRINGs.
Try looking at the tokens produced for that input using grun Mdb tokens -tokens. It will tell you that the input consists of two table names, an equals sign and then another table name. To match your grammar it would have needed to be a table name, a field name, an equals sign and a string.
The first problem is that TABLENAME and FIELDNAME have the exact same definition. In cases where two lexer rules would produce a match of the same length on the current input, ANTLR prefers the one that comes first in the grammar. So it will never produce a FIELDNAME token. To fix that just replace both of those rules with a single ID rule. If you want to, you can then introduce parser rules tableName : ID ; and fieldName : ID ; if you want to keep the names.
The other problem is more straight forward: John simply does not match your rules for a string since it's not in quotes. If you do want to allow John as a valid search term, you might want to define it as searchterm : STRING | ID ; instead of only allowing STRINGs.
edited Nov 12 '18 at 23:24
answered Nov 10 '18 at 18:44
sepp2ksepp2k
293k38593609
293k38593609
Perfect reply, I understand the problem now. Thank you so much!
– Eric '3ToedSloth'
Nov 10 '18 at 22:07
add a comment |
Perfect reply, I understand the problem now. Thank you so much!
– Eric '3ToedSloth'
Nov 10 '18 at 22:07
Perfect reply, I understand the problem now. Thank you so much!
– Eric '3ToedSloth'
Nov 10 '18 at 22:07
Perfect reply, I understand the problem now. Thank you so much!
– Eric '3ToedSloth'
Nov 10 '18 at 22:07
add a comment |
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