Simple jQuery .size() and .length() 'not a function' error [duplicate]
Simple jQuery .size() and .length() 'not a function' error [duplicate]
This question already has an answer here:
I am getting this error:
TypeError: $(this).find('.btn-default').size is not a function. (In '$(this).find('.btn-default').size()', '$(this).find('.btn-default').size' is undefined)
As a result of this code:
console.log($(this).find('.btn-default').size());
I get the same error if I use .length() instead. I am using jQuery 3.3.1. This working example is using jQuery 3.1.1 with size(). I'm sure I'm doing something incredibly simple but wrong, but I cannot find the problem.
.length()
size()
EDIT: Once again, the problem was my bad eyesight. The answer is: length is a property, not a function.
length
Who knows why the codeply example claims to be using jQuery 3.1.1. with size() but clearly that should not be possible, according to comments below.
codeply
size()
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size()
length
.length
size()
length
Your example is using jQuery 1.9.1, not 3.3.1 as you claim
– j08691
Sep 5 '18 at 20:54
Why exactly are you using .size() and .length()?
– Kevin B
Sep 5 '18 at 20:55
console.log($(this).find('.btn').length); fails the same way.– CXJ
Sep 5 '18 at 20:55
console.log($(this).find('.btn').length);
In my haste to respond to all of your comments, I misread the console error messages a bit:
.length did not fail, but rather a later call to .length() leftover from my experiments failed. Answer below is correct. I needed to use a property, not a function.– CXJ
Sep 5 '18 at 21:04
.length
.length()
1 Answer
1
the size is deprected since 1.8 and removed in 3.0 see here size()
Use $(this).find('.btn-default').length (property not function ) instead
$(this).find('.btn-default').length
"property not function" is the key. I misread the docs, and then further misread my debug output on the console, and got mislead.
– CXJ
Sep 5 '18 at 21:05
@CXJ I'm glad you fixed your issue :)
– Boo Berr'ita
Sep 5 '18 at 21:07
size()is depreciated as of jQuery v1.8 andlengthdoes not accept parameters, so it would just be.length. Seesize()andlength– showdev
Sep 5 '18 at 20:53