Ajax request, when formatting the results, certain elements fail if I add over 2 lines of code
Sorry for the very weird wording of that question, I don't know how to explain it. Basically, I have a text input that acts as a search. Whenever you type a letter or word in, it makes a request to the Spotify API and returns the 5 best matching results; the code is below.
$("#SongSearch").keyup(function()
$.ajax(
url: "https://api.spotify.com/v1/search?q=" + encodeURI(document.getElementById("SongSearch").value) + "&type=track&market=US&limit=5&offset=0",
headers:
'Authorization': 'Bearer ' + access_token
,
success: function(InfoGained)
document.getElementById("result1").innerHTML = InfoGained.tracks.items[0].name + ", " + InfoGained.tracks.items[0].artists[0].name;
document.getElementById("result2").innerHTML = InfoGained.tracks.items[1].name + ", " + InfoGained.tracks.items[1].artists[1].name;
document.getElementById("result3").innerHTML = InfoGained.tracks.items[2].name + ", " + InfoGained.tracks.items[2].artists[2].name;
document.getElementById("result4").innerHTML = InfoGained.tracks.items[3].name + ", " + InfoGained.tracks.items[3].artists[3].name;
document.getElementById("result5").innerHTML = InfoGained.tracks.items[4].name + ", " + InfoGained.tracks.items[4].artists[4].name;
);
);
This code correctly calls the API and gets the results. However, when formatting it, if I add more than two of the document.getElementByID... lines in, only two lines work. Example, this works:
$("#SongSearch").keyup(function()
$.ajax(
url: "https://api.spotify.com/v1/search?q=" + encodeURI(document.getElementById("SongSearch").value) + "&type=track&market=US&limit=5&offset=0",
headers:
'Authorization': 'Bearer ' + access_token
,
success: function(InfoGained)
document.getElementById("result1").innerHTML = InfoGained.tracks.items[0].name + ", " + InfoGained.tracks.items[0].artists[0].name;
document.getElementById("result2").innerHTML = InfoGained.tracks.items[1].name + ", " + InfoGained.tracks.items[1].artists[1].name;
);
);
But more than two lines of the document.getElementID..., such as the first segment of code listed results in the error: "Uncaught TypeError: Cannot read property 'name' of undefined". Any help is appreciated as I truly have no idea what is causing this. Thanks in advance,
Justin
javascript jquery json spotify
asked Nov 10 '18 at 15:41
JustluceJustluce
141
add a comment |
Sorry for the very weird wording of that question, I don't know how to explain it. Basically, I have a text input that acts as a search. Whenever you type a letter or word in, it makes a request to the Spotify API and returns the 5 best matching results; the code is below.
$("#SongSearch").keyup(function()
$.ajax(
url: "https://api.spotify.com/v1/search?q=" + encodeURI(document.getElementById("SongSearch").value) + "&type=track&market=US&limit=5&offset=0",
headers:
'Authorization': 'Bearer ' + access_token
,
success: function(InfoGained)
document.getElementById("result1").innerHTML = InfoGained.tracks.items[0].name + ", " + InfoGained.tracks.items[0].artists[0].name;
document.getElementById("result2").innerHTML = InfoGained.tracks.items[1].name + ", " + InfoGained.tracks.items[1].artists[1].name;
document.getElementById("result3").innerHTML = InfoGained.tracks.items[2].name + ", " + InfoGained.tracks.items[2].artists[2].name;
document.getElementById("result4").innerHTML = InfoGained.tracks.items[3].name + ", " + InfoGained.tracks.items[3].artists[3].name;
document.getElementById("result5").innerHTML = InfoGained.tracks.items[4].name + ", " + InfoGained.tracks.items[4].artists[4].name;
);
);
This code correctly calls the API and gets the results. However, when formatting it, if I add more than two of the document.getElementByID... lines in, only two lines work. Example, this works:
$("#SongSearch").keyup(function()
$.ajax(
url: "https://api.spotify.com/v1/search?q=" + encodeURI(document.getElementById("SongSearch").value) + "&type=track&market=US&limit=5&offset=0",
headers:
'Authorization': 'Bearer ' + access_token
,
success: function(InfoGained)
document.getElementById("result1").innerHTML = InfoGained.tracks.items[0].name + ", " + InfoGained.tracks.items[0].artists[0].name;
document.getElementById("result2").innerHTML = InfoGained.tracks.items[1].name + ", " + InfoGained.tracks.items[1].artists[1].name;
);
);
But more than two lines of the document.getElementID..., such as the first segment of code listed results in the error: "Uncaught TypeError: Cannot read property 'name' of undefined". Any help is appreciated as I truly have no idea what is causing this. Thanks in advance,
Justin
javascript jquery json spotify
asked Nov 10 '18 at 15:41
JustluceJustluce
141
1) Why aren't you using jQuery for those element selections? 2) You should add a sample of the ajax response to your question because you're likely selecting a property from a non-existent array element.
– Andy
Nov 10 '18 at 15:44
I guess you really want to checkartists[0].namefor all tracks. Not many tracks have 5 artists.
– Frax
Nov 10 '18 at 15:47
1
Also, try learning how to debug your code. You really have everything in the error message here, and you could probably find the error quickly by inspecting the response withconsole.log(InfoGained)or something similar. It's simply much faster to find it yourself.
– Frax
Nov 10 '18 at 15:54
Okay, so, some clarifications. Each call works individually. so if I called tracks.items[4].name + ... it works, so I know that's not the problem. It's only when I call them together/call more than 2 that it gives an error. Also, its getting the artist of each track individually, not getting 5 artists from one track.
– Justluce
Nov 10 '18 at 16:00
You should create a loop to loop over the array and handle specific instance inside the loop
– charlietfl
Nov 10 '18 at 16:04
add a comment |
Sorry for the very weird wording of that question, I don't know how to explain it. Basically, I have a text input that acts as a search. Whenever you type a letter or word in, it makes a request to the Spotify API and returns the 5 best matching results; the code is below.
$("#SongSearch").keyup(function()
$.ajax(
url: "https://api.spotify.com/v1/search?q=" + encodeURI(document.getElementById("SongSearch").value) + "&type=track&market=US&limit=5&offset=0",
headers:
'Authorization': 'Bearer ' + access_token
,
success: function(InfoGained)
document.getElementById("result1").innerHTML = InfoGained.tracks.items[0].name + ", " + InfoGained.tracks.items[0].artists[0].name;
document.getElementById("result2").innerHTML = InfoGained.tracks.items[1].name + ", " + InfoGained.tracks.items[1].artists[1].name;
document.getElementById("result3").innerHTML = InfoGained.tracks.items[2].name + ", " + InfoGained.tracks.items[2].artists[2].name;
document.getElementById("result4").innerHTML = InfoGained.tracks.items[3].name + ", " + InfoGained.tracks.items[3].artists[3].name;
document.getElementById("result5").innerHTML = InfoGained.tracks.items[4].name + ", " + InfoGained.tracks.items[4].artists[4].name;
);
);
This code correctly calls the API and gets the results. However, when formatting it, if I add more than two of the document.getElementByID... lines in, only two lines work. Example, this works:
$("#SongSearch").keyup(function()
$.ajax(
url: "https://api.spotify.com/v1/search?q=" + encodeURI(document.getElementById("SongSearch").value) + "&type=track&market=US&limit=5&offset=0",
headers:
'Authorization': 'Bearer ' + access_token
,
success: function(InfoGained)
document.getElementById("result1").innerHTML = InfoGained.tracks.items[0].name + ", " + InfoGained.tracks.items[0].artists[0].name;
document.getElementById("result2").innerHTML = InfoGained.tracks.items[1].name + ", " + InfoGained.tracks.items[1].artists[1].name;
);
);
But more than two lines of the document.getElementID..., such as the first segment of code listed results in the error: "Uncaught TypeError: Cannot read property 'name' of undefined". Any help is appreciated as I truly have no idea what is causing this. Thanks in advance,
Justin
javascript jquery json spotify
asked Nov 10 '18 at 15:41
JustluceJustluce
141
Sorry for the very weird wording of that question, I don't know how to explain it. Basically, I have a text input that acts as a search. Whenever you type a letter or word in, it makes a request to the Spotify API and returns the 5 best matching results; the code is below.
$("#SongSearch").keyup(function()
$.ajax(
url: "https://api.spotify.com/v1/search?q=" + encodeURI(document.getElementById("SongSearch").value) + "&type=track&market=US&limit=5&offset=0",
headers:
'Authorization': 'Bearer ' + access_token
,
success: function(InfoGained)
document.getElementById("result1").innerHTML = InfoGained.tracks.items[0].name + ", " + InfoGained.tracks.items[0].artists[0].name;
document.getElementById("result2").innerHTML = InfoGained.tracks.items[1].name + ", " + InfoGained.tracks.items[1].artists[1].name;
document.getElementById("result3").innerHTML = InfoGained.tracks.items[2].name + ", " + InfoGained.tracks.items[2].artists[2].name;
document.getElementById("result4").innerHTML = InfoGained.tracks.items[3].name + ", " + InfoGained.tracks.items[3].artists[3].name;
document.getElementById("result5").innerHTML = InfoGained.tracks.items[4].name + ", " + InfoGained.tracks.items[4].artists[4].name;
);
);
This code correctly calls the API and gets the results. However, when formatting it, if I add more than two of the document.getElementByID... lines in, only two lines work. Example, this works:
$("#SongSearch").keyup(function()
$.ajax(
url: "https://api.spotify.com/v1/search?q=" + encodeURI(document.getElementById("SongSearch").value) + "&type=track&market=US&limit=5&offset=0",
headers:
'Authorization': 'Bearer ' + access_token
,
success: function(InfoGained)
document.getElementById("result1").innerHTML = InfoGained.tracks.items[0].name + ", " + InfoGained.tracks.items[0].artists[0].name;
document.getElementById("result2").innerHTML = InfoGained.tracks.items[1].name + ", " + InfoGained.tracks.items[1].artists[1].name;
);
);
But more than two lines of the document.getElementID..., such as the first segment of code listed results in the error: "Uncaught TypeError: Cannot read property 'name' of undefined". Any help is appreciated as I truly have no idea what is causing this. Thanks in advance,
Justin
javascript jquery json spotify
javascript jquery json spotify
asked Nov 10 '18 at 15:41
JustluceJustluce
141
asked Nov 10 '18 at 15:41
JustluceJustluce
141
asked Nov 10 '18 at 15:41
JustluceJustluce
141
asked Nov 10 '18 at 15:41
JustluceJustluce
141
asked Nov 10 '18 at 15:41
JustluceJustluce
141
141
1) Why aren't you using jQuery for those element selections? 2) You should add a sample of the ajax response to your question because you're likely selecting a property from a non-existent array element.
– Andy
Nov 10 '18 at 15:44
I guess you really want to checkartists[0].namefor all tracks. Not many tracks have 5 artists.
– Frax
Nov 10 '18 at 15:47
1
Also, try learning how to debug your code. You really have everything in the error message here, and you could probably find the error quickly by inspecting the response withconsole.log(InfoGained)or something similar. It's simply much faster to find it yourself.
– Frax
Nov 10 '18 at 15:54
Okay, so, some clarifications. Each call works individually. so if I called tracks.items[4].name + ... it works, so I know that's not the problem. It's only when I call them together/call more than 2 that it gives an error. Also, its getting the artist of each track individually, not getting 5 artists from one track.
– Justluce
Nov 10 '18 at 16:00
You should create a loop to loop over the array and handle specific instance inside the loop
– charlietfl
Nov 10 '18 at 16:04
add a comment |
1) Why aren't you using jQuery for those element selections? 2) You should add a sample of the ajax response to your question because you're likely selecting a property from a non-existent array element.
– Andy
Nov 10 '18 at 15:44
I guess you really want to checkartists[0].namefor all tracks. Not many tracks have 5 artists.
– Frax
Nov 10 '18 at 15:47
1
Also, try learning how to debug your code. You really have everything in the error message here, and you could probably find the error quickly by inspecting the response withconsole.log(InfoGained)or something similar. It's simply much faster to find it yourself.
– Frax
Nov 10 '18 at 15:54
Okay, so, some clarifications. Each call works individually. so if I called tracks.items[4].name + ... it works, so I know that's not the problem. It's only when I call them together/call more than 2 that it gives an error. Also, its getting the artist of each track individually, not getting 5 artists from one track.
– Justluce
Nov 10 '18 at 16:00
You should create a loop to loop over the array and handle specific instance inside the loop
– charlietfl
Nov 10 '18 at 16:04
1) Why aren't you using jQuery for those element selections? 2) You should add a sample of the ajax response to your question because you're likely selecting a property from a non-existent array element.
– Andy
Nov 10 '18 at 15:44
1) Why aren't you using jQuery for those element selections? 2) You should add a sample of the ajax response to your question because you're likely selecting a property from a non-existent array element.
– Andy
Nov 10 '18 at 15:44
I guess you really want to check
artists[0].name for all tracks. Not many tracks have 5 artists.– Frax
Nov 10 '18 at 15:47
I guess you really want to check
artists[0].name for all tracks. Not many tracks have 5 artists.– Frax
Nov 10 '18 at 15:47
1
1
Also, try learning how to debug your code. You really have everything in the error message here, and you could probably find the error quickly by inspecting the response with
console.log(InfoGained) or something similar. It's simply much faster to find it yourself.– Frax
Nov 10 '18 at 15:54
Also, try learning how to debug your code. You really have everything in the error message here, and you could probably find the error quickly by inspecting the response with
console.log(InfoGained) or something similar. It's simply much faster to find it yourself.– Frax
Nov 10 '18 at 15:54
Okay, so, some clarifications. Each call works individually. so if I called tracks.items[4].name + ... it works, so I know that's not the problem. It's only when I call them together/call more than 2 that it gives an error. Also, its getting the artist of each track individually, not getting 5 artists from one track.
– Justluce
Nov 10 '18 at 16:00
Okay, so, some clarifications. Each call works individually. so if I called tracks.items[4].name + ... it works, so I know that's not the problem. It's only when I call them together/call more than 2 that it gives an error. Also, its getting the artist of each track individually, not getting 5 artists from one track.
– Justluce
Nov 10 '18 at 16:00
You should create a loop to loop over the array and handle specific instance inside the loop
– charlietfl
Nov 10 '18 at 16:04
You should create a loop to loop over the array and handle specific instance inside the loop
– charlietfl
Nov 10 '18 at 16:04
add a comment |
1 Answer
1
active
oldest
votes
I realized after staring at it for an hour or two that InfoGained.tracks.items[4].artists[4].name; is calling the 5th artist for the 5th song. It should have been InfoGained.tracks.items[4].artists[0].name; Thank you everyone, especially Frax, for the help!
answered Nov 10 '18 at 17:25
JustluceJustluce
141
add a comment |
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I realized after staring at it for an hour or two that InfoGained.tracks.items[4].artists[4].name; is calling the 5th artist for the 5th song. It should have been InfoGained.tracks.items[4].artists[0].name; Thank you everyone, especially Frax, for the help!
answered Nov 10 '18 at 17:25
JustluceJustluce
141
add a comment |
I realized after staring at it for an hour or two that InfoGained.tracks.items[4].artists[4].name; is calling the 5th artist for the 5th song. It should have been InfoGained.tracks.items[4].artists[0].name; Thank you everyone, especially Frax, for the help!
answered Nov 10 '18 at 17:25
JustluceJustluce
141
add a comment |
I realized after staring at it for an hour or two that InfoGained.tracks.items[4].artists[4].name; is calling the 5th artist for the 5th song. It should have been InfoGained.tracks.items[4].artists[0].name; Thank you everyone, especially Frax, for the help!
answered Nov 10 '18 at 17:25
JustluceJustluce
141
I realized after staring at it for an hour or two that InfoGained.tracks.items[4].artists[4].name; is calling the 5th artist for the 5th song. It should have been InfoGained.tracks.items[4].artists[0].name; Thank you everyone, especially Frax, for the help!
answered Nov 10 '18 at 17:25
JustluceJustluce
141
answered Nov 10 '18 at 17:25
JustluceJustluce
141
answered Nov 10 '18 at 17:25
JustluceJustluce
141
answered Nov 10 '18 at 17:25
JustluceJustluce
141
141
add a comment |
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1) Why aren't you using jQuery for those element selections? 2) You should add a sample of the ajax response to your question because you're likely selecting a property from a non-existent array element.
– Andy
Nov 10 '18 at 15:44
I guess you really want to check
artists[0].namefor all tracks. Not many tracks have 5 artists.– Frax
Nov 10 '18 at 15:47
1
Also, try learning how to debug your code. You really have everything in the error message here, and you could probably find the error quickly by inspecting the response with
console.log(InfoGained)or something similar. It's simply much faster to find it yourself.– Frax
Nov 10 '18 at 15:54
Okay, so, some clarifications. Each call works individually. so if I called tracks.items[4].name + ... it works, so I know that's not the problem. It's only when I call them together/call more than 2 that it gives an error. Also, its getting the artist of each track individually, not getting 5 artists from one track.
– Justluce
Nov 10 '18 at 16:00
You should create a loop to loop over the array and handle specific instance inside the loop
– charlietfl
Nov 10 '18 at 16:04