Firebase query results are mistaken










1














This is my database design.



foodie-ab2b4
Foods
0
FoodName: "Baked Beans In Tomato Sauce"
FoodRecipe:
FoodUri:
Image:

1
FoodName: "Another bean




I'm working on an ios project and this is how my firebase json structured.



let ref = Database.database().reference()
func searchFoodByName(FoodName: String)
let foodsRef = ref.child("Foods")

let input = FoodName
let query = foodsRef.child(key).queryOrdered(byChild: "FoodName").queryEnding(atValue: input)
query.observeSingleEvent(of: .value, with: snapshot in
print(snapshot)
for child in snapshot.children
let snap = child as! DataSnapshot
let dict = snap.value as! [String: Any]
let fName = dict["FoodName"] as! String
let fIngredients = dict["Ingredients"] as! [String]
print(fName)
print(fIngredients)

let key = snapshot.key
print(key)

)



I'm trying to filter my food objects by their names. I have 10 objects in my database. In most cases this search return true objects. But there is one example i can not solve.



When i query the "tomato" word i need to get 1 object. But there is two. Although there is no tomato word in my second object.



The two object is in my json file.



If it is necessary i can upload my whole JSON file to here.










share|improve this question























  • What is the value of key?
    – Frank van Puffelen
    Nov 10 '18 at 17:47















1














This is my database design.



foodie-ab2b4
Foods
0
FoodName: "Baked Beans In Tomato Sauce"
FoodRecipe:
FoodUri:
Image:

1
FoodName: "Another bean




I'm working on an ios project and this is how my firebase json structured.



let ref = Database.database().reference()
func searchFoodByName(FoodName: String)
let foodsRef = ref.child("Foods")

let input = FoodName
let query = foodsRef.child(key).queryOrdered(byChild: "FoodName").queryEnding(atValue: input)
query.observeSingleEvent(of: .value, with: snapshot in
print(snapshot)
for child in snapshot.children
let snap = child as! DataSnapshot
let dict = snap.value as! [String: Any]
let fName = dict["FoodName"] as! String
let fIngredients = dict["Ingredients"] as! [String]
print(fName)
print(fIngredients)

let key = snapshot.key
print(key)

)



I'm trying to filter my food objects by their names. I have 10 objects in my database. In most cases this search return true objects. But there is one example i can not solve.



When i query the "tomato" word i need to get 1 object. But there is two. Although there is no tomato word in my second object.



The two object is in my json file.



If it is necessary i can upload my whole JSON file to here.










share|improve this question























  • What is the value of key?
    – Frank van Puffelen
    Nov 10 '18 at 17:47













1












1








1







This is my database design.



foodie-ab2b4
Foods
0
FoodName: "Baked Beans In Tomato Sauce"
FoodRecipe:
FoodUri:
Image:

1
FoodName: "Another bean




I'm working on an ios project and this is how my firebase json structured.



let ref = Database.database().reference()
func searchFoodByName(FoodName: String)
let foodsRef = ref.child("Foods")

let input = FoodName
let query = foodsRef.child(key).queryOrdered(byChild: "FoodName").queryEnding(atValue: input)
query.observeSingleEvent(of: .value, with: snapshot in
print(snapshot)
for child in snapshot.children
let snap = child as! DataSnapshot
let dict = snap.value as! [String: Any]
let fName = dict["FoodName"] as! String
let fIngredients = dict["Ingredients"] as! [String]
print(fName)
print(fIngredients)

let key = snapshot.key
print(key)

)



I'm trying to filter my food objects by their names. I have 10 objects in my database. In most cases this search return true objects. But there is one example i can not solve.



When i query the "tomato" word i need to get 1 object. But there is two. Although there is no tomato word in my second object.



The two object is in my json file.



If it is necessary i can upload my whole JSON file to here.










share|improve this question















This is my database design.



foodie-ab2b4
Foods
0
FoodName: "Baked Beans In Tomato Sauce"
FoodRecipe:
FoodUri:
Image:

1
FoodName: "Another bean




I'm working on an ios project and this is how my firebase json structured.



let ref = Database.database().reference()
func searchFoodByName(FoodName: String)
let foodsRef = ref.child("Foods")

let input = FoodName
let query = foodsRef.child(key).queryOrdered(byChild: "FoodName").queryEnding(atValue: input)
query.observeSingleEvent(of: .value, with: snapshot in
print(snapshot)
for child in snapshot.children
let snap = child as! DataSnapshot
let dict = snap.value as! [String: Any]
let fName = dict["FoodName"] as! String
let fIngredients = dict["Ingredients"] as! [String]
print(fName)
print(fIngredients)

let key = snapshot.key
print(key)

)



I'm trying to filter my food objects by their names. I have 10 objects in my database. In most cases this search return true objects. But there is one example i can not solve.



When i query the "tomato" word i need to get 1 object. But there is two. Although there is no tomato word in my second object.



The two object is in my json file.



If it is necessary i can upload my whole JSON file to here.







ios swift firebase firebase-realtime-database






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edited Nov 10 '18 at 17:46









Frank van Puffelen

228k28374398




228k28374398










asked Nov 10 '18 at 15:46









AsgencerAsgencer

62




62











  • What is the value of key?
    – Frank van Puffelen
    Nov 10 '18 at 17:47
















  • What is the value of key?
    – Frank van Puffelen
    Nov 10 '18 at 17:47















What is the value of key?
– Frank van Puffelen
Nov 10 '18 at 17:47




What is the value of key?
– Frank van Puffelen
Nov 10 '18 at 17:47












1 Answer
1






active

oldest

votes


















0














You seem to assume that Firebase can filter based on strings that contain a value, but it can't. See Firebase query - Find item with child that contains string (and the many links from there).



What Firebase can do is search for string values that start with a certain value. You do that by using a combination of queryStarting(atValue:) and queryEnding(atValue:):



let query = foodsRef
.queryOrdered(byChild: "FoodName")
.queryStarting(atValue: input)
.queryEnding(atValue: input+"\uf8ff")


If you use this query, and input is ``Baked`, it will only match the first food from your JSON.






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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    You seem to assume that Firebase can filter based on strings that contain a value, but it can't. See Firebase query - Find item with child that contains string (and the many links from there).



    What Firebase can do is search for string values that start with a certain value. You do that by using a combination of queryStarting(atValue:) and queryEnding(atValue:):



    let query = foodsRef
    .queryOrdered(byChild: "FoodName")
    .queryStarting(atValue: input)
    .queryEnding(atValue: input+"\uf8ff")


    If you use this query, and input is ``Baked`, it will only match the first food from your JSON.






    share|improve this answer



























      0














      You seem to assume that Firebase can filter based on strings that contain a value, but it can't. See Firebase query - Find item with child that contains string (and the many links from there).



      What Firebase can do is search for string values that start with a certain value. You do that by using a combination of queryStarting(atValue:) and queryEnding(atValue:):



      let query = foodsRef
      .queryOrdered(byChild: "FoodName")
      .queryStarting(atValue: input)
      .queryEnding(atValue: input+"\uf8ff")


      If you use this query, and input is ``Baked`, it will only match the first food from your JSON.






      share|improve this answer

























        0












        0








        0






        You seem to assume that Firebase can filter based on strings that contain a value, but it can't. See Firebase query - Find item with child that contains string (and the many links from there).



        What Firebase can do is search for string values that start with a certain value. You do that by using a combination of queryStarting(atValue:) and queryEnding(atValue:):



        let query = foodsRef
        .queryOrdered(byChild: "FoodName")
        .queryStarting(atValue: input)
        .queryEnding(atValue: input+"\uf8ff")


        If you use this query, and input is ``Baked`, it will only match the first food from your JSON.






        share|improve this answer














        You seem to assume that Firebase can filter based on strings that contain a value, but it can't. See Firebase query - Find item with child that contains string (and the many links from there).



        What Firebase can do is search for string values that start with a certain value. You do that by using a combination of queryStarting(atValue:) and queryEnding(atValue:):



        let query = foodsRef
        .queryOrdered(byChild: "FoodName")
        .queryStarting(atValue: input)
        .queryEnding(atValue: input+"\uf8ff")


        If you use this query, and input is ``Baked`, it will only match the first food from your JSON.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 25 '18 at 21:44









        marc_s

        572k12811051252




        572k12811051252










        answered Nov 10 '18 at 17:54









        Frank van PuffelenFrank van Puffelen

        228k28374398




        228k28374398



























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