Set a minimum value for randomly generated numbers [duplicate]

This question already has an answer here:

Generate random number between two numbers in JavaScript

18 answers

I am using this function to generate and alternate random values inside a div

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text( ''+ Math.floor(Math.random() * 100) ); 
, 1000);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

What I want to do is to control the min value too.
For example, to have random generated values from 50 to 100.
Not starting from zero(0) as other posts do

edited Nov 11 '18 at 10:39

Mohammad

15.5k123461

asked Nov 11 '18 at 10:11

Bill

7017

marked as duplicate by Mohammad, trincot javascript
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Nov 11 '18 at 10:31

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

1

developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

– Álvaro González
Nov 11 '18 at 10:16

@Mohammad I want to control the minimum value. The answer you posted is about to generate random number too, but with no minimum limit. values there starting from 0

– Bill
Nov 11 '18 at 10:27

@Bill Promlem fixed

– Mohammad
Nov 11 '18 at 10:30

add a comment |

This question already has an answer here:

Generate random number between two numbers in JavaScript

18 answers

I am using this function to generate and alternate random values inside a div

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text( ''+ Math.floor(Math.random() * 100) ); 
, 1000);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

What I want to do is to control the min value too.
For example, to have random generated values from 50 to 100.
Not starting from zero(0) as other posts do

edited Nov 11 '18 at 10:39

Mohammad

15.5k123461

asked Nov 11 '18 at 10:11

Bill

7017

marked as duplicate by Mohammad, trincot javascript
Users with the javascript badge can single-handedly close javascript questions as duplicates and reopen them as needed.

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Nov 11 '18 at 10:31

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

1

developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

– Álvaro González
Nov 11 '18 at 10:16

@Mohammad I want to control the minimum value. The answer you posted is about to generate random number too, but with no minimum limit. values there starting from 0

– Bill
Nov 11 '18 at 10:27

@Bill Promlem fixed

– Mohammad
Nov 11 '18 at 10:30

add a comment |

This question already has an answer here:

Generate random number between two numbers in JavaScript

18 answers

I am using this function to generate and alternate random values inside a div

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text( ''+ Math.floor(Math.random() * 100) ); 
, 1000);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

What I want to do is to control the min value too.
For example, to have random generated values from 50 to 100.
Not starting from zero(0) as other posts do

edited Nov 11 '18 at 10:39

Mohammad

15.5k123461

asked Nov 11 '18 at 10:11

Bill

7017

This question already has an answer here:

Generate random number between two numbers in JavaScript

18 answers

I am using this function to generate and alternate random values inside a div

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text( ''+ Math.floor(Math.random() * 100) ); 
, 1000);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

What I want to do is to control the min value too.
For example, to have random generated values from 50 to 100.
Not starting from zero(0) as other posts do

This question already has an answer here:

Generate random number between two numbers in JavaScript

18 answers

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text( ''+ Math.floor(Math.random() * 100) ); 
, 1000);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text( ''+ Math.floor(Math.random() * 100) ); 
, 1000);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

javascript jquery random

edited Nov 11 '18 at 10:39

Mohammad

15.5k123461

asked Nov 11 '18 at 10:11

Bill

7017

edited Nov 11 '18 at 10:39

Mohammad

15.5k123461

asked Nov 11 '18 at 10:11

Bill

7017

edited Nov 11 '18 at 10:39

Mohammad

15.5k123461

edited Nov 11 '18 at 10:39

Mohammad

15.5k123461

edited Nov 11 '18 at 10:39

Mohammad

15.5k123461

asked Nov 11 '18 at 10:11

Bill

7017

asked Nov 11 '18 at 10:11

Bill

7017

asked Nov 11 '18 at 10:11

Bill

7017

marked as duplicate by Mohammad, trincot javascript
Users with the javascript badge can single-handedly close javascript questions as duplicates and reopen them as needed.

StackExchange.ready(function()
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$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
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dismissable: false,
relativeToBody: true
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StackExchange.helpers.removeMessages();

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Nov 11 '18 at 10:31

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by Mohammad, trincot javascript
Users with the javascript badge can single-handedly close javascript questions as duplicates and reopen them as needed.

StackExchange.ready(function()
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StackExchange.helpers.removeMessages();

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Nov 11 '18 at 10:31

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

1

developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

– Álvaro González
Nov 11 '18 at 10:16

@Mohammad I want to control the minimum value. The answer you posted is about to generate random number too, but with no minimum limit. values there starting from 0

– Bill
Nov 11 '18 at 10:27

@Bill Promlem fixed

– Mohammad
Nov 11 '18 at 10:30

add a comment |

1

developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

– Álvaro González
Nov 11 '18 at 10:16

@Mohammad I want to control the minimum value. The answer you posted is about to generate random number too, but with no minimum limit. values there starting from 0

– Bill
Nov 11 '18 at 10:27

@Bill Promlem fixed

– Mohammad
Nov 11 '18 at 10:30

developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/…

– Álvaro González
Nov 11 '18 at 10:16

@Mohammad I want to control the minimum value. The answer you posted is about to generate random number too, but with no minimum limit. values there starting from 0

– Bill
Nov 11 '18 at 10:27

@Bill Promlem fixed

– Mohammad
Nov 11 '18 at 10:30

add a comment |

1 Answer
1

active

oldest

votes

As mentioned in mozilla developer you can generate random number between max and min as shown in bottom

Math.floor(Math.random() * (max - min + 1)) + min;

So your code should changed to

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text(Math.floor(Math.random() * (100-50+1)) + 50);
, 100);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

edited Nov 11 '18 at 10:29

answered Nov 11 '18 at 10:21

Mohammad

15.5k123461

please add the function to your post too, getRandomIntInclusive

– hanshenrik
Nov 11 '18 at 10:23

1

@hanshenrik For this question only need this part of function so i removed additional code

– Mohammad
Nov 11 '18 at 10:27

@Mohammad I can see that the most generated numbers are above 50, but I am still getting numbers under 50 too.

– Bill
Nov 11 '18 at 10:31

1

@Bill that means you did not do it as in this answer. Run the snippet -- there is never a value below 50.

– trincot
Nov 11 '18 at 10:32

1

@Bill Check jsfiddle if number is below 50 color changed to red

– Mohammad
Nov 11 '18 at 10:36

|
show 1 more comment

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

As mentioned in mozilla developer you can generate random number between max and min as shown in bottom

Math.floor(Math.random() * (max - min + 1)) + min;

So your code should changed to

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text(Math.floor(Math.random() * (100-50+1)) + 50);
, 100);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

edited Nov 11 '18 at 10:29

answered Nov 11 '18 at 10:21

Mohammad

15.5k123461

please add the function to your post too, getRandomIntInclusive

– hanshenrik
Nov 11 '18 at 10:23

1

@hanshenrik For this question only need this part of function so i removed additional code

– Mohammad
Nov 11 '18 at 10:27

@Mohammad I can see that the most generated numbers are above 50, but I am still getting numbers under 50 too.

– Bill
Nov 11 '18 at 10:31

1

@Bill that means you did not do it as in this answer. Run the snippet -- there is never a value below 50.

– trincot
Nov 11 '18 at 10:32

1

@Bill Check jsfiddle if number is below 50 color changed to red

– Mohammad
Nov 11 '18 at 10:36

|
show 1 more comment

As mentioned in mozilla developer you can generate random number between max and min as shown in bottom

Math.floor(Math.random() * (max - min + 1)) + min;

So your code should changed to

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text(Math.floor(Math.random() * (100-50+1)) + 50);
, 100);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

edited Nov 11 '18 at 10:29

answered Nov 11 '18 at 10:21

Mohammad

15.5k123461

please add the function to your post too, getRandomIntInclusive

– hanshenrik
Nov 11 '18 at 10:23

1

@hanshenrik For this question only need this part of function so i removed additional code

– Mohammad
Nov 11 '18 at 10:27

@Mohammad I can see that the most generated numbers are above 50, but I am still getting numbers under 50 too.

– Bill
Nov 11 '18 at 10:31

1

@Bill that means you did not do it as in this answer. Run the snippet -- there is never a value below 50.

– trincot
Nov 11 '18 at 10:32

1

@Bill Check jsfiddle if number is below 50 color changed to red

– Mohammad
Nov 11 '18 at 10:36

|
show 1 more comment

As mentioned in mozilla developer you can generate random number between max and min as shown in bottom

Math.floor(Math.random() * (max - min + 1)) + min;

So your code should changed to

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text(Math.floor(Math.random() * (100-50+1)) + 50);
, 100);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

edited Nov 11 '18 at 10:29

answered Nov 11 '18 at 10:21

Mohammad

15.5k123461

As mentioned in mozilla developer you can generate random number between max and min as shown in bottom

Math.floor(Math.random() * (max - min + 1)) + min;

So your code should changed to

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text(Math.floor(Math.random() * (100-50+1)) + 50);
, 100);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text(Math.floor(Math.random() * (100-50+1)) + 50);
, 100);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

var change_price = $('#myprice');
animationTimer = setInterval(function() 
 change_price.text(Math.floor(Math.random() * (100-50+1)) + 50);
, 100);

#myprice 
 padding: 20px;
 font-size:24px;
 color: green;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="myprice">50</div>

edited Nov 11 '18 at 10:29

answered Nov 11 '18 at 10:21

Mohammad

15.5k123461

edited Nov 11 '18 at 10:29

answered Nov 11 '18 at 10:21

Mohammad

15.5k123461

answered Nov 11 '18 at 10:21

Mohammad

15.5k123461

answered Nov 11 '18 at 10:21

Mohammad

15.5k123461

please add the function to your post too, getRandomIntInclusive

– hanshenrik
Nov 11 '18 at 10:23

1

@hanshenrik For this question only need this part of function so i removed additional code

– Mohammad
Nov 11 '18 at 10:27

@Mohammad I can see that the most generated numbers are above 50, but I am still getting numbers under 50 too.

– Bill
Nov 11 '18 at 10:31

1

@Bill that means you did not do it as in this answer. Run the snippet -- there is never a value below 50.

– trincot
Nov 11 '18 at 10:32

1

@Bill Check jsfiddle if number is below 50 color changed to red

– Mohammad
Nov 11 '18 at 10:36

|
show 1 more comment

please add the function to your post too, getRandomIntInclusive

– hanshenrik
Nov 11 '18 at 10:23

1

@hanshenrik For this question only need this part of function so i removed additional code

– Mohammad
Nov 11 '18 at 10:27

@Mohammad I can see that the most generated numbers are above 50, but I am still getting numbers under 50 too.

– Bill
Nov 11 '18 at 10:31

1

@Bill that means you did not do it as in this answer. Run the snippet -- there is never a value below 50.

– trincot
Nov 11 '18 at 10:32

1

@Bill Check jsfiddle if number is below 50 color changed to red

– Mohammad
Nov 11 '18 at 10:36

please add the function to your post too, getRandomIntInclusive

– hanshenrik
Nov 11 '18 at 10:23

@hanshenrik For this question only need this part of function so i removed additional code

– Mohammad
Nov 11 '18 at 10:27

@Mohammad I can see that the most generated numbers are above 50, but I am still getting numbers under 50 too.

– Bill
Nov 11 '18 at 10:31

@Bill that means you did not do it as in this answer. Run the snippet -- there is never a value below 50.

– trincot
Nov 11 '18 at 10:32

@Bill Check jsfiddle if number is below 50 color changed to red

– Mohammad
Nov 11 '18 at 10:36

|
show 1 more comment

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