Add property to an array of objects










31















I have an array of objects as shown below



Object Results:Array[2]
Results:Array[2]
[0-1]
0:Object
id=1
name: "Rick"
1:Object
id=2
name:'david'


I want to add one more property named Active to each element of this array of Objects.



The final outcome should be as follows.



Object Results:Array[2]
Results:Array[2]
[0-1]
0:Object
id=1
name: "Rick"
Active: "false"
1:Object
id=2
name:'david'
Active: "false"


Can someone please let me know how to achieve this.










share|improve this question



















  • 4





    Loop through the array. Add properties to each array element while looping. Which part do you not know how to do?

    – JJJ
    Aug 12 '16 at 16:58















31















I have an array of objects as shown below



Object Results:Array[2]
Results:Array[2]
[0-1]
0:Object
id=1
name: "Rick"
1:Object
id=2
name:'david'


I want to add one more property named Active to each element of this array of Objects.



The final outcome should be as follows.



Object Results:Array[2]
Results:Array[2]
[0-1]
0:Object
id=1
name: "Rick"
Active: "false"
1:Object
id=2
name:'david'
Active: "false"


Can someone please let me know how to achieve this.










share|improve this question



















  • 4





    Loop through the array. Add properties to each array element while looping. Which part do you not know how to do?

    – JJJ
    Aug 12 '16 at 16:58













31












31








31


6






I have an array of objects as shown below



Object Results:Array[2]
Results:Array[2]
[0-1]
0:Object
id=1
name: "Rick"
1:Object
id=2
name:'david'


I want to add one more property named Active to each element of this array of Objects.



The final outcome should be as follows.



Object Results:Array[2]
Results:Array[2]
[0-1]
0:Object
id=1
name: "Rick"
Active: "false"
1:Object
id=2
name:'david'
Active: "false"


Can someone please let me know how to achieve this.










share|improve this question
















I have an array of objects as shown below



Object Results:Array[2]
Results:Array[2]
[0-1]
0:Object
id=1
name: "Rick"
1:Object
id=2
name:'david'


I want to add one more property named Active to each element of this array of Objects.



The final outcome should be as follows.



Object Results:Array[2]
Results:Array[2]
[0-1]
0:Object
id=1
name: "Rick"
Active: "false"
1:Object
id=2
name:'david'
Active: "false"


Can someone please let me know how to achieve this.







javascript arrays object underscore.js






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 4 '16 at 6:25







user663031

















asked Aug 12 '16 at 16:53









PatrickPatrick

5602720




5602720







  • 4





    Loop through the array. Add properties to each array element while looping. Which part do you not know how to do?

    – JJJ
    Aug 12 '16 at 16:58












  • 4





    Loop through the array. Add properties to each array element while looping. Which part do you not know how to do?

    – JJJ
    Aug 12 '16 at 16:58







4




4





Loop through the array. Add properties to each array element while looping. Which part do you not know how to do?

– JJJ
Aug 12 '16 at 16:58





Loop through the array. Add properties to each array element while looping. Which part do you not know how to do?

– JJJ
Aug 12 '16 at 16:58












2 Answers
2






active

oldest

votes


















61














You can use the forEach method to execute a provided function once for each element in the array. In this provided function you can add the Active property to the element.



Results.forEach(function(element) element.Active = "false"; );





share|improve this answer

























  • @tholle- it gives me synatax error near "=>"

    – Patrick
    Aug 12 '16 at 17:08












  • @Patrick Excuse me. Updated the answer.

    – Tholle
    Aug 12 '16 at 17:10











  • update your browser or node version.

    – Azarus
    Oct 3 '17 at 21:45











  • Or if you're looking for an actual bool: false (with no quotes).

    – FernandoG
    Oct 24 '18 at 17:10


















43














or use map



Results.map((obj) => 
obj.Active = 'false';
return obj;
)


Read the spec






share|improve this answer




















  • 1





    only supported in ES6

    – Amaynut
    Mar 15 '18 at 19:36






  • 3





    ES5 to be precise ;) - but babel will happily decompile it

    – sidonaldson
    Mar 16 '18 at 11:19






  • 9





    map should return a new array not mutate the object, in this case forEach would be better, or use map and return a new object Results.map(obj=> ( ...obj, Active : 'false' ))

    – adrianolsk
    Jul 17 '18 at 15:11







  • 1





    Great solution @adrianolsk, you should submit that as a separate answer.

    – Michael Hays
    Aug 24 '18 at 16:21










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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









61














You can use the forEach method to execute a provided function once for each element in the array. In this provided function you can add the Active property to the element.



Results.forEach(function(element) element.Active = "false"; );





share|improve this answer

























  • @tholle- it gives me synatax error near "=>"

    – Patrick
    Aug 12 '16 at 17:08












  • @Patrick Excuse me. Updated the answer.

    – Tholle
    Aug 12 '16 at 17:10











  • update your browser or node version.

    – Azarus
    Oct 3 '17 at 21:45











  • Or if you're looking for an actual bool: false (with no quotes).

    – FernandoG
    Oct 24 '18 at 17:10















61














You can use the forEach method to execute a provided function once for each element in the array. In this provided function you can add the Active property to the element.



Results.forEach(function(element) element.Active = "false"; );





share|improve this answer

























  • @tholle- it gives me synatax error near "=>"

    – Patrick
    Aug 12 '16 at 17:08












  • @Patrick Excuse me. Updated the answer.

    – Tholle
    Aug 12 '16 at 17:10











  • update your browser or node version.

    – Azarus
    Oct 3 '17 at 21:45











  • Or if you're looking for an actual bool: false (with no quotes).

    – FernandoG
    Oct 24 '18 at 17:10













61












61








61







You can use the forEach method to execute a provided function once for each element in the array. In this provided function you can add the Active property to the element.



Results.forEach(function(element) element.Active = "false"; );





share|improve this answer















You can use the forEach method to execute a provided function once for each element in the array. In this provided function you can add the Active property to the element.



Results.forEach(function(element) element.Active = "false"; );






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 11 '18 at 12:00

























answered Aug 12 '16 at 17:05









TholleTholle

34.2k53760




34.2k53760












  • @tholle- it gives me synatax error near "=>"

    – Patrick
    Aug 12 '16 at 17:08












  • @Patrick Excuse me. Updated the answer.

    – Tholle
    Aug 12 '16 at 17:10











  • update your browser or node version.

    – Azarus
    Oct 3 '17 at 21:45











  • Or if you're looking for an actual bool: false (with no quotes).

    – FernandoG
    Oct 24 '18 at 17:10

















  • @tholle- it gives me synatax error near "=>"

    – Patrick
    Aug 12 '16 at 17:08












  • @Patrick Excuse me. Updated the answer.

    – Tholle
    Aug 12 '16 at 17:10











  • update your browser or node version.

    – Azarus
    Oct 3 '17 at 21:45











  • Or if you're looking for an actual bool: false (with no quotes).

    – FernandoG
    Oct 24 '18 at 17:10
















@tholle- it gives me synatax error near "=>"

– Patrick
Aug 12 '16 at 17:08






@tholle- it gives me synatax error near "=>"

– Patrick
Aug 12 '16 at 17:08














@Patrick Excuse me. Updated the answer.

– Tholle
Aug 12 '16 at 17:10





@Patrick Excuse me. Updated the answer.

– Tholle
Aug 12 '16 at 17:10













update your browser or node version.

– Azarus
Oct 3 '17 at 21:45





update your browser or node version.

– Azarus
Oct 3 '17 at 21:45













Or if you're looking for an actual bool: false (with no quotes).

– FernandoG
Oct 24 '18 at 17:10





Or if you're looking for an actual bool: false (with no quotes).

– FernandoG
Oct 24 '18 at 17:10













43














or use map



Results.map((obj) => 
obj.Active = 'false';
return obj;
)


Read the spec






share|improve this answer




















  • 1





    only supported in ES6

    – Amaynut
    Mar 15 '18 at 19:36






  • 3





    ES5 to be precise ;) - but babel will happily decompile it

    – sidonaldson
    Mar 16 '18 at 11:19






  • 9





    map should return a new array not mutate the object, in this case forEach would be better, or use map and return a new object Results.map(obj=> ( ...obj, Active : 'false' ))

    – adrianolsk
    Jul 17 '18 at 15:11







  • 1





    Great solution @adrianolsk, you should submit that as a separate answer.

    – Michael Hays
    Aug 24 '18 at 16:21















43














or use map



Results.map((obj) => 
obj.Active = 'false';
return obj;
)


Read the spec






share|improve this answer




















  • 1





    only supported in ES6

    – Amaynut
    Mar 15 '18 at 19:36






  • 3





    ES5 to be precise ;) - but babel will happily decompile it

    – sidonaldson
    Mar 16 '18 at 11:19






  • 9





    map should return a new array not mutate the object, in this case forEach would be better, or use map and return a new object Results.map(obj=> ( ...obj, Active : 'false' ))

    – adrianolsk
    Jul 17 '18 at 15:11







  • 1





    Great solution @adrianolsk, you should submit that as a separate answer.

    – Michael Hays
    Aug 24 '18 at 16:21













43












43








43







or use map



Results.map((obj) => 
obj.Active = 'false';
return obj;
)


Read the spec






share|improve this answer















or use map



Results.map((obj) => 
obj.Active = 'false';
return obj;
)


Read the spec







share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 29 '18 at 10:57

























answered Jun 7 '17 at 8:55









sidonaldsonsidonaldson

13.8k73649




13.8k73649







  • 1





    only supported in ES6

    – Amaynut
    Mar 15 '18 at 19:36






  • 3





    ES5 to be precise ;) - but babel will happily decompile it

    – sidonaldson
    Mar 16 '18 at 11:19






  • 9





    map should return a new array not mutate the object, in this case forEach would be better, or use map and return a new object Results.map(obj=> ( ...obj, Active : 'false' ))

    – adrianolsk
    Jul 17 '18 at 15:11







  • 1





    Great solution @adrianolsk, you should submit that as a separate answer.

    – Michael Hays
    Aug 24 '18 at 16:21












  • 1





    only supported in ES6

    – Amaynut
    Mar 15 '18 at 19:36






  • 3





    ES5 to be precise ;) - but babel will happily decompile it

    – sidonaldson
    Mar 16 '18 at 11:19






  • 9





    map should return a new array not mutate the object, in this case forEach would be better, or use map and return a new object Results.map(obj=> ( ...obj, Active : 'false' ))

    – adrianolsk
    Jul 17 '18 at 15:11







  • 1





    Great solution @adrianolsk, you should submit that as a separate answer.

    – Michael Hays
    Aug 24 '18 at 16:21







1




1





only supported in ES6

– Amaynut
Mar 15 '18 at 19:36





only supported in ES6

– Amaynut
Mar 15 '18 at 19:36




3




3





ES5 to be precise ;) - but babel will happily decompile it

– sidonaldson
Mar 16 '18 at 11:19





ES5 to be precise ;) - but babel will happily decompile it

– sidonaldson
Mar 16 '18 at 11:19




9




9





map should return a new array not mutate the object, in this case forEach would be better, or use map and return a new object Results.map(obj=> ( ...obj, Active : 'false' ))

– adrianolsk
Jul 17 '18 at 15:11






map should return a new array not mutate the object, in this case forEach would be better, or use map and return a new object Results.map(obj=> ( ...obj, Active : 'false' ))

– adrianolsk
Jul 17 '18 at 15:11





1




1





Great solution @adrianolsk, you should submit that as a separate answer.

– Michael Hays
Aug 24 '18 at 16:21





Great solution @adrianolsk, you should submit that as a separate answer.

– Michael Hays
Aug 24 '18 at 16:21

















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