How to compare two instances of an object Python?

How to compare two instances of an object Python?



Attempting to compare two objects data members; however, the error message has no specific details, which leaves me with little information on how to go about correcting it


class Person:
def __init__(self, name, age, id):
self.name = name
self.age = age
self.id = id

def same_person(Person lhs, Person rhs):
return lhs.id == rhs.id

person1 = Person("David Joyner", 30, 901234567)
person2 = Person("D. Joyner", 29, 901234567)
person3 = Person("David Joyner", 30, 903987654)
# print calls provided as part of an exercise: not my implementation
print(same_person(person1, person2))
print(same_person(person1, person3))





Among other things, you are probably mixing tabs and spaces in your indentation somewhere.
– DYZ
Sep 1 at 19:40





4 Answers
4



The other answers are correct and provide the best way to do it, but I realized that you wrote:



print calls provided as part of an exercise: not my implementation


print(same_person(person1, person2))
print(same_person(person1, person3))



The exercise probably wants you to define a function outside the class. You can do that by removing that function from the class and writing it un-indented outside the class (without providing class type too). For example:


class Person:
def __init__(self, name, age, id):
self.name = name
self.age = age
self.id = id

def same_person(lhs, rhs):
return lhs.id == rhs.id

person1 = Person("David Joyner", 30, 901234567)
person2 = Person("D. Joyner", 29, 901234567)
person3 = Person("David Joyner", 30, 903987654)

print(same_person(person1, person2))
print(same_person(person1, person3))





Much appreciated
– aguilar
Sep 1 at 20:06





Glad to help :-)
– Moe A
Sep 1 at 20:06





@aguilar keep in mind that the best way to compare two objects would be overriding __eq__() method of the class, have a look at this
– Moe A
Sep 1 at 20:10



__eq__()



same_person is a method of the class Person and should take just an argument as input. It should be defined as:


Person


def same_person(self, other):
return self.id == other.id



and called as


person1.same_person(person2)



or you could override the __eq__ method (i.e., ==).


__eq__


==


def __eq__(self, other):
return self.id == other.id



in order to be able to do it as person1 == person2


person1 == person2





return self is other is a bit more elegant.
– DYZ
Sep 1 at 19:45


return self is other





@DYZ: but then Person(1, 2, 3) != Person(1, 2, 3), since they're not the same object.
– Blender
Sep 1 at 19:54


Person(1, 2, 3) != Person(1, 2, 3)





If you suggest to add self.id is other.id I don't really understand why, we are checking equality not object identity.
– abc
Sep 1 at 19:57


self.id is other.id





I suggest to replace self.id == other.id with self is other (both expressions are fully equivalent).
– DYZ
Sep 1 at 20:13



self.id == other.id


self is other


class Person:
def __init__(self, name, age, id):
self.name = name
self.age = age
self.id = id

def same_person(self, lhs, rhs):
return lhs.id == rhs.id



you dont have to define lhs and rhs type in python unless you are using typings.



Quite a few mistakes:


Person


person1


person2


person3


same_person



This is what I would do:


class Person:
def __init__(self, name, age, id):
self.name = name
self.age = age
self.id = id

def same_person(self, other):
return self.id == other.id

person1 = Person("Bob", 25, 1)
person2 = Person("Mike", 33, 1)
person3 = Person("Maria", 28, 2)

print(person1.same_person(person2))
print(person1.same_person(person3))



Output:


True
False



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