What is $/makefile.inc.system in makefile?

In the makefile, the following include statement.

include $/makefile.inc.system

What does $ mean here?

When I changed ./ to $/ in the other command lines, it is not working.

But in the include $/makefile.inc.system, it is working as ./

I couldn't find any explanation about it.

$

./

$/

1 Answer
1

$/ in this case is just expanding a makefile variable like you would any other variable, e.g. $(foo). Somewhere in the main makefile you should see the variable / defined with something like / = somedir.

$/

$(foo)

/

/ = somedir

Thanks for the answer.Is there any difference with ./makefile.inc.system? What is the difference between $/makefile.inc and ./makefile.inc? Why use $/makefile.inc form?
– J. Shin
Aug 23 at 18:35

You'll need to look at the makefile to determine why it uses a variable instead of hard-coding the path, my guess is it's to allow makefile.inc to be dynamically included from somewhere else.
– user657267
Aug 24 at 4:46

makefile.inc

I couldn't find "/=" and include $/makefile.ins is working, but cp -p ./test.c .. is changed to cp -p $/test.c .. , then fail. It looks still confusing.
– J. Shin
Aug 30 at 19:39

include $/makefile.ins

cp -p ./test.c ..

cp -p $/test.c ..

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