How to select the first child of each element in list in Beautiful Soup

I want to get the text from the first inner div in each outer div

<body> <div class="outer"> <div class="inner">text1</div> <div class="inner">text2</div> <div class="inner">text3</div> </div> <div class="outer"> <div class="inner">text4</div> </div> <div class="outer"> <div class="inner">text5</div> <div class="inner">text6</div> </div> </body>

This is means retrieving text1, text4, text5

I've experimented with the code shown below but can't get it to work

outers = soup.select('body > .outer') for outer in outers: inners = outer.select_one('.inner') for inner in inners: print(inner.text)

Thanks in advanced

2 Answers
2

May be this works,

soup = BeautifulSoup(text, 'html.parser') for outer in soup.find_all('div', class_='outer'): inners = outer.find('div', class_='inner') for inner in inners: print(inner) # Output as: # text1 # text4 # text5

OR
You can use this way,

soup = BeautifulSoup(text, 'html.parser') for outer in soup.find_all('div', class_='outer'): inners = outer.find('div', class_='inner') print(inners.get_text())

This gives TypeError: 'NoneType' object is not iterable after the for inner in inners: line
– tokism
Aug 27 at 14:00

TypeError: 'NoneType' object is not iterable

for inner in inners:

@tokism Hope this works in you case
– utks009
Aug 27 at 14:06

The edited solution works great! I was trying to iterate over the non-iterable inners as it is only a single element. Thanks
– tokism
Aug 27 at 14:26

inners

Welcome to StackOverflow!

This code worked for me:

[div.find("div", "class": "inner") for div in soup.findAll("div", "class": "outer")]

That is, a one-line version of the same thing.

I can't figure out how to print each section of text. Any ideas?
– tokism
Aug 27 at 14:03

Do you mean you want to print the text in the div? If not; have you tried putting my code in a print() command? If yes, maybe try div.findAll("div", "class": "inner"))[0].text instead of div.findAll("div", "class": "inner"))[0].
– Josh Friedlander
Aug 27 at 14:05

div.findAll("div", "class": "inner"))[0].text

div.findAll("div", "class": "inner"))[0]

@JoshFriedlander, find_all(...)[0] is equivalent to find(...).
– Keyur Potdar
Aug 27 at 14:08

find_all(...)[0]

find(...)

Thanks Keyur! I'll update my answer.
– Josh Friedlander
Aug 27 at 14:09

Also, you don't have to convert it to a list. find_all returns a list.
– Keyur Potdar
Aug 27 at 14:09

find_all

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