Using a function in a select statement with multiple tables while creating a view



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1















I'm using oracle SQL developer, the create view tool. I have a function called LastNameFirst that I want to use to reorganize the customers first name / last name to appear with the last name being first.



SELECT SALE.SaleID,SALE.SaleDate, CUSTOMER.LastNameFirst(LastName,FirstName), 
SALE_ITEM.SaleItemID,SALE_ITEM.ItemID,ITEM.ItemDescription, ITEM.ItemPrice

FROM SALE_ITEM
INNER JOIN SALE on SALE.SaleID = SALE_ITEM.SaleID
INNER JOIN ITEM on ITEM.ItemID = SALE_ITEM.ItemID
INNER JOIN CUSTOMER on CUSTOMER.CustomerID = SALE.CUSTOMERID;


The error i'm getting is :
ORA-00904: "CUSTOMER"."LASTNAMEFIRST": invalid identifier



How do I call the function in that part of my select statement? I can't seem to find any examples of functions being called in select statements where joins are involved, other than using "cross apply" or "outer apply" in some way. I understand (I think) that the syntax is



SELECT 'tableName'.'columnName'


and I know my function isn't a column and that's why I'm getting that error. But I'm really not sure of how to set up the code. I tried changing it to something like:



SELECT SALE.SaleID,SALE.SaleDate,CUSTOMER.LastName, CUSTOMER.FirstName AS LastNameFirst(LastName,FirstName),SALE_ITEM.SaleItemID,SALE_ITEM.ItemID,ITEM.ItemDescription, ITEM.ItemPrice


But nothing like that worked for me either. I'd appreciate any help anyone could give me.










share|improve this question




























    1















    I'm using oracle SQL developer, the create view tool. I have a function called LastNameFirst that I want to use to reorganize the customers first name / last name to appear with the last name being first.



    SELECT SALE.SaleID,SALE.SaleDate, CUSTOMER.LastNameFirst(LastName,FirstName), 
    SALE_ITEM.SaleItemID,SALE_ITEM.ItemID,ITEM.ItemDescription, ITEM.ItemPrice

    FROM SALE_ITEM
    INNER JOIN SALE on SALE.SaleID = SALE_ITEM.SaleID
    INNER JOIN ITEM on ITEM.ItemID = SALE_ITEM.ItemID
    INNER JOIN CUSTOMER on CUSTOMER.CustomerID = SALE.CUSTOMERID;


    The error i'm getting is :
    ORA-00904: "CUSTOMER"."LASTNAMEFIRST": invalid identifier



    How do I call the function in that part of my select statement? I can't seem to find any examples of functions being called in select statements where joins are involved, other than using "cross apply" or "outer apply" in some way. I understand (I think) that the syntax is



    SELECT 'tableName'.'columnName'


    and I know my function isn't a column and that's why I'm getting that error. But I'm really not sure of how to set up the code. I tried changing it to something like:



    SELECT SALE.SaleID,SALE.SaleDate,CUSTOMER.LastName, CUSTOMER.FirstName AS LastNameFirst(LastName,FirstName),SALE_ITEM.SaleItemID,SALE_ITEM.ItemID,ITEM.ItemDescription, ITEM.ItemPrice


    But nothing like that worked for me either. I'd appreciate any help anyone could give me.










    share|improve this question
























      1












      1








      1








      I'm using oracle SQL developer, the create view tool. I have a function called LastNameFirst that I want to use to reorganize the customers first name / last name to appear with the last name being first.



      SELECT SALE.SaleID,SALE.SaleDate, CUSTOMER.LastNameFirst(LastName,FirstName), 
      SALE_ITEM.SaleItemID,SALE_ITEM.ItemID,ITEM.ItemDescription, ITEM.ItemPrice

      FROM SALE_ITEM
      INNER JOIN SALE on SALE.SaleID = SALE_ITEM.SaleID
      INNER JOIN ITEM on ITEM.ItemID = SALE_ITEM.ItemID
      INNER JOIN CUSTOMER on CUSTOMER.CustomerID = SALE.CUSTOMERID;


      The error i'm getting is :
      ORA-00904: "CUSTOMER"."LASTNAMEFIRST": invalid identifier



      How do I call the function in that part of my select statement? I can't seem to find any examples of functions being called in select statements where joins are involved, other than using "cross apply" or "outer apply" in some way. I understand (I think) that the syntax is



      SELECT 'tableName'.'columnName'


      and I know my function isn't a column and that's why I'm getting that error. But I'm really not sure of how to set up the code. I tried changing it to something like:



      SELECT SALE.SaleID,SALE.SaleDate,CUSTOMER.LastName, CUSTOMER.FirstName AS LastNameFirst(LastName,FirstName),SALE_ITEM.SaleItemID,SALE_ITEM.ItemID,ITEM.ItemDescription, ITEM.ItemPrice


      But nothing like that worked for me either. I'd appreciate any help anyone could give me.










      share|improve this question














      I'm using oracle SQL developer, the create view tool. I have a function called LastNameFirst that I want to use to reorganize the customers first name / last name to appear with the last name being first.



      SELECT SALE.SaleID,SALE.SaleDate, CUSTOMER.LastNameFirst(LastName,FirstName), 
      SALE_ITEM.SaleItemID,SALE_ITEM.ItemID,ITEM.ItemDescription, ITEM.ItemPrice

      FROM SALE_ITEM
      INNER JOIN SALE on SALE.SaleID = SALE_ITEM.SaleID
      INNER JOIN ITEM on ITEM.ItemID = SALE_ITEM.ItemID
      INNER JOIN CUSTOMER on CUSTOMER.CustomerID = SALE.CUSTOMERID;


      The error i'm getting is :
      ORA-00904: "CUSTOMER"."LASTNAMEFIRST": invalid identifier



      How do I call the function in that part of my select statement? I can't seem to find any examples of functions being called in select statements where joins are involved, other than using "cross apply" or "outer apply" in some way. I understand (I think) that the syntax is



      SELECT 'tableName'.'columnName'


      and I know my function isn't a column and that's why I'm getting that error. But I'm really not sure of how to set up the code. I tried changing it to something like:



      SELECT SALE.SaleID,SALE.SaleDate,CUSTOMER.LastName, CUSTOMER.FirstName AS LastNameFirst(LastName,FirstName),SALE_ITEM.SaleItemID,SALE_ITEM.ItemID,ITEM.ItemDescription, ITEM.ItemPrice


      But nothing like that worked for me either. I'd appreciate any help anyone could give me.







      sql oracle






      share|improve this question













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      asked Nov 14 '18 at 2:10









      J.Griff2J.Griff2

      61




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          1 Answer
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          oldest

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          1














          Functions are not properties of tables to be allowed to period qualify them. However, functions and tables among other objects share the same namespace. As mentioned in docs:




          The following schema objects share one namespace:



          • Tables

          • Views

          • Sequences

          • Private synonyms

          • Stand-alone procedures

          • Stand-alone stored functions

          • Packages

          • Materialized views

          • User-defined types



          Therefore, simply remove the CUSTOMER. qualifier as schema is implicitly defined:



          SELECT SALE.SaleID, 
          SALE.SaleDate,
          LastNameFirst(LastName, FirstName) AS Customer_Name, ...


          Alternatively, explicitly qualify the schema name on all table and function objects in the manner: "schema"."table"."column" or "schema"."function":



          SELECT myschema.SALE.SaleID, 
          myschema.SALE.SaleDate,
          myschema.LastNameFirst(myschema.CUSTOMER.LastName,
          myschema.CUSTOMER.FirstName) AS Customer_Name, ...





          share|improve this answer























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            1 Answer
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            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            Functions are not properties of tables to be allowed to period qualify them. However, functions and tables among other objects share the same namespace. As mentioned in docs:




            The following schema objects share one namespace:



            • Tables

            • Views

            • Sequences

            • Private synonyms

            • Stand-alone procedures

            • Stand-alone stored functions

            • Packages

            • Materialized views

            • User-defined types



            Therefore, simply remove the CUSTOMER. qualifier as schema is implicitly defined:



            SELECT SALE.SaleID, 
            SALE.SaleDate,
            LastNameFirst(LastName, FirstName) AS Customer_Name, ...


            Alternatively, explicitly qualify the schema name on all table and function objects in the manner: "schema"."table"."column" or "schema"."function":



            SELECT myschema.SALE.SaleID, 
            myschema.SALE.SaleDate,
            myschema.LastNameFirst(myschema.CUSTOMER.LastName,
            myschema.CUSTOMER.FirstName) AS Customer_Name, ...





            share|improve this answer



























              1














              Functions are not properties of tables to be allowed to period qualify them. However, functions and tables among other objects share the same namespace. As mentioned in docs:




              The following schema objects share one namespace:



              • Tables

              • Views

              • Sequences

              • Private synonyms

              • Stand-alone procedures

              • Stand-alone stored functions

              • Packages

              • Materialized views

              • User-defined types



              Therefore, simply remove the CUSTOMER. qualifier as schema is implicitly defined:



              SELECT SALE.SaleID, 
              SALE.SaleDate,
              LastNameFirst(LastName, FirstName) AS Customer_Name, ...


              Alternatively, explicitly qualify the schema name on all table and function objects in the manner: "schema"."table"."column" or "schema"."function":



              SELECT myschema.SALE.SaleID, 
              myschema.SALE.SaleDate,
              myschema.LastNameFirst(myschema.CUSTOMER.LastName,
              myschema.CUSTOMER.FirstName) AS Customer_Name, ...





              share|improve this answer

























                1












                1








                1







                Functions are not properties of tables to be allowed to period qualify them. However, functions and tables among other objects share the same namespace. As mentioned in docs:




                The following schema objects share one namespace:



                • Tables

                • Views

                • Sequences

                • Private synonyms

                • Stand-alone procedures

                • Stand-alone stored functions

                • Packages

                • Materialized views

                • User-defined types



                Therefore, simply remove the CUSTOMER. qualifier as schema is implicitly defined:



                SELECT SALE.SaleID, 
                SALE.SaleDate,
                LastNameFirst(LastName, FirstName) AS Customer_Name, ...


                Alternatively, explicitly qualify the schema name on all table and function objects in the manner: "schema"."table"."column" or "schema"."function":



                SELECT myschema.SALE.SaleID, 
                myschema.SALE.SaleDate,
                myschema.LastNameFirst(myschema.CUSTOMER.LastName,
                myschema.CUSTOMER.FirstName) AS Customer_Name, ...





                share|improve this answer













                Functions are not properties of tables to be allowed to period qualify them. However, functions and tables among other objects share the same namespace. As mentioned in docs:




                The following schema objects share one namespace:



                • Tables

                • Views

                • Sequences

                • Private synonyms

                • Stand-alone procedures

                • Stand-alone stored functions

                • Packages

                • Materialized views

                • User-defined types



                Therefore, simply remove the CUSTOMER. qualifier as schema is implicitly defined:



                SELECT SALE.SaleID, 
                SALE.SaleDate,
                LastNameFirst(LastName, FirstName) AS Customer_Name, ...


                Alternatively, explicitly qualify the schema name on all table and function objects in the manner: "schema"."table"."column" or "schema"."function":



                SELECT myschema.SALE.SaleID, 
                myschema.SALE.SaleDate,
                myschema.LastNameFirst(myschema.CUSTOMER.LastName,
                myschema.CUSTOMER.FirstName) AS Customer_Name, ...






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 14 '18 at 3:26









                ParfaitParfait

                54.3k104872




                54.3k104872





























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