List with output from for loop returns empty

List with output from for loop returns empty



I have written a code to obtain crosstab results of a rasterstack for different regions (delimited by a shapefile) covering the raster. However, I am getting an empty list.



This is the function:


transitions <- function(bound, themat) # bound = shapefile # themat = rasterstack
result = vector("list", nrow(bound)) # empty result list
names(result) = bound@data$GEOCODIGO

for (i in 1:nrow(bound)) # this is the number of polygons to iterate through
single <- bound[i,] # selects a single polygon
clip <- mask(crop(themat, single), single) # crops the raster to the polygon boundary

result[i] <- crosstab(clip, digits = 0, long = FALSE, useNA = FALSE)
return(result)




I have tested the steps for the first object in the shapefile/bound outside of the for loop; and it worked well. But I still cannot figure out why I am getting an empty list. Any ideas?






Put return(result) outside the for loop. And I would use result[[i]] <- crosstab(...) with double [[ .

– Rui Barradas
Sep 17 '18 at 15:53



return(result)


for


result[[i]] <- crosstab(...)


[[




1 Answer
1



Example data:


p <- shapefile(system.file("external/lux.shp", package="raster"))
b <- brick(raster(p), nl=2)
values(b) = sample(2, 200, replace=TRUE)



fixed function:


transitions <- function(poly, rast)
result = vector("list", nrow(poly))
for (i in 1:nrow(poly))
clip <- mask(crop(rast, poly[i,]), poly[i,])
result[[i]] <- crosstab(clip, digits = 0, long = FALSE, useNA = FALSE)

return(result)


transitions(p, b)



An alternative would be to use extract


e <- extract(b, p)



To tabulate as in crosstab:


ee <- lapply(e, function(x) aggregate(data.frame(count=rep(1, nrow(x))), data.frame(x), FUN=sum))



To understand that last line, you need to unpack it.


class(e)
#[1] "list"
length(e)
#[1] 12
e[[1]]
# layer.1 layer.2
#[1,] 1 1
#[2,] 1 2
#[3,] 2 2
#[4,] 2 1
#[5,] 2 1
#[6,] 1 2
#[7,] 2 2



e is a list with the same length as the number of polygons (see length(p))


e


length(p)



Let's that the first element and aggregate it to get a table with cases and counts.


x <- e[[1]]

aggregate(data.frame(count=rep(1, nrow(x))), data.frame(x), FUN=sum)
# layer.1 layer.2 count
#1 1 1 1
#2 2 1 2
#3 1 2 2
#4 2 2 2



A similar approach via table (the difference is that you could get Freq values that are zero


as.data.frame(table(x[,1], x[,2]))
# Var1 Var2 Freq
#1 1 1 1
#2 2 1 2
#3 1 2 2
#4 2 2 2



Now wrap the function you like into a lapply


lapply


z <- lapply(e, function(x) aggregate(data.frame(count=rep(1, nrow(x))), data.frame(x), FUN=sum))



And to take it further, bind the data.frames and add an identifier to link the data back to the polygons


y <- do.call(rbind, z,)
y$id <- rep(1:length(z), sapply(z, nrow))

head(y)
# Var1 Var2 Freq id
#1 1 1 1 1
#2 2 1 2 1
#3 1 2 2 1
#4 2 2 2 1
#5 1 1 1 2
#6 2 1 2 2






Thanks a lot for the answer. It worked pretty well now. Still, I did not follow what the last line lapply(e, function(x) aggregate(data.frame(count=rep(1, nrow(x))), data.frame(x), FUN=sum)) is appropriate for. Could you give me a hint on this?

– 1Garcia
Sep 19 '18 at 20:25



lapply(e, function(x) aggregate(data.frame(count=rep(1, nrow(x))), data.frame(x), FUN=sum))






I have added some hints

– Robert Hijmans
Sep 20 '18 at 2:03






Awesome!! Thanks a lot!!

– 1Garcia
Sep 21 '18 at 13:17



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