System.arraycopy getting java.lang.ArrayIndexOutOfBoundsException

System.arraycopy getting ava.lang.ArrayIndexOutOfBoundsException.. I am trying to copy data from one array to the next. but I am getting a exception

private String array = "NO DATA YET" ;


private void setListData()

String array2 = "Iphone", "Tutorials", "Gallery", "Android", "item 1", "item 2", "item3", "item 4" ;
System.arraycopy(array2, 0, array, 0, array2.length);



4 Answers
4

You're trying to copy 8 items into an array of length 1. You can't do that.

From the documentation:

Otherwise, if any of the following is true, an IndexOutOfBoundsException is thrown and the destination is not modified:

In this case, destPos + length is 8, and dest.length is 1, hence the exception is being thrown.

destPos + length

dest.length

Note that arrays in Java have a fixed length. If you want an expandable container, look at ArrayList.

ArrayList

IndexOutOfBoundsException

ArrayIndexOutOfBoundsException

ArrayIndexOutOfBoundsException

IndexOutOfBoundsException

Because the length of array is 1.

array

The declaration array = "NO DATA YET" ; creates an array of length 1 with one item in it.

array = "NO DATA YET" ;

Instead declare destination array as:

private String array = new String[8];


array only has a length of 1 and you're trying to copy 8 things into it from array2. Try using an ArrayList or something that will grow as you need it to grow.

SOLUTION TO ALL TYPES OF ARRAYINDEXOUTOFBOUNDS EXCEPTION:

Understand this with the help of following example facing ArrayIndexOutOfBoundsException:

public static void main(String args)
String dest = "Iphone", "Tutorials", "Gallery", "Android", "item 1", "item 2", "item3", "item 4" ;
String src=new String[8];
System.arraycopy(src, 0, dest, 1, src.length);
System.out.println(dest[4]);



Solution to this above case can be any of the following:
1. Either increase the size of destination array so it could find a place.
2. Since we are starting from index 1 so you may copy only 7 elements from the source array.
3. Or you can start copying from index 0 in the destination array so it can accommodate all the array elements of source array.

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