XSLT 1.0 delete nodes
How can i delete some specific nodes?
In my example, i have lot of nodes at segment REF, but i just want to use REF with Qualifier GS, all others should be deleted.
<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>CR</QUALIFIER>
<REFERENCE>1234</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>LI</QUALIFIER>
<REFERENCE>1</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>
Do you need more info about my XML?
Edit: Output should be:
<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>
My current attempt is like this:
<!--delete REF node-->
<xsl:template match="REF">
<xsl:for-each select ="./REF">
<xsl:if test="./QUALIFIER='LI'">
</xsl:if>
</xsl:for-each>
<!--copy all other nodes-->
<xsl:apply-templates select="@* | node()"/>
</xsl:template>
My only solution at the moment is, to delete all others separately with:
<xsl:template match="REF[QUALIFIER='CR']"/>
<xsl:template match="REF[QUALIFIER='LI']"/>
xml xslt xslt-1.0
add a comment |
How can i delete some specific nodes?
In my example, i have lot of nodes at segment REF, but i just want to use REF with Qualifier GS, all others should be deleted.
<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>CR</QUALIFIER>
<REFERENCE>1234</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>LI</QUALIFIER>
<REFERENCE>1</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>
Do you need more info about my XML?
Edit: Output should be:
<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>
My current attempt is like this:
<!--delete REF node-->
<xsl:template match="REF">
<xsl:for-each select ="./REF">
<xsl:if test="./QUALIFIER='LI'">
</xsl:if>
</xsl:for-each>
<!--copy all other nodes-->
<xsl:apply-templates select="@* | node()"/>
</xsl:template>
My only solution at the moment is, to delete all others separately with:
<xsl:template match="REF[QUALIFIER='CR']"/>
<xsl:template match="REF[QUALIFIER='LI']"/>
xml xslt xslt-1.0
Can you show us your XSLT? What you have tried so far?
– ophychius
Nov 12 '18 at 11:20
<!--delete REF node--> <xsl:template match="REF"> <xsl:for-each select ="./REF"> <xsl:if test="./QUALIFIER='LI'"> </xsl:if> </xsl:for-each> <!--copy all other nodes--> <xsl:apply-templates select="@* | node()"/> </xsl:template>
– juls_pro_37
Nov 12 '18 at 11:59
<xsl:template match="REF[@QUALIFER='LI']"/>
– juls_pro_37
Nov 12 '18 at 12:00
thx!! i used: <xsl:template match="REF[QUALIFIER !='GS']"/>
– juls_pro_37
Nov 12 '18 at 12:46
add a comment |
How can i delete some specific nodes?
In my example, i have lot of nodes at segment REF, but i just want to use REF with Qualifier GS, all others should be deleted.
<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>CR</QUALIFIER>
<REFERENCE>1234</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>LI</QUALIFIER>
<REFERENCE>1</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>
Do you need more info about my XML?
Edit: Output should be:
<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>
My current attempt is like this:
<!--delete REF node-->
<xsl:template match="REF">
<xsl:for-each select ="./REF">
<xsl:if test="./QUALIFIER='LI'">
</xsl:if>
</xsl:for-each>
<!--copy all other nodes-->
<xsl:apply-templates select="@* | node()"/>
</xsl:template>
My only solution at the moment is, to delete all others separately with:
<xsl:template match="REF[QUALIFIER='CR']"/>
<xsl:template match="REF[QUALIFIER='LI']"/>
xml xslt xslt-1.0
How can i delete some specific nodes?
In my example, i have lot of nodes at segment REF, but i just want to use REF with Qualifier GS, all others should be deleted.
<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>CR</QUALIFIER>
<REFERENCE>1234</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>LI</QUALIFIER>
<REFERENCE>1</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>
Do you need more info about my XML?
Edit: Output should be:
<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>
My current attempt is like this:
<!--delete REF node-->
<xsl:template match="REF">
<xsl:for-each select ="./REF">
<xsl:if test="./QUALIFIER='LI'">
</xsl:if>
</xsl:for-each>
<!--copy all other nodes-->
<xsl:apply-templates select="@* | node()"/>
</xsl:template>
My only solution at the moment is, to delete all others separately with:
<xsl:template match="REF[QUALIFIER='CR']"/>
<xsl:template match="REF[QUALIFIER='LI']"/>
xml xslt xslt-1.0
xml xslt xslt-1.0
edited Nov 12 '18 at 12:13
Tomalak
259k52429547
259k52429547
asked Nov 12 '18 at 10:49
juls_pro_37juls_pro_37
326
326
Can you show us your XSLT? What you have tried so far?
– ophychius
Nov 12 '18 at 11:20
<!--delete REF node--> <xsl:template match="REF"> <xsl:for-each select ="./REF"> <xsl:if test="./QUALIFIER='LI'"> </xsl:if> </xsl:for-each> <!--copy all other nodes--> <xsl:apply-templates select="@* | node()"/> </xsl:template>
– juls_pro_37
Nov 12 '18 at 11:59
<xsl:template match="REF[@QUALIFER='LI']"/>
– juls_pro_37
Nov 12 '18 at 12:00
thx!! i used: <xsl:template match="REF[QUALIFIER !='GS']"/>
– juls_pro_37
Nov 12 '18 at 12:46
add a comment |
Can you show us your XSLT? What you have tried so far?
– ophychius
Nov 12 '18 at 11:20
<!--delete REF node--> <xsl:template match="REF"> <xsl:for-each select ="./REF"> <xsl:if test="./QUALIFIER='LI'"> </xsl:if> </xsl:for-each> <!--copy all other nodes--> <xsl:apply-templates select="@* | node()"/> </xsl:template>
– juls_pro_37
Nov 12 '18 at 11:59
<xsl:template match="REF[@QUALIFER='LI']"/>
– juls_pro_37
Nov 12 '18 at 12:00
thx!! i used: <xsl:template match="REF[QUALIFIER !='GS']"/>
– juls_pro_37
Nov 12 '18 at 12:46
Can you show us your XSLT? What you have tried so far?
– ophychius
Nov 12 '18 at 11:20
Can you show us your XSLT? What you have tried so far?
– ophychius
Nov 12 '18 at 11:20
<!--delete REF node--> <xsl:template match="REF"> <xsl:for-each select ="./REF"> <xsl:if test="./QUALIFIER='LI'"> </xsl:if> </xsl:for-each> <!--copy all other nodes--> <xsl:apply-templates select="@* | node()"/> </xsl:template>
– juls_pro_37
Nov 12 '18 at 11:59
<!--delete REF node--> <xsl:template match="REF"> <xsl:for-each select ="./REF"> <xsl:if test="./QUALIFIER='LI'"> </xsl:if> </xsl:for-each> <!--copy all other nodes--> <xsl:apply-templates select="@* | node()"/> </xsl:template>
– juls_pro_37
Nov 12 '18 at 11:59
<xsl:template match="REF[@QUALIFER='LI']"/>
– juls_pro_37
Nov 12 '18 at 12:00
<xsl:template match="REF[@QUALIFER='LI']"/>
– juls_pro_37
Nov 12 '18 at 12:00
thx!! i used: <xsl:template match="REF[QUALIFIER !='GS']"/>
– juls_pro_37
Nov 12 '18 at 12:46
thx!! i used: <xsl:template match="REF[QUALIFIER !='GS']"/>
– juls_pro_37
Nov 12 '18 at 12:46
add a comment |
1 Answer
1
active
oldest
votes
You want to delete all <REF>
nodes where the qualifier is not "GS".
<xsl:template match="REF[@QUALIFER != 'GS']" />
That's all that is necessary, in addition to the identity template (which you already seem to have).
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You want to delete all <REF>
nodes where the qualifier is not "GS".
<xsl:template match="REF[@QUALIFER != 'GS']" />
That's all that is necessary, in addition to the identity template (which you already seem to have).
add a comment |
You want to delete all <REF>
nodes where the qualifier is not "GS".
<xsl:template match="REF[@QUALIFER != 'GS']" />
That's all that is necessary, in addition to the identity template (which you already seem to have).
add a comment |
You want to delete all <REF>
nodes where the qualifier is not "GS".
<xsl:template match="REF[@QUALIFER != 'GS']" />
That's all that is necessary, in addition to the identity template (which you already seem to have).
You want to delete all <REF>
nodes where the qualifier is not "GS".
<xsl:template match="REF[@QUALIFER != 'GS']" />
That's all that is necessary, in addition to the identity template (which you already seem to have).
answered Nov 12 '18 at 12:11
TomalakTomalak
259k52429547
259k52429547
add a comment |
add a comment |
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Can you show us your XSLT? What you have tried so far?
– ophychius
Nov 12 '18 at 11:20
<!--delete REF node--> <xsl:template match="REF"> <xsl:for-each select ="./REF"> <xsl:if test="./QUALIFIER='LI'"> </xsl:if> </xsl:for-each> <!--copy all other nodes--> <xsl:apply-templates select="@* | node()"/> </xsl:template>
– juls_pro_37
Nov 12 '18 at 11:59
<xsl:template match="REF[@QUALIFER='LI']"/>
– juls_pro_37
Nov 12 '18 at 12:00
thx!! i used: <xsl:template match="REF[QUALIFIER !='GS']"/>
– juls_pro_37
Nov 12 '18 at 12:46