XSLT 1.0 delete nodes










1















How can i delete some specific nodes?



In my example, i have lot of nodes at segment REF, but i just want to use REF with Qualifier GS, all others should be deleted.



<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>CR</QUALIFIER>
<REFERENCE>1234</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>LI</QUALIFIER>
<REFERENCE>1</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>


Do you need more info about my XML?



Edit: Output should be:



<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>


My current attempt is like this:



<!--delete REF node-->
<xsl:template match="REF">
<xsl:for-each select ="./REF">
<xsl:if test="./QUALIFIER='LI'">
</xsl:if>
</xsl:for-each>
<!--copy all other nodes-->
<xsl:apply-templates select="@* | node()"/>
</xsl:template>


My only solution at the moment is, to delete all others separately with:



<xsl:template match="REF[QUALIFIER='CR']"/>

<xsl:template match="REF[QUALIFIER='LI']"/>









share|improve this question
























  • Can you show us your XSLT? What you have tried so far?

    – ophychius
    Nov 12 '18 at 11:20











  • <!--delete REF node--> <xsl:template match="REF"> <xsl:for-each select ="./REF"> <xsl:if test="./QUALIFIER='LI'"> </xsl:if> </xsl:for-each> <!--copy all other nodes--> <xsl:apply-templates select="@* | node()"/> </xsl:template>

    – juls_pro_37
    Nov 12 '18 at 11:59











  • <xsl:template match="REF[@QUALIFER='LI']"/>

    – juls_pro_37
    Nov 12 '18 at 12:00











  • thx!! i used: <xsl:template match="REF[QUALIFIER !='GS']"/>

    – juls_pro_37
    Nov 12 '18 at 12:46















1















How can i delete some specific nodes?



In my example, i have lot of nodes at segment REF, but i just want to use REF with Qualifier GS, all others should be deleted.



<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>CR</QUALIFIER>
<REFERENCE>1234</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>LI</QUALIFIER>
<REFERENCE>1</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>


Do you need more info about my XML?



Edit: Output should be:



<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>


My current attempt is like this:



<!--delete REF node-->
<xsl:template match="REF">
<xsl:for-each select ="./REF">
<xsl:if test="./QUALIFIER='LI'">
</xsl:if>
</xsl:for-each>
<!--copy all other nodes-->
<xsl:apply-templates select="@* | node()"/>
</xsl:template>


My only solution at the moment is, to delete all others separately with:



<xsl:template match="REF[QUALIFIER='CR']"/>

<xsl:template match="REF[QUALIFIER='LI']"/>









share|improve this question
























  • Can you show us your XSLT? What you have tried so far?

    – ophychius
    Nov 12 '18 at 11:20











  • <!--delete REF node--> <xsl:template match="REF"> <xsl:for-each select ="./REF"> <xsl:if test="./QUALIFIER='LI'"> </xsl:if> </xsl:for-each> <!--copy all other nodes--> <xsl:apply-templates select="@* | node()"/> </xsl:template>

    – juls_pro_37
    Nov 12 '18 at 11:59











  • <xsl:template match="REF[@QUALIFER='LI']"/>

    – juls_pro_37
    Nov 12 '18 at 12:00











  • thx!! i used: <xsl:template match="REF[QUALIFIER !='GS']"/>

    – juls_pro_37
    Nov 12 '18 at 12:46













1












1








1








How can i delete some specific nodes?



In my example, i have lot of nodes at segment REF, but i just want to use REF with Qualifier GS, all others should be deleted.



<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>CR</QUALIFIER>
<REFERENCE>1234</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>LI</QUALIFIER>
<REFERENCE>1</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>


Do you need more info about my XML?



Edit: Output should be:



<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>


My current attempt is like this:



<!--delete REF node-->
<xsl:template match="REF">
<xsl:for-each select ="./REF">
<xsl:if test="./QUALIFIER='LI'">
</xsl:if>
</xsl:for-each>
<!--copy all other nodes-->
<xsl:apply-templates select="@* | node()"/>
</xsl:template>


My only solution at the moment is, to delete all others separately with:



<xsl:template match="REF[QUALIFIER='CR']"/>

<xsl:template match="REF[QUALIFIER='LI']"/>









share|improve this question
















How can i delete some specific nodes?



In my example, i have lot of nodes at segment REF, but i just want to use REF with Qualifier GS, all others should be deleted.



<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>CR</QUALIFIER>
<REFERENCE>1234</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<REF>
<QUALIFIER>LI</QUALIFIER>
<REFERENCE>1</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>


Do you need more info about my XML?



Edit: Output should be:



<ITEM>
<ITEM_NUMBER_EN>123456789</ITEM_NUMBER_EN>
<ITEM_NUMBER_IN>1234</ITEM_NUMBER_IN>
<ITEM_NUMBER_SA>1234</ITEM_NUMBER_SA>
<QUANTITY>1</QUANTITY>
<QUANTITY_UNIT>PCE</QUANTITY_UNIT>
<LINE_ITEM_NUMBER>1</LINE_ITEM_NUMBER>
<AMOUNT_DETAILS>
<QUALIFIER>AAA</QUALIFIER>
<AMOUNT>1.00</AMOUNT>
<CURRENCY>EUR</CURRENCY>
</AMOUNT_DETAILS>
<REF>
<QUALIFIER>GS</QUALIFIER>
<REFERENCE>5647</REFERENCE>
<ADDITIONAL_INFO/>
</REF>
<PACKAGE_DETAILS>
<!-- ... -->
</PACKAGE_DETAILS>
</ITEM>


My current attempt is like this:



<!--delete REF node-->
<xsl:template match="REF">
<xsl:for-each select ="./REF">
<xsl:if test="./QUALIFIER='LI'">
</xsl:if>
</xsl:for-each>
<!--copy all other nodes-->
<xsl:apply-templates select="@* | node()"/>
</xsl:template>


My only solution at the moment is, to delete all others separately with:



<xsl:template match="REF[QUALIFIER='CR']"/>

<xsl:template match="REF[QUALIFIER='LI']"/>






xml xslt xslt-1.0






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 '18 at 12:13









Tomalak

259k52429547




259k52429547










asked Nov 12 '18 at 10:49









juls_pro_37juls_pro_37

326




326












  • Can you show us your XSLT? What you have tried so far?

    – ophychius
    Nov 12 '18 at 11:20











  • <!--delete REF node--> <xsl:template match="REF"> <xsl:for-each select ="./REF"> <xsl:if test="./QUALIFIER='LI'"> </xsl:if> </xsl:for-each> <!--copy all other nodes--> <xsl:apply-templates select="@* | node()"/> </xsl:template>

    – juls_pro_37
    Nov 12 '18 at 11:59











  • <xsl:template match="REF[@QUALIFER='LI']"/>

    – juls_pro_37
    Nov 12 '18 at 12:00











  • thx!! i used: <xsl:template match="REF[QUALIFIER !='GS']"/>

    – juls_pro_37
    Nov 12 '18 at 12:46

















  • Can you show us your XSLT? What you have tried so far?

    – ophychius
    Nov 12 '18 at 11:20











  • <!--delete REF node--> <xsl:template match="REF"> <xsl:for-each select ="./REF"> <xsl:if test="./QUALIFIER='LI'"> </xsl:if> </xsl:for-each> <!--copy all other nodes--> <xsl:apply-templates select="@* | node()"/> </xsl:template>

    – juls_pro_37
    Nov 12 '18 at 11:59











  • <xsl:template match="REF[@QUALIFER='LI']"/>

    – juls_pro_37
    Nov 12 '18 at 12:00











  • thx!! i used: <xsl:template match="REF[QUALIFIER !='GS']"/>

    – juls_pro_37
    Nov 12 '18 at 12:46
















Can you show us your XSLT? What you have tried so far?

– ophychius
Nov 12 '18 at 11:20





Can you show us your XSLT? What you have tried so far?

– ophychius
Nov 12 '18 at 11:20













<!--delete REF node--> <xsl:template match="REF"> <xsl:for-each select ="./REF"> <xsl:if test="./QUALIFIER='LI'"> </xsl:if> </xsl:for-each> <!--copy all other nodes--> <xsl:apply-templates select="@* | node()"/> </xsl:template>

– juls_pro_37
Nov 12 '18 at 11:59





<!--delete REF node--> <xsl:template match="REF"> <xsl:for-each select ="./REF"> <xsl:if test="./QUALIFIER='LI'"> </xsl:if> </xsl:for-each> <!--copy all other nodes--> <xsl:apply-templates select="@* | node()"/> </xsl:template>

– juls_pro_37
Nov 12 '18 at 11:59













<xsl:template match="REF[@QUALIFER='LI']"/>

– juls_pro_37
Nov 12 '18 at 12:00





<xsl:template match="REF[@QUALIFER='LI']"/>

– juls_pro_37
Nov 12 '18 at 12:00













thx!! i used: <xsl:template match="REF[QUALIFIER !='GS']"/>

– juls_pro_37
Nov 12 '18 at 12:46





thx!! i used: <xsl:template match="REF[QUALIFIER !='GS']"/>

– juls_pro_37
Nov 12 '18 at 12:46












1 Answer
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oldest

votes


















2














You want to delete all <REF> nodes where the qualifier is not "GS".



<xsl:template match="REF[@QUALIFER != 'GS']" />


That's all that is necessary, in addition to the identity template (which you already seem to have).






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    1 Answer
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    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    You want to delete all <REF> nodes where the qualifier is not "GS".



    <xsl:template match="REF[@QUALIFER != 'GS']" />


    That's all that is necessary, in addition to the identity template (which you already seem to have).






    share|improve this answer



























      2














      You want to delete all <REF> nodes where the qualifier is not "GS".



      <xsl:template match="REF[@QUALIFER != 'GS']" />


      That's all that is necessary, in addition to the identity template (which you already seem to have).






      share|improve this answer

























        2












        2








        2







        You want to delete all <REF> nodes where the qualifier is not "GS".



        <xsl:template match="REF[@QUALIFER != 'GS']" />


        That's all that is necessary, in addition to the identity template (which you already seem to have).






        share|improve this answer













        You want to delete all <REF> nodes where the qualifier is not "GS".



        <xsl:template match="REF[@QUALIFER != 'GS']" />


        That's all that is necessary, in addition to the identity template (which you already seem to have).







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 12 '18 at 12:11









        TomalakTomalak

        259k52429547




        259k52429547





























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