SUBTIME returning incorrect value on time difference
I have two times, start time and end time, end time is always greater than start which is my case is:
SUBTIME('22:00', '06:00')
This returns 16:00 because its considering it as same date but 06:00 is greater so the difference should come out as 08:00 hours. I tried swapping but it gives -16 instead.
Is there a way to get the correct value without adding date to time values?
Ended up doing this
SELECT * FROM Table
WHERE check_in BETWEEN CONCAT(schedule_date,' ',start_time) AND (CASE WHEN(SUBTIME(end_time, start_time) < 0) THEN CONCAT(schedule_date + INTERVAL 1 DAY,' ',end_time) ELSE CONCAT(schedule_date,' ',end_time) END)
mysql
asked Nov 12 '18 at 7:59
SW DevSW Dev
11
add a comment |
I have two times, start time and end time, end time is always greater than start which is my case is:
SUBTIME('22:00', '06:00')
This returns 16:00 because its considering it as same date but 06:00 is greater so the difference should come out as 08:00 hours. I tried swapping but it gives -16 instead.
Is there a way to get the correct value without adding date to time values?
Ended up doing this
SELECT * FROM Table
WHERE check_in BETWEEN CONCAT(schedule_date,' ',start_time) AND (CASE WHEN(SUBTIME(end_time, start_time) < 0) THEN CONCAT(schedule_date + INTERVAL 1 DAY,' ',end_time) ELSE CONCAT(schedule_date,' ',end_time) END)
mysql
asked Nov 12 '18 at 7:59
SW DevSW Dev
11
You can add a CASE statement - adding 24 hours to end times that are 'less' than start times.
– Strawberry
Nov 12 '18 at 8:03
Thanks looks interesting let me try
– SW Dev
Nov 12 '18 at 8:14
So 22:00 is the start time?
– Salman A
Nov 12 '18 at 9:28
add a comment |
I have two times, start time and end time, end time is always greater than start which is my case is:
SUBTIME('22:00', '06:00')
This returns 16:00 because its considering it as same date but 06:00 is greater so the difference should come out as 08:00 hours. I tried swapping but it gives -16 instead.
Is there a way to get the correct value without adding date to time values?
Ended up doing this
SELECT * FROM Table
WHERE check_in BETWEEN CONCAT(schedule_date,' ',start_time) AND (CASE WHEN(SUBTIME(end_time, start_time) < 0) THEN CONCAT(schedule_date + INTERVAL 1 DAY,' ',end_time) ELSE CONCAT(schedule_date,' ',end_time) END)
mysql
asked Nov 12 '18 at 7:59
SW DevSW Dev
11
I have two times, start time and end time, end time is always greater than start which is my case is:
SUBTIME('22:00', '06:00')
This returns 16:00 because its considering it as same date but 06:00 is greater so the difference should come out as 08:00 hours. I tried swapping but it gives -16 instead.
Is there a way to get the correct value without adding date to time values?
Ended up doing this
SELECT * FROM Table
WHERE check_in BETWEEN CONCAT(schedule_date,' ',start_time) AND (CASE WHEN(SUBTIME(end_time, start_time) < 0) THEN CONCAT(schedule_date + INTERVAL 1 DAY,' ',end_time) ELSE CONCAT(schedule_date,' ',end_time) END)
mysql
mysql
asked Nov 12 '18 at 7:59
SW DevSW Dev
11
asked Nov 12 '18 at 7:59
SW DevSW Dev
11
edited Nov 12 '18 at 10:11
SW Dev
asked Nov 12 '18 at 7:59
SW DevSW Dev
11
asked Nov 12 '18 at 7:59
SW DevSW Dev
11
asked Nov 12 '18 at 7:59
SW DevSW Dev
11
11
You can add a CASE statement - adding 24 hours to end times that are 'less' than start times.
– Strawberry
Nov 12 '18 at 8:03
Thanks looks interesting let me try
– SW Dev
Nov 12 '18 at 8:14
So 22:00 is the start time?
– Salman A
Nov 12 '18 at 9:28
add a comment |
You can add a CASE statement - adding 24 hours to end times that are 'less' than start times.
– Strawberry
Nov 12 '18 at 8:03
Thanks looks interesting let me try
– SW Dev
Nov 12 '18 at 8:14
So 22:00 is the start time?
– Salman A
Nov 12 '18 at 9:28
You can add a CASE statement - adding 24 hours to end times that are 'less' than start times.
– Strawberry
Nov 12 '18 at 8:03
You can add a CASE statement - adding 24 hours to end times that are 'less' than start times.
– Strawberry
Nov 12 '18 at 8:03
Thanks looks interesting let me try
– SW Dev
Nov 12 '18 at 8:14
Thanks looks interesting let me try
– SW Dev
Nov 12 '18 at 8:14
So 22:00 is the start time?
– Salman A
Nov 12 '18 at 9:28
So 22:00 is the start time?
– Salman A
Nov 12 '18 at 9:28
add a comment |
1 Answer
1
active
oldest
votes
Then don't use simple times, but dates.
SELECT TIMESTAMPDIFF(HOUR, CONCAT('1970-01-01 ', '22:00'), CONCAT('1970-01-02 ', '06:00'));
This returns 8, when you want to have it as 08:00, try this:
SELECT SEC_TO_TIME(TIMESTAMPDIFF(SECOND, CONCAT('1970-01-01 ', '22:00'), CONCAT('1970-01-02 ', '06:00')));
answered Nov 12 '18 at 8:08
fancyPantsfancyPants
39.5k166883
Thanks if i couldn't find an answer i ll go this way
– SW Dev
Nov 12 '18 at 8:15
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53257936%2fsubtime-returning-incorrect-value-on-time-difference%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Then don't use simple times, but dates.
SELECT TIMESTAMPDIFF(HOUR, CONCAT('1970-01-01 ', '22:00'), CONCAT('1970-01-02 ', '06:00'));
This returns 8, when you want to have it as 08:00, try this:
SELECT SEC_TO_TIME(TIMESTAMPDIFF(SECOND, CONCAT('1970-01-01 ', '22:00'), CONCAT('1970-01-02 ', '06:00')));
answered Nov 12 '18 at 8:08
fancyPantsfancyPants
39.5k166883
Thanks if i couldn't find an answer i ll go this way
– SW Dev
Nov 12 '18 at 8:15
add a comment |
Then don't use simple times, but dates.
SELECT TIMESTAMPDIFF(HOUR, CONCAT('1970-01-01 ', '22:00'), CONCAT('1970-01-02 ', '06:00'));
This returns 8, when you want to have it as 08:00, try this:
SELECT SEC_TO_TIME(TIMESTAMPDIFF(SECOND, CONCAT('1970-01-01 ', '22:00'), CONCAT('1970-01-02 ', '06:00')));
answered Nov 12 '18 at 8:08
fancyPantsfancyPants
39.5k166883
Thanks if i couldn't find an answer i ll go this way
– SW Dev
Nov 12 '18 at 8:15
add a comment |
Then don't use simple times, but dates.
SELECT TIMESTAMPDIFF(HOUR, CONCAT('1970-01-01 ', '22:00'), CONCAT('1970-01-02 ', '06:00'));
This returns 8, when you want to have it as 08:00, try this:
SELECT SEC_TO_TIME(TIMESTAMPDIFF(SECOND, CONCAT('1970-01-01 ', '22:00'), CONCAT('1970-01-02 ', '06:00')));
answered Nov 12 '18 at 8:08
fancyPantsfancyPants
39.5k166883
Then don't use simple times, but dates.
SELECT TIMESTAMPDIFF(HOUR, CONCAT('1970-01-01 ', '22:00'), CONCAT('1970-01-02 ', '06:00'));
This returns 8, when you want to have it as 08:00, try this:
SELECT SEC_TO_TIME(TIMESTAMPDIFF(SECOND, CONCAT('1970-01-01 ', '22:00'), CONCAT('1970-01-02 ', '06:00')));
answered Nov 12 '18 at 8:08
fancyPantsfancyPants
39.5k166883
answered Nov 12 '18 at 8:08
fancyPantsfancyPants
39.5k166883
answered Nov 12 '18 at 8:08
fancyPantsfancyPants
39.5k166883
answered Nov 12 '18 at 8:08
fancyPantsfancyPants
39.5k166883
39.5k166883
Thanks if i couldn't find an answer i ll go this way
– SW Dev
Nov 12 '18 at 8:15
add a comment |
Thanks if i couldn't find an answer i ll go this way
– SW Dev
Nov 12 '18 at 8:15
Thanks if i couldn't find an answer i ll go this way
– SW Dev
Nov 12 '18 at 8:15
Thanks if i couldn't find an answer i ll go this way
– SW Dev
Nov 12 '18 at 8:15
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53257936%2fsubtime-returning-incorrect-value-on-time-difference%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
You can add a CASE statement - adding 24 hours to end times that are 'less' than start times.
– Strawberry
Nov 12 '18 at 8:03
Thanks looks interesting let me try
– SW Dev
Nov 12 '18 at 8:14
So 22:00 is the start time?
– Salman A
Nov 12 '18 at 9:28