Two Table Join with Sub-query?
So I am working on an exercise to improve my SQL skills and I need to modify my query to add a subquery that looks for the existence of a customer ID in the CUSTOMERS table. The exercise also notes that this is a correlated sub-query so you will have to match the customer ID from the sub-query to the customer ID in the outer query. The title of the section of this exercise is "Two Table Join with Subquery". After researching and trying for a few hours now, I've exhausted all my resources but one. Any help would be much appreciated! (I am using Oracle Apex for this.)
SELECT ORDER_ID, ORDER_MODE, CUSTOMER_ID, PRODUCT_ID
FROM ORDERS
NATURAL JOIN ORDER_ITEMS;
sql oracle oracle-apex
asked Nov 11 '18 at 2:27
Dominic DeveroDominic Devero
266
|
show 5 more comments
So I am working on an exercise to improve my SQL skills and I need to modify my query to add a subquery that looks for the existence of a customer ID in the CUSTOMERS table. The exercise also notes that this is a correlated sub-query so you will have to match the customer ID from the sub-query to the customer ID in the outer query. The title of the section of this exercise is "Two Table Join with Subquery". After researching and trying for a few hours now, I've exhausted all my resources but one. Any help would be much appreciated! (I am using Oracle Apex for this.)
SELECT ORDER_ID, ORDER_MODE, CUSTOMER_ID, PRODUCT_ID
FROM ORDERS
NATURAL JOIN ORDER_ITEMS;
sql oracle oracle-apex
asked Nov 11 '18 at 2:27
Dominic DeveroDominic Devero
266
A sample set of data would be helpful
– Ajan Balakumaran
Nov 11 '18 at 2:31
I've added the table data!
– Dominic Devero
Nov 11 '18 at 2:40
check the solution and let be know whether it helped :)
– Ajan Balakumaran
Nov 11 '18 at 2:54
That worked great! Just one last thing I hope you could help me with! The exercise now wants me to modify the previous SQL query to add the translated name column from the PRODUCT_DESCRIPTIONS table. I've added that table data to the post, thanks!
– Dominic Devero
Nov 11 '18 at 3:02
Since you are learning I would like to help you rather giving the answer, so now you have product_id in one of the tables join that id to products and in the select statement select the translation name
– Ajan Balakumaran
Nov 11 '18 at 3:05
|
show 5 more comments
So I am working on an exercise to improve my SQL skills and I need to modify my query to add a subquery that looks for the existence of a customer ID in the CUSTOMERS table. The exercise also notes that this is a correlated sub-query so you will have to match the customer ID from the sub-query to the customer ID in the outer query. The title of the section of this exercise is "Two Table Join with Subquery". After researching and trying for a few hours now, I've exhausted all my resources but one. Any help would be much appreciated! (I am using Oracle Apex for this.)
SELECT ORDER_ID, ORDER_MODE, CUSTOMER_ID, PRODUCT_ID
FROM ORDERS
NATURAL JOIN ORDER_ITEMS;
sql oracle oracle-apex
asked Nov 11 '18 at 2:27
Dominic DeveroDominic Devero
266
So I am working on an exercise to improve my SQL skills and I need to modify my query to add a subquery that looks for the existence of a customer ID in the CUSTOMERS table. The exercise also notes that this is a correlated sub-query so you will have to match the customer ID from the sub-query to the customer ID in the outer query. The title of the section of this exercise is "Two Table Join with Subquery". After researching and trying for a few hours now, I've exhausted all my resources but one. Any help would be much appreciated! (I am using Oracle Apex for this.)
SELECT ORDER_ID, ORDER_MODE, CUSTOMER_ID, PRODUCT_ID
FROM ORDERS
NATURAL JOIN ORDER_ITEMS;
sql oracle oracle-apex
sql oracle oracle-apex
asked Nov 11 '18 at 2:27
Dominic DeveroDominic Devero
266
asked Nov 11 '18 at 2:27
Dominic DeveroDominic Devero
266
edited Nov 11 '18 at 3:00
Dominic Devero
asked Nov 11 '18 at 2:27
Dominic DeveroDominic Devero
266
asked Nov 11 '18 at 2:27
Dominic DeveroDominic Devero
266
asked Nov 11 '18 at 2:27
Dominic DeveroDominic Devero
266
266
A sample set of data would be helpful
– Ajan Balakumaran
Nov 11 '18 at 2:31
I've added the table data!
– Dominic Devero
Nov 11 '18 at 2:40
check the solution and let be know whether it helped :)
– Ajan Balakumaran
Nov 11 '18 at 2:54
That worked great! Just one last thing I hope you could help me with! The exercise now wants me to modify the previous SQL query to add the translated name column from the PRODUCT_DESCRIPTIONS table. I've added that table data to the post, thanks!
– Dominic Devero
Nov 11 '18 at 3:02
Since you are learning I would like to help you rather giving the answer, so now you have product_id in one of the tables join that id to products and in the select statement select the translation name
– Ajan Balakumaran
Nov 11 '18 at 3:05
|
show 5 more comments
A sample set of data would be helpful
– Ajan Balakumaran
Nov 11 '18 at 2:31
I've added the table data!
– Dominic Devero
Nov 11 '18 at 2:40
check the solution and let be know whether it helped :)
– Ajan Balakumaran
Nov 11 '18 at 2:54
That worked great! Just one last thing I hope you could help me with! The exercise now wants me to modify the previous SQL query to add the translated name column from the PRODUCT_DESCRIPTIONS table. I've added that table data to the post, thanks!
– Dominic Devero
Nov 11 '18 at 3:02
Since you are learning I would like to help you rather giving the answer, so now you have product_id in one of the tables join that id to products and in the select statement select the translation name
– Ajan Balakumaran
Nov 11 '18 at 3:05
A sample set of data would be helpful
– Ajan Balakumaran
Nov 11 '18 at 2:31
A sample set of data would be helpful
– Ajan Balakumaran
Nov 11 '18 at 2:31
I've added the table data!
– Dominic Devero
Nov 11 '18 at 2:40
I've added the table data!
– Dominic Devero
Nov 11 '18 at 2:40
check the solution and let be know whether it helped :)
– Ajan Balakumaran
Nov 11 '18 at 2:54
check the solution and let be know whether it helped :)
– Ajan Balakumaran
Nov 11 '18 at 2:54
That worked great! Just one last thing I hope you could help me with! The exercise now wants me to modify the previous SQL query to add the translated name column from the PRODUCT_DESCRIPTIONS table. I've added that table data to the post, thanks!
– Dominic Devero
Nov 11 '18 at 3:02
That worked great! Just one last thing I hope you could help me with! The exercise now wants me to modify the previous SQL query to add the translated name column from the PRODUCT_DESCRIPTIONS table. I've added that table data to the post, thanks!
– Dominic Devero
Nov 11 '18 at 3:02
Since you are learning I would like to help you rather giving the answer, so now you have product_id in one of the tables join that id to products and in the select statement select the translation name
– Ajan Balakumaran
Nov 11 '18 at 3:05
Since you are learning I would like to help you rather giving the answer, so now you have product_id in one of the tables join that id to products and in the select statement select the translation name
– Ajan Balakumaran
Nov 11 '18 at 3:05
|
show 5 more comments
1 Answer
1
active
oldest
votes
Using exists you can check for existence,
SELECT O.ORDER_ID, O.ORDER_MODE, O.CUSTOMER_ID, OI.PRODUCT_ID
FROM ORDERS O
INNER JOIN ORDER_ITEMS OI on O.ORDER_ID=OI.ORDER_ID
WHERE EXISTS(
SELECT * FROM CUSTOMERS C
WHERE O.CUSTOMER_ID=C.CUSTOMER_ID
);
This would do the second,
SELECT O.ORDER_ID, O.ORDER_MODE, O.CUSTOMER_ID, OI.PRODUCT_ID,P.TRANSLATED_NAME
FROM ORDERS O
INNER JOIN ORDER_ITEMS OI on O.ORDER_ID=OI.ORDER_ID
INNER JOIN PRODUCT_DESCRIPTIONS P on P.PRODUCT_ID=OI.PRODUCT_ID
WHERE EXISTS(
SELECT * FROM CUSTOMERS C
WHERE O.CUSTOMER_ID=C.CUSTOMER_ID
);
answered Nov 11 '18 at 2:47
Ajan BalakumaranAjan Balakumaran
661210
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53245329%2ftwo-table-join-with-sub-query%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Using exists you can check for existence,
SELECT O.ORDER_ID, O.ORDER_MODE, O.CUSTOMER_ID, OI.PRODUCT_ID
FROM ORDERS O
INNER JOIN ORDER_ITEMS OI on O.ORDER_ID=OI.ORDER_ID
WHERE EXISTS(
SELECT * FROM CUSTOMERS C
WHERE O.CUSTOMER_ID=C.CUSTOMER_ID
);
This would do the second,
SELECT O.ORDER_ID, O.ORDER_MODE, O.CUSTOMER_ID, OI.PRODUCT_ID,P.TRANSLATED_NAME
FROM ORDERS O
INNER JOIN ORDER_ITEMS OI on O.ORDER_ID=OI.ORDER_ID
INNER JOIN PRODUCT_DESCRIPTIONS P on P.PRODUCT_ID=OI.PRODUCT_ID
WHERE EXISTS(
SELECT * FROM CUSTOMERS C
WHERE O.CUSTOMER_ID=C.CUSTOMER_ID
);
answered Nov 11 '18 at 2:47
Ajan BalakumaranAjan Balakumaran
661210
add a comment |
Using exists you can check for existence,
SELECT O.ORDER_ID, O.ORDER_MODE, O.CUSTOMER_ID, OI.PRODUCT_ID
FROM ORDERS O
INNER JOIN ORDER_ITEMS OI on O.ORDER_ID=OI.ORDER_ID
WHERE EXISTS(
SELECT * FROM CUSTOMERS C
WHERE O.CUSTOMER_ID=C.CUSTOMER_ID
);
This would do the second,
SELECT O.ORDER_ID, O.ORDER_MODE, O.CUSTOMER_ID, OI.PRODUCT_ID,P.TRANSLATED_NAME
FROM ORDERS O
INNER JOIN ORDER_ITEMS OI on O.ORDER_ID=OI.ORDER_ID
INNER JOIN PRODUCT_DESCRIPTIONS P on P.PRODUCT_ID=OI.PRODUCT_ID
WHERE EXISTS(
SELECT * FROM CUSTOMERS C
WHERE O.CUSTOMER_ID=C.CUSTOMER_ID
);
answered Nov 11 '18 at 2:47
Ajan BalakumaranAjan Balakumaran
661210
add a comment |
Using exists you can check for existence,
SELECT O.ORDER_ID, O.ORDER_MODE, O.CUSTOMER_ID, OI.PRODUCT_ID
FROM ORDERS O
INNER JOIN ORDER_ITEMS OI on O.ORDER_ID=OI.ORDER_ID
WHERE EXISTS(
SELECT * FROM CUSTOMERS C
WHERE O.CUSTOMER_ID=C.CUSTOMER_ID
);
This would do the second,
SELECT O.ORDER_ID, O.ORDER_MODE, O.CUSTOMER_ID, OI.PRODUCT_ID,P.TRANSLATED_NAME
FROM ORDERS O
INNER JOIN ORDER_ITEMS OI on O.ORDER_ID=OI.ORDER_ID
INNER JOIN PRODUCT_DESCRIPTIONS P on P.PRODUCT_ID=OI.PRODUCT_ID
WHERE EXISTS(
SELECT * FROM CUSTOMERS C
WHERE O.CUSTOMER_ID=C.CUSTOMER_ID
);
answered Nov 11 '18 at 2:47
Ajan BalakumaranAjan Balakumaran
661210
Using exists you can check for existence,
SELECT O.ORDER_ID, O.ORDER_MODE, O.CUSTOMER_ID, OI.PRODUCT_ID
FROM ORDERS O
INNER JOIN ORDER_ITEMS OI on O.ORDER_ID=OI.ORDER_ID
WHERE EXISTS(
SELECT * FROM CUSTOMERS C
WHERE O.CUSTOMER_ID=C.CUSTOMER_ID
);
This would do the second,
SELECT O.ORDER_ID, O.ORDER_MODE, O.CUSTOMER_ID, OI.PRODUCT_ID,P.TRANSLATED_NAME
FROM ORDERS O
INNER JOIN ORDER_ITEMS OI on O.ORDER_ID=OI.ORDER_ID
INNER JOIN PRODUCT_DESCRIPTIONS P on P.PRODUCT_ID=OI.PRODUCT_ID
WHERE EXISTS(
SELECT * FROM CUSTOMERS C
WHERE O.CUSTOMER_ID=C.CUSTOMER_ID
);
answered Nov 11 '18 at 2:47
Ajan BalakumaranAjan Balakumaran
661210
edited Nov 11 '18 at 3:18
answered Nov 11 '18 at 2:47
Ajan BalakumaranAjan Balakumaran
661210
answered Nov 11 '18 at 2:47
Ajan BalakumaranAjan Balakumaran
661210
answered Nov 11 '18 at 2:47
Ajan BalakumaranAjan Balakumaran
661210
661210
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53245329%2ftwo-table-join-with-sub-query%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
A sample set of data would be helpful
– Ajan Balakumaran
Nov 11 '18 at 2:31
I've added the table data!
– Dominic Devero
Nov 11 '18 at 2:40
check the solution and let be know whether it helped :)
– Ajan Balakumaran
Nov 11 '18 at 2:54
That worked great! Just one last thing I hope you could help me with! The exercise now wants me to modify the previous SQL query to add the translated name column from the PRODUCT_DESCRIPTIONS table. I've added that table data to the post, thanks!
– Dominic Devero
Nov 11 '18 at 3:02
Since you are learning I would like to help you rather giving the answer, so now you have product_id in one of the tables join that id to products and in the select statement select the translation name
– Ajan Balakumaran
Nov 11 '18 at 3:05