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So I split a .txt file into a list of lists (shown below). However, when I try to run print(splitKeyword(keywords[1][0])) to try and print the first element of the second list/element within keywordList, I get the error: NameError: name 'keywordList' is not defined. How can I fix this?

def functionOne(textFile):
 textFileVar = open(textFile, 'r')

 def splitKeyword(argument):
 keywordList = 
 for line in argument:
 keywordList.append(line.strip().split(','))
 return keywordList

 splitKeyword(textFileVar)
 print(keywordList[1][0])

results = functionOne("text1.txt")
print(results)

This is the text1.txt/textFile/textFileVar contents

hello,world

123,456

This is what keywordList looks like when printed:

[[hello, world], [123, 456]]

Try this:

def functionOne(textFile):
 textFileVar = open(textFile, 'r')

 def splitKeyword(argument):
 keywordList = 
 for line in argument:
 keywordList.append(line.strip().split(','))
 return keywordList

 output = splitKeyword(textFileVar)
 print(output[1][0])
 return output

results = functionOne("text1.txt")
print(results)

look at return keywordList in splitKeyword function. it returns the value(keywordList). but in other scopes you can not access that variable, so you need to store that in something.

Your keywordList is local to the function splitKeyword(), not to the function functionOne(). That's why you're getting a NameError.

keywordlist is a local variable to the function splitKeyword which return it so you can directly use this function and reduce the code.

def functionOne(textFile):
 textFileVar = open(textFile, 'r')
 def splitKeyword(argument):
 keywordList = 
 for line in argument:
 keywordList.append(line.strip().split(','))
 return keywordList

 print(splitKeyword(textFileVar))

results = functionOne("text1.txt")
print(results)