Countable version of Erdös-Lovasz-Faber conjecture
Countable version of Erdös-Lovasz-Faber conjecture
Let $X$ be an infinite set, and let $(A_n)_ninomega$ be a collection of subsets of $X$ with the following properties:
We consider the following statement:
(EFL$_omega$:) There is $f:Xto omega$ such that for all $ninomega$ the restriction $f|_A_n:A_ntoomega$ is a bijection.
Questions. Is (EFL$_omega$) true? Or does (EFL$_omega$) imply the original Erdös-Faber-Lovasz conjecture?
1 Answer
1
If I understand it correctly, it's false. Let $x notin A_0 = 1,2,dots $. Then let $A_i$ all meet at $x$, and also each meet $A$ at $i$ (add extra elements as necessary; they should be irrelevant). Then $f(x) neq f(i)$ for any $i$, so $f(x) notin f(A)$.
This didn't work in the finite case because the sets meeting $A$ cannot exhaust $A$, as the number of such sets is strictly less than the number of elements of $A$. When working over infinite sets, this is no longer true.
Thanks for contributing an answer to MathOverflow!
But avoid …
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
But avoid …
To learn more, see our tips on writing great answers.
Required, but never shown
Required, but never shown
By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.
Nice construction, thanks! (There is one typo, I guess by $A$ you mean $A_0$?)
– Dominic van der Zypen
Sep 5 '18 at 8:04