How to add colorbars to scatterplots created like this?
up vote
8
down vote
favorite
I create scatterplots with code that, in essence, goes like this
cmap = (matplotlib.color.LinearSegmentedColormap.
from_list('blueWhiteRed', ['blue', 'white', 'red']))
fig = matplotlib.figure.Figure(figsize=(4, 4), dpi=72)
ax = fig.gca()
for record in data:
level = record.level # a float in [0.0, 1.0]
marker = record.marker # one of 'o', 's', '^', '*', etc.
ax.scatter(record.x, record.y, marker=marker,
c=level, vmin=0, vmax=1, cmap=cmap, **otherkwargs)
# various settings of ticks, labels, etc. omitted
canvas = matplotlib.backends.backend_agg.FigureCanvasAgg(fig)
fig.set_canvas(canvas)
canvas.print_png('/path/to/output/fig.png')
My question is this:
What do I need add to the code above to get a vertical colorbar (representing the colormap in
cmap
) along the plot's right edge?
NOTE: I find Matplotlib utterly incomprehensible, and this goes for both its design as well as its documentation. (Not for lack of trying: I have putting a lot of time, effort, and even some money, into it.) So I would appreciate complete, working code (even if it's just a toy example), because most likely I won't be able to fill in omitted details or fix bugs in the code.
EDIT: I fixed an important omission in the "code sketch" above, namely a record-specific marker specification in each call to ax.scatter
. This is the reason for creating the scatterplot with multiple calls to ax.scatter
, although, admittedly, one could at least reduce the number of calls to scatter to one per maker shape used; e.g.
for marker in set(record.marker for record in data):
X, Y, COLOR = zip(*((record.x, record.y, record.level)
for record in data if record.marker == marker))
ax.scatter(X, Y, marker=marker,
c=COLOR, vmin=0, vmax=1, cmap=cmap,
**otherkwargs)
I tried to extend the same trick to collapse all calls to ax.scatter
into one (by passing a sequence of markers as the marker
argument), like this:
X, Y, COLOR, MARKER = zip(*((record.x, record.y, record.level, record.marker)
for record in data))
ax.scatter(X, Y, marker=MARKER,
c=COLOR, vmin=0, vmax=1, cmap=cmap,
**otherkwargs)
...but this fails. The error goes something like this (after pruning some long paths):
Traceback (most recent call last):
File "src/demo.py", line 222, in <module>
main()
File "src/demo.py", line 91, in main
**otherkwargs)
File "<abbreviated-path>/matplotlib/axes.py", line 6100, in scatter
marker_obj = mmarkers.MarkerStyle(marker)
File "<abbreviated-path>/matplotlib/markers.py", line 113, in __init__
self.set_marker(marker)
File "<abbreviated-path>/matplotlib/markers.py", line 179, in set_marker
raise ValueError('Unrecognized marker style '.format(marker))
ValueError: Unrecognized marker style ('^', 'o', '^', '*', 'o', 's', 'o', 'o', '^', 's', 'o', 'o', '^', '^', '*', 'o', '*', '*', 's', 's', 'o', 's', 'o', '^', 'o', 'o', '*', '^', 's', '^', '^', 's', '*')
AFAICT, tcaswell's recipe requires reducing the calls to ax.scatter
to a single one, but this requirement appears to conflict with my absolute requirement for multiple marker shapes in the same scatterplot.
python matplotlib
|
show 4 more comments
up vote
8
down vote
favorite
I create scatterplots with code that, in essence, goes like this
cmap = (matplotlib.color.LinearSegmentedColormap.
from_list('blueWhiteRed', ['blue', 'white', 'red']))
fig = matplotlib.figure.Figure(figsize=(4, 4), dpi=72)
ax = fig.gca()
for record in data:
level = record.level # a float in [0.0, 1.0]
marker = record.marker # one of 'o', 's', '^', '*', etc.
ax.scatter(record.x, record.y, marker=marker,
c=level, vmin=0, vmax=1, cmap=cmap, **otherkwargs)
# various settings of ticks, labels, etc. omitted
canvas = matplotlib.backends.backend_agg.FigureCanvasAgg(fig)
fig.set_canvas(canvas)
canvas.print_png('/path/to/output/fig.png')
My question is this:
What do I need add to the code above to get a vertical colorbar (representing the colormap in
cmap
) along the plot's right edge?
NOTE: I find Matplotlib utterly incomprehensible, and this goes for both its design as well as its documentation. (Not for lack of trying: I have putting a lot of time, effort, and even some money, into it.) So I would appreciate complete, working code (even if it's just a toy example), because most likely I won't be able to fill in omitted details or fix bugs in the code.
EDIT: I fixed an important omission in the "code sketch" above, namely a record-specific marker specification in each call to ax.scatter
. This is the reason for creating the scatterplot with multiple calls to ax.scatter
, although, admittedly, one could at least reduce the number of calls to scatter to one per maker shape used; e.g.
for marker in set(record.marker for record in data):
X, Y, COLOR = zip(*((record.x, record.y, record.level)
for record in data if record.marker == marker))
ax.scatter(X, Y, marker=marker,
c=COLOR, vmin=0, vmax=1, cmap=cmap,
**otherkwargs)
I tried to extend the same trick to collapse all calls to ax.scatter
into one (by passing a sequence of markers as the marker
argument), like this:
X, Y, COLOR, MARKER = zip(*((record.x, record.y, record.level, record.marker)
for record in data))
ax.scatter(X, Y, marker=MARKER,
c=COLOR, vmin=0, vmax=1, cmap=cmap,
**otherkwargs)
...but this fails. The error goes something like this (after pruning some long paths):
Traceback (most recent call last):
File "src/demo.py", line 222, in <module>
main()
File "src/demo.py", line 91, in main
**otherkwargs)
File "<abbreviated-path>/matplotlib/axes.py", line 6100, in scatter
marker_obj = mmarkers.MarkerStyle(marker)
File "<abbreviated-path>/matplotlib/markers.py", line 113, in __init__
self.set_marker(marker)
File "<abbreviated-path>/matplotlib/markers.py", line 179, in set_marker
raise ValueError('Unrecognized marker style '.format(marker))
ValueError: Unrecognized marker style ('^', 'o', '^', '*', 'o', 's', 'o', 'o', '^', 's', 'o', 'o', '^', '^', '*', 'o', '*', '*', 's', 's', 'o', 's', 'o', '^', 'o', 'o', '*', '^', 's', '^', '^', 's', '*')
AFAICT, tcaswell's recipe requires reducing the calls to ax.scatter
to a single one, but this requirement appears to conflict with my absolute requirement for multiple marker shapes in the same scatterplot.
python matplotlib
see edit and other comment.
– tacaswell
Dec 20 '12 at 16:53
i don't think there's a requirement for multiple marker shapes inscatter
. just feed it a single marker for each group of data.
– Paul H
Dec 20 '12 at 23:38
the requirement is mine: I require multiple marker shapes in the scatterplots I'm making.
– kjo
Dec 21 '12 at 1:26
@kjo see my response below
– Paul H
Dec 21 '12 at 2:00
@kjo Sorry I was rude the other day, I was in a bad mood and your rant set me off. Did you get this sorted out?
– tacaswell
Dec 22 '12 at 23:55
|
show 4 more comments
up vote
8
down vote
favorite
up vote
8
down vote
favorite
I create scatterplots with code that, in essence, goes like this
cmap = (matplotlib.color.LinearSegmentedColormap.
from_list('blueWhiteRed', ['blue', 'white', 'red']))
fig = matplotlib.figure.Figure(figsize=(4, 4), dpi=72)
ax = fig.gca()
for record in data:
level = record.level # a float in [0.0, 1.0]
marker = record.marker # one of 'o', 's', '^', '*', etc.
ax.scatter(record.x, record.y, marker=marker,
c=level, vmin=0, vmax=1, cmap=cmap, **otherkwargs)
# various settings of ticks, labels, etc. omitted
canvas = matplotlib.backends.backend_agg.FigureCanvasAgg(fig)
fig.set_canvas(canvas)
canvas.print_png('/path/to/output/fig.png')
My question is this:
What do I need add to the code above to get a vertical colorbar (representing the colormap in
cmap
) along the plot's right edge?
NOTE: I find Matplotlib utterly incomprehensible, and this goes for both its design as well as its documentation. (Not for lack of trying: I have putting a lot of time, effort, and even some money, into it.) So I would appreciate complete, working code (even if it's just a toy example), because most likely I won't be able to fill in omitted details or fix bugs in the code.
EDIT: I fixed an important omission in the "code sketch" above, namely a record-specific marker specification in each call to ax.scatter
. This is the reason for creating the scatterplot with multiple calls to ax.scatter
, although, admittedly, one could at least reduce the number of calls to scatter to one per maker shape used; e.g.
for marker in set(record.marker for record in data):
X, Y, COLOR = zip(*((record.x, record.y, record.level)
for record in data if record.marker == marker))
ax.scatter(X, Y, marker=marker,
c=COLOR, vmin=0, vmax=1, cmap=cmap,
**otherkwargs)
I tried to extend the same trick to collapse all calls to ax.scatter
into one (by passing a sequence of markers as the marker
argument), like this:
X, Y, COLOR, MARKER = zip(*((record.x, record.y, record.level, record.marker)
for record in data))
ax.scatter(X, Y, marker=MARKER,
c=COLOR, vmin=0, vmax=1, cmap=cmap,
**otherkwargs)
...but this fails. The error goes something like this (after pruning some long paths):
Traceback (most recent call last):
File "src/demo.py", line 222, in <module>
main()
File "src/demo.py", line 91, in main
**otherkwargs)
File "<abbreviated-path>/matplotlib/axes.py", line 6100, in scatter
marker_obj = mmarkers.MarkerStyle(marker)
File "<abbreviated-path>/matplotlib/markers.py", line 113, in __init__
self.set_marker(marker)
File "<abbreviated-path>/matplotlib/markers.py", line 179, in set_marker
raise ValueError('Unrecognized marker style '.format(marker))
ValueError: Unrecognized marker style ('^', 'o', '^', '*', 'o', 's', 'o', 'o', '^', 's', 'o', 'o', '^', '^', '*', 'o', '*', '*', 's', 's', 'o', 's', 'o', '^', 'o', 'o', '*', '^', 's', '^', '^', 's', '*')
AFAICT, tcaswell's recipe requires reducing the calls to ax.scatter
to a single one, but this requirement appears to conflict with my absolute requirement for multiple marker shapes in the same scatterplot.
python matplotlib
I create scatterplots with code that, in essence, goes like this
cmap = (matplotlib.color.LinearSegmentedColormap.
from_list('blueWhiteRed', ['blue', 'white', 'red']))
fig = matplotlib.figure.Figure(figsize=(4, 4), dpi=72)
ax = fig.gca()
for record in data:
level = record.level # a float in [0.0, 1.0]
marker = record.marker # one of 'o', 's', '^', '*', etc.
ax.scatter(record.x, record.y, marker=marker,
c=level, vmin=0, vmax=1, cmap=cmap, **otherkwargs)
# various settings of ticks, labels, etc. omitted
canvas = matplotlib.backends.backend_agg.FigureCanvasAgg(fig)
fig.set_canvas(canvas)
canvas.print_png('/path/to/output/fig.png')
My question is this:
What do I need add to the code above to get a vertical colorbar (representing the colormap in
cmap
) along the plot's right edge?
NOTE: I find Matplotlib utterly incomprehensible, and this goes for both its design as well as its documentation. (Not for lack of trying: I have putting a lot of time, effort, and even some money, into it.) So I would appreciate complete, working code (even if it's just a toy example), because most likely I won't be able to fill in omitted details or fix bugs in the code.
EDIT: I fixed an important omission in the "code sketch" above, namely a record-specific marker specification in each call to ax.scatter
. This is the reason for creating the scatterplot with multiple calls to ax.scatter
, although, admittedly, one could at least reduce the number of calls to scatter to one per maker shape used; e.g.
for marker in set(record.marker for record in data):
X, Y, COLOR = zip(*((record.x, record.y, record.level)
for record in data if record.marker == marker))
ax.scatter(X, Y, marker=marker,
c=COLOR, vmin=0, vmax=1, cmap=cmap,
**otherkwargs)
I tried to extend the same trick to collapse all calls to ax.scatter
into one (by passing a sequence of markers as the marker
argument), like this:
X, Y, COLOR, MARKER = zip(*((record.x, record.y, record.level, record.marker)
for record in data))
ax.scatter(X, Y, marker=MARKER,
c=COLOR, vmin=0, vmax=1, cmap=cmap,
**otherkwargs)
...but this fails. The error goes something like this (after pruning some long paths):
Traceback (most recent call last):
File "src/demo.py", line 222, in <module>
main()
File "src/demo.py", line 91, in main
**otherkwargs)
File "<abbreviated-path>/matplotlib/axes.py", line 6100, in scatter
marker_obj = mmarkers.MarkerStyle(marker)
File "<abbreviated-path>/matplotlib/markers.py", line 113, in __init__
self.set_marker(marker)
File "<abbreviated-path>/matplotlib/markers.py", line 179, in set_marker
raise ValueError('Unrecognized marker style '.format(marker))
ValueError: Unrecognized marker style ('^', 'o', '^', '*', 'o', 's', 'o', 'o', '^', 's', 'o', 'o', '^', '^', '*', 'o', '*', '*', 's', 's', 'o', 's', 'o', '^', 'o', 'o', '*', '^', 's', '^', '^', 's', '*')
AFAICT, tcaswell's recipe requires reducing the calls to ax.scatter
to a single one, but this requirement appears to conflict with my absolute requirement for multiple marker shapes in the same scatterplot.
python matplotlib
python matplotlib
edited Dec 21 '12 at 1:27
asked Dec 18 '12 at 23:29
kjo
11.5k2992183
11.5k2992183
see edit and other comment.
– tacaswell
Dec 20 '12 at 16:53
i don't think there's a requirement for multiple marker shapes inscatter
. just feed it a single marker for each group of data.
– Paul H
Dec 20 '12 at 23:38
the requirement is mine: I require multiple marker shapes in the scatterplots I'm making.
– kjo
Dec 21 '12 at 1:26
@kjo see my response below
– Paul H
Dec 21 '12 at 2:00
@kjo Sorry I was rude the other day, I was in a bad mood and your rant set me off. Did you get this sorted out?
– tacaswell
Dec 22 '12 at 23:55
|
show 4 more comments
see edit and other comment.
– tacaswell
Dec 20 '12 at 16:53
i don't think there's a requirement for multiple marker shapes inscatter
. just feed it a single marker for each group of data.
– Paul H
Dec 20 '12 at 23:38
the requirement is mine: I require multiple marker shapes in the scatterplots I'm making.
– kjo
Dec 21 '12 at 1:26
@kjo see my response below
– Paul H
Dec 21 '12 at 2:00
@kjo Sorry I was rude the other day, I was in a bad mood and your rant set me off. Did you get this sorted out?
– tacaswell
Dec 22 '12 at 23:55
see edit and other comment.
– tacaswell
Dec 20 '12 at 16:53
see edit and other comment.
– tacaswell
Dec 20 '12 at 16:53
i don't think there's a requirement for multiple marker shapes in
scatter
. just feed it a single marker for each group of data.– Paul H
Dec 20 '12 at 23:38
i don't think there's a requirement for multiple marker shapes in
scatter
. just feed it a single marker for each group of data.– Paul H
Dec 20 '12 at 23:38
the requirement is mine: I require multiple marker shapes in the scatterplots I'm making.
– kjo
Dec 21 '12 at 1:26
the requirement is mine: I require multiple marker shapes in the scatterplots I'm making.
– kjo
Dec 21 '12 at 1:26
@kjo see my response below
– Paul H
Dec 21 '12 at 2:00
@kjo see my response below
– Paul H
Dec 21 '12 at 2:00
@kjo Sorry I was rude the other day, I was in a bad mood and your rant set me off. Did you get this sorted out?
– tacaswell
Dec 22 '12 at 23:55
@kjo Sorry I was rude the other day, I was in a bad mood and your rant set me off. Did you get this sorted out?
– tacaswell
Dec 22 '12 at 23:55
|
show 4 more comments
4 Answers
4
active
oldest
votes
up vote
8
down vote
If you have to use a different marker for each set, you have to do a bit of extra work and force all of the clims
to be the same (otherwise they default to scaling from the min/max of the c
data per scatter plot).
from pylab import *
import matplotlib.lines as mlines
import itertools
fig = gcf()
ax = fig.gca()
# make some temorary arrays
X =
Y =
C =
cb = None
# generate fake data
markers = ['','o','*','^','v']
cmin = 0
cmax = 1
for record,marker in itertools.izip(range(5),itertools.cycle(mlines.Line2D.filled_markers)):
x = rand(50)
y = rand(50)
c = rand(1)[0] * np.ones(x.shape)
if cb is None:
s = ax.scatter(x,y,c=c,marker=markers[record],linewidths=0)
s.set_clim([cmin,cmax])
cb = fig.colorbar(s)
else:
s = ax.scatter(x,y,c=c,marker=markers[record],linewidths=0)
s.set_clim([cmin,cmax])
cb.set_label('Cbar Label Here')
thelinewidths=0
sets the width of the border on the shapes, I find that for small shapes the black border can overwhelm the color of the fill.
If you only need one shape you can do this all with a single scatter plot, there is no need to make a separate one for each pass through your loop.
from pylab import *
fig = gcf()
ax = fig.gca()
# make some temorary arrays
X =
Y =
C =
# generate fake data
for record in range(5):
x = rand(50)
y = rand(50)
c = rand(1)[0] * np.ones(x.shape)
print c
X.append(x)
Y.append(y)
C.append(c)
X = np.hstack(X)
Y = np.hstack(Y)
C = np.hstack(C)
once you have the data all beaten down into a 1D array, make the scatter plot, and keep the returned value:
s = ax.scatter(X,Y,c=C)
You then make your color bar and pass the object returned by scatter
as the first argument.
cb = plt.colorbar(s)
cb.set_label('Cbar Label Here')
You need do this so that the color bar knows which color map (both the map and the range) to use.
the code I posted is everything I did except for afig.savefig()
– tacaswell
Dec 20 '12 at 15:27
one question ... what is the point of having in both conditions (if .... else
block) the lines = x.scatter(x,y,c=c,marker=markers[record],linewidths=0)
?
– gluuke
Sep 21 at 17:03
add a comment |
up vote
5
down vote
I think your best bet will be to stuff your data into a pandas dataframe, and loop through all of your markers like so:
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
markers = ['s', 'o', '^']
records =
for n in range(37):
records.append([np.random.normal(), np.random.normal(), np.random.normal(),
markers[np.random.randint(0, high=3)]])
records = pd.DataFrame(records, columns=['x', 'y', 'z', 'marker'])
fig, ax = plt.subplots()
for m in np.unique(records.marker):
selector = records.marker == m
s = ax.scatter(records[selector].x, records[selector].y, c=records[selector].z,
marker=m, cmap=plt.cm.coolwarm,
vmin=records.z.min(), vmax=records.z.max())
cbar = plt.colorbar(mappable=s, ax=ax)
cbar.set_label('My Label')
add a comment |
up vote
1
down vote
I think this should do the trick. I'm pretty sure I grabbed this from one of the matplotlib cookbook examples a while back, but I can't seem to find it now...
from mpl_toolkits.axes_grid1 import make_axes_locatable
cmap = (matplotlib.color.LinearSegmentedColormap.
from_list('blueWhiteRed', ['blue', 'white', 'red']))
fig = matplotlib.figure.Figure(figsize=(4, 4), dpi=72)
ax = fig.gca()
for record in data:
level = record.level # a float in [0.0, 1.0]
ax.scatter(record.x, record.y,
c=level, vmin=0, vmax=1, cmap=cmap, **otherkwargs)
# various settings of ticks, labels, etc. omitted
divider= make_axes_locatable(ax)
cax = divider.append_axes("right", size="1%", pad=0.05)
cb = plt.colorbar(cax=cax)
cb.set_label('Cbar Label Here')
canvas = matplotlib.backends.backend_agg.FigureCanvasAgg(fig)
fig.set_canvas(canvas)
canvas.print_png('/path/to/output/fig.png')
did you test this?
– tacaswell
Dec 19 '12 at 5:22
@JoshaInglis: the linecb = plt.colorbar(cax=cax)
fails, with the errorRuntimeError: No mappable was found to use for colorbar creation. First define a mappable such as an image (with imshow) or a contour set (with contourf).
It may be very simple to fix this problem, but as I explained in an addition to my post, I am a complete Matplotlib dunce...
– kjo
Dec 20 '12 at 14:13
add a comment |
up vote
1
down vote
The answer to this can be to only plot a single scatter, which would then directly allow for a colobar to be created.
This involves putting the markers into the PathCollection
created by the scatter a posteriori, but it can be easily placed in a function. This function comes from my answer on another question, but is directly applicable here.
Taking the data from @PaulH's post this would look like
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
def mscatter(x,y,ax=None, m=None, **kw):
import matplotlib.markers as mmarkers
ax = ax or plt.gca()
sc = ax.scatter(x,y,**kw)
if (m is not None) and (len(m)==len(x)):
paths =
for marker in m:
if isinstance(marker, mmarkers.MarkerStyle):
marker_obj = marker
else:
marker_obj = mmarkers.MarkerStyle(marker)
path = marker_obj.get_path().transformed(
marker_obj.get_transform())
paths.append(path)
sc.set_paths(paths)
return sc
markers = ['s', 'o', '^']
records =
for n in range(37):
records.append([np.random.normal(), np.random.normal(), np.random.normal(),
markers[np.random.randint(0, high=3)]])
records = pd.DataFrame(records, columns=['x', 'y', 'z', 'marker'])
fig, ax = plt.subplots()
sc = mscatter(records.x, records.y, c=records.z, m=records.marker, ax=ax)
fig.colorbar(sc, ax=ax)
plt.show()
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
8
down vote
If you have to use a different marker for each set, you have to do a bit of extra work and force all of the clims
to be the same (otherwise they default to scaling from the min/max of the c
data per scatter plot).
from pylab import *
import matplotlib.lines as mlines
import itertools
fig = gcf()
ax = fig.gca()
# make some temorary arrays
X =
Y =
C =
cb = None
# generate fake data
markers = ['','o','*','^','v']
cmin = 0
cmax = 1
for record,marker in itertools.izip(range(5),itertools.cycle(mlines.Line2D.filled_markers)):
x = rand(50)
y = rand(50)
c = rand(1)[0] * np.ones(x.shape)
if cb is None:
s = ax.scatter(x,y,c=c,marker=markers[record],linewidths=0)
s.set_clim([cmin,cmax])
cb = fig.colorbar(s)
else:
s = ax.scatter(x,y,c=c,marker=markers[record],linewidths=0)
s.set_clim([cmin,cmax])
cb.set_label('Cbar Label Here')
thelinewidths=0
sets the width of the border on the shapes, I find that for small shapes the black border can overwhelm the color of the fill.
If you only need one shape you can do this all with a single scatter plot, there is no need to make a separate one for each pass through your loop.
from pylab import *
fig = gcf()
ax = fig.gca()
# make some temorary arrays
X =
Y =
C =
# generate fake data
for record in range(5):
x = rand(50)
y = rand(50)
c = rand(1)[0] * np.ones(x.shape)
print c
X.append(x)
Y.append(y)
C.append(c)
X = np.hstack(X)
Y = np.hstack(Y)
C = np.hstack(C)
once you have the data all beaten down into a 1D array, make the scatter plot, and keep the returned value:
s = ax.scatter(X,Y,c=C)
You then make your color bar and pass the object returned by scatter
as the first argument.
cb = plt.colorbar(s)
cb.set_label('Cbar Label Here')
You need do this so that the color bar knows which color map (both the map and the range) to use.
the code I posted is everything I did except for afig.savefig()
– tacaswell
Dec 20 '12 at 15:27
one question ... what is the point of having in both conditions (if .... else
block) the lines = x.scatter(x,y,c=c,marker=markers[record],linewidths=0)
?
– gluuke
Sep 21 at 17:03
add a comment |
up vote
8
down vote
If you have to use a different marker for each set, you have to do a bit of extra work and force all of the clims
to be the same (otherwise they default to scaling from the min/max of the c
data per scatter plot).
from pylab import *
import matplotlib.lines as mlines
import itertools
fig = gcf()
ax = fig.gca()
# make some temorary arrays
X =
Y =
C =
cb = None
# generate fake data
markers = ['','o','*','^','v']
cmin = 0
cmax = 1
for record,marker in itertools.izip(range(5),itertools.cycle(mlines.Line2D.filled_markers)):
x = rand(50)
y = rand(50)
c = rand(1)[0] * np.ones(x.shape)
if cb is None:
s = ax.scatter(x,y,c=c,marker=markers[record],linewidths=0)
s.set_clim([cmin,cmax])
cb = fig.colorbar(s)
else:
s = ax.scatter(x,y,c=c,marker=markers[record],linewidths=0)
s.set_clim([cmin,cmax])
cb.set_label('Cbar Label Here')
thelinewidths=0
sets the width of the border on the shapes, I find that for small shapes the black border can overwhelm the color of the fill.
If you only need one shape you can do this all with a single scatter plot, there is no need to make a separate one for each pass through your loop.
from pylab import *
fig = gcf()
ax = fig.gca()
# make some temorary arrays
X =
Y =
C =
# generate fake data
for record in range(5):
x = rand(50)
y = rand(50)
c = rand(1)[0] * np.ones(x.shape)
print c
X.append(x)
Y.append(y)
C.append(c)
X = np.hstack(X)
Y = np.hstack(Y)
C = np.hstack(C)
once you have the data all beaten down into a 1D array, make the scatter plot, and keep the returned value:
s = ax.scatter(X,Y,c=C)
You then make your color bar and pass the object returned by scatter
as the first argument.
cb = plt.colorbar(s)
cb.set_label('Cbar Label Here')
You need do this so that the color bar knows which color map (both the map and the range) to use.
the code I posted is everything I did except for afig.savefig()
– tacaswell
Dec 20 '12 at 15:27
one question ... what is the point of having in both conditions (if .... else
block) the lines = x.scatter(x,y,c=c,marker=markers[record],linewidths=0)
?
– gluuke
Sep 21 at 17:03
add a comment |
up vote
8
down vote
up vote
8
down vote
If you have to use a different marker for each set, you have to do a bit of extra work and force all of the clims
to be the same (otherwise they default to scaling from the min/max of the c
data per scatter plot).
from pylab import *
import matplotlib.lines as mlines
import itertools
fig = gcf()
ax = fig.gca()
# make some temorary arrays
X =
Y =
C =
cb = None
# generate fake data
markers = ['','o','*','^','v']
cmin = 0
cmax = 1
for record,marker in itertools.izip(range(5),itertools.cycle(mlines.Line2D.filled_markers)):
x = rand(50)
y = rand(50)
c = rand(1)[0] * np.ones(x.shape)
if cb is None:
s = ax.scatter(x,y,c=c,marker=markers[record],linewidths=0)
s.set_clim([cmin,cmax])
cb = fig.colorbar(s)
else:
s = ax.scatter(x,y,c=c,marker=markers[record],linewidths=0)
s.set_clim([cmin,cmax])
cb.set_label('Cbar Label Here')
thelinewidths=0
sets the width of the border on the shapes, I find that for small shapes the black border can overwhelm the color of the fill.
If you only need one shape you can do this all with a single scatter plot, there is no need to make a separate one for each pass through your loop.
from pylab import *
fig = gcf()
ax = fig.gca()
# make some temorary arrays
X =
Y =
C =
# generate fake data
for record in range(5):
x = rand(50)
y = rand(50)
c = rand(1)[0] * np.ones(x.shape)
print c
X.append(x)
Y.append(y)
C.append(c)
X = np.hstack(X)
Y = np.hstack(Y)
C = np.hstack(C)
once you have the data all beaten down into a 1D array, make the scatter plot, and keep the returned value:
s = ax.scatter(X,Y,c=C)
You then make your color bar and pass the object returned by scatter
as the first argument.
cb = plt.colorbar(s)
cb.set_label('Cbar Label Here')
You need do this so that the color bar knows which color map (both the map and the range) to use.
If you have to use a different marker for each set, you have to do a bit of extra work and force all of the clims
to be the same (otherwise they default to scaling from the min/max of the c
data per scatter plot).
from pylab import *
import matplotlib.lines as mlines
import itertools
fig = gcf()
ax = fig.gca()
# make some temorary arrays
X =
Y =
C =
cb = None
# generate fake data
markers = ['','o','*','^','v']
cmin = 0
cmax = 1
for record,marker in itertools.izip(range(5),itertools.cycle(mlines.Line2D.filled_markers)):
x = rand(50)
y = rand(50)
c = rand(1)[0] * np.ones(x.shape)
if cb is None:
s = ax.scatter(x,y,c=c,marker=markers[record],linewidths=0)
s.set_clim([cmin,cmax])
cb = fig.colorbar(s)
else:
s = ax.scatter(x,y,c=c,marker=markers[record],linewidths=0)
s.set_clim([cmin,cmax])
cb.set_label('Cbar Label Here')
thelinewidths=0
sets the width of the border on the shapes, I find that for small shapes the black border can overwhelm the color of the fill.
If you only need one shape you can do this all with a single scatter plot, there is no need to make a separate one for each pass through your loop.
from pylab import *
fig = gcf()
ax = fig.gca()
# make some temorary arrays
X =
Y =
C =
# generate fake data
for record in range(5):
x = rand(50)
y = rand(50)
c = rand(1)[0] * np.ones(x.shape)
print c
X.append(x)
Y.append(y)
C.append(c)
X = np.hstack(X)
Y = np.hstack(Y)
C = np.hstack(C)
once you have the data all beaten down into a 1D array, make the scatter plot, and keep the returned value:
s = ax.scatter(X,Y,c=C)
You then make your color bar and pass the object returned by scatter
as the first argument.
cb = plt.colorbar(s)
cb.set_label('Cbar Label Here')
You need do this so that the color bar knows which color map (both the map and the range) to use.
edited Dec 20 '12 at 16:43
answered Dec 19 '12 at 5:21
tacaswell
54.1k9138149
54.1k9138149
the code I posted is everything I did except for afig.savefig()
– tacaswell
Dec 20 '12 at 15:27
one question ... what is the point of having in both conditions (if .... else
block) the lines = x.scatter(x,y,c=c,marker=markers[record],linewidths=0)
?
– gluuke
Sep 21 at 17:03
add a comment |
the code I posted is everything I did except for afig.savefig()
– tacaswell
Dec 20 '12 at 15:27
one question ... what is the point of having in both conditions (if .... else
block) the lines = x.scatter(x,y,c=c,marker=markers[record],linewidths=0)
?
– gluuke
Sep 21 at 17:03
the code I posted is everything I did except for a
fig.savefig()
– tacaswell
Dec 20 '12 at 15:27
the code I posted is everything I did except for a
fig.savefig()
– tacaswell
Dec 20 '12 at 15:27
one question ... what is the point of having in both conditions (
if .... else
block) the line s = x.scatter(x,y,c=c,marker=markers[record],linewidths=0)
?– gluuke
Sep 21 at 17:03
one question ... what is the point of having in both conditions (
if .... else
block) the line s = x.scatter(x,y,c=c,marker=markers[record],linewidths=0)
?– gluuke
Sep 21 at 17:03
add a comment |
up vote
5
down vote
I think your best bet will be to stuff your data into a pandas dataframe, and loop through all of your markers like so:
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
markers = ['s', 'o', '^']
records =
for n in range(37):
records.append([np.random.normal(), np.random.normal(), np.random.normal(),
markers[np.random.randint(0, high=3)]])
records = pd.DataFrame(records, columns=['x', 'y', 'z', 'marker'])
fig, ax = plt.subplots()
for m in np.unique(records.marker):
selector = records.marker == m
s = ax.scatter(records[selector].x, records[selector].y, c=records[selector].z,
marker=m, cmap=plt.cm.coolwarm,
vmin=records.z.min(), vmax=records.z.max())
cbar = plt.colorbar(mappable=s, ax=ax)
cbar.set_label('My Label')
add a comment |
up vote
5
down vote
I think your best bet will be to stuff your data into a pandas dataframe, and loop through all of your markers like so:
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
markers = ['s', 'o', '^']
records =
for n in range(37):
records.append([np.random.normal(), np.random.normal(), np.random.normal(),
markers[np.random.randint(0, high=3)]])
records = pd.DataFrame(records, columns=['x', 'y', 'z', 'marker'])
fig, ax = plt.subplots()
for m in np.unique(records.marker):
selector = records.marker == m
s = ax.scatter(records[selector].x, records[selector].y, c=records[selector].z,
marker=m, cmap=plt.cm.coolwarm,
vmin=records.z.min(), vmax=records.z.max())
cbar = plt.colorbar(mappable=s, ax=ax)
cbar.set_label('My Label')
add a comment |
up vote
5
down vote
up vote
5
down vote
I think your best bet will be to stuff your data into a pandas dataframe, and loop through all of your markers like so:
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
markers = ['s', 'o', '^']
records =
for n in range(37):
records.append([np.random.normal(), np.random.normal(), np.random.normal(),
markers[np.random.randint(0, high=3)]])
records = pd.DataFrame(records, columns=['x', 'y', 'z', 'marker'])
fig, ax = plt.subplots()
for m in np.unique(records.marker):
selector = records.marker == m
s = ax.scatter(records[selector].x, records[selector].y, c=records[selector].z,
marker=m, cmap=plt.cm.coolwarm,
vmin=records.z.min(), vmax=records.z.max())
cbar = plt.colorbar(mappable=s, ax=ax)
cbar.set_label('My Label')
I think your best bet will be to stuff your data into a pandas dataframe, and loop through all of your markers like so:
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
markers = ['s', 'o', '^']
records =
for n in range(37):
records.append([np.random.normal(), np.random.normal(), np.random.normal(),
markers[np.random.randint(0, high=3)]])
records = pd.DataFrame(records, columns=['x', 'y', 'z', 'marker'])
fig, ax = plt.subplots()
for m in np.unique(records.marker):
selector = records.marker == m
s = ax.scatter(records[selector].x, records[selector].y, c=records[selector].z,
marker=m, cmap=plt.cm.coolwarm,
vmin=records.z.min(), vmax=records.z.max())
cbar = plt.colorbar(mappable=s, ax=ax)
cbar.set_label('My Label')
answered Dec 21 '12 at 1:59
Paul H
30k8100106
30k8100106
add a comment |
add a comment |
up vote
1
down vote
I think this should do the trick. I'm pretty sure I grabbed this from one of the matplotlib cookbook examples a while back, but I can't seem to find it now...
from mpl_toolkits.axes_grid1 import make_axes_locatable
cmap = (matplotlib.color.LinearSegmentedColormap.
from_list('blueWhiteRed', ['blue', 'white', 'red']))
fig = matplotlib.figure.Figure(figsize=(4, 4), dpi=72)
ax = fig.gca()
for record in data:
level = record.level # a float in [0.0, 1.0]
ax.scatter(record.x, record.y,
c=level, vmin=0, vmax=1, cmap=cmap, **otherkwargs)
# various settings of ticks, labels, etc. omitted
divider= make_axes_locatable(ax)
cax = divider.append_axes("right", size="1%", pad=0.05)
cb = plt.colorbar(cax=cax)
cb.set_label('Cbar Label Here')
canvas = matplotlib.backends.backend_agg.FigureCanvasAgg(fig)
fig.set_canvas(canvas)
canvas.print_png('/path/to/output/fig.png')
did you test this?
– tacaswell
Dec 19 '12 at 5:22
@JoshaInglis: the linecb = plt.colorbar(cax=cax)
fails, with the errorRuntimeError: No mappable was found to use for colorbar creation. First define a mappable such as an image (with imshow) or a contour set (with contourf).
It may be very simple to fix this problem, but as I explained in an addition to my post, I am a complete Matplotlib dunce...
– kjo
Dec 20 '12 at 14:13
add a comment |
up vote
1
down vote
I think this should do the trick. I'm pretty sure I grabbed this from one of the matplotlib cookbook examples a while back, but I can't seem to find it now...
from mpl_toolkits.axes_grid1 import make_axes_locatable
cmap = (matplotlib.color.LinearSegmentedColormap.
from_list('blueWhiteRed', ['blue', 'white', 'red']))
fig = matplotlib.figure.Figure(figsize=(4, 4), dpi=72)
ax = fig.gca()
for record in data:
level = record.level # a float in [0.0, 1.0]
ax.scatter(record.x, record.y,
c=level, vmin=0, vmax=1, cmap=cmap, **otherkwargs)
# various settings of ticks, labels, etc. omitted
divider= make_axes_locatable(ax)
cax = divider.append_axes("right", size="1%", pad=0.05)
cb = plt.colorbar(cax=cax)
cb.set_label('Cbar Label Here')
canvas = matplotlib.backends.backend_agg.FigureCanvasAgg(fig)
fig.set_canvas(canvas)
canvas.print_png('/path/to/output/fig.png')
did you test this?
– tacaswell
Dec 19 '12 at 5:22
@JoshaInglis: the linecb = plt.colorbar(cax=cax)
fails, with the errorRuntimeError: No mappable was found to use for colorbar creation. First define a mappable such as an image (with imshow) or a contour set (with contourf).
It may be very simple to fix this problem, but as I explained in an addition to my post, I am a complete Matplotlib dunce...
– kjo
Dec 20 '12 at 14:13
add a comment |
up vote
1
down vote
up vote
1
down vote
I think this should do the trick. I'm pretty sure I grabbed this from one of the matplotlib cookbook examples a while back, but I can't seem to find it now...
from mpl_toolkits.axes_grid1 import make_axes_locatable
cmap = (matplotlib.color.LinearSegmentedColormap.
from_list('blueWhiteRed', ['blue', 'white', 'red']))
fig = matplotlib.figure.Figure(figsize=(4, 4), dpi=72)
ax = fig.gca()
for record in data:
level = record.level # a float in [0.0, 1.0]
ax.scatter(record.x, record.y,
c=level, vmin=0, vmax=1, cmap=cmap, **otherkwargs)
# various settings of ticks, labels, etc. omitted
divider= make_axes_locatable(ax)
cax = divider.append_axes("right", size="1%", pad=0.05)
cb = plt.colorbar(cax=cax)
cb.set_label('Cbar Label Here')
canvas = matplotlib.backends.backend_agg.FigureCanvasAgg(fig)
fig.set_canvas(canvas)
canvas.print_png('/path/to/output/fig.png')
I think this should do the trick. I'm pretty sure I grabbed this from one of the matplotlib cookbook examples a while back, but I can't seem to find it now...
from mpl_toolkits.axes_grid1 import make_axes_locatable
cmap = (matplotlib.color.LinearSegmentedColormap.
from_list('blueWhiteRed', ['blue', 'white', 'red']))
fig = matplotlib.figure.Figure(figsize=(4, 4), dpi=72)
ax = fig.gca()
for record in data:
level = record.level # a float in [0.0, 1.0]
ax.scatter(record.x, record.y,
c=level, vmin=0, vmax=1, cmap=cmap, **otherkwargs)
# various settings of ticks, labels, etc. omitted
divider= make_axes_locatable(ax)
cax = divider.append_axes("right", size="1%", pad=0.05)
cb = plt.colorbar(cax=cax)
cb.set_label('Cbar Label Here')
canvas = matplotlib.backends.backend_agg.FigureCanvasAgg(fig)
fig.set_canvas(canvas)
canvas.print_png('/path/to/output/fig.png')
answered Dec 19 '12 at 2:44
Josha Inglis
818817
818817
did you test this?
– tacaswell
Dec 19 '12 at 5:22
@JoshaInglis: the linecb = plt.colorbar(cax=cax)
fails, with the errorRuntimeError: No mappable was found to use for colorbar creation. First define a mappable such as an image (with imshow) or a contour set (with contourf).
It may be very simple to fix this problem, but as I explained in an addition to my post, I am a complete Matplotlib dunce...
– kjo
Dec 20 '12 at 14:13
add a comment |
did you test this?
– tacaswell
Dec 19 '12 at 5:22
@JoshaInglis: the linecb = plt.colorbar(cax=cax)
fails, with the errorRuntimeError: No mappable was found to use for colorbar creation. First define a mappable such as an image (with imshow) or a contour set (with contourf).
It may be very simple to fix this problem, but as I explained in an addition to my post, I am a complete Matplotlib dunce...
– kjo
Dec 20 '12 at 14:13
did you test this?
– tacaswell
Dec 19 '12 at 5:22
did you test this?
– tacaswell
Dec 19 '12 at 5:22
@JoshaInglis: the line
cb = plt.colorbar(cax=cax)
fails, with the error RuntimeError: No mappable was found to use for colorbar creation. First define a mappable such as an image (with imshow) or a contour set (with contourf).
It may be very simple to fix this problem, but as I explained in an addition to my post, I am a complete Matplotlib dunce...– kjo
Dec 20 '12 at 14:13
@JoshaInglis: the line
cb = plt.colorbar(cax=cax)
fails, with the error RuntimeError: No mappable was found to use for colorbar creation. First define a mappable such as an image (with imshow) or a contour set (with contourf).
It may be very simple to fix this problem, but as I explained in an addition to my post, I am a complete Matplotlib dunce...– kjo
Dec 20 '12 at 14:13
add a comment |
up vote
1
down vote
The answer to this can be to only plot a single scatter, which would then directly allow for a colobar to be created.
This involves putting the markers into the PathCollection
created by the scatter a posteriori, but it can be easily placed in a function. This function comes from my answer on another question, but is directly applicable here.
Taking the data from @PaulH's post this would look like
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
def mscatter(x,y,ax=None, m=None, **kw):
import matplotlib.markers as mmarkers
ax = ax or plt.gca()
sc = ax.scatter(x,y,**kw)
if (m is not None) and (len(m)==len(x)):
paths =
for marker in m:
if isinstance(marker, mmarkers.MarkerStyle):
marker_obj = marker
else:
marker_obj = mmarkers.MarkerStyle(marker)
path = marker_obj.get_path().transformed(
marker_obj.get_transform())
paths.append(path)
sc.set_paths(paths)
return sc
markers = ['s', 'o', '^']
records =
for n in range(37):
records.append([np.random.normal(), np.random.normal(), np.random.normal(),
markers[np.random.randint(0, high=3)]])
records = pd.DataFrame(records, columns=['x', 'y', 'z', 'marker'])
fig, ax = plt.subplots()
sc = mscatter(records.x, records.y, c=records.z, m=records.marker, ax=ax)
fig.colorbar(sc, ax=ax)
plt.show()
add a comment |
up vote
1
down vote
The answer to this can be to only plot a single scatter, which would then directly allow for a colobar to be created.
This involves putting the markers into the PathCollection
created by the scatter a posteriori, but it can be easily placed in a function. This function comes from my answer on another question, but is directly applicable here.
Taking the data from @PaulH's post this would look like
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
def mscatter(x,y,ax=None, m=None, **kw):
import matplotlib.markers as mmarkers
ax = ax or plt.gca()
sc = ax.scatter(x,y,**kw)
if (m is not None) and (len(m)==len(x)):
paths =
for marker in m:
if isinstance(marker, mmarkers.MarkerStyle):
marker_obj = marker
else:
marker_obj = mmarkers.MarkerStyle(marker)
path = marker_obj.get_path().transformed(
marker_obj.get_transform())
paths.append(path)
sc.set_paths(paths)
return sc
markers = ['s', 'o', '^']
records =
for n in range(37):
records.append([np.random.normal(), np.random.normal(), np.random.normal(),
markers[np.random.randint(0, high=3)]])
records = pd.DataFrame(records, columns=['x', 'y', 'z', 'marker'])
fig, ax = plt.subplots()
sc = mscatter(records.x, records.y, c=records.z, m=records.marker, ax=ax)
fig.colorbar(sc, ax=ax)
plt.show()
add a comment |
up vote
1
down vote
up vote
1
down vote
The answer to this can be to only plot a single scatter, which would then directly allow for a colobar to be created.
This involves putting the markers into the PathCollection
created by the scatter a posteriori, but it can be easily placed in a function. This function comes from my answer on another question, but is directly applicable here.
Taking the data from @PaulH's post this would look like
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
def mscatter(x,y,ax=None, m=None, **kw):
import matplotlib.markers as mmarkers
ax = ax or plt.gca()
sc = ax.scatter(x,y,**kw)
if (m is not None) and (len(m)==len(x)):
paths =
for marker in m:
if isinstance(marker, mmarkers.MarkerStyle):
marker_obj = marker
else:
marker_obj = mmarkers.MarkerStyle(marker)
path = marker_obj.get_path().transformed(
marker_obj.get_transform())
paths.append(path)
sc.set_paths(paths)
return sc
markers = ['s', 'o', '^']
records =
for n in range(37):
records.append([np.random.normal(), np.random.normal(), np.random.normal(),
markers[np.random.randint(0, high=3)]])
records = pd.DataFrame(records, columns=['x', 'y', 'z', 'marker'])
fig, ax = plt.subplots()
sc = mscatter(records.x, records.y, c=records.z, m=records.marker, ax=ax)
fig.colorbar(sc, ax=ax)
plt.show()
The answer to this can be to only plot a single scatter, which would then directly allow for a colobar to be created.
This involves putting the markers into the PathCollection
created by the scatter a posteriori, but it can be easily placed in a function. This function comes from my answer on another question, but is directly applicable here.
Taking the data from @PaulH's post this would look like
import numpy as np
import pandas as pd
import matplotlib.pyplot as plt
def mscatter(x,y,ax=None, m=None, **kw):
import matplotlib.markers as mmarkers
ax = ax or plt.gca()
sc = ax.scatter(x,y,**kw)
if (m is not None) and (len(m)==len(x)):
paths =
for marker in m:
if isinstance(marker, mmarkers.MarkerStyle):
marker_obj = marker
else:
marker_obj = mmarkers.MarkerStyle(marker)
path = marker_obj.get_path().transformed(
marker_obj.get_transform())
paths.append(path)
sc.set_paths(paths)
return sc
markers = ['s', 'o', '^']
records =
for n in range(37):
records.append([np.random.normal(), np.random.normal(), np.random.normal(),
markers[np.random.randint(0, high=3)]])
records = pd.DataFrame(records, columns=['x', 'y', 'z', 'marker'])
fig, ax = plt.subplots()
sc = mscatter(records.x, records.y, c=records.z, m=records.marker, ax=ax)
fig.colorbar(sc, ax=ax)
plt.show()
answered Nov 9 at 14:57
ImportanceOfBeingErnest
123k10127203
123k10127203
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see edit and other comment.
– tacaswell
Dec 20 '12 at 16:53
i don't think there's a requirement for multiple marker shapes in
scatter
. just feed it a single marker for each group of data.– Paul H
Dec 20 '12 at 23:38
the requirement is mine: I require multiple marker shapes in the scatterplots I'm making.
– kjo
Dec 21 '12 at 1:26
@kjo see my response below
– Paul H
Dec 21 '12 at 2:00
@kjo Sorry I was rude the other day, I was in a bad mood and your rant set me off. Did you get this sorted out?
– tacaswell
Dec 22 '12 at 23:55