How can I do to extract some information with SQL Server ?
I have this column with Microsoft SQL Server :
Date
6/19/2019 3:10:12 PM
12/23/2016 5:02:15 AM
13/25/2015 2:15:35 PM
And I would like to get two new column like this :
Date Hour
06/19/2019 15:10:12
12/23/2016 05:02:15
13/25/2015 14:15:35
For the first column I just split the original column and I add a 0 for the first line and for the second I add a 0 and transform 03 to 15 removing PM. Thank you very much for the help !
sql sql-server database
add a comment |
I have this column with Microsoft SQL Server :
Date
6/19/2019 3:10:12 PM
12/23/2016 5:02:15 AM
13/25/2015 2:15:35 PM
And I would like to get two new column like this :
Date Hour
06/19/2019 15:10:12
12/23/2016 05:02:15
13/25/2015 14:15:35
For the first column I just split the original column and I add a 0 for the first line and for the second I add a 0 and transform 03 to 15 removing PM. Thank you very much for the help !
sql sql-server database
any comments on the answers below?
– scsimon
Dec 6 at 20:02
add a comment |
I have this column with Microsoft SQL Server :
Date
6/19/2019 3:10:12 PM
12/23/2016 5:02:15 AM
13/25/2015 2:15:35 PM
And I would like to get two new column like this :
Date Hour
06/19/2019 15:10:12
12/23/2016 05:02:15
13/25/2015 14:15:35
For the first column I just split the original column and I add a 0 for the first line and for the second I add a 0 and transform 03 to 15 removing PM. Thank you very much for the help !
sql sql-server database
I have this column with Microsoft SQL Server :
Date
6/19/2019 3:10:12 PM
12/23/2016 5:02:15 AM
13/25/2015 2:15:35 PM
And I would like to get two new column like this :
Date Hour
06/19/2019 15:10:12
12/23/2016 05:02:15
13/25/2015 14:15:35
For the first column I just split the original column and I add a 0 for the first line and for the second I add a 0 and transform 03 to 15 removing PM. Thank you very much for the help !
sql sql-server database
sql sql-server database
asked Nov 9 at 22:01
Peter H
81
81
any comments on the answers below?
– scsimon
Dec 6 at 20:02
add a comment |
any comments on the answers below?
– scsimon
Dec 6 at 20:02
any comments on the answers below?
– scsimon
Dec 6 at 20:02
any comments on the answers below?
– scsimon
Dec 6 at 20:02
add a comment |
2 Answers
2
active
oldest
votes
If I understand correctly, you would just cast to the types you want:
select cast(datetimecol as date) as datecol,
cast(datetimecol as time) as timecol
from t;
add a comment |
You can use try_parse
as another option if it is a varchar
column.
select try_parse('6/19/2019 3:10:12 PM' as date using 'en-US')
select try_parse('6/19/2019 3:10:12 PM' as time using 'en-US')
Or for your query
select
try_parse('datetimecol' as date using 'en-US'),
try_parse('datetimecol' as time using 'en-US')
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If I understand correctly, you would just cast to the types you want:
select cast(datetimecol as date) as datecol,
cast(datetimecol as time) as timecol
from t;
add a comment |
If I understand correctly, you would just cast to the types you want:
select cast(datetimecol as date) as datecol,
cast(datetimecol as time) as timecol
from t;
add a comment |
If I understand correctly, you would just cast to the types you want:
select cast(datetimecol as date) as datecol,
cast(datetimecol as time) as timecol
from t;
If I understand correctly, you would just cast to the types you want:
select cast(datetimecol as date) as datecol,
cast(datetimecol as time) as timecol
from t;
answered Nov 9 at 22:02
Gordon Linoff
755k35290398
755k35290398
add a comment |
add a comment |
You can use try_parse
as another option if it is a varchar
column.
select try_parse('6/19/2019 3:10:12 PM' as date using 'en-US')
select try_parse('6/19/2019 3:10:12 PM' as time using 'en-US')
Or for your query
select
try_parse('datetimecol' as date using 'en-US'),
try_parse('datetimecol' as time using 'en-US')
add a comment |
You can use try_parse
as another option if it is a varchar
column.
select try_parse('6/19/2019 3:10:12 PM' as date using 'en-US')
select try_parse('6/19/2019 3:10:12 PM' as time using 'en-US')
Or for your query
select
try_parse('datetimecol' as date using 'en-US'),
try_parse('datetimecol' as time using 'en-US')
add a comment |
You can use try_parse
as another option if it is a varchar
column.
select try_parse('6/19/2019 3:10:12 PM' as date using 'en-US')
select try_parse('6/19/2019 3:10:12 PM' as time using 'en-US')
Or for your query
select
try_parse('datetimecol' as date using 'en-US'),
try_parse('datetimecol' as time using 'en-US')
You can use try_parse
as another option if it is a varchar
column.
select try_parse('6/19/2019 3:10:12 PM' as date using 'en-US')
select try_parse('6/19/2019 3:10:12 PM' as time using 'en-US')
Or for your query
select
try_parse('datetimecol' as date using 'en-US'),
try_parse('datetimecol' as time using 'en-US')
answered Nov 9 at 22:03
scsimon
20.5k41536
20.5k41536
add a comment |
add a comment |
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any comments on the answers below?
– scsimon
Dec 6 at 20:02