Connecting selection of row in 2 QTableWidget
up vote
1
down vote
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I am trying to connect row selections from two QTableWidget.
I mean, when I select one row in Table 1, I want my program selects the same row in table 2. The two table dont have the same number of column so I cannot just select one item for the first and select the same item on the second able.
I have tried to use the following without success:
connect(ui->table1->selectionModel(), SIGNAL(currentRowChanged(QModelIndex, QModelIndex)), ui->table2->selectionModel(), SLOT(setCurrentIndex(QModelIndex)));
It is written:
QObject::connect: No such slot QItemSelectionModel::setCurrentIndex(QModelIndex)
Do you know what is going wrong?
c++ qt qt5 selection qtablewidget
add a comment |
up vote
1
down vote
favorite
I am trying to connect row selections from two QTableWidget.
I mean, when I select one row in Table 1, I want my program selects the same row in table 2. The two table dont have the same number of column so I cannot just select one item for the first and select the same item on the second able.
I have tried to use the following without success:
connect(ui->table1->selectionModel(), SIGNAL(currentRowChanged(QModelIndex, QModelIndex)), ui->table2->selectionModel(), SLOT(setCurrentIndex(QModelIndex)));
It is written:
QObject::connect: No such slot QItemSelectionModel::setCurrentIndex(QModelIndex)
Do you know what is going wrong?
c++ qt qt5 selection qtablewidget
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I am trying to connect row selections from two QTableWidget.
I mean, when I select one row in Table 1, I want my program selects the same row in table 2. The two table dont have the same number of column so I cannot just select one item for the first and select the same item on the second able.
I have tried to use the following without success:
connect(ui->table1->selectionModel(), SIGNAL(currentRowChanged(QModelIndex, QModelIndex)), ui->table2->selectionModel(), SLOT(setCurrentIndex(QModelIndex)));
It is written:
QObject::connect: No such slot QItemSelectionModel::setCurrentIndex(QModelIndex)
Do you know what is going wrong?
c++ qt qt5 selection qtablewidget
I am trying to connect row selections from two QTableWidget.
I mean, when I select one row in Table 1, I want my program selects the same row in table 2. The two table dont have the same number of column so I cannot just select one item for the first and select the same item on the second able.
I have tried to use the following without success:
connect(ui->table1->selectionModel(), SIGNAL(currentRowChanged(QModelIndex, QModelIndex)), ui->table2->selectionModel(), SLOT(setCurrentIndex(QModelIndex)));
It is written:
QObject::connect: No such slot QItemSelectionModel::setCurrentIndex(QModelIndex)
Do you know what is going wrong?
c++ qt qt5 selection qtablewidget
c++ qt qt5 selection qtablewidget
edited Nov 9 at 19:23
eyllanesc
72.2k93054
72.2k93054
asked Nov 9 at 18:19
froz
215
215
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add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
The problem is caused because setCurrentIndex()
has two parameters, and not just one, plus the signatures do not match. So in these cases you should use a lambda and use selectRow()
:
#include <QApplication>
#include <QHBoxLayout>
#include <QTableWidget>
#include <QItemSelectionModel>
int main(int argc, char *argv)
QApplication a(argc, argv);
auto *table1 = new QTableWidget(4, 3);
table1->setSelectionBehavior(QAbstractItemView::SelectRows);
auto table2 = new QTableWidget(4, 4);
table2->setSelectionBehavior(QAbstractItemView::SelectRows);
QObject::connect(table1->selectionModel(), &QItemSelectionModel::currentRowChanged,
[table2](const QModelIndex ¤t, const QModelIndex & previous)
if(previous.isValid())
table2->selectRow(current.row());
);
QWidget w;
auto lay = new QHBoxLayout(&w);
lay->addWidget(table1);
lay->addWidget(table2);
w.show();
return a.exec();
Dear eyllanesc, Thank you for your answer. I tried to adapt your code to mine without success. I get compil error:expected ',' or ']' in lambda capture list. I did the following:
– froz
Nov 9 at 19:03
QObject::connect(ui->table1->selectionModel(), &QItemSelectionModel::currentRowChanged, [ui->table2](const QModelIndex ¤t, const QModelIndex & previous) if(previous.isValid()) QItemSelectionModel::SelectionFlags command = QItemSelectionModel::Rows );
– froz
Nov 9 at 19:03
@froz Do you have any error or warning message?
– eyllanesc
Nov 9 at 19:05
@froz change[ui->table2]
to[this]
– eyllanesc
Nov 9 at 19:06
Thanks, It is working :) However, one last thing, I have in the terminal sometimes the following:qt.accessibility.core: Cannot create accessible child interface for object: QTableWidget(0x5593ad844f30, name = "table2") index: 23
– froz
Nov 9 at 19:12
|
show 4 more comments
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
The problem is caused because setCurrentIndex()
has two parameters, and not just one, plus the signatures do not match. So in these cases you should use a lambda and use selectRow()
:
#include <QApplication>
#include <QHBoxLayout>
#include <QTableWidget>
#include <QItemSelectionModel>
int main(int argc, char *argv)
QApplication a(argc, argv);
auto *table1 = new QTableWidget(4, 3);
table1->setSelectionBehavior(QAbstractItemView::SelectRows);
auto table2 = new QTableWidget(4, 4);
table2->setSelectionBehavior(QAbstractItemView::SelectRows);
QObject::connect(table1->selectionModel(), &QItemSelectionModel::currentRowChanged,
[table2](const QModelIndex ¤t, const QModelIndex & previous)
if(previous.isValid())
table2->selectRow(current.row());
);
QWidget w;
auto lay = new QHBoxLayout(&w);
lay->addWidget(table1);
lay->addWidget(table2);
w.show();
return a.exec();
Dear eyllanesc, Thank you for your answer. I tried to adapt your code to mine without success. I get compil error:expected ',' or ']' in lambda capture list. I did the following:
– froz
Nov 9 at 19:03
QObject::connect(ui->table1->selectionModel(), &QItemSelectionModel::currentRowChanged, [ui->table2](const QModelIndex ¤t, const QModelIndex & previous) if(previous.isValid()) QItemSelectionModel::SelectionFlags command = QItemSelectionModel::Rows );
– froz
Nov 9 at 19:03
@froz Do you have any error or warning message?
– eyllanesc
Nov 9 at 19:05
@froz change[ui->table2]
to[this]
– eyllanesc
Nov 9 at 19:06
Thanks, It is working :) However, one last thing, I have in the terminal sometimes the following:qt.accessibility.core: Cannot create accessible child interface for object: QTableWidget(0x5593ad844f30, name = "table2") index: 23
– froz
Nov 9 at 19:12
|
show 4 more comments
up vote
1
down vote
accepted
The problem is caused because setCurrentIndex()
has two parameters, and not just one, plus the signatures do not match. So in these cases you should use a lambda and use selectRow()
:
#include <QApplication>
#include <QHBoxLayout>
#include <QTableWidget>
#include <QItemSelectionModel>
int main(int argc, char *argv)
QApplication a(argc, argv);
auto *table1 = new QTableWidget(4, 3);
table1->setSelectionBehavior(QAbstractItemView::SelectRows);
auto table2 = new QTableWidget(4, 4);
table2->setSelectionBehavior(QAbstractItemView::SelectRows);
QObject::connect(table1->selectionModel(), &QItemSelectionModel::currentRowChanged,
[table2](const QModelIndex ¤t, const QModelIndex & previous)
if(previous.isValid())
table2->selectRow(current.row());
);
QWidget w;
auto lay = new QHBoxLayout(&w);
lay->addWidget(table1);
lay->addWidget(table2);
w.show();
return a.exec();
Dear eyllanesc, Thank you for your answer. I tried to adapt your code to mine without success. I get compil error:expected ',' or ']' in lambda capture list. I did the following:
– froz
Nov 9 at 19:03
QObject::connect(ui->table1->selectionModel(), &QItemSelectionModel::currentRowChanged, [ui->table2](const QModelIndex ¤t, const QModelIndex & previous) if(previous.isValid()) QItemSelectionModel::SelectionFlags command = QItemSelectionModel::Rows );
– froz
Nov 9 at 19:03
@froz Do you have any error or warning message?
– eyllanesc
Nov 9 at 19:05
@froz change[ui->table2]
to[this]
– eyllanesc
Nov 9 at 19:06
Thanks, It is working :) However, one last thing, I have in the terminal sometimes the following:qt.accessibility.core: Cannot create accessible child interface for object: QTableWidget(0x5593ad844f30, name = "table2") index: 23
– froz
Nov 9 at 19:12
|
show 4 more comments
up vote
1
down vote
accepted
up vote
1
down vote
accepted
The problem is caused because setCurrentIndex()
has two parameters, and not just one, plus the signatures do not match. So in these cases you should use a lambda and use selectRow()
:
#include <QApplication>
#include <QHBoxLayout>
#include <QTableWidget>
#include <QItemSelectionModel>
int main(int argc, char *argv)
QApplication a(argc, argv);
auto *table1 = new QTableWidget(4, 3);
table1->setSelectionBehavior(QAbstractItemView::SelectRows);
auto table2 = new QTableWidget(4, 4);
table2->setSelectionBehavior(QAbstractItemView::SelectRows);
QObject::connect(table1->selectionModel(), &QItemSelectionModel::currentRowChanged,
[table2](const QModelIndex ¤t, const QModelIndex & previous)
if(previous.isValid())
table2->selectRow(current.row());
);
QWidget w;
auto lay = new QHBoxLayout(&w);
lay->addWidget(table1);
lay->addWidget(table2);
w.show();
return a.exec();
The problem is caused because setCurrentIndex()
has two parameters, and not just one, plus the signatures do not match. So in these cases you should use a lambda and use selectRow()
:
#include <QApplication>
#include <QHBoxLayout>
#include <QTableWidget>
#include <QItemSelectionModel>
int main(int argc, char *argv)
QApplication a(argc, argv);
auto *table1 = new QTableWidget(4, 3);
table1->setSelectionBehavior(QAbstractItemView::SelectRows);
auto table2 = new QTableWidget(4, 4);
table2->setSelectionBehavior(QAbstractItemView::SelectRows);
QObject::connect(table1->selectionModel(), &QItemSelectionModel::currentRowChanged,
[table2](const QModelIndex ¤t, const QModelIndex & previous)
if(previous.isValid())
table2->selectRow(current.row());
);
QWidget w;
auto lay = new QHBoxLayout(&w);
lay->addWidget(table1);
lay->addWidget(table2);
w.show();
return a.exec();
edited Nov 9 at 19:06
answered Nov 9 at 18:42
eyllanesc
72.2k93054
72.2k93054
Dear eyllanesc, Thank you for your answer. I tried to adapt your code to mine without success. I get compil error:expected ',' or ']' in lambda capture list. I did the following:
– froz
Nov 9 at 19:03
QObject::connect(ui->table1->selectionModel(), &QItemSelectionModel::currentRowChanged, [ui->table2](const QModelIndex ¤t, const QModelIndex & previous) if(previous.isValid()) QItemSelectionModel::SelectionFlags command = QItemSelectionModel::Rows );
– froz
Nov 9 at 19:03
@froz Do you have any error or warning message?
– eyllanesc
Nov 9 at 19:05
@froz change[ui->table2]
to[this]
– eyllanesc
Nov 9 at 19:06
Thanks, It is working :) However, one last thing, I have in the terminal sometimes the following:qt.accessibility.core: Cannot create accessible child interface for object: QTableWidget(0x5593ad844f30, name = "table2") index: 23
– froz
Nov 9 at 19:12
|
show 4 more comments
Dear eyllanesc, Thank you for your answer. I tried to adapt your code to mine without success. I get compil error:expected ',' or ']' in lambda capture list. I did the following:
– froz
Nov 9 at 19:03
QObject::connect(ui->table1->selectionModel(), &QItemSelectionModel::currentRowChanged, [ui->table2](const QModelIndex ¤t, const QModelIndex & previous) if(previous.isValid()) QItemSelectionModel::SelectionFlags command = QItemSelectionModel::Rows );
– froz
Nov 9 at 19:03
@froz Do you have any error or warning message?
– eyllanesc
Nov 9 at 19:05
@froz change[ui->table2]
to[this]
– eyllanesc
Nov 9 at 19:06
Thanks, It is working :) However, one last thing, I have in the terminal sometimes the following:qt.accessibility.core: Cannot create accessible child interface for object: QTableWidget(0x5593ad844f30, name = "table2") index: 23
– froz
Nov 9 at 19:12
Dear eyllanesc, Thank you for your answer. I tried to adapt your code to mine without success. I get compil error:expected ',' or ']' in lambda capture list. I did the following:
– froz
Nov 9 at 19:03
Dear eyllanesc, Thank you for your answer. I tried to adapt your code to mine without success. I get compil error:expected ',' or ']' in lambda capture list. I did the following:
– froz
Nov 9 at 19:03
QObject::connect(ui->table1->selectionModel(), &QItemSelectionModel::currentRowChanged, [ui->table2](const QModelIndex ¤t, const QModelIndex & previous) if(previous.isValid()) QItemSelectionModel::SelectionFlags command = QItemSelectionModel::Rows );
– froz
Nov 9 at 19:03
QObject::connect(ui->table1->selectionModel(), &QItemSelectionModel::currentRowChanged, [ui->table2](const QModelIndex ¤t, const QModelIndex & previous) if(previous.isValid()) QItemSelectionModel::SelectionFlags command = QItemSelectionModel::Rows );
– froz
Nov 9 at 19:03
@froz Do you have any error or warning message?
– eyllanesc
Nov 9 at 19:05
@froz Do you have any error or warning message?
– eyllanesc
Nov 9 at 19:05
@froz change
[ui->table2]
to [this]
– eyllanesc
Nov 9 at 19:06
@froz change
[ui->table2]
to [this]
– eyllanesc
Nov 9 at 19:06
Thanks, It is working :) However, one last thing, I have in the terminal sometimes the following:
qt.accessibility.core: Cannot create accessible child interface for object: QTableWidget(0x5593ad844f30, name = "table2") index: 23
– froz
Nov 9 at 19:12
Thanks, It is working :) However, one last thing, I have in the terminal sometimes the following:
qt.accessibility.core: Cannot create accessible child interface for object: QTableWidget(0x5593ad844f30, name = "table2") index: 23
– froz
Nov 9 at 19:12
|
show 4 more comments
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