Compiling dict of users in Python for search results
I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:
user = db.execute(
'SELECT * FROM user WHERE email = ?', (emailInput,)
).fetchone()
if user is None:
user_details =
'first' : 'error'
y = json.dumps(user_details)
return jsonify(y)
if user['first'] is None:
first = ""
else:
first = user['first']
if user['email'] is None:
email = ""
else:
email = user['email']
if user['last'] is None:
last = ""
else:
last = user['last']
if user['address_line1'] is None:
address_line1 = ""
else:
address_line1 = user['address_line1']
if user['address_line2'] is None:
address_line2 = ""
else:
address_line2 = user['address_line2']
if user['username'] is None:
username = ""
else:
username = user['username']
user_details =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
y = json.dumps(user_details)
return jsonify(y)
Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.
EDIT:
what I really need help with is turning multiple structs like these:
user_details =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
into one big struct like this:
users =
user_details1 =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
user_details2 =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
etc.
python sql json
add a comment |
I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:
user = db.execute(
'SELECT * FROM user WHERE email = ?', (emailInput,)
).fetchone()
if user is None:
user_details =
'first' : 'error'
y = json.dumps(user_details)
return jsonify(y)
if user['first'] is None:
first = ""
else:
first = user['first']
if user['email'] is None:
email = ""
else:
email = user['email']
if user['last'] is None:
last = ""
else:
last = user['last']
if user['address_line1'] is None:
address_line1 = ""
else:
address_line1 = user['address_line1']
if user['address_line2'] is None:
address_line2 = ""
else:
address_line2 = user['address_line2']
if user['username'] is None:
username = ""
else:
username = user['username']
user_details =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
y = json.dumps(user_details)
return jsonify(y)
Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.
EDIT:
what I really need help with is turning multiple structs like these:
user_details =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
into one big struct like this:
users =
user_details1 =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
user_details2 =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
etc.
python sql json
add a comment |
I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:
user = db.execute(
'SELECT * FROM user WHERE email = ?', (emailInput,)
).fetchone()
if user is None:
user_details =
'first' : 'error'
y = json.dumps(user_details)
return jsonify(y)
if user['first'] is None:
first = ""
else:
first = user['first']
if user['email'] is None:
email = ""
else:
email = user['email']
if user['last'] is None:
last = ""
else:
last = user['last']
if user['address_line1'] is None:
address_line1 = ""
else:
address_line1 = user['address_line1']
if user['address_line2'] is None:
address_line2 = ""
else:
address_line2 = user['address_line2']
if user['username'] is None:
username = ""
else:
username = user['username']
user_details =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
y = json.dumps(user_details)
return jsonify(y)
Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.
EDIT:
what I really need help with is turning multiple structs like these:
user_details =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
into one big struct like this:
users =
user_details1 =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
user_details2 =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
etc.
python sql json
I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:
user = db.execute(
'SELECT * FROM user WHERE email = ?', (emailInput,)
).fetchone()
if user is None:
user_details =
'first' : 'error'
y = json.dumps(user_details)
return jsonify(y)
if user['first'] is None:
first = ""
else:
first = user['first']
if user['email'] is None:
email = ""
else:
email = user['email']
if user['last'] is None:
last = ""
else:
last = user['last']
if user['address_line1'] is None:
address_line1 = ""
else:
address_line1 = user['address_line1']
if user['address_line2'] is None:
address_line2 = ""
else:
address_line2 = user['address_line2']
if user['username'] is None:
username = ""
else:
username = user['username']
user_details =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
y = json.dumps(user_details)
return jsonify(y)
Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.
EDIT:
what I really need help with is turning multiple structs like these:
user_details =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
into one big struct like this:
users =
user_details1 =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
user_details2 =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username
etc.
python sql json
python sql json
edited Nov 13 '18 at 0:23
Japhy
asked Nov 13 '18 at 0:01
JaphyJaphy
234
234
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)
add a comment |
fetchall
returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:
users = db.execute(
'SELECT * FROM user WHERE email = ?', (emailInput,)
).fetchall()
for user in users:
if user['first'] is None:
<etc>
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53271863%2fcompiling-dict-of-users-in-python-for-search-results%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)
add a comment |
Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)
add a comment |
Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)
Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)
answered Nov 13 '18 at 0:08
rikAteerikAtee
4,92053059
4,92053059
add a comment |
add a comment |
fetchall
returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:
users = db.execute(
'SELECT * FROM user WHERE email = ?', (emailInput,)
).fetchall()
for user in users:
if user['first'] is None:
<etc>
add a comment |
fetchall
returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:
users = db.execute(
'SELECT * FROM user WHERE email = ?', (emailInput,)
).fetchall()
for user in users:
if user['first'] is None:
<etc>
add a comment |
fetchall
returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:
users = db.execute(
'SELECT * FROM user WHERE email = ?', (emailInput,)
).fetchall()
for user in users:
if user['first'] is None:
<etc>
fetchall
returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:
users = db.execute(
'SELECT * FROM user WHERE email = ?', (emailInput,)
).fetchall()
for user in users:
if user['first'] is None:
<etc>
answered Nov 13 '18 at 0:12
rd_nielsenrd_nielsen
1,6102616
1,6102616
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53271863%2fcompiling-dict-of-users-in-python-for-search-results%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown