Compiling dict of users in Python for search results










0















I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:



 user = db.execute(
'SELECT * FROM user WHERE email = ?', (emailInput,)
).fetchone()
if user is None:
user_details =
'first' : 'error'

y = json.dumps(user_details)
return jsonify(y)
if user['first'] is None:
first = ""
else:
first = user['first']
if user['email'] is None:
email = ""
else:
email = user['email']
if user['last'] is None:
last = ""
else:
last = user['last']
if user['address_line1'] is None:
address_line1 = ""
else:
address_line1 = user['address_line1']
if user['address_line2'] is None:
address_line2 = ""
else:
address_line2 = user['address_line2']
if user['username'] is None:
username = ""
else:
username = user['username']
user_details =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username

y = json.dumps(user_details)
return jsonify(y)


Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.



EDIT:
what I really need help with is turning multiple structs like these:



 user_details = 
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username



into one big struct like this:



 users = 
user_details1 =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username

user_details2 =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username

etc.










share|improve this question




























    0















    I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:



     user = db.execute(
    'SELECT * FROM user WHERE email = ?', (emailInput,)
    ).fetchone()
    if user is None:
    user_details =
    'first' : 'error'

    y = json.dumps(user_details)
    return jsonify(y)
    if user['first'] is None:
    first = ""
    else:
    first = user['first']
    if user['email'] is None:
    email = ""
    else:
    email = user['email']
    if user['last'] is None:
    last = ""
    else:
    last = user['last']
    if user['address_line1'] is None:
    address_line1 = ""
    else:
    address_line1 = user['address_line1']
    if user['address_line2'] is None:
    address_line2 = ""
    else:
    address_line2 = user['address_line2']
    if user['username'] is None:
    username = ""
    else:
    username = user['username']
    user_details =
    'first': first,
    'last': last,
    'email': email,
    'address1': address_line1,
    'address2': address_line2,
    'username': username

    y = json.dumps(user_details)
    return jsonify(y)


    Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.



    EDIT:
    what I really need help with is turning multiple structs like these:



     user_details = 
    'first': first,
    'last': last,
    'email': email,
    'address1': address_line1,
    'address2': address_line2,
    'username': username



    into one big struct like this:



     users = 
    user_details1 =
    'first': first,
    'last': last,
    'email': email,
    'address1': address_line1,
    'address2': address_line2,
    'username': username

    user_details2 =
    'first': first,
    'last': last,
    'email': email,
    'address1': address_line1,
    'address2': address_line2,
    'username': username

    etc.










    share|improve this question


























      0












      0








      0








      I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:



       user = db.execute(
      'SELECT * FROM user WHERE email = ?', (emailInput,)
      ).fetchone()
      if user is None:
      user_details =
      'first' : 'error'

      y = json.dumps(user_details)
      return jsonify(y)
      if user['first'] is None:
      first = ""
      else:
      first = user['first']
      if user['email'] is None:
      email = ""
      else:
      email = user['email']
      if user['last'] is None:
      last = ""
      else:
      last = user['last']
      if user['address_line1'] is None:
      address_line1 = ""
      else:
      address_line1 = user['address_line1']
      if user['address_line2'] is None:
      address_line2 = ""
      else:
      address_line2 = user['address_line2']
      if user['username'] is None:
      username = ""
      else:
      username = user['username']
      user_details =
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username

      y = json.dumps(user_details)
      return jsonify(y)


      Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.



      EDIT:
      what I really need help with is turning multiple structs like these:



       user_details = 
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username



      into one big struct like this:



       users = 
      user_details1 =
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username

      user_details2 =
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username

      etc.










      share|improve this question
















      I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:



       user = db.execute(
      'SELECT * FROM user WHERE email = ?', (emailInput,)
      ).fetchone()
      if user is None:
      user_details =
      'first' : 'error'

      y = json.dumps(user_details)
      return jsonify(y)
      if user['first'] is None:
      first = ""
      else:
      first = user['first']
      if user['email'] is None:
      email = ""
      else:
      email = user['email']
      if user['last'] is None:
      last = ""
      else:
      last = user['last']
      if user['address_line1'] is None:
      address_line1 = ""
      else:
      address_line1 = user['address_line1']
      if user['address_line2'] is None:
      address_line2 = ""
      else:
      address_line2 = user['address_line2']
      if user['username'] is None:
      username = ""
      else:
      username = user['username']
      user_details =
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username

      y = json.dumps(user_details)
      return jsonify(y)


      Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.



      EDIT:
      what I really need help with is turning multiple structs like these:



       user_details = 
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username



      into one big struct like this:



       users = 
      user_details1 =
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username

      user_details2 =
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username

      etc.







      python sql json






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 13 '18 at 0:23







      Japhy

















      asked Nov 13 '18 at 0:01









      JaphyJaphy

      234




      234






















          2 Answers
          2






          active

          oldest

          votes


















          0














          Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)






          share|improve this answer






























            0














            fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



            users = db.execute(
            'SELECT * FROM user WHERE email = ?', (emailInput,)
            ).fetchall()
            for user in users:
            if user['first'] is None:
            <etc>





            share|improve this answer






















              Your Answer






              StackExchange.ifUsing("editor", function ()
              StackExchange.using("externalEditor", function ()
              StackExchange.using("snippets", function ()
              StackExchange.snippets.init();
              );
              );
              , "code-snippets");

              StackExchange.ready(function()
              var channelOptions =
              tags: "".split(" "),
              id: "1"
              ;
              initTagRenderer("".split(" "), "".split(" "), channelOptions);

              StackExchange.using("externalEditor", function()
              // Have to fire editor after snippets, if snippets enabled
              if (StackExchange.settings.snippets.snippetsEnabled)
              StackExchange.using("snippets", function()
              createEditor();
              );

              else
              createEditor();

              );

              function createEditor()
              StackExchange.prepareEditor(
              heartbeatType: 'answer',
              autoActivateHeartbeat: false,
              convertImagesToLinks: true,
              noModals: true,
              showLowRepImageUploadWarning: true,
              reputationToPostImages: 10,
              bindNavPrevention: true,
              postfix: "",
              imageUploader:
              brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
              contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
              allowUrls: true
              ,
              onDemand: true,
              discardSelector: ".discard-answer"
              ,immediatelyShowMarkdownHelp:true
              );



              );













              draft saved

              draft discarded


















              StackExchange.ready(
              function ()
              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53271863%2fcompiling-dict-of-users-in-python-for-search-results%23new-answer', 'question_page');

              );

              Post as a guest















              Required, but never shown

























              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              0














              Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)






              share|improve this answer



























                0














                Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)






                share|improve this answer

























                  0












                  0








                  0







                  Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)






                  share|improve this answer













                  Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 13 '18 at 0:08









                  rikAteerikAtee

                  4,92053059




                  4,92053059























                      0














                      fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



                      users = db.execute(
                      'SELECT * FROM user WHERE email = ?', (emailInput,)
                      ).fetchall()
                      for user in users:
                      if user['first'] is None:
                      <etc>





                      share|improve this answer



























                        0














                        fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



                        users = db.execute(
                        'SELECT * FROM user WHERE email = ?', (emailInput,)
                        ).fetchall()
                        for user in users:
                        if user['first'] is None:
                        <etc>





                        share|improve this answer

























                          0












                          0








                          0







                          fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



                          users = db.execute(
                          'SELECT * FROM user WHERE email = ?', (emailInput,)
                          ).fetchall()
                          for user in users:
                          if user['first'] is None:
                          <etc>





                          share|improve this answer













                          fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



                          users = db.execute(
                          'SELECT * FROM user WHERE email = ?', (emailInput,)
                          ).fetchall()
                          for user in users:
                          if user['first'] is None:
                          <etc>






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 13 '18 at 0:12









                          rd_nielsenrd_nielsen

                          1,6102616




                          1,6102616



























                              draft saved

                              draft discarded
















































                              Thanks for contributing an answer to Stack Overflow!


                              • Please be sure to answer the question. Provide details and share your research!

                              But avoid


                              • Asking for help, clarification, or responding to other answers.

                              • Making statements based on opinion; back them up with references or personal experience.

                              To learn more, see our tips on writing great answers.




                              draft saved


                              draft discarded














                              StackExchange.ready(
                              function ()
                              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53271863%2fcompiling-dict-of-users-in-python-for-search-results%23new-answer', 'question_page');

                              );

                              Post as a guest















                              Required, but never shown





















































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown

































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown







                              Popular posts from this blog

                              𛂒𛀶,𛀽𛀑𛂀𛃧𛂓𛀙𛃆𛃑𛃷𛂟𛁡𛀢𛀟𛁤𛂽𛁕𛁪𛂟𛂯,𛁞𛂧𛀴𛁄𛁠𛁼𛂿𛀤 𛂘,𛁺𛂾𛃭𛃭𛃵𛀺,𛂣𛃍𛂖𛃶 𛀸𛃀𛂖𛁶𛁏𛁚 𛂢𛂞 𛁰𛂆𛀔,𛁸𛀽𛁓𛃋𛂇𛃧𛀧𛃣𛂐𛃇,𛂂𛃻𛃲𛁬𛃞𛀧𛃃𛀅 𛂭𛁠𛁡𛃇𛀷𛃓𛁥,𛁙𛁘𛁞𛃸𛁸𛃣𛁜,𛂛,𛃿,𛁯𛂘𛂌𛃛𛁱𛃌𛂈𛂇 𛁊𛃲,𛀕𛃴𛀜 𛀶𛂆𛀶𛃟𛂉𛀣,𛂐𛁞𛁾 𛁷𛂑𛁳𛂯𛀬𛃅,𛃶𛁼

                              Crossroads (UK TV series)

                              ữḛḳṊẴ ẋ,Ẩṙ,ỹḛẪẠứụỿṞṦ,Ṉẍừ,ứ Ị,Ḵ,ṏ ṇỪḎḰṰọửḊ ṾḨḮữẑỶṑỗḮṣṉẃ Ữẩụ,ṓ,ḹẕḪḫỞṿḭ ỒṱṨẁṋṜ ḅẈ ṉ ứṀḱṑỒḵ,ḏ,ḊḖỹẊ Ẻḷổ,ṥ ẔḲẪụḣể Ṱ ḭỏựẶ Ồ Ṩ,ẂḿṡḾồ ỗṗṡịṞẤḵṽẃ ṸḒẄẘ,ủẞẵṦṟầṓế