Plot y = mx + c with ggplot
Basic question, ggplot doesn't seem to be doing what I expect though.
ggplot(data=data.frame( x=c(-1,2),y=c(-1,2) ), aes(x=x,y=y)) +
geom_blank() +
geom_abline(slope = -1 , intercept = 1)
I'm expecting this to plot :
It's plotting :
r ggplot2
asked Nov 11 '18 at 13:48
baxxbaxx
403522
add a comment |
Basic question, ggplot doesn't seem to be doing what I expect though.
ggplot(data=data.frame( x=c(-1,2),y=c(-1,2) ), aes(x=x,y=y)) +
geom_blank() +
geom_abline(slope = -1 , intercept = 1)
I'm expecting this to plot :
It's plotting :
r ggplot2
asked Nov 11 '18 at 13:48
baxxbaxx
403522
3
Then you may need to clarify "the correct result". Intercept in a linear regression is commonly defined as the value of y when x is zero. Your abline clearly runs through (x = 0, y = 1). The limits of the plot area is given by the range of your data.
– Henrik
Nov 11 '18 at 14:23
Also please read the help text?geom_abline: "If you use arguments, e.g.geom_abline(intercept = 0, slope = 1), then behind the scenes the geom makes a new data frame containing just the data you've supplied"
– Henrik
Nov 11 '18 at 14:37
add a comment |
Basic question, ggplot doesn't seem to be doing what I expect though.
ggplot(data=data.frame( x=c(-1,2),y=c(-1,2) ), aes(x=x,y=y)) +
geom_blank() +
geom_abline(slope = -1 , intercept = 1)
I'm expecting this to plot :
It's plotting :
r ggplot2
asked Nov 11 '18 at 13:48
baxxbaxx
403522
Basic question, ggplot doesn't seem to be doing what I expect though.
ggplot(data=data.frame( x=c(-1,2),y=c(-1,2) ), aes(x=x,y=y)) +
geom_blank() +
geom_abline(slope = -1 , intercept = 1)
I'm expecting this to plot :
It's plotting :
r ggplot2
r ggplot2
asked Nov 11 '18 at 13:48
baxxbaxx
403522
asked Nov 11 '18 at 13:48
baxxbaxx
403522
edited Nov 11 '18 at 14:28
baxx
asked Nov 11 '18 at 13:48
baxxbaxx
403522
asked Nov 11 '18 at 13:48
baxxbaxx
403522
asked Nov 11 '18 at 13:48
baxxbaxx
403522
403522
3
Then you may need to clarify "the correct result". Intercept in a linear regression is commonly defined as the value of y when x is zero. Your abline clearly runs through (x = 0, y = 1). The limits of the plot area is given by the range of your data.
– Henrik
Nov 11 '18 at 14:23
Also please read the help text?geom_abline: "If you use arguments, e.g.geom_abline(intercept = 0, slope = 1), then behind the scenes the geom makes a new data frame containing just the data you've supplied"
– Henrik
Nov 11 '18 at 14:37
add a comment |
3
Then you may need to clarify "the correct result". Intercept in a linear regression is commonly defined as the value of y when x is zero. Your abline clearly runs through (x = 0, y = 1). The limits of the plot area is given by the range of your data.
– Henrik
Nov 11 '18 at 14:23
Also please read the help text?geom_abline: "If you use arguments, e.g.geom_abline(intercept = 0, slope = 1), then behind the scenes the geom makes a new data frame containing just the data you've supplied"
– Henrik
Nov 11 '18 at 14:37
3
3
Then you may need to clarify "the correct result". Intercept in a linear regression is commonly defined as the value of y when x is zero. Your abline clearly runs through (x = 0, y = 1). The limits of the plot area is given by the range of your data.
– Henrik
Nov 11 '18 at 14:23
Then you may need to clarify "the correct result". Intercept in a linear regression is commonly defined as the value of y when x is zero. Your abline clearly runs through (x = 0, y = 1). The limits of the plot area is given by the range of your data.
– Henrik
Nov 11 '18 at 14:23
Also please read the help text
?geom_abline: "If you use arguments, e.g. geom_abline(intercept = 0, slope = 1), then behind the scenes the geom makes a new data frame containing just the data you've supplied"– Henrik
Nov 11 '18 at 14:37
Also please read the help text
?geom_abline: "If you use arguments, e.g. geom_abline(intercept = 0, slope = 1), then behind the scenes the geom makes a new data frame containing just the data you've supplied"– Henrik
Nov 11 '18 at 14:37
add a comment |
2 Answers
2
active
oldest
votes
The plot ggplot2 draws is not incorrect. It draws the function over the scales necessary to represent the data you pass to the aes call. It doesn't care whether you actually draw the data in a geom or not.
To illustrate the issue, it is helpful to add the actual data points to a plot and make the x- and y-axis more visible. The code below
ggplot(data=data.frame( x=c(-1,2),y=c(-1,2) ), aes(x=x,y=y)) +
geom_point(shape = 1) +
geom_abline(intercept = 1, slope = -1, col = "red") +
geom_hline(yintercept = 0) +
geom_vline(xintercept = 0)
gives you:
Since you only want to plot a subsection of the above plot, just correct the scales (and don't draw the axes and datapoints). Then you get the result you desire:
ggplot(data=data.frame(x=c(-1,2), y=c(-1,2)), aes(x=x,y=y)) +
geom_blank() + # not necessary, taken from the OP's question
geom_abline(intercept = 1, slope = -1) +
scale_x_continuous(limits = c(0, 1)) +
scale_y_continuous(limits = c(0, 1))
answered Nov 11 '18 at 14:34
apitschapitsch
582216
1
@baxx Do you happen to remember this post: How to set limits for axes in ggplot2 R plots? ;)
– Henrik
Nov 11 '18 at 14:40
1
the problem was basic interpretation, as markus seems to have made a similar error. I feel that having something basic like this that directly answers how to plot y=mx + c might be useful to others in future though. In this case, plotting the axis with geom_hline() and geom_vline() would have been enough to demonstrate that the graph was in fact correct, and that I am in fact too tired.
– baxx
Nov 11 '18 at 14:42
@apitsch perhaps you could consider adding the case of there being axis lines to more clearly demonstrate the problem. Here's a link to a plot you could use : i.imgur.com/kh4FLaw.png , here's a link to the code : vpaste.net/IVLln
– baxx
Nov 11 '18 at 14:48
I learned something about setting the limits inggplot2but wouldn't it have been easier to justggplot()+ geom_abline(intercept = 1, slope = -1) + scale_x_continuous(limits = c(0, 1)) + scale_y_continuous(limits = c(0, 1))instead of going throughgeom_blankin the first place. Is there some subtility i am missing?
– Jrakru56
Nov 11 '18 at 14:57
add a comment |
I think ggplot2 does exactly what you ask it to do: you draw an empty canvans with goes from (-1, -1) to (2, 2) and then you add a abline. If you want to match the canvans to your exampe, just adjust the coordinates of the points that you specify:
library(tidyverse)
ggplot(data=data.frame( x=c(0,2),y=c(1,0)), aes(x=x,y=y)) +
geom_blank() +
geom_abline(slope = -1 , intercept = 1)
answered Nov 11 '18 at 14:33
JReddigJReddig
7117
add a comment |
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The plot ggplot2 draws is not incorrect. It draws the function over the scales necessary to represent the data you pass to the aes call. It doesn't care whether you actually draw the data in a geom or not.
To illustrate the issue, it is helpful to add the actual data points to a plot and make the x- and y-axis more visible. The code below
ggplot(data=data.frame( x=c(-1,2),y=c(-1,2) ), aes(x=x,y=y)) +
geom_point(shape = 1) +
geom_abline(intercept = 1, slope = -1, col = "red") +
geom_hline(yintercept = 0) +
geom_vline(xintercept = 0)
gives you:
Since you only want to plot a subsection of the above plot, just correct the scales (and don't draw the axes and datapoints). Then you get the result you desire:
ggplot(data=data.frame(x=c(-1,2), y=c(-1,2)), aes(x=x,y=y)) +
geom_blank() + # not necessary, taken from the OP's question
geom_abline(intercept = 1, slope = -1) +
scale_x_continuous(limits = c(0, 1)) +
scale_y_continuous(limits = c(0, 1))
answered Nov 11 '18 at 14:34
apitschapitsch
582216
1
@baxx Do you happen to remember this post: How to set limits for axes in ggplot2 R plots? ;)
– Henrik
Nov 11 '18 at 14:40
1
the problem was basic interpretation, as markus seems to have made a similar error. I feel that having something basic like this that directly answers how to plot y=mx + c might be useful to others in future though. In this case, plotting the axis with geom_hline() and geom_vline() would have been enough to demonstrate that the graph was in fact correct, and that I am in fact too tired.
– baxx
Nov 11 '18 at 14:42
@apitsch perhaps you could consider adding the case of there being axis lines to more clearly demonstrate the problem. Here's a link to a plot you could use : i.imgur.com/kh4FLaw.png , here's a link to the code : vpaste.net/IVLln
– baxx
Nov 11 '18 at 14:48
I learned something about setting the limits inggplot2but wouldn't it have been easier to justggplot()+ geom_abline(intercept = 1, slope = -1) + scale_x_continuous(limits = c(0, 1)) + scale_y_continuous(limits = c(0, 1))instead of going throughgeom_blankin the first place. Is there some subtility i am missing?
– Jrakru56
Nov 11 '18 at 14:57
add a comment |
The plot ggplot2 draws is not incorrect. It draws the function over the scales necessary to represent the data you pass to the aes call. It doesn't care whether you actually draw the data in a geom or not.
To illustrate the issue, it is helpful to add the actual data points to a plot and make the x- and y-axis more visible. The code below
ggplot(data=data.frame( x=c(-1,2),y=c(-1,2) ), aes(x=x,y=y)) +
geom_point(shape = 1) +
geom_abline(intercept = 1, slope = -1, col = "red") +
geom_hline(yintercept = 0) +
geom_vline(xintercept = 0)
gives you:
Since you only want to plot a subsection of the above plot, just correct the scales (and don't draw the axes and datapoints). Then you get the result you desire:
ggplot(data=data.frame(x=c(-1,2), y=c(-1,2)), aes(x=x,y=y)) +
geom_blank() + # not necessary, taken from the OP's question
geom_abline(intercept = 1, slope = -1) +
scale_x_continuous(limits = c(0, 1)) +
scale_y_continuous(limits = c(0, 1))
answered Nov 11 '18 at 14:34
apitschapitsch
582216
1
@baxx Do you happen to remember this post: How to set limits for axes in ggplot2 R plots? ;)
– Henrik
Nov 11 '18 at 14:40
1
the problem was basic interpretation, as markus seems to have made a similar error. I feel that having something basic like this that directly answers how to plot y=mx + c might be useful to others in future though. In this case, plotting the axis with geom_hline() and geom_vline() would have been enough to demonstrate that the graph was in fact correct, and that I am in fact too tired.
– baxx
Nov 11 '18 at 14:42
@apitsch perhaps you could consider adding the case of there being axis lines to more clearly demonstrate the problem. Here's a link to a plot you could use : i.imgur.com/kh4FLaw.png , here's a link to the code : vpaste.net/IVLln
– baxx
Nov 11 '18 at 14:48
I learned something about setting the limits inggplot2but wouldn't it have been easier to justggplot()+ geom_abline(intercept = 1, slope = -1) + scale_x_continuous(limits = c(0, 1)) + scale_y_continuous(limits = c(0, 1))instead of going throughgeom_blankin the first place. Is there some subtility i am missing?
– Jrakru56
Nov 11 '18 at 14:57
add a comment |
The plot ggplot2 draws is not incorrect. It draws the function over the scales necessary to represent the data you pass to the aes call. It doesn't care whether you actually draw the data in a geom or not.
To illustrate the issue, it is helpful to add the actual data points to a plot and make the x- and y-axis more visible. The code below
ggplot(data=data.frame( x=c(-1,2),y=c(-1,2) ), aes(x=x,y=y)) +
geom_point(shape = 1) +
geom_abline(intercept = 1, slope = -1, col = "red") +
geom_hline(yintercept = 0) +
geom_vline(xintercept = 0)
gives you:
Since you only want to plot a subsection of the above plot, just correct the scales (and don't draw the axes and datapoints). Then you get the result you desire:
ggplot(data=data.frame(x=c(-1,2), y=c(-1,2)), aes(x=x,y=y)) +
geom_blank() + # not necessary, taken from the OP's question
geom_abline(intercept = 1, slope = -1) +
scale_x_continuous(limits = c(0, 1)) +
scale_y_continuous(limits = c(0, 1))
answered Nov 11 '18 at 14:34
apitschapitsch
582216
The plot ggplot2 draws is not incorrect. It draws the function over the scales necessary to represent the data you pass to the aes call. It doesn't care whether you actually draw the data in a geom or not.
To illustrate the issue, it is helpful to add the actual data points to a plot and make the x- and y-axis more visible. The code below
ggplot(data=data.frame( x=c(-1,2),y=c(-1,2) ), aes(x=x,y=y)) +
geom_point(shape = 1) +
geom_abline(intercept = 1, slope = -1, col = "red") +
geom_hline(yintercept = 0) +
geom_vline(xintercept = 0)
gives you:
Since you only want to plot a subsection of the above plot, just correct the scales (and don't draw the axes and datapoints). Then you get the result you desire:
ggplot(data=data.frame(x=c(-1,2), y=c(-1,2)), aes(x=x,y=y)) +
geom_blank() + # not necessary, taken from the OP's question
geom_abline(intercept = 1, slope = -1) +
scale_x_continuous(limits = c(0, 1)) +
scale_y_continuous(limits = c(0, 1))
answered Nov 11 '18 at 14:34
apitschapitsch
582216
edited Nov 11 '18 at 15:01
answered Nov 11 '18 at 14:34
apitschapitsch
582216
answered Nov 11 '18 at 14:34
apitschapitsch
582216
answered Nov 11 '18 at 14:34
apitschapitsch
582216
582216
1
@baxx Do you happen to remember this post: How to set limits for axes in ggplot2 R plots? ;)
– Henrik
Nov 11 '18 at 14:40
1
the problem was basic interpretation, as markus seems to have made a similar error. I feel that having something basic like this that directly answers how to plot y=mx + c might be useful to others in future though. In this case, plotting the axis with geom_hline() and geom_vline() would have been enough to demonstrate that the graph was in fact correct, and that I am in fact too tired.
– baxx
Nov 11 '18 at 14:42
@apitsch perhaps you could consider adding the case of there being axis lines to more clearly demonstrate the problem. Here's a link to a plot you could use : i.imgur.com/kh4FLaw.png , here's a link to the code : vpaste.net/IVLln
– baxx
Nov 11 '18 at 14:48
I learned something about setting the limits inggplot2but wouldn't it have been easier to justggplot()+ geom_abline(intercept = 1, slope = -1) + scale_x_continuous(limits = c(0, 1)) + scale_y_continuous(limits = c(0, 1))instead of going throughgeom_blankin the first place. Is there some subtility i am missing?
– Jrakru56
Nov 11 '18 at 14:57
add a comment |
1
@baxx Do you happen to remember this post: How to set limits for axes in ggplot2 R plots? ;)
– Henrik
Nov 11 '18 at 14:40
1
the problem was basic interpretation, as markus seems to have made a similar error. I feel that having something basic like this that directly answers how to plot y=mx + c might be useful to others in future though. In this case, plotting the axis with geom_hline() and geom_vline() would have been enough to demonstrate that the graph was in fact correct, and that I am in fact too tired.
– baxx
Nov 11 '18 at 14:42
@apitsch perhaps you could consider adding the case of there being axis lines to more clearly demonstrate the problem. Here's a link to a plot you could use : i.imgur.com/kh4FLaw.png , here's a link to the code : vpaste.net/IVLln
– baxx
Nov 11 '18 at 14:48
I learned something about setting the limits inggplot2but wouldn't it have been easier to justggplot()+ geom_abline(intercept = 1, slope = -1) + scale_x_continuous(limits = c(0, 1)) + scale_y_continuous(limits = c(0, 1))instead of going throughgeom_blankin the first place. Is there some subtility i am missing?
– Jrakru56
Nov 11 '18 at 14:57
1
1
@baxx Do you happen to remember this post: How to set limits for axes in ggplot2 R plots? ;)
– Henrik
Nov 11 '18 at 14:40
@baxx Do you happen to remember this post: How to set limits for axes in ggplot2 R plots? ;)
– Henrik
Nov 11 '18 at 14:40
1
1
the problem was basic interpretation, as markus seems to have made a similar error. I feel that having something basic like this that directly answers how to plot y=mx + c might be useful to others in future though. In this case, plotting the axis with geom_hline() and geom_vline() would have been enough to demonstrate that the graph was in fact correct, and that I am in fact too tired.
– baxx
Nov 11 '18 at 14:42
the problem was basic interpretation, as markus seems to have made a similar error. I feel that having something basic like this that directly answers how to plot y=mx + c might be useful to others in future though. In this case, plotting the axis with geom_hline() and geom_vline() would have been enough to demonstrate that the graph was in fact correct, and that I am in fact too tired.
– baxx
Nov 11 '18 at 14:42
@apitsch perhaps you could consider adding the case of there being axis lines to more clearly demonstrate the problem. Here's a link to a plot you could use : i.imgur.com/kh4FLaw.png , here's a link to the code : vpaste.net/IVLln
– baxx
Nov 11 '18 at 14:48
@apitsch perhaps you could consider adding the case of there being axis lines to more clearly demonstrate the problem. Here's a link to a plot you could use : i.imgur.com/kh4FLaw.png , here's a link to the code : vpaste.net/IVLln
– baxx
Nov 11 '18 at 14:48
I learned something about setting the limits in
ggplot2 but wouldn't it have been easier to just ggplot()+ geom_abline(intercept = 1, slope = -1) + scale_x_continuous(limits = c(0, 1)) + scale_y_continuous(limits = c(0, 1)) instead of going through geom_blank in the first place. Is there some subtility i am missing?– Jrakru56
Nov 11 '18 at 14:57
I learned something about setting the limits in
ggplot2 but wouldn't it have been easier to just ggplot()+ geom_abline(intercept = 1, slope = -1) + scale_x_continuous(limits = c(0, 1)) + scale_y_continuous(limits = c(0, 1)) instead of going through geom_blank in the first place. Is there some subtility i am missing?– Jrakru56
Nov 11 '18 at 14:57
add a comment |
I think ggplot2 does exactly what you ask it to do: you draw an empty canvans with goes from (-1, -1) to (2, 2) and then you add a abline. If you want to match the canvans to your exampe, just adjust the coordinates of the points that you specify:
library(tidyverse)
ggplot(data=data.frame( x=c(0,2),y=c(1,0)), aes(x=x,y=y)) +
geom_blank() +
geom_abline(slope = -1 , intercept = 1)
answered Nov 11 '18 at 14:33
JReddigJReddig
7117
add a comment |
I think ggplot2 does exactly what you ask it to do: you draw an empty canvans with goes from (-1, -1) to (2, 2) and then you add a abline. If you want to match the canvans to your exampe, just adjust the coordinates of the points that you specify:
library(tidyverse)
ggplot(data=data.frame( x=c(0,2),y=c(1,0)), aes(x=x,y=y)) +
geom_blank() +
geom_abline(slope = -1 , intercept = 1)
answered Nov 11 '18 at 14:33
JReddigJReddig
7117
add a comment |
I think ggplot2 does exactly what you ask it to do: you draw an empty canvans with goes from (-1, -1) to (2, 2) and then you add a abline. If you want to match the canvans to your exampe, just adjust the coordinates of the points that you specify:
library(tidyverse)
ggplot(data=data.frame( x=c(0,2),y=c(1,0)), aes(x=x,y=y)) +
geom_blank() +
geom_abline(slope = -1 , intercept = 1)
answered Nov 11 '18 at 14:33
JReddigJReddig
7117
I think ggplot2 does exactly what you ask it to do: you draw an empty canvans with goes from (-1, -1) to (2, 2) and then you add a abline. If you want to match the canvans to your exampe, just adjust the coordinates of the points that you specify:
library(tidyverse)
ggplot(data=data.frame( x=c(0,2),y=c(1,0)), aes(x=x,y=y)) +
geom_blank() +
geom_abline(slope = -1 , intercept = 1)
answered Nov 11 '18 at 14:33
JReddigJReddig
7117
answered Nov 11 '18 at 14:33
JReddigJReddig
7117
answered Nov 11 '18 at 14:33
JReddigJReddig
7117
answered Nov 11 '18 at 14:33
JReddigJReddig
7117
7117
add a comment |
add a comment |
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3
Then you may need to clarify "the correct result". Intercept in a linear regression is commonly defined as the value of y when x is zero. Your abline clearly runs through (x = 0, y = 1). The limits of the plot area is given by the range of your data.
– Henrik
Nov 11 '18 at 14:23
Also please read the help text
?geom_abline: "If you use arguments, e.g.geom_abline(intercept = 0, slope = 1), then behind the scenes the geom makes a new data frame containing just the data you've supplied"– Henrik
Nov 11 '18 at 14:37