<String.h> is my implementation of my strncpy right?

char *strncpy(char *dest, char *src, unsigned int n)

unsigned int a;
a = 0;
while (src[a] && a < n)

dest[a] = src[a];
a++;

while (a < n)//if src not bigger than n should I put '' at the end of dest ?

dest[a] = '';
a++;

dest[a] = '';
return (dest);



Hello Stackoverflow

I am looking for my mistake, I know that when n > strlen(dest), it does abort on the real strncpy and I am wondering why it is wrong ?
Thanks for your help

strncpy

strncpy

dest[a] = '';

dest[n] = '';

n

strncpy() would only touch

strncpy()

1 Answer
1

You no need to append '' continuously, if you want to rest of the memory of dest to be filled with zeros you can use calloc() while allocating memory

dest

calloc()

char *strnncpy(char *dest, char *src, unsigned int n)

unsigned int a;
a = 0;
while ( src[a] && a < n)

dest[a] = src[a];
a++;

dest[a] = '';
return (dest);



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