Delete specific values in 2-Dimension array - Numpy

Delete specific values in 2-Dimension array - Numpy


import numpy as np



I have two arrays of size n (to simplify, I use in this example n = 2):


A = array([[1,2,3],[1,2,3]])



B has two dimensions with n time a random integer: 1, 2 or 3.



Let's pretend:


B = array([[1],[3]])



What is the most pythonic way to subtract B from A in order to obtain C, C = array([2,3],[1,2]) ?


C = array([2,3],[1,2])



I tried to use np.subtract but due to the broadcasting rules I do not obtain C. I do not want to use mask or indices but element's values. I also tried to use np.delete, np.where without success.
Thank you.


np.subtract


np.delete


np.where






What if there are duplicates in any row of A?

– Divakar
Sep 14 '18 at 13:32


A






In my case, there is no duplicate. But if there is let 's say substract the first iteration.

– Tousalouest
Sep 14 '18 at 13:35






Check this link, hope it will help you out stackoverflow.com/questions/42557558/…

– JON
Sep 14 '18 at 13:36






And what if no match is found? For ex. : B = array([[5],[3]])?

– Divakar
Sep 14 '18 at 13:38



B = array([[5],[3]])






In my case, there will alway be a match.

– Tousalouest
Sep 14 '18 at 13:45




1 Answer
1



This might work and should be quite Pythonic:


dd=[[val for val in A[i] if val not in B[i]] for i in xrange(len(A))]






Thank you. It does work with 'range' instead of 'xrange'.

– Tousalouest
Sep 14 '18 at 13:44






I am still using Python2.X, therefore xrange... Glad it worked!

– msi_gerva
Sep 14 '18 at 13:46



xrange



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