How to join complex sql queries within a table using subqueries










0














I have a table with "userid", "bookid", "sessionid".



When a book(bookid) is viewed by a visitor(userid), the web application will find all books(bookids) viewed by users(userids) who viewed this book(bookid) and display the top 5 books.










share|improve this question

















  • 3




    Great. Do you have a question?
    – Gordon Linoff
    Nov 10 '18 at 13:28











  • Just as you did above, then access the properties with book.bookid, you can also declare multiple properties e.g. book(bookId int, name char(max))
    – Jay
    Nov 10 '18 at 13:29










  • @GordonLinoff my question is what will be the sql query to retrieve the top 5 books
    – Achala Yasas Piyarathna
    Nov 10 '18 at 14:27















0














I have a table with "userid", "bookid", "sessionid".



When a book(bookid) is viewed by a visitor(userid), the web application will find all books(bookids) viewed by users(userids) who viewed this book(bookid) and display the top 5 books.










share|improve this question

















  • 3




    Great. Do you have a question?
    – Gordon Linoff
    Nov 10 '18 at 13:28











  • Just as you did above, then access the properties with book.bookid, you can also declare multiple properties e.g. book(bookId int, name char(max))
    – Jay
    Nov 10 '18 at 13:29










  • @GordonLinoff my question is what will be the sql query to retrieve the top 5 books
    – Achala Yasas Piyarathna
    Nov 10 '18 at 14:27













0












0








0


1





I have a table with "userid", "bookid", "sessionid".



When a book(bookid) is viewed by a visitor(userid), the web application will find all books(bookids) viewed by users(userids) who viewed this book(bookid) and display the top 5 books.










share|improve this question













I have a table with "userid", "bookid", "sessionid".



When a book(bookid) is viewed by a visitor(userid), the web application will find all books(bookids) viewed by users(userids) who viewed this book(bookid) and display the top 5 books.







sql join






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 10 '18 at 13:25









Achala Yasas PiyarathnaAchala Yasas Piyarathna

160112




160112







  • 3




    Great. Do you have a question?
    – Gordon Linoff
    Nov 10 '18 at 13:28











  • Just as you did above, then access the properties with book.bookid, you can also declare multiple properties e.g. book(bookId int, name char(max))
    – Jay
    Nov 10 '18 at 13:29










  • @GordonLinoff my question is what will be the sql query to retrieve the top 5 books
    – Achala Yasas Piyarathna
    Nov 10 '18 at 14:27












  • 3




    Great. Do you have a question?
    – Gordon Linoff
    Nov 10 '18 at 13:28











  • Just as you did above, then access the properties with book.bookid, you can also declare multiple properties e.g. book(bookId int, name char(max))
    – Jay
    Nov 10 '18 at 13:29










  • @GordonLinoff my question is what will be the sql query to retrieve the top 5 books
    – Achala Yasas Piyarathna
    Nov 10 '18 at 14:27







3




3




Great. Do you have a question?
– Gordon Linoff
Nov 10 '18 at 13:28





Great. Do you have a question?
– Gordon Linoff
Nov 10 '18 at 13:28













Just as you did above, then access the properties with book.bookid, you can also declare multiple properties e.g. book(bookId int, name char(max))
– Jay
Nov 10 '18 at 13:29




Just as you did above, then access the properties with book.bookid, you can also declare multiple properties e.g. book(bookId int, name char(max))
– Jay
Nov 10 '18 at 13:29












@GordonLinoff my question is what will be the sql query to retrieve the top 5 books
– Achala Yasas Piyarathna
Nov 10 '18 at 14:27




@GordonLinoff my question is what will be the sql query to retrieve the top 5 books
– Achala Yasas Piyarathna
Nov 10 '18 at 14:27












1 Answer
1






active

oldest

votes


















1














I will assume the following:



  • You are using MySQL as DBMS.

  • With "Top 5 books" you mean "the 5 most viewed books considering the views by the users who viewed the current book".

Assuming as an example that the user is visiting the book 151 at the moment, you can do it with the following query:



SELECT bookid, COUNT(*) AS BookViews
FROM YourTable
WHERE userid IN (SELECT userid FROM YourTable WHERE bookid = 151)
GROUP BY bookid
ORDER BY 2 DESC
LIMIT 5;





share|improve this answer




















    Your Answer






    StackExchange.ifUsing("editor", function ()
    StackExchange.using("externalEditor", function ()
    StackExchange.using("snippets", function ()
    StackExchange.snippets.init();
    );
    );
    , "code-snippets");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "1"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53239393%2fhow-to-join-complex-sql-queries-within-a-table-using-subqueries%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    I will assume the following:



    • You are using MySQL as DBMS.

    • With "Top 5 books" you mean "the 5 most viewed books considering the views by the users who viewed the current book".

    Assuming as an example that the user is visiting the book 151 at the moment, you can do it with the following query:



    SELECT bookid, COUNT(*) AS BookViews
    FROM YourTable
    WHERE userid IN (SELECT userid FROM YourTable WHERE bookid = 151)
    GROUP BY bookid
    ORDER BY 2 DESC
    LIMIT 5;





    share|improve this answer

























      1














      I will assume the following:



      • You are using MySQL as DBMS.

      • With "Top 5 books" you mean "the 5 most viewed books considering the views by the users who viewed the current book".

      Assuming as an example that the user is visiting the book 151 at the moment, you can do it with the following query:



      SELECT bookid, COUNT(*) AS BookViews
      FROM YourTable
      WHERE userid IN (SELECT userid FROM YourTable WHERE bookid = 151)
      GROUP BY bookid
      ORDER BY 2 DESC
      LIMIT 5;





      share|improve this answer























        1












        1








        1






        I will assume the following:



        • You are using MySQL as DBMS.

        • With "Top 5 books" you mean "the 5 most viewed books considering the views by the users who viewed the current book".

        Assuming as an example that the user is visiting the book 151 at the moment, you can do it with the following query:



        SELECT bookid, COUNT(*) AS BookViews
        FROM YourTable
        WHERE userid IN (SELECT userid FROM YourTable WHERE bookid = 151)
        GROUP BY bookid
        ORDER BY 2 DESC
        LIMIT 5;





        share|improve this answer












        I will assume the following:



        • You are using MySQL as DBMS.

        • With "Top 5 books" you mean "the 5 most viewed books considering the views by the users who viewed the current book".

        Assuming as an example that the user is visiting the book 151 at the moment, you can do it with the following query:



        SELECT bookid, COUNT(*) AS BookViews
        FROM YourTable
        WHERE userid IN (SELECT userid FROM YourTable WHERE bookid = 151)
        GROUP BY bookid
        ORDER BY 2 DESC
        LIMIT 5;






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 10 '18 at 15:14









        Antonio AlvarezAntonio Alvarez

        147115




        147115



























            draft saved

            draft discarded
















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.





            Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


            Please pay close attention to the following guidance:


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53239393%2fhow-to-join-complex-sql-queries-within-a-table-using-subqueries%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            𛂒𛀶,𛀽𛀑𛂀𛃧𛂓𛀙𛃆𛃑𛃷𛂟𛁡𛀢𛀟𛁤𛂽𛁕𛁪𛂟𛂯,𛁞𛂧𛀴𛁄𛁠𛁼𛂿𛀤 𛂘,𛁺𛂾𛃭𛃭𛃵𛀺,𛂣𛃍𛂖𛃶 𛀸𛃀𛂖𛁶𛁏𛁚 𛂢𛂞 𛁰𛂆𛀔,𛁸𛀽𛁓𛃋𛂇𛃧𛀧𛃣𛂐𛃇,𛂂𛃻𛃲𛁬𛃞𛀧𛃃𛀅 𛂭𛁠𛁡𛃇𛀷𛃓𛁥,𛁙𛁘𛁞𛃸𛁸𛃣𛁜,𛂛,𛃿,𛁯𛂘𛂌𛃛𛁱𛃌𛂈𛂇 𛁊𛃲,𛀕𛃴𛀜 𛀶𛂆𛀶𛃟𛂉𛀣,𛂐𛁞𛁾 𛁷𛂑𛁳𛂯𛀬𛃅,𛃶𛁼

            Edmonton

            Crossroads (UK TV series)