java print in textarea text file in reverse order

up vote
-2
down vote

favorite

I'm using this code, it runs well but i need to add "n" to each line

private void jButton2ActionPerformed(java.awt.event.ActionEvent evt) 
 filename = "Reverse.txt";
 file = new File(filename);
 try (final Stream<String> lines = Files.lines(Paths.get(filename))) 
 lines.collect(Collectors.toCollection(LinkedList::new))
 .descendingIterator()
 .forEachRemaining(jTextArea1::append); // <<<<<<< need "n"
 
 catch (IOException ex) 
 Logger.getLogger(TextAreaReverseReadFrame.class.getName()).log(Level.SEVERE, null, ex);

edited Nov 9 at 9:40

SaviNuclear

692517

asked Nov 9 at 8:31

patel

114

add a comment |

up vote
-2
down vote

favorite

I'm using this code, it runs well but i need to add "n" to each line

private void jButton2ActionPerformed(java.awt.event.ActionEvent evt) 
 filename = "Reverse.txt";
 file = new File(filename);
 try (final Stream<String> lines = Files.lines(Paths.get(filename))) 
 lines.collect(Collectors.toCollection(LinkedList::new))
 .descendingIterator()
 .forEachRemaining(jTextArea1::append); // <<<<<<< need "n"
 
 catch (IOException ex) 
 Logger.getLogger(TextAreaReverseReadFrame.class.getName()).log(Level.SEVERE, null, ex);

edited Nov 9 at 9:40

SaviNuclear

692517

asked Nov 9 at 8:31

patel

114

add a comment |

up vote
-2
down vote

favorite

I'm using this code, it runs well but i need to add "n" to each line

private void jButton2ActionPerformed(java.awt.event.ActionEvent evt) 
 filename = "Reverse.txt";
 file = new File(filename);
 try (final Stream<String> lines = Files.lines(Paths.get(filename))) 
 lines.collect(Collectors.toCollection(LinkedList::new))
 .descendingIterator()
 .forEachRemaining(jTextArea1::append); // <<<<<<< need "n"
 
 catch (IOException ex) 
 Logger.getLogger(TextAreaReverseReadFrame.class.getName()).log(Level.SEVERE, null, ex);

edited Nov 9 at 9:40

SaviNuclear

692517

asked Nov 9 at 8:31

patel

114

I'm using this code, it runs well but i need to add "n" to each line

private void jButton2ActionPerformed(java.awt.event.ActionEvent evt) 
 filename = "Reverse.txt";
 file = new File(filename);
 try (final Stream<String> lines = Files.lines(Paths.get(filename))) 
 lines.collect(Collectors.toCollection(LinkedList::new))
 .descendingIterator()
 .forEachRemaining(jTextArea1::append); // <<<<<<< need "n"
 
 catch (IOException ex) 
 Logger.getLogger(TextAreaReverseReadFrame.class.getName()).log(Level.SEVERE, null, ex);

java

edited Nov 9 at 9:40

SaviNuclear

692517

asked Nov 9 at 8:31

patel

114

edited Nov 9 at 9:40

SaviNuclear

692517

asked Nov 9 at 8:31

patel

114

edited Nov 9 at 9:40

SaviNuclear

692517

edited Nov 9 at 9:40

SaviNuclear

692517

edited Nov 9 at 9:40

SaviNuclear

692517

asked Nov 9 at 8:31

patel

114

asked Nov 9 at 8:31

patel

114

asked Nov 9 at 8:31

patel

114

add a comment |

2 Answers
2

active

oldest

votes

up vote
0
down vote

accepted

Simply try to change

.forEachRemaining(jTextArea1::append);

to:

.forEachRemaining(singleLine -> jTextArea1.append(singleLine + "n"));

answered Nov 9 at 8:39

Pijotrek

4841416

I think it would be more stream-esque if you add n to the text with a separate .map call
– Tim Castelijns
Nov 9 at 8:41

I don't understand what that has to do with my comment
– Tim Castelijns
Nov 9 at 8:48

thanks Pijotrek, your code solved my problem, why I can not vote up ?
– patel
Nov 9 at 12:11

add a comment |

up vote
1
down vote

You can transform each line at source, meaning adding a map instruction just before the collect one:

lines.map(element -> element + 'n').collect(Collectors.toCollection(LinkedList::new)).descendingIterator()
 .forEachRemaining(testBuilder::append);

answered Nov 9 at 8:50

Bsquare

2,0561828

thanks Bsquare, at the beginning I did not understand your solution, but it works well
– patel
Nov 9 at 16:34

Nice it solves your issue. On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Nov 9 at 17:26

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
0
down vote

accepted

Simply try to change

.forEachRemaining(jTextArea1::append);

to:

.forEachRemaining(singleLine -> jTextArea1.append(singleLine + "n"));

answered Nov 9 at 8:39

Pijotrek

4841416

I think it would be more stream-esque if you add n to the text with a separate .map call
– Tim Castelijns
Nov 9 at 8:41

I don't understand what that has to do with my comment
– Tim Castelijns
Nov 9 at 8:48

thanks Pijotrek, your code solved my problem, why I can not vote up ?
– patel
Nov 9 at 12:11

add a comment |

up vote
0
down vote

accepted

Simply try to change

.forEachRemaining(jTextArea1::append);

to:

.forEachRemaining(singleLine -> jTextArea1.append(singleLine + "n"));

answered Nov 9 at 8:39

Pijotrek

4841416

I think it would be more stream-esque if you add n to the text with a separate .map call
– Tim Castelijns
Nov 9 at 8:41

I don't understand what that has to do with my comment
– Tim Castelijns
Nov 9 at 8:48

thanks Pijotrek, your code solved my problem, why I can not vote up ?
– patel
Nov 9 at 12:11

add a comment |

up vote
0
down vote

accepted

Simply try to change

.forEachRemaining(jTextArea1::append);

to:

.forEachRemaining(singleLine -> jTextArea1.append(singleLine + "n"));

answered Nov 9 at 8:39

Pijotrek

4841416

Simply try to change

.forEachRemaining(jTextArea1::append);

to:

.forEachRemaining(singleLine -> jTextArea1.append(singleLine + "n"));

answered Nov 9 at 8:39

Pijotrek

4841416

answered Nov 9 at 8:39

Pijotrek

4841416

answered Nov 9 at 8:39

Pijotrek

4841416

answered Nov 9 at 8:39

Pijotrek

4841416

I think it would be more stream-esque if you add n to the text with a separate .map call
– Tim Castelijns
Nov 9 at 8:41

I don't understand what that has to do with my comment
– Tim Castelijns
Nov 9 at 8:48

thanks Pijotrek, your code solved my problem, why I can not vote up ?
– patel
Nov 9 at 12:11

add a comment |

I think it would be more stream-esque if you add n to the text with a separate .map call
– Tim Castelijns
Nov 9 at 8:41

I don't understand what that has to do with my comment
– Tim Castelijns
Nov 9 at 8:48

thanks Pijotrek, your code solved my problem, why I can not vote up ?
– patel
Nov 9 at 12:11

I think it would be more stream-esque if you add n to the text with a separate .map call
– Tim Castelijns
Nov 9 at 8:41

I don't understand what that has to do with my comment
– Tim Castelijns
Nov 9 at 8:48

thanks Pijotrek, your code solved my problem, why I can not vote up ?
– patel
Nov 9 at 12:11

add a comment |

up vote
1
down vote

You can transform each line at source, meaning adding a map instruction just before the collect one:

lines.map(element -> element + 'n').collect(Collectors.toCollection(LinkedList::new)).descendingIterator()
 .forEachRemaining(testBuilder::append);

answered Nov 9 at 8:50

Bsquare

2,0561828

thanks Bsquare, at the beginning I did not understand your solution, but it works well
– patel
Nov 9 at 16:34

Nice it solves your issue. On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Nov 9 at 17:26

add a comment |

up vote
1
down vote

You can transform each line at source, meaning adding a map instruction just before the collect one:

lines.map(element -> element + 'n').collect(Collectors.toCollection(LinkedList::new)).descendingIterator()
 .forEachRemaining(testBuilder::append);

answered Nov 9 at 8:50

Bsquare

2,0561828

thanks Bsquare, at the beginning I did not understand your solution, but it works well
– patel
Nov 9 at 16:34

Nice it solves your issue. On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Nov 9 at 17:26

add a comment |

up vote
1
down vote

You can transform each line at source, meaning adding a map instruction just before the collect one:

lines.map(element -> element + 'n').collect(Collectors.toCollection(LinkedList::new)).descendingIterator()
 .forEachRemaining(testBuilder::append);

answered Nov 9 at 8:50

Bsquare

2,0561828

You can transform each line at source, meaning adding a map instruction just before the collect one:

lines.map(element -> element + 'n').collect(Collectors.toCollection(LinkedList::new)).descendingIterator()
 .forEachRemaining(testBuilder::append);

answered Nov 9 at 8:50

Bsquare

2,0561828

answered Nov 9 at 8:50

Bsquare

2,0561828

answered Nov 9 at 8:50

Bsquare

2,0561828

answered Nov 9 at 8:50

Bsquare

2,0561828

thanks Bsquare, at the beginning I did not understand your solution, but it works well
– patel
Nov 9 at 16:34

Nice it solves your issue. On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Nov 9 at 17:26

add a comment |

thanks Bsquare, at the beginning I did not understand your solution, but it works well
– patel
Nov 9 at 16:34

Nice it solves your issue. On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Nov 9 at 17:26

thanks Bsquare, at the beginning I did not understand your solution, but it works well
– patel
Nov 9 at 16:34

Nice it solves your issue. On Stackoverflow you could give up-vote to people's helpful answers to thank them and select any one of the answer as correct answer too out of all.
– Bsquare
Nov 9 at 17:26

add a comment |

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