Different output from dfs iterative and dfs recursive









up vote
3
down vote

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This program is for dfs traversal of graph one function is a iterative method and another function is a recursive method but both are giving different answer
from iterative i am getting 01234
from recursive i am getting 02341 can any one explain me why?




NOTE -> User is entering weights here but they are of no use in this implementation of dfs ,i was implementing dijkstra so i considered the weights there ,iam telling you this so that you will not confuse




program is exactly correct you can paste it in your compiler



// C program for array implementation of stack
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>

// A structure to represent a stack
struct Stack

int top;
unsigned capacity;
int* array;
;
int visited[100];
// function to create a stack of given capacity. It initializes size of
// stack as 0
struct Stack* createStack(unsigned capacity)

struct Stack* stack = (struct Stack*) malloc(sizeof(struct Stack));
stack->capacity = capacity;
stack->top = -1;
stack->array = (int*)malloc(stack->capacity * sizeof(int));
return stack;


// Stack is full when top is equal to the last index
int isFull(struct Stack* stack)

return stack->top == stack->capacity - 1;


// Stack is empty when top is equal to -1
int isEmpty(struct Stack* stack)

return stack->top == -1;


// Function to add an item to stack. It increases top by 1
void push(struct Stack* stack, int item)

if (isFull(stack))
return;
stack->array[++stack->top] = item;
//printf("%d pushed to stackn", item);


// Function to remove an item from stack. It decreases top by 1
int pop(struct Stack* stack)

if (isEmpty(stack))
return INT_MIN;
return stack->array[stack->top--];




struct adjlistnode
int data;
struct adjlistnode* next;
;
struct adjlist
struct adjlistnode* head;
;
struct graph
int v;
struct adjlist* array;
;
struct graph* creategraph(int v)
struct graph* G = (struct graph*) malloc(sizeof(struct graph));
G->v = v;
int i;
G->array = (struct adjlist*)malloc(sizeof(struct adjlist)*v);
for (i = 0; i < v; i++)
G->array[i].head = NULL;

return G;

int weight[100][100], Distance[50], path[50];
struct adjlistnode* getnewnode(int ver)
struct adjlistnode* newnode = (struct adjlistnode*)malloc(sizeof(struct adjlistnode));
newnode->data = ver;
newnode->next = NULL;
return newnode;


void addedge(struct graph* G, int src, int dest)
struct adjlistnode* temp;
temp = getnewnode(dest);
temp->next = G->array[src].head;
G->array[src].head = temp;

//temp = getnewnode(src);
///*temp->next = G->array[dest].head;
//G->array[dest].head = temp;*/
printf(" Enter the weight : ");
int w;
scanf("%d", &w);
weight[src][dest] = w;
weight[dest][src] = w;

void printgraph(struct graph* G)
for (int i = 0; i < G->v; i++)
struct adjlistnode* temp = G->array[i].head;
printf("%d-> ", i);
while (temp)
printf(" %d", temp->data);
temp = temp->next;

printf("n");








// Driver program to test above functions
void dfsiterative(struct graph* G, struct Stack* stack, int s)
int v, w;
push(stack, s);
visited[s] = 1;
while (!isEmpty(stack))
v = pop(stack);

printf("%d", v); ///process v
struct adjlistnode* temp = G->array[v].head;
while (temp)
w = temp->data;
if (visited[w] == 0)
push(stack, w);
visited[w] = 1;

temp = temp->next;



void dfsrecursive(struct graph* G, int s)
visited[s] = 1;
printf("%d", s);
struct adjlistnode* temp = G->array[s].head;
while (temp)
int w = temp->data;
if (visited[w] == 0)
dfsrecursive(G, w);
temp = temp->next;




int main()

// Create a Priority Queue
// 7->4->5->6
struct Stack* stack = createStack(100);
struct graph* G = creategraph(5);
addedge(G, 0, 1);
addedge(G, 1, 2);
addedge(G, 2, 3);
addedge(G, 3, 4);
addedge(G, 0, 2);
for (int i = 0; i < 30; i++)
visited[i] = 0;

printgraph(G);
printf("n");

//dfsiterative(G,stack,0);
dfsrecursive(G, 0);

return 0;










share|improve this question























  • So, basically You're asking what Your program is doing?
    – Kamiccolo
    Nov 9 at 10:55














up vote
3
down vote

favorite












This program is for dfs traversal of graph one function is a iterative method and another function is a recursive method but both are giving different answer
from iterative i am getting 01234
from recursive i am getting 02341 can any one explain me why?




NOTE -> User is entering weights here but they are of no use in this implementation of dfs ,i was implementing dijkstra so i considered the weights there ,iam telling you this so that you will not confuse




program is exactly correct you can paste it in your compiler



// C program for array implementation of stack
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>

// A structure to represent a stack
struct Stack

int top;
unsigned capacity;
int* array;
;
int visited[100];
// function to create a stack of given capacity. It initializes size of
// stack as 0
struct Stack* createStack(unsigned capacity)

struct Stack* stack = (struct Stack*) malloc(sizeof(struct Stack));
stack->capacity = capacity;
stack->top = -1;
stack->array = (int*)malloc(stack->capacity * sizeof(int));
return stack;


// Stack is full when top is equal to the last index
int isFull(struct Stack* stack)

return stack->top == stack->capacity - 1;


// Stack is empty when top is equal to -1
int isEmpty(struct Stack* stack)

return stack->top == -1;


// Function to add an item to stack. It increases top by 1
void push(struct Stack* stack, int item)

if (isFull(stack))
return;
stack->array[++stack->top] = item;
//printf("%d pushed to stackn", item);


// Function to remove an item from stack. It decreases top by 1
int pop(struct Stack* stack)

if (isEmpty(stack))
return INT_MIN;
return stack->array[stack->top--];




struct adjlistnode
int data;
struct adjlistnode* next;
;
struct adjlist
struct adjlistnode* head;
;
struct graph
int v;
struct adjlist* array;
;
struct graph* creategraph(int v)
struct graph* G = (struct graph*) malloc(sizeof(struct graph));
G->v = v;
int i;
G->array = (struct adjlist*)malloc(sizeof(struct adjlist)*v);
for (i = 0; i < v; i++)
G->array[i].head = NULL;

return G;

int weight[100][100], Distance[50], path[50];
struct adjlistnode* getnewnode(int ver)
struct adjlistnode* newnode = (struct adjlistnode*)malloc(sizeof(struct adjlistnode));
newnode->data = ver;
newnode->next = NULL;
return newnode;


void addedge(struct graph* G, int src, int dest)
struct adjlistnode* temp;
temp = getnewnode(dest);
temp->next = G->array[src].head;
G->array[src].head = temp;

//temp = getnewnode(src);
///*temp->next = G->array[dest].head;
//G->array[dest].head = temp;*/
printf(" Enter the weight : ");
int w;
scanf("%d", &w);
weight[src][dest] = w;
weight[dest][src] = w;

void printgraph(struct graph* G)
for (int i = 0; i < G->v; i++)
struct adjlistnode* temp = G->array[i].head;
printf("%d-> ", i);
while (temp)
printf(" %d", temp->data);
temp = temp->next;

printf("n");








// Driver program to test above functions
void dfsiterative(struct graph* G, struct Stack* stack, int s)
int v, w;
push(stack, s);
visited[s] = 1;
while (!isEmpty(stack))
v = pop(stack);

printf("%d", v); ///process v
struct adjlistnode* temp = G->array[v].head;
while (temp)
w = temp->data;
if (visited[w] == 0)
push(stack, w);
visited[w] = 1;

temp = temp->next;



void dfsrecursive(struct graph* G, int s)
visited[s] = 1;
printf("%d", s);
struct adjlistnode* temp = G->array[s].head;
while (temp)
int w = temp->data;
if (visited[w] == 0)
dfsrecursive(G, w);
temp = temp->next;




int main()

// Create a Priority Queue
// 7->4->5->6
struct Stack* stack = createStack(100);
struct graph* G = creategraph(5);
addedge(G, 0, 1);
addedge(G, 1, 2);
addedge(G, 2, 3);
addedge(G, 3, 4);
addedge(G, 0, 2);
for (int i = 0; i < 30; i++)
visited[i] = 0;

printgraph(G);
printf("n");

//dfsiterative(G,stack,0);
dfsrecursive(G, 0);

return 0;










share|improve this question























  • So, basically You're asking what Your program is doing?
    – Kamiccolo
    Nov 9 at 10:55












up vote
3
down vote

favorite









up vote
3
down vote

favorite











This program is for dfs traversal of graph one function is a iterative method and another function is a recursive method but both are giving different answer
from iterative i am getting 01234
from recursive i am getting 02341 can any one explain me why?




NOTE -> User is entering weights here but they are of no use in this implementation of dfs ,i was implementing dijkstra so i considered the weights there ,iam telling you this so that you will not confuse




program is exactly correct you can paste it in your compiler



// C program for array implementation of stack
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>

// A structure to represent a stack
struct Stack

int top;
unsigned capacity;
int* array;
;
int visited[100];
// function to create a stack of given capacity. It initializes size of
// stack as 0
struct Stack* createStack(unsigned capacity)

struct Stack* stack = (struct Stack*) malloc(sizeof(struct Stack));
stack->capacity = capacity;
stack->top = -1;
stack->array = (int*)malloc(stack->capacity * sizeof(int));
return stack;


// Stack is full when top is equal to the last index
int isFull(struct Stack* stack)

return stack->top == stack->capacity - 1;


// Stack is empty when top is equal to -1
int isEmpty(struct Stack* stack)

return stack->top == -1;


// Function to add an item to stack. It increases top by 1
void push(struct Stack* stack, int item)

if (isFull(stack))
return;
stack->array[++stack->top] = item;
//printf("%d pushed to stackn", item);


// Function to remove an item from stack. It decreases top by 1
int pop(struct Stack* stack)

if (isEmpty(stack))
return INT_MIN;
return stack->array[stack->top--];




struct adjlistnode
int data;
struct adjlistnode* next;
;
struct adjlist
struct adjlistnode* head;
;
struct graph
int v;
struct adjlist* array;
;
struct graph* creategraph(int v)
struct graph* G = (struct graph*) malloc(sizeof(struct graph));
G->v = v;
int i;
G->array = (struct adjlist*)malloc(sizeof(struct adjlist)*v);
for (i = 0; i < v; i++)
G->array[i].head = NULL;

return G;

int weight[100][100], Distance[50], path[50];
struct adjlistnode* getnewnode(int ver)
struct adjlistnode* newnode = (struct adjlistnode*)malloc(sizeof(struct adjlistnode));
newnode->data = ver;
newnode->next = NULL;
return newnode;


void addedge(struct graph* G, int src, int dest)
struct adjlistnode* temp;
temp = getnewnode(dest);
temp->next = G->array[src].head;
G->array[src].head = temp;

//temp = getnewnode(src);
///*temp->next = G->array[dest].head;
//G->array[dest].head = temp;*/
printf(" Enter the weight : ");
int w;
scanf("%d", &w);
weight[src][dest] = w;
weight[dest][src] = w;

void printgraph(struct graph* G)
for (int i = 0; i < G->v; i++)
struct adjlistnode* temp = G->array[i].head;
printf("%d-> ", i);
while (temp)
printf(" %d", temp->data);
temp = temp->next;

printf("n");








// Driver program to test above functions
void dfsiterative(struct graph* G, struct Stack* stack, int s)
int v, w;
push(stack, s);
visited[s] = 1;
while (!isEmpty(stack))
v = pop(stack);

printf("%d", v); ///process v
struct adjlistnode* temp = G->array[v].head;
while (temp)
w = temp->data;
if (visited[w] == 0)
push(stack, w);
visited[w] = 1;

temp = temp->next;



void dfsrecursive(struct graph* G, int s)
visited[s] = 1;
printf("%d", s);
struct adjlistnode* temp = G->array[s].head;
while (temp)
int w = temp->data;
if (visited[w] == 0)
dfsrecursive(G, w);
temp = temp->next;




int main()

// Create a Priority Queue
// 7->4->5->6
struct Stack* stack = createStack(100);
struct graph* G = creategraph(5);
addedge(G, 0, 1);
addedge(G, 1, 2);
addedge(G, 2, 3);
addedge(G, 3, 4);
addedge(G, 0, 2);
for (int i = 0; i < 30; i++)
visited[i] = 0;

printgraph(G);
printf("n");

//dfsiterative(G,stack,0);
dfsrecursive(G, 0);

return 0;










share|improve this question















This program is for dfs traversal of graph one function is a iterative method and another function is a recursive method but both are giving different answer
from iterative i am getting 01234
from recursive i am getting 02341 can any one explain me why?




NOTE -> User is entering weights here but they are of no use in this implementation of dfs ,i was implementing dijkstra so i considered the weights there ,iam telling you this so that you will not confuse




program is exactly correct you can paste it in your compiler



// C program for array implementation of stack
#include <stdio.h>
#include <stdlib.h>
#include <limits.h>

// A structure to represent a stack
struct Stack

int top;
unsigned capacity;
int* array;
;
int visited[100];
// function to create a stack of given capacity. It initializes size of
// stack as 0
struct Stack* createStack(unsigned capacity)

struct Stack* stack = (struct Stack*) malloc(sizeof(struct Stack));
stack->capacity = capacity;
stack->top = -1;
stack->array = (int*)malloc(stack->capacity * sizeof(int));
return stack;


// Stack is full when top is equal to the last index
int isFull(struct Stack* stack)

return stack->top == stack->capacity - 1;


// Stack is empty when top is equal to -1
int isEmpty(struct Stack* stack)

return stack->top == -1;


// Function to add an item to stack. It increases top by 1
void push(struct Stack* stack, int item)

if (isFull(stack))
return;
stack->array[++stack->top] = item;
//printf("%d pushed to stackn", item);


// Function to remove an item from stack. It decreases top by 1
int pop(struct Stack* stack)

if (isEmpty(stack))
return INT_MIN;
return stack->array[stack->top--];




struct adjlistnode
int data;
struct adjlistnode* next;
;
struct adjlist
struct adjlistnode* head;
;
struct graph
int v;
struct adjlist* array;
;
struct graph* creategraph(int v)
struct graph* G = (struct graph*) malloc(sizeof(struct graph));
G->v = v;
int i;
G->array = (struct adjlist*)malloc(sizeof(struct adjlist)*v);
for (i = 0; i < v; i++)
G->array[i].head = NULL;

return G;

int weight[100][100], Distance[50], path[50];
struct adjlistnode* getnewnode(int ver)
struct adjlistnode* newnode = (struct adjlistnode*)malloc(sizeof(struct adjlistnode));
newnode->data = ver;
newnode->next = NULL;
return newnode;


void addedge(struct graph* G, int src, int dest)
struct adjlistnode* temp;
temp = getnewnode(dest);
temp->next = G->array[src].head;
G->array[src].head = temp;

//temp = getnewnode(src);
///*temp->next = G->array[dest].head;
//G->array[dest].head = temp;*/
printf(" Enter the weight : ");
int w;
scanf("%d", &w);
weight[src][dest] = w;
weight[dest][src] = w;

void printgraph(struct graph* G)
for (int i = 0; i < G->v; i++)
struct adjlistnode* temp = G->array[i].head;
printf("%d-> ", i);
while (temp)
printf(" %d", temp->data);
temp = temp->next;

printf("n");








// Driver program to test above functions
void dfsiterative(struct graph* G, struct Stack* stack, int s)
int v, w;
push(stack, s);
visited[s] = 1;
while (!isEmpty(stack))
v = pop(stack);

printf("%d", v); ///process v
struct adjlistnode* temp = G->array[v].head;
while (temp)
w = temp->data;
if (visited[w] == 0)
push(stack, w);
visited[w] = 1;

temp = temp->next;



void dfsrecursive(struct graph* G, int s)
visited[s] = 1;
printf("%d", s);
struct adjlistnode* temp = G->array[s].head;
while (temp)
int w = temp->data;
if (visited[w] == 0)
dfsrecursive(G, w);
temp = temp->next;




int main()

// Create a Priority Queue
// 7->4->5->6
struct Stack* stack = createStack(100);
struct graph* G = creategraph(5);
addedge(G, 0, 1);
addedge(G, 1, 2);
addedge(G, 2, 3);
addedge(G, 3, 4);
addedge(G, 0, 2);
for (int i = 0; i < 30; i++)
visited[i] = 0;

printgraph(G);
printf("n");

//dfsiterative(G,stack,0);
dfsrecursive(G, 0);

return 0;







c algorithm data-structures graph-theory depth-first-search






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edited Nov 9 at 16:02









Dominique Fortin

1,642816




1,642816










asked Nov 9 at 10:54









humblefool

1396




1396











  • So, basically You're asking what Your program is doing?
    – Kamiccolo
    Nov 9 at 10:55
















  • So, basically You're asking what Your program is doing?
    – Kamiccolo
    Nov 9 at 10:55















So, basically You're asking what Your program is doing?
– Kamiccolo
Nov 9 at 10:55




So, basically You're asking what Your program is doing?
– Kamiccolo
Nov 9 at 10:55












1 Answer
1






active

oldest

votes

















up vote
2
down vote



accepted










Your iterative and recursive dfs functions produce different outputs because they operate differently when a node is connected to multiple nodes.



To take your example, 0 is connected to 1 and 2.



The recursive function will call dfsrecursive on 1 as it's the first node in adjacency list and thus 1 will appear before 2.



In the iterative version, both 1 and 2 will be pushed on the stack in order. Since 2 was pushed last, it will be popped before 1. Hence, 2 will be printed before 1.



Obviously, this change in order also affects other nodes as the two algorithms diverge.



I don't really see any problem with this, but if it bothers you, you can try reversing the order in which you push adjacent nodes to the stack. That should fix this problem.






share|improve this answer




















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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    2
    down vote



    accepted










    Your iterative and recursive dfs functions produce different outputs because they operate differently when a node is connected to multiple nodes.



    To take your example, 0 is connected to 1 and 2.



    The recursive function will call dfsrecursive on 1 as it's the first node in adjacency list and thus 1 will appear before 2.



    In the iterative version, both 1 and 2 will be pushed on the stack in order. Since 2 was pushed last, it will be popped before 1. Hence, 2 will be printed before 1.



    Obviously, this change in order also affects other nodes as the two algorithms diverge.



    I don't really see any problem with this, but if it bothers you, you can try reversing the order in which you push adjacent nodes to the stack. That should fix this problem.






    share|improve this answer
























      up vote
      2
      down vote



      accepted










      Your iterative and recursive dfs functions produce different outputs because they operate differently when a node is connected to multiple nodes.



      To take your example, 0 is connected to 1 and 2.



      The recursive function will call dfsrecursive on 1 as it's the first node in adjacency list and thus 1 will appear before 2.



      In the iterative version, both 1 and 2 will be pushed on the stack in order. Since 2 was pushed last, it will be popped before 1. Hence, 2 will be printed before 1.



      Obviously, this change in order also affects other nodes as the two algorithms diverge.



      I don't really see any problem with this, but if it bothers you, you can try reversing the order in which you push adjacent nodes to the stack. That should fix this problem.






      share|improve this answer






















        up vote
        2
        down vote



        accepted







        up vote
        2
        down vote



        accepted






        Your iterative and recursive dfs functions produce different outputs because they operate differently when a node is connected to multiple nodes.



        To take your example, 0 is connected to 1 and 2.



        The recursive function will call dfsrecursive on 1 as it's the first node in adjacency list and thus 1 will appear before 2.



        In the iterative version, both 1 and 2 will be pushed on the stack in order. Since 2 was pushed last, it will be popped before 1. Hence, 2 will be printed before 1.



        Obviously, this change in order also affects other nodes as the two algorithms diverge.



        I don't really see any problem with this, but if it bothers you, you can try reversing the order in which you push adjacent nodes to the stack. That should fix this problem.






        share|improve this answer












        Your iterative and recursive dfs functions produce different outputs because they operate differently when a node is connected to multiple nodes.



        To take your example, 0 is connected to 1 and 2.



        The recursive function will call dfsrecursive on 1 as it's the first node in adjacency list and thus 1 will appear before 2.



        In the iterative version, both 1 and 2 will be pushed on the stack in order. Since 2 was pushed last, it will be popped before 1. Hence, 2 will be printed before 1.



        Obviously, this change in order also affects other nodes as the two algorithms diverge.



        I don't really see any problem with this, but if it bothers you, you can try reversing the order in which you push adjacent nodes to the stack. That should fix this problem.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 9 at 11:16









        merlyn

        1,28011221




        1,28011221



























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