Query string parameter name different than model property name









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Have a basic search form. Is there something built into the MVC model binder that can take a different (shorter) name of the parameter and bind it with the desired model property?



For instance I want fn instead of SearchFirstName to appear in the address bar.



Model:



public class SampleModel

public string SearchFirstName get; set;



Controller:



public ActionResult Search([FromUri] SampleModel model)




Sending /search?fn=foo makes SearchFirstName=foo



I know I can do something manually within the controller property by property but don't want to reinvent the wheel if it's built in already.



Using .NET framework 4.6.1










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  • You would need to create a custom ModelBinder to read the value from the request and set the property of your model.
    – Stephen Muecke
    Nov 8 at 21:04














up vote
1
down vote

favorite












Have a basic search form. Is there something built into the MVC model binder that can take a different (shorter) name of the parameter and bind it with the desired model property?



For instance I want fn instead of SearchFirstName to appear in the address bar.



Model:



public class SampleModel

public string SearchFirstName get; set;



Controller:



public ActionResult Search([FromUri] SampleModel model)




Sending /search?fn=foo makes SearchFirstName=foo



I know I can do something manually within the controller property by property but don't want to reinvent the wheel if it's built in already.



Using .NET framework 4.6.1










share|improve this question





















  • You would need to create a custom ModelBinder to read the value from the request and set the property of your model.
    – Stephen Muecke
    Nov 8 at 21:04












up vote
1
down vote

favorite









up vote
1
down vote

favorite











Have a basic search form. Is there something built into the MVC model binder that can take a different (shorter) name of the parameter and bind it with the desired model property?



For instance I want fn instead of SearchFirstName to appear in the address bar.



Model:



public class SampleModel

public string SearchFirstName get; set;



Controller:



public ActionResult Search([FromUri] SampleModel model)




Sending /search?fn=foo makes SearchFirstName=foo



I know I can do something manually within the controller property by property but don't want to reinvent the wheel if it's built in already.



Using .NET framework 4.6.1










share|improve this question













Have a basic search form. Is there something built into the MVC model binder that can take a different (shorter) name of the parameter and bind it with the desired model property?



For instance I want fn instead of SearchFirstName to appear in the address bar.



Model:



public class SampleModel

public string SearchFirstName get; set;



Controller:



public ActionResult Search([FromUri] SampleModel model)




Sending /search?fn=foo makes SearchFirstName=foo



I know I can do something manually within the controller property by property but don't want to reinvent the wheel if it's built in already.



Using .NET framework 4.6.1







asp.net-mvc model-binding






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 8 at 20:15









joym8

1,61022145




1,61022145











  • You would need to create a custom ModelBinder to read the value from the request and set the property of your model.
    – Stephen Muecke
    Nov 8 at 21:04
















  • You would need to create a custom ModelBinder to read the value from the request and set the property of your model.
    – Stephen Muecke
    Nov 8 at 21:04















You would need to create a custom ModelBinder to read the value from the request and set the property of your model.
– Stephen Muecke
Nov 8 at 21:04




You would need to create a custom ModelBinder to read the value from the request and set the property of your model.
– Stephen Muecke
Nov 8 at 21:04

















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