Compiling dict of users in Python for search results










0















I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:



 user = db.execute(
'SELECT * FROM user WHERE email = ?', (emailInput,)
).fetchone()
if user is None:
user_details =
'first' : 'error'

y = json.dumps(user_details)
return jsonify(y)
if user['first'] is None:
first = ""
else:
first = user['first']
if user['email'] is None:
email = ""
else:
email = user['email']
if user['last'] is None:
last = ""
else:
last = user['last']
if user['address_line1'] is None:
address_line1 = ""
else:
address_line1 = user['address_line1']
if user['address_line2'] is None:
address_line2 = ""
else:
address_line2 = user['address_line2']
if user['username'] is None:
username = ""
else:
username = user['username']
user_details =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username

y = json.dumps(user_details)
return jsonify(y)


Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.



EDIT:
what I really need help with is turning multiple structs like these:



 user_details = 
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username



into one big struct like this:



 users = 
user_details1 =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username

user_details2 =
'first': first,
'last': last,
'email': email,
'address1': address_line1,
'address2': address_line2,
'username': username

etc.










share|improve this question




























    0















    I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:



     user = db.execute(
    'SELECT * FROM user WHERE email = ?', (emailInput,)
    ).fetchone()
    if user is None:
    user_details =
    'first' : 'error'

    y = json.dumps(user_details)
    return jsonify(y)
    if user['first'] is None:
    first = ""
    else:
    first = user['first']
    if user['email'] is None:
    email = ""
    else:
    email = user['email']
    if user['last'] is None:
    last = ""
    else:
    last = user['last']
    if user['address_line1'] is None:
    address_line1 = ""
    else:
    address_line1 = user['address_line1']
    if user['address_line2'] is None:
    address_line2 = ""
    else:
    address_line2 = user['address_line2']
    if user['username'] is None:
    username = ""
    else:
    username = user['username']
    user_details =
    'first': first,
    'last': last,
    'email': email,
    'address1': address_line1,
    'address2': address_line2,
    'username': username

    y = json.dumps(user_details)
    return jsonify(y)


    Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.



    EDIT:
    what I really need help with is turning multiple structs like these:



     user_details = 
    'first': first,
    'last': last,
    'email': email,
    'address1': address_line1,
    'address2': address_line2,
    'username': username



    into one big struct like this:



     users = 
    user_details1 =
    'first': first,
    'last': last,
    'email': email,
    'address1': address_line1,
    'address2': address_line2,
    'username': username

    user_details2 =
    'first': first,
    'last': last,
    'email': email,
    'address1': address_line1,
    'address2': address_line2,
    'username': username

    etc.










    share|improve this question


























      0












      0








      0








      I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:



       user = db.execute(
      'SELECT * FROM user WHERE email = ?', (emailInput,)
      ).fetchone()
      if user is None:
      user_details =
      'first' : 'error'

      y = json.dumps(user_details)
      return jsonify(y)
      if user['first'] is None:
      first = ""
      else:
      first = user['first']
      if user['email'] is None:
      email = ""
      else:
      email = user['email']
      if user['last'] is None:
      last = ""
      else:
      last = user['last']
      if user['address_line1'] is None:
      address_line1 = ""
      else:
      address_line1 = user['address_line1']
      if user['address_line2'] is None:
      address_line2 = ""
      else:
      address_line2 = user['address_line2']
      if user['username'] is None:
      username = ""
      else:
      username = user['username']
      user_details =
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username

      y = json.dumps(user_details)
      return jsonify(y)


      Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.



      EDIT:
      what I really need help with is turning multiple structs like these:



       user_details = 
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username



      into one big struct like this:



       users = 
      user_details1 =
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username

      user_details2 =
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username

      etc.










      share|improve this question
















      I am not very familiar with Python or SQL and have been tasked with creating a search results page to display user information from an SQL database. I am using flask, sending JSON objects from the python back-end to the javascript/jquery front-end. I have managed to display a user when there is only one user returned from a search (a search by email address) with the following code:



       user = db.execute(
      'SELECT * FROM user WHERE email = ?', (emailInput,)
      ).fetchone()
      if user is None:
      user_details =
      'first' : 'error'

      y = json.dumps(user_details)
      return jsonify(y)
      if user['first'] is None:
      first = ""
      else:
      first = user['first']
      if user['email'] is None:
      email = ""
      else:
      email = user['email']
      if user['last'] is None:
      last = ""
      else:
      last = user['last']
      if user['address_line1'] is None:
      address_line1 = ""
      else:
      address_line1 = user['address_line1']
      if user['address_line2'] is None:
      address_line2 = ""
      else:
      address_line2 = user['address_line2']
      if user['username'] is None:
      username = ""
      else:
      username = user['username']
      user_details =
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username

      y = json.dumps(user_details)
      return jsonify(y)


      Now I want to upgrade this code with a fetchall() to return the user_details of every user fetched by the SQL call but I don't know how to go about it. Thanks in advance for the help.



      EDIT:
      what I really need help with is turning multiple structs like these:



       user_details = 
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username



      into one big struct like this:



       users = 
      user_details1 =
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username

      user_details2 =
      'first': first,
      'last': last,
      'email': email,
      'address1': address_line1,
      'address2': address_line2,
      'username': username

      etc.







      python sql json






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      share|improve this question




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      edited Nov 13 '18 at 0:23







      Japhy

















      asked Nov 13 '18 at 0:01









      JaphyJaphy

      234




      234






















          2 Answers
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          0














          Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)






          share|improve this answer






























            0














            fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



            users = db.execute(
            'SELECT * FROM user WHERE email = ?', (emailInput,)
            ).fetchall()
            for user in users:
            if user['first'] is None:
            <etc>





            share|improve this answer






















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              2 Answers
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              2 Answers
              2






              active

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              active

              oldest

              votes






              active

              oldest

              votes









              0














              Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)






              share|improve this answer



























                0














                Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)






                share|improve this answer

























                  0












                  0








                  0







                  Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)






                  share|improve this answer













                  Instead of spending a few hours solving this specific SQL problem, spend a few hours learning an ORM like sqlalchemy so you never have to write SQL again :)







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 13 '18 at 0:08









                  rikAteerikAtee

                  4,92053059




                  4,92053059























                      0














                      fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



                      users = db.execute(
                      'SELECT * FROM user WHERE email = ?', (emailInput,)
                      ).fetchall()
                      for user in users:
                      if user['first'] is None:
                      <etc>





                      share|improve this answer



























                        0














                        fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



                        users = db.execute(
                        'SELECT * FROM user WHERE email = ?', (emailInput,)
                        ).fetchall()
                        for user in users:
                        if user['first'] is None:
                        <etc>





                        share|improve this answer

























                          0












                          0








                          0







                          fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



                          users = db.execute(
                          'SELECT * FROM user WHERE email = ?', (emailInput,)
                          ).fetchall()
                          for user in users:
                          if user['first'] is None:
                          <etc>





                          share|improve this answer













                          fetchall returns a list of lists, so you just need to iterate over the outer list (rows of the table). For example:



                          users = db.execute(
                          'SELECT * FROM user WHERE email = ?', (emailInput,)
                          ).fetchall()
                          for user in users:
                          if user['first'] is None:
                          <etc>






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 13 '18 at 0:12









                          rd_nielsenrd_nielsen

                          1,6102616




                          1,6102616



























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