How to sort multi-level dictionaries by it's value?

I just wanted to sort this dict by value of runs scored by the player, but I'm not getting it how to do this.

orangecap('test1':'Ashwin':84, 'Kohli':120, 'test2':'ashwin':59, 'Pujara':42)


here "orangecap" is the def for the function to be called, and I want to return the name of highest scorer's name (in this case: Kohli)..

Can this be done without using external libraries?

2 Answers
2

Setup

dict_of_dicts =
'test1': 'Ashwin' :84, 'Kohli': 120,
'test2': 'ashwin': 59, 'Pujara': 42,
'test3': 'Pandas': 120, 'R': 119



Solution

It appears that you have a dict of dicts (not a list). You need to iterate through each value in the list and see if it is higher that the max value (initially set to None, along with the name of the player and the first key, e.g. test1, test2, etc.). If it is, reset their values to the new max value and append the player name and key to the list holding those who obtained the max value (to account for ties, e.g. Kohli & Pandas).

test1

test2

def orangecap(dict_of_dicts):
max_key_name =
max_score = None
for key in dict_of_dicts:
for name, score in dict_of_dicts[key].iteritems(): # .items() in Python 3.
if score > max_score:
max_key_name = [(key, name)]
max_score = score
elif score == max_score:
max_key_name.append((key, name))
return max_key_name, max_score

>>> orangecap(dict_of_dicts=dict_of_dicts)
([('test1', 'Kohli'), ('test3', 'Pandas')], 120)


iteritems

items

A very simple solution for this would be to iterate over the dict of dict, use two variables to store runs and player, like this -

def orangecap(your_dict):
max_runs = 0
player_scored = ''

for match, stats in your_dict.items():
for player, runs in stats.items():
if runs > max_runs:
max_runs = runs
player_scored = player
return player_scored


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