How can I do to extract some information with SQL Server ?










-1














I have this column with Microsoft SQL Server :



Date
6/19/2019 3:10:12 PM
12/23/2016 5:02:15 AM
13/25/2015 2:15:35 PM


And I would like to get two new column like this :



Date Hour 
06/19/2019 15:10:12
12/23/2016 05:02:15
13/25/2015 14:15:35


For the first column I just split the original column and I add a 0 for the first line and for the second I add a 0 and transform 03 to 15 removing PM. Thank you very much for the help !










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  • any comments on the answers below?
    – scsimon
    Dec 6 at 20:02















-1














I have this column with Microsoft SQL Server :



Date
6/19/2019 3:10:12 PM
12/23/2016 5:02:15 AM
13/25/2015 2:15:35 PM


And I would like to get two new column like this :



Date Hour 
06/19/2019 15:10:12
12/23/2016 05:02:15
13/25/2015 14:15:35


For the first column I just split the original column and I add a 0 for the first line and for the second I add a 0 and transform 03 to 15 removing PM. Thank you very much for the help !










share|improve this question





















  • any comments on the answers below?
    – scsimon
    Dec 6 at 20:02













-1












-1








-1







I have this column with Microsoft SQL Server :



Date
6/19/2019 3:10:12 PM
12/23/2016 5:02:15 AM
13/25/2015 2:15:35 PM


And I would like to get two new column like this :



Date Hour 
06/19/2019 15:10:12
12/23/2016 05:02:15
13/25/2015 14:15:35


For the first column I just split the original column and I add a 0 for the first line and for the second I add a 0 and transform 03 to 15 removing PM. Thank you very much for the help !










share|improve this question













I have this column with Microsoft SQL Server :



Date
6/19/2019 3:10:12 PM
12/23/2016 5:02:15 AM
13/25/2015 2:15:35 PM


And I would like to get two new column like this :



Date Hour 
06/19/2019 15:10:12
12/23/2016 05:02:15
13/25/2015 14:15:35


For the first column I just split the original column and I add a 0 for the first line and for the second I add a 0 and transform 03 to 15 removing PM. Thank you very much for the help !







sql sql-server database






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asked Nov 9 at 22:01









Peter H

81




81











  • any comments on the answers below?
    – scsimon
    Dec 6 at 20:02
















  • any comments on the answers below?
    – scsimon
    Dec 6 at 20:02















any comments on the answers below?
– scsimon
Dec 6 at 20:02




any comments on the answers below?
– scsimon
Dec 6 at 20:02












2 Answers
2






active

oldest

votes


















1














If I understand correctly, you would just cast to the types you want:



select cast(datetimecol as date) as datecol,
cast(datetimecol as time) as timecol
from t;





share|improve this answer




























    1














    You can use try_parse as another option if it is a varchar column.



    select try_parse('6/19/2019 3:10:12 PM' as date using 'en-US')
    select try_parse('6/19/2019 3:10:12 PM' as time using 'en-US')


    Or for your query



    select 
    try_parse('datetimecol' as date using 'en-US'),
    try_parse('datetimecol' as time using 'en-US')





    share|improve this answer




















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      If I understand correctly, you would just cast to the types you want:



      select cast(datetimecol as date) as datecol,
      cast(datetimecol as time) as timecol
      from t;





      share|improve this answer

























        1














        If I understand correctly, you would just cast to the types you want:



        select cast(datetimecol as date) as datecol,
        cast(datetimecol as time) as timecol
        from t;





        share|improve this answer























          1












          1








          1






          If I understand correctly, you would just cast to the types you want:



          select cast(datetimecol as date) as datecol,
          cast(datetimecol as time) as timecol
          from t;





          share|improve this answer












          If I understand correctly, you would just cast to the types you want:



          select cast(datetimecol as date) as datecol,
          cast(datetimecol as time) as timecol
          from t;






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 9 at 22:02









          Gordon Linoff

          755k35290398




          755k35290398























              1














              You can use try_parse as another option if it is a varchar column.



              select try_parse('6/19/2019 3:10:12 PM' as date using 'en-US')
              select try_parse('6/19/2019 3:10:12 PM' as time using 'en-US')


              Or for your query



              select 
              try_parse('datetimecol' as date using 'en-US'),
              try_parse('datetimecol' as time using 'en-US')





              share|improve this answer

























                1














                You can use try_parse as another option if it is a varchar column.



                select try_parse('6/19/2019 3:10:12 PM' as date using 'en-US')
                select try_parse('6/19/2019 3:10:12 PM' as time using 'en-US')


                Or for your query



                select 
                try_parse('datetimecol' as date using 'en-US'),
                try_parse('datetimecol' as time using 'en-US')





                share|improve this answer























                  1












                  1








                  1






                  You can use try_parse as another option if it is a varchar column.



                  select try_parse('6/19/2019 3:10:12 PM' as date using 'en-US')
                  select try_parse('6/19/2019 3:10:12 PM' as time using 'en-US')


                  Or for your query



                  select 
                  try_parse('datetimecol' as date using 'en-US'),
                  try_parse('datetimecol' as time using 'en-US')





                  share|improve this answer












                  You can use try_parse as another option if it is a varchar column.



                  select try_parse('6/19/2019 3:10:12 PM' as date using 'en-US')
                  select try_parse('6/19/2019 3:10:12 PM' as time using 'en-US')


                  Or for your query



                  select 
                  try_parse('datetimecol' as date using 'en-US'),
                  try_parse('datetimecol' as time using 'en-US')






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 9 at 22:03









                  scsimon

                  20.5k41536




                  20.5k41536



























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