Python text replace with for loop
Python text replace with for loop
I am just trying to remove all datetime values...
but everytime it is going to the beginning and refreshing the text with the last value. How can i delete the all time values ?
My text file is hey.txt and this is the inside of it:
14:15
24:32
trying
42:56
1:42
for
testing
Code part:
import re
filename = "hey.txt"
text = open(filename).read()
n,i,c,x,=(0,0,0,0)
datetimes =
for number in range(3600):
n+=1
b=str(n)
if n<10:
b = "0"+str(n)
elif n==60:
i+=1
n=0
datetimes.append("%d:%s"%(i,b))
for word in datetimes:
matches = re.compile(word).finditer(text)
for match in matches:
z= match.group(0)
print(z)
if z==word:
open("datetimes-doc.txt","w+").write(text.replace(z,""))
c+=1
elif z!=word:
c+=1
print("proccess:%d"%c)
and this is the my sending file datetimes-doc.txt
14:15
24:32
trying
1:42
for
testing
here is the some of output from console:
1:42
proccess:1
2:56
proccess:2
4:15
proccess:3
4:32
proccess:4
14:15
proccess:5
24:32
proccess:6
42:56
proccess:7
i am a newbie is there a better way ?
– San Diego
Aug 30 at 2:18
If your file is all times, and you want to remove them, why not just delete the file. If your file is not all datetimes, please provide an example to show what the other data looks like, in other words, an Minimal, Complete, and Verifiable example
– user3483203
Aug 30 at 2:18
Need more information. The output shown is what you expected or the result of your code? Are you trying to remove the hours and minutes?
– MichaelR
Aug 30 at 2:21
What are trying to accomplish?
– tpk
Aug 30 at 2:24
1 Answer
1
Rather than a for loop, why not:
#read entire file's content
with open('hey.txt') as f:
content = f.read()
# find time and replace with empty string
new_content = re.sub(r'[0-5]*[0-9]:[0-5]*[0-9]n','', content)
#write results into file
with open('hey2.txt', 'w') as f:
f.write(new_content)
It really worked. Thank you
– San Diego
Aug 30 at 22:21
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Why do you overwrite the file at each iteration?
– DYZ
Aug 30 at 2:15